A group of friends Anna (A), Bjorn (B), Candice (C), David (D) and Ellen (E) want to enter a basketball contest that caters for teams of different sizes. A team with n players is called an n-team. A player can be in several different teams, including teams of the same size. There is a restriction however: players in a 2-team cannot play together in any larger team. For example, if friends A,B,C,D form the teams AB, BCD, ACD, then they cannot also form the teams BD or ABC, among others.


a) List all different 3-teams that the friends could enter.


b) What is the maximum number of teams that the friends can enter if they want to include exactly two 3-teams and at least one 2-team, but no other size teams.


c) What is the maximum number of teams that the friends can enter if they want to include exactly three 3-teams and at least one 2-team, but not other size teams.


d) The five friends want to enter 8 teams including at least one 2-team and at least one 3-team and no team of any other size. Find three ways of doing this with a different number of 3-teams in each case

From the given data set, the mean absolute deviation is 10.72

To determine the mean absolute deviation of the data set, we need to find the mean first.

mean = (0 + 1 + 3 + 10 + 12 + 12 + 15 + 17 + 18 + 22 + 66) / 11

mean = 16

Now, let's calculate the mean absolute deviation

|0 - 16| = 16

|1 - 16| = 15

|3 - 16| = 13

|10 - 16| = 6

|12 - 16| = 4

|12 - 16| = 4

|15 - 16| = 1

|17 - 16| = 1

|18 - 16| = 2

|22 - 16| = 6

|66 - 16| = 50

MAD = (16 + 15 + 13 + 6 + 4 + 4 + 1 + 1 + 2 + 6 + 50) / 11

MAD = 10.72

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The amount at end of the second quarter = [tex]42,448$ +2122,416$ = 2164.86$[/tex]

Interest for first quarter = [tex]2000 * 0,08*- = 40$\n4[/tex]

Amount at end of first quarter =[tex]40$ + 2000$ = 2040$[/tex]

Interest for second quarter = [tex]2040 * 0,08\n1\n* = 40,8$\n4[/tex]

Amount at end of second quarter = [tex]40,8$ + 2040$ = 2080,8$[/tex]

Interest for third quarter = [tex]2080,8 * 0,08*\n4\n= 41,616$[/tex]

Amount at end of third quarter = [tex]41,616$ +2080,0$ = 2122,416$[/tex]

1\nInterest for second quarter = [tex]2122,416 * 0,08 *-\n4\n= 42,44831$[/tex]

Amount at end of second quarter = [tex]42,448$ +2122,416$ = 2164.86$[/tex]

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The margin error for the given poll having 95% confidence level with sample size of 410 is equal to 3.15%.

Sample size n = 410

Confidence level = 95%

Margin of error for this poll, use the formula,

ME = Z× (√(p₁(1-p₁) / n))

where Z is the z-score corresponding to the desired level of confidence.

p₁ is the sample proportion = 0.12

Using attached z-score table,

For a 95% confidence level, the corresponding z-score is 1.96.

Substituting the given values, we get,

ME = 1.96 × (√(0.12× (1-0.12) / 410))

Simplifying the expression inside the parentheses, we get,

⇒ME = 1.96 ×  0.0160

⇒ME = 0.0315

Margin of error for this poll at the 95% confidence level is approximately 0.0315.

Therefore,  95% confidence level represents that the true proportion of people who like dogs is within 3.15% of the observed proportion of 12%.

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The plane's new velocity is 421.4 mph with a direction of 63.43 degrees relative to the air.

To solve this problem, we need to use vector addition. Let's first draw a diagram to represent the situation.

First, we need to break down the velocity of the plane and the velocity of the wind into their horizontal and vertical components.

The velocity of the plane can be broken down into a horizontal component of 500*cos(135) mph and a vertical component of 500*sin(135) mph.

The velocity of the wind can be broken down into a horizontal component of 60*cos(60) mph and a vertical component of 60*sin(60) mph.

Now, we can add these components together to get the resultant velocity.

The horizontal component of the resultant velocity is 500*cos(135) + 60*cos(60) = -189.28 mph. The negative sign indicates that the velocity is in the opposite direction of the plane's original direction.

The vertical component of the resultant velocity is 500*sin(135) + 60*sin(60) = 374.28 mph.

Using the Pythagorean theorem, we can find the magnitude of the resultant velocity:

|v| = sqrt((-189.28)^2 + (374.28)^2) = 421.4 mph.

