A jumpy squirrel is trying to cross the street. Its velocity v as a function of time t is given in the graph
below where rightwards is the positive velocity direction
v (m/s)
3
4
-2-+
-3
-4-
-5
What is the squirrel's displacement Au from t = 1s to 2 s?
Answer with two significant digits.
m
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Answers

Answer 1

Answer: 2.5 m

Explanation: 1/2(1s)(5m/s)

=2.5.

Got it from Khan Academy


Related Questions

Bill is making waves on a rope with one end attached to a wall. When he starts moving the rope quickly, the frequency of the waves created on the rope doubles. What happens to the energy that is transferred to the wall when the frequency of the waves doubles?
a. halved
b. quadrupled
c. doubled
d. tripled

Answers

Answer:

The answer is C

Explanation:

The same amount of force is applied to both the wall and the rope

When the frequency of the wave is doubled the energy that is transferred to the wall will be doubled.

What is the frequency?

Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.

Bill is making waves on a rope with one end attached to a wall. When he starts moving the rope quickly, the frequency of the waves created on the rope doubles.

The energy that is transferred to the wall is propotional to the frequency of the waves.

Hence the energy that is transferred to the wall will be doubled.

To learn more about the frequency reference the link;

https://brainly.com/question/14926605

According to Rahul any two bricks tied together would fall faster than a single
one under the action of gravity by neglecting air resistance. Do you agree with
Rahul? Give a reason to support your answer.

Answers

Answer:

Rahul is wrong.

Explanation:

From Newton's universal law of gravitation, we know that the force of attraction between two falling body masses is directly proportional to product of masses of two bodies and has an inverse proportional relation with the square of the distance between the masses.

If the 2 masses are M1 & M2, while distance between them is d, this can be written as;

F ∝ M1•M2

And F ∝ 1/d²

We also know that the acceleration due to gravity is given as;

g = GM/r²

Where;

M is the mass of earth

r is the radius of earth

From the above 3 formulas, we can deduce that the value of the acceleration due to gravity(g) is independent of the 2 masses of the falling body as it depends on only the mass of the earth and radius of the earth.

This means that the acceleration due to gravity will be the same whether the bricks are doubled or whether it remains single.

Thus, they will fall with same velocity in each case. So Rahul is wrong.

Neutrons have a ____ charge

Answers

Answer:

Neutrons have no charge

Explanation:

Answer:

Neutrons don't have a charge....

Explanation:

Hope this helped!!!

Atoms of the same element can have different properties.

A) True

B) False

Answers

Answer:

False.

Explanation:

All atoms of the same element have the same number of protons, but some may have different numbers of neutrons.

PLEASE HELP 2 or 3 SENTENCES PLSLSLSLSL
How have scientists, inventors and / or engineers used the properties of States of Matter to benefit our society?

Answers

Answer:

threy need to do it. becuse they do

Explanation:

If a ball is rolled down a frictionless inclined plane from a height of 3 feet, to what height would it roll up to on the other side?

Answers

Answer:

It will roll up to its initial height from which it rolled from on the first hill

Explanation:

The given information are;

The height from which the ball is rolled = 3 feet[

The equation of the potential energy of the ball as it rolled down the frictionless inclined plane is given by the following equation;

m × g × h₁ = 1/2 × m × v² + 1/2×[2/5× m × r²) × [v/r]

Where;

m = The mass of the ball

h = The from which the ball is rolled down

v = The velocity of the ball

r = The radius of the ball

Therefore, all the potential energy, m × g × h, is converted into kinetic energy when the ball reached the ground

Similarly, as the ball rolls up on the other side, by the principle of energy conservation, all the kinetic energy is transformed into potential energy as follows

1/2 × m × v² + 1/2×[2/5× m × r²) × [v/r] = m × g × h₂, therefore, we have;

1/2 × m × v² + 1/2×[2/5× m × r²) × [v/r] = m × g × h₁ =  m × g × h₂

Therefore since m × g × h₁ =  m × g × h₂, then h₁ = h₂, the ball rises to the same height it started rolling from on the first hill.

what is torricellian vaccum

Answers

Answer:

a vacuum formed above the column of mercury in a mercury barometer.

Answer:

An air-free space above the free surface of a liquid in a vessel that is closed above the liquid

A gymnast pushed down on a trampoline during a routine. What is the reaction
force on the gymnast?
a) Friction pushes the gymnast forward across the trampoline.
b) Gravity pulls down on the gymnast.
c)Air resistance pushes back on the gymnast
d) The trampoline pushes back up on the gymnast.

Answers

Answer:

d) The trampoline pushes back up on the gymnast.

Explanation:

According to Newton's third law of motion; for every action force, there is an equal and opposite reaction force. The action force and reaction force are reciprocal to one another i.e. they act oppositely to one another. The reaction force acts in an opposite direction to the action force and vice versa.

In this question, a gymnast pushed down on a trampoline during a routine. This is called the ACTION FORCE. In conformity to Newton's third law, the trampoline pushes back up on the gymnast. This opposite force is called the REACTION FORCE.

Answer:

D) the trampoline pushes back up they gymnast

Explanation:

I NEED HELP SOLVING THIS!!!!!!!!!!!!

Jose Altuve hits a fastball with a velocity of 49.1 m/s (109.9 mph) at an angle of 22º. If left field is 96 m (315 ft) away, will this be a home run?

Answers

Answer:

Yes

Explanation:

The given parameters are;

The speed with which the fastball is hit, u = 49.1 m/s (109.9 mph)

The angle in which the fastball is hit, θ = 22°

The distance of the field = 96 m (315 ft)

The range of the projectile motion of the fastball is given by the following formula

[tex]Range = \dfrac{u^2 \times sin(2\cdot \theta)}{g}[/tex]

Where;

g = The acceleration due to gravity = 9.81 m/s², we have;

[tex]Range = \dfrac{49.1^2 \times sin(2\times22^{\circ})}{9.81} \approx 170.71 \ m[/tex]

Yes, given that the ball's range is larger than the extent of the field, the batter is able to safely reach home.

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