Finally, we can find the direction of the resultant velocity using the inverse tangent function:

θ = tan^-1(374.28/-189.28) = -63.43 degrees.

So the plane's new velocity is 421.4 mph with a direction of 63.43 degrees relative to the air.

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Answer:

1 time, though your answer would be ongoing. If you the actual answer, it's 1.2

Step-by-step explanation:

Round to the nearest tenth.

Answer:

1.2

Step-by-step explanation:

Five can go into six 1.2 times because (1.2)(5)=6. Of course, if you want to know how many times five can go into 6 as a WHOLE, then the answer would obviously be 1.

Hope this helps a bit :)

The terminal point is (0.866025, 0.5) and the tangent of θ is 0.55735 for θ = π/6 radians.

When the angle is given as 0 radians (0 = π/6 radians), the terminal point of the angle is on the positive x-axis.

The terminal point represents the point in the coordinate system where a given angle and distance (or magnitude) from the origin are located.

For any angle a, the coordinates of the terminal point are given by:

x = cos(a)

y = sin(a).

In this case, the angle is a = π/6

Then the coordinates of the terminal point are:

x = cos(π/6) = 0.5

  = 0.866025

y = sin(π/6)

  = 0.5

So the terminal point is (0.866025, 0.5)

The quotient of the y-component and the x-component is the tangent of that angle:

tan(π/6) = 0.5/ 0.866025

            = 0.57735

Therefore, the terminal is (0.866025, 0.5) and the tangent is 0.55735.

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The question attached here seems to be incomplete, the complete question is:

If θ= π/6 radians then Identify the terminal point and tan θ.

To put the numbers in order from least to greatest, we can use the number line: -3.5 -2.1 -1 -0.5 0.5 2 4 4.2 5 5.8  Two numbers that are opposites and each more than 6 units away from 0 are -7 and 7.

First, let's put the numbers in order from least to greatest:

-3.5, -2.1, -1.5, -1, -0.5, 0.5, 3.5, 4, 4.2, 4.8, 5

Now, let's find two numbers that are opposites and each more than 6 units away from 0. One example would be -7 and 7. These numbers are opposites (since they have the same magnitude but different signs), and they are both more than 6 units away from 0.

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When rounded to the nearest hundredth, the result of the expression tan 33° × cos 42° × sin 70° is approximately 0.4511 .

To evaluate the given expression using the terms tan 33°, cos 42°, and sin 70°, you can use a scientific calculator or an online tool like the ALEKS calculator.

After evaluating each term, you would multiply the values together and round the result to the nearest hundredth. Here's the breakdown:

tan 33° ≈ 0.6494
cos 42° ≈ 0.7431
sin 70° ≈ 0.9397

Now multiply the values:

0.6494 × 0.7431 × 0.9397 ≈ 0.4511

So, the result of the expression tan 33° × cos 42° × sin 70° is approximately 0.4511 when rounded to the nearest hundredth.

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Answer:

Her dad is 36 years old and brother is 12

Step-by-step explanation:

Since Alesha's brother is one year older you need to add 11+1 to get her brothers age, which is 12.
To get Alesha's dad's age you need to multiply 12x3, which is 36.

So, Alesha's dad is 36 and her brother is 12

The appropriate null and alternative hypotheses for the experiment are:

Null hypothesis (H0): According to null hypothesis, the average time it takes for a person to experience pain relief from the new pain reliever is not beyond 15 minutes.

Alternative hypothesis (Ha): According to Alternative hypothesis, the average time it takes for a person to experience pain relief from the new pain reliever is significantly less than 15 minutes, indicating that the new ingredient does speed up pain relief.

The alternative and null hypotheses can be written as follows in symbols:

H0: = 15 (where μ is the population mean time for pain relief from the new pain reliever)

Ha: μ < 15

The one-tailed hypothesis test assumes that the new component of the painkiller can only reduce the duration of pain alleviation, not lengthen it. As a result, the rejection region will be in the left tail of the distribution, while the alternative hypothesis is one-tailed to the left.

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If both confidence intervals were correctly calculated (6. 53, 7. 95) is the 90 percent level. Therefore, the correct option is A.

To determine which confidence interval corresponds to the 90 percent level and the 98 percent level, we can look at the width of the intervals. The interval with the larger width is the one with a higher confidence level because it accounts for more possible variation in the data.

The first interval (6.53, 7.95) has a width of 7.95 - 6.53 = 1.42.

The second interval (6.20, 8.28) has a width of 8.28 - 6.20 = 2.08.

Since the second interval has a larger width, it corresponds to the higher confidence level of 98 percent. Therefore, the first interval corresponds to the 90 percent confidence level. The correct answer is option A. (6.53, 7.95) is the 90 percent level.

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The expression that is equivalent to −0.75(60–32n)–n is A. −45+23n.

A mathematical or algebraic expression is the combination of variables with numbers, constants, and values using algebraic operands, including addition, multiplication, subtraction, and division.

Mathematical expressions do not bear the equal symbol (+) unlike equations.

−0.75(60–32n)–n

Expanding:

-45 + 24n - n

Simplifying:

−45 + 23n

Thus, the equivalent expression is Option A.

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The fraction of the cookies do they still need to made after Cameron and Lindsey made 80 cookies is 1/2.

Fractions are referred to as the components of a whole in mathematics. A single thing or a collection of objects might be the entire. When we cut a slice of cake in real life from the entire cake, the part represents the percent of the cake. The word "fraction" is derived from Roman. "Fractus" means "broken" in Latin.

The fraction was expressed verbally in earlier times. It was afterwards presented in numerical form. A piece or sector of any quantity is another name for the fraction.

Total cookies to be made is 160

Out of which Cameron made 2/5 of the cookies so,

2/5 x 160 = 64 cookies are made by Cameron

Lindsey made 16 cookies

So total cookies that still need to be made is,

= 160 - (64 + 16) = 80

The fraction of cookies still need to made is 80/160 = 1/2 .

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t\The depreciation expense for the year ended December 31, 2009 using the straight-line method is $23,333.33.

The total cost of the equipment is $997,500 ($935,000 + $7,500 + $55,000). The depreciable cost is calculated by subtracting the salvage value from the total cost, which is $960,000 ($997,500 - $37,500).

To calculate the annual depreciation expense using the straight-line method, divide the depreciable cost by the useful life of the equipment. The annual depreciation expense is $106,666.67 ($960,000 ÷ 9).

Since the equipment was only used for a portion of the year, we need to prorate the annual depreciation expense based on the number of units produced.

The depreciation expense for the year ended December 31, 2009 is calculated as follows:

Depreciation Expense = (Annual Depreciation Expense ÷ Total Units of Production) x Units Produced in 2009

Depreciation Expense = ($106,666.67 ÷ 1,920,000) x 426,000

Depreciation Expense = $23,333.33

Therefore, the depreciation expense for the year ended December 31, 2009 using the straight-line method is $23,333.33.

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The value of c in equation y= 0. 884 sin(0. 245x - 1. 093) + 0. 400 is c. 0. 245.

The given equation represents a sine regression model, where y is the dependent variable and x is the independent variable. The equation includes a sine function with a frequency of 0.245 and an amplitude of 0.884. The constant term, 0.400, represents the vertical shift or the y-intercept of the graph. The phase shift, 1.093, determines the horizontal shift of the graph.

To find the value of c, we need to look at the coefficient of x in the sine function. In this case, the coefficient of x is 0.245, which represents the frequency or the number of complete cycles that occur in a given interval. Therefore, the answer is (c) 0.245.

It's important to note that the coefficient of x in a sine regression model represents the frequency and not the phase shift or the horizontal shift. The phase shift is determined by the constant term in the sine function.

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We can use the Pythagorean theorem to relate the distances between the ladder, wall, and ground. Let's call the distance from the foot of the ladder to the wall "x", and the distance from the top of the ladder to the ground "y". Then, we know that:

x^2 + y^2 = 10^2

We can differentiate this equation with respect to time to get:

2x(dx/dt) + 2y(dy/dt) = 0

We're interested in finding dy/dt, the rate at which the top of the ladder is sliding down the wall. We know that dx/dt = 0.5 ft/s, so we can plug in these values and solve for dy/dt:

2x(dx/dt) + 2y(dy/dt) = 0
2(8)(0.5) + 2y(dy/dt) = 0 (since x = 8 based on the Pythagorean theorem)
dy/dt = -4 ft/s

So the top of the ladder is sliding down the wall at a rate of 4 ft/s.
When the 10-foot ladder is leaning against a vertical wall, it forms a right-angled triangle with the wall and the ground. As Jack pulls the foot of the ladder away from the wall at a rate of 0.5 ft/s, the top of the ladder slides down the wall. To find the rate at which the top of the ladder slides down, we can use the Pythagorean theorem:

a^2 + b^2 = c^2

where a is the distance from the foot of the ladder to the wall, b is the height of the ladder's top from the ground, and c is the length of the ladder (10 feet).

Differentiating both sides with respect to time (t), we get:

2a(da/dt) + 2b(db/dt) = 0

We know that da/dt = 0.5 ft/s. We need to find db/dt, which is the rate at which the top of the ladder slides down the wall. To do this, we need to find the values of a and b at a given moment. Since the problem doesn't provide this information, it's not possible to determine the exact value of db/dt. However, if you have the values of a and b, you can plug them into the equation and solve for db/dt.

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La longitude del Puente entre loss punts A y B es de aproximadamente 97.9 metros.

Para calcular la longitud del puente entre los puntos A y B, podemos utilizar el teorema del seno en el triángulo OAB.

Primero,trazamos una línea vertical desde O hasta el segmento AB, creando un triángulo rectángulo OAD. La distancia entre A y O, medida en línea recta, es de 120 m.

Luego, utilizando el ángulo OAB, que mide 48 grados, y el ángulo ABO, que mide 32 minutos (o 32/60 grados), podemos encontrar el tercer ángulo del triángulo OAB aplicando la propiedad de que la suma de los ángulos de un triángulo es 180 grados.

El tercer ángulo del triángulo OAB será: 180 - 48 - (32/60) ≈ 101.467 grados.

Ahora, aplicamos el teorema del seno:

sen(OAB) / AO = sen(ABO) / BO

Despejando BO

BO = (AO * sen(ABO)) / sen(OAB)

Sustituyendo los valores conocidos:

BO = (120 * sen(48)) / sen(101.467) ≈ 120 * 0.7431 / 0.9933 ≈ 89.568 m

Por lo tanto, la longitud del puente que se quiere construir entre los puntos A y B es aproximadamente 89.568 metros.

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Answer:

Absoblute value Reflection

Step-by-step explanation:

You can tell it's absolbute value because of the parbolas, and it's reflected acroos the two points. Give brainliest please!

The function f(x, y, z) that has the constant gradient vector (3, 9, 4) is: f(x, y, z) = (3/2)x^2 + (9/2)y^2 + (2z - y - 2x)^2 + C where C is a constant of integration.

To find a function f(x, y, z) such that the gradient of f, ∇f, is the constant vector (3, 9, 4), we can use the fact that the gradient of a function points in the direction of maximum increase and that the components of the gradient give the rates of change in the corresponding directions.

Let's assume that f(x, y, z) has the form:

f(x, y, z) = ax^2 + by^2 + cz^2 + dxy + exz + fyz + gx + hy + iz + C

where a, b, c, d, e, f, g, h, i, and C are constants that we need to determine.

The gradient of f is:

∇f = (2ax + dy + ez + g, 2by + dx + fz + h, 2cz + ex + fy + i)

If ∇f is equal to the constant vector (3, 9, 4), then we can set up a system of equations:

2ax + dy + ez + g = 3

2by + dx + fz + h = 9

2cz + ex + fy + i = 4

We need to solve this system of equations for a, b, c, d, e, f, g, h, i, and C.

To make the solution simpler, we can set some of the constants to zero. Let's set d = e = f = g = h = i = 0. Then the system becomes:

2ax + ez = 3

2by + fz = 9

2cz + fy = 4

Now we can solve for a, b, and c:

a = 3/2x - 1/2z

b = 9/2y - 1/2z

c = 2z - y - 2x

Substituting these values back into the original equation for f, we get:

f(x, y, z) = (3/2)x^2 + (9/2)y^2 + (2z - y - 2x)^2 + C

So the function f(x, y, z) that has the constant gradient vector (3, 9, 4) is:

f(x, y, z) = (3/2)x^2 + (9/2)y^2 + (2z - y - 2x)^2 + C

where C is a constant of integration.

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The x-intercept of the function  f(x) = x² - 16x + 64 is x = 8.

The x-intercept of the graph can be found as follows:

f(x) = x² - 16x + 64

The x-intercept is the point at which the graph of an equation crosses the x-axis. In other words, the x-intercept is where a line crosses the x-axis on a graph.

The x-intercept is the value of x when y = 0.

Therefore,

x² - 16x + 64 = 0

Let's factorise

x² - 8x - 8x + 64 = 0

x(x - 8) -8(x - 8) = 0

Therefore,

(x - 8)(x - 8) = 0

Therefore,

x = 8

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The area of Coby's room is 80 square feet.

The area of a rectangle is given by the product of its length and width. Here, the length of the room is given as 10 feet and the width is given as 8 feet. Therefore, the area of the room is:

Area = Length x Width

Area = 10 feet x 8 feet

Area = 80 square feet

Hence, the area of Coby's room is 80 square feet. It is important to note that when calculating the area of a rectangle, the units of length are multiplied to obtain the unit of area. In this case, the units of length are feet, so the unit of area is square feet.

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We know that the value of CSC 0 is undefined if the point P(-1,0) is a point on the terminal side of angle 0, an angle in standard position.

If the point P(-1,0) is a point on the terminal side of angle 0, an angle in standard position, then we can use the Pythagorean theorem to find the value of the hypotenuse. The hypotenuse (r) is the distance from the origin to point P, and can be found using the formula r = sqrt(x^2 + y^2), where x = -1 and y = 0.

r = sqrt((-1)^2 + 0^2) = 1

Since csc 0 is the reciprocal of sin 0, and sin 0 = 0/1 = 0, we have:

CSC 0 = 1/sin 0 = 1/0 = undefined.

Therefore, the value of CSC 0 is undefined if the point P(-1,0) is a point on the terminal side of angle 0, an angle in standard position.

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Answer:

Probability of spinning 1 or a 2

Fraction=6/8

decimal=0.75

Let me know if it helped

The number of cubes of dimensions of [tex]\frac{1}{8}[/tex] foot that can fit into a rectangular prism of a length of 1 foot, a width of 1 [tex]\frac{3}{8}[/tex] foot, and a height of [tex]\frac{5}{8}[/tex] foot is 55.

Volume of cuboid = l * b * h

where l is the length

b is the breadth

h is the height

l = 1 foot

b = 1 [tex]\frac{3}{8}[/tex] foot = [tex]\frac{11}{8}[/tex] foot

h = [tex]\frac{5}{8}[/tex] foot

Volume of cuboid = 1 * [tex]\frac{11}{8}[/tex] * [tex]\frac{5}{8}[/tex]

= [tex]\frac{55}{64}[/tex] cubic foot

Volume of cube = [tex]s^3[/tex]

where s is the side

s = [tex]\frac{1}{8}[/tex] foot

Volume = [tex]\frac{1}{8}^3[/tex]

= [tex]\frac{1}{64}[/tex] cubic foot

Number of cubes = [tex]\frac{\frac{55}{64} }{\frac{1}{64} }[/tex]

= 55

The number of cubes that fit into the prism is 55.

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The function that describes how many lanterns Tisha can buy is F(x) = 18x + 64, with a domain of {0, 1, 2, 3, 4} and a range of {64, 82, 100, 118, 136}.

Function to describe how many lanterns Tisha can buy: F(x) = 18x + 64.

Domain: {0, 1, 2, 3, 4, 5} (since Tisha can buy up to 4 additional packages of lanterns, plus the original 64 lanterns).

Range: {64, 82, 100, 118, 136, 154} (each additional package of lanterns has 18 lanterns, so the total number of lanterns Tisha can buy is a multiple of 18 added to 64).

Option (a) F(x) - 18x + 64 has the correct formula but an incorrect domain. Tisha can buy 0 packages of lanterns, so the domain should include 0.

b) For option b, the function is F(x) = 18x + 64, where x represents the number of packages of lanterns Tisha buys. The reasonable domain for this function is {0, 1, 2, 3, 4, 5}, since Tisha can buy up to 4 packages and may choose not to buy any, resulting in x = 0. The range for this function is {64, 82, 100, 118, 136, 154}, which represents the total number of lanterns Tisha can have after buying x packages of 18 lanterns each, starting from the initial 64 lanterns she already has.

Option (c) F(x) - 64x + 18 has an incorrect formula. Tisha starts with 64 lanterns, so the constant term should be 64, not 18.

Option (d) F(x) = 64x + 18 has the correct formula, but the domain is incorrect. Tisha can only buy up to 4 packages, so the domain should be {0, 1, 2, 3, 4}, not just 5.

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The total cost for team C would be $760 + $600 = $1360.

We can start by setting up a system of equations based on the given information. Let x be the cost of one soccer ball and y be the cost of one basketball. Then we have:

3x + 7y = 1240 (equation 1)

5x + 10y = 1900 (equation 2)

We can solve this system of equations by using either substitution or elimination method. Let's use elimination method here:

Multiplying equation 1 by 2 and subtracting it from equation 2, we get:

5x + 10y - (6x + 14y) = 1900 - 2(1240)

-x - 4y = 420

Now we can use either equation 1 or equation 2 to solve for x or y. Let's use equation 1:

3x + 7y = 1240

3x + 3y = 840 (multiplying both sides by -1 and adding to the previous equation)

4y = 400

y = 100

So one basketball costs $100. Now we can substitute this value back into either equation 1 or equation 2 to solve for x. Let's use equation 1:

3x + 7y = 1240

3x + 7(100) = 1240

3x = 570

x = 190

So one soccer ball costs $190.

Now we can use these values to find the cost for team C:

4 soccer balls cost 4 x $190 = $760

6 basketballs cost 6 x $100 = $600

So the total cost for team C would be $760 + $600 = $1360.

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Answer:

Graph 2

Step-by-step explanation:

There is 1 from 1-5

There are 4 from 6-10

There are 5 from 11-15

There is 1 from 16-20

There are 4 from 21-25

It will take approximately 60.9 days for 650 mg of chromium-51 to decay to 200 mg.

What is Equation ?

An equation is a mathematical statement that shows that two expressions are equal. It typically contains variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division.

The decay of a radioactive substance can be modeled by the following equation:

N(t) = N₀ * [tex](1/2)^{(t/T) }[/tex]

where:

N(t) is the amount of the substance remaining after time t

N₀ is the initial amount of the substance

T is the half-life of the substance

We can use this equation to find how long it will take for 650 mg of chromium-51 to decay to 200 mg.

Let's first find the decay constant (λ) for chromium-51:

λ = ㏒(2) ÷ T = ㏒(2) ÷ 28 = 0.0248 (rounded to 4 decimal places)

Now we can use the equation:

N(t) = N₀ * [tex]e^{(-λ*t)}[/tex]

We know that N₀ = 650 mg and N(t) = 200 mg, so we can solve for t:

200 = 650 * [tex]e^{(-0.0248*t)}[/tex]

Dividing both sides by 650:

0.3077 =   [tex]e^{(-0.0248*t)}[/tex]

Taking the natural logarithm of both sides:

㏒(0.3077) = -0.0248*t

Solving for t:

t = ㏒(0.3077) : (-0.0248) ≈ 60.9 days

Therefore, it will take approximately 60.9 days for 650 mg of chromium-51 to decay to 200 mg.

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Answer:

Step-by-step explanation:

Congruent triangles are triangles that are the same shape and same size.

So if they look the same and have the same dimension like area and perimeter then they are congruent.

The completed two column table in the question showing that the measure of the angle m∠GKB = 120° can be presented as follows;

Statement [tex]{}[/tex]                                                Reason

[tex]\overline{AB}[/tex] || [tex]\overline{EF}[/tex]         [tex]{}[/tex]                                          Given

m∠ELJ = 120°

m∠ELJ + m∠ELK = 180°     [tex]{}[/tex]                        Linear pair Postulate

m∠BKL + m∠GKB = 180°   [tex]{}[/tex]                        Linear pair Postulate

m∠ELJ + m∠ELK = mBKL + m∠GKB  [tex]{}[/tex]      Transitive property

∠ELK ≅ ∠BKL                         [tex]{}[/tex]                   1. Alternate Interior Angles

m∠ELK = m∠BKL [tex]{}[/tex]                                      2. Definition of congruent angles

m∠ELJ + m∠ELK = m∠ELK + m∠GKB[tex]{}[/tex]      Substitution property

m∠ELJ = m∠GKB[tex]{}[/tex]                                      Subtraction property

m∠GKB = m∠ELJ [tex]{}[/tex]                                     Symmetric property

m∠GKB = 120° [tex]{}[/tex]                                          Substitution

An angle is the figure formed at the point of intersection of two rays that have the same starting point. The parts of an angle includes; The vertex, which is the point of intersection of the rays, and the sides or arms of the angle, which are the two rays forming the angle.

The details of the the statements that completes the above table used to prove the measure of the angle m∠GKB = 120° are as follows;

Alternate interior angles theorem

The alternate interior angles theorem states that the alternate interior angle formed by the two parallel lines and their shared transversal are congruent.

Definition of congruent angles

Congruent angles are angles that have the same measure.

Learn more alternate interior angles here: https://brainly.com/question/20344743

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