A graph titled Janelle's Trip Home. The horizontal axis shows time (minutes) and the vertical axis shows distance from her home (miles). The line shows a decrease as time increases, a constant as time increases, and then another decrease as time continues.
Based on the graph, which statement could describe Janelle’s trip home from school?

Janelle waited for the bus, rode the bus, and then walked home.
Janelle walked the opposite direction from home to the library, rode the bus, and then walked to a friend’s house.
Janelle walked home at a constant speed.
Janelle rode the bus to the bus stop, talked with a friend, and then walked home.

Answer:

8x + 100

Step-by-step explanation:

Your answer is correct! But because the equation is already set to "y =", you do not need the "f(x)" in your equation.

Answer: The graph crosses the x-axis at x = 2.

Step-by-step explanation:

The root has a multiplicity of 3, meaning that it crosses the x axis at x=2.

Answer:

51° and 39°

Step-by-step explanation:

x + 4x - 165 = 90

5x = 90 + 165

5x = 255

x = 255 / 5

x = 51

4 x 51 = 204

204 - 165 = 39

2 angles are 51 and 39

Answer: 2

Step-by-step explanation:

[tex]a_{n}=2(2)^{n-1}\\\\a_{1}=2(2)^{1-1}=2\\\\a_{2}=2(2)^{2-1}=4[/tex]

Average rate of change:

[tex]\frac{4-2}{2-1}=\boxed{2}[/tex]

Answer: Figure QRTS is congruent to figure Q'R'T'S'.

Step-by-step explanation:

A reflection is a rigid motion, and rigid motions preserve congruency.

Answer:

1.6

Step-by-step explanation:

4,4-2.8 = 1.6

6-4.4 = 1.6

7.6-6 = 1.6

Then common difference is 1.6

Answer:

length=22 [cm].

Step-by-step explanation:

1) if the length is 'l' and the width is 'w', then it is possible

2) to write the given perimeter: 62=2(l+w), - this is the 1st equation of system;

3) to write the condition 'the length of a rectangle is 5 cm less than 3 times its width' as 3w-5=l, - this is the 2d equation of the system.

4) using two equations above it is possible to make up the next system:

[tex]\left \{ {{2(w+l)=62} \atop {3w-5=l}} \right. \ = > \ \left \{ {{w+l=31} \atop {3w-l=5}} \right. \ = > \ \left \{ {{l=22} \atop {w=9}} \right.[/tex]

5) finally, the length=22 [cm].

Answer:

The plots are (0,2) (1,-1)

Step-by-step explanation:

a slanted line starting from top left corner ending in the bottom right

To simplify the equation, we have y = [tex]\frac{3}{4x^2 + 24x} + 8[/tex]

Given the expression

y-8 = 3/4x [x-(-6)]

First, expand the bracket

[tex]y - 8[/tex]= [tex]\frac{3}{4x^2 + 24x}[/tex]

Make 'y' the subject of formula

y = [tex]\frac{3}{4x^2 + 24x} + 8[/tex]

Thus, to simplify the equation, we have y = [tex]\frac{3}{4x^2 + 24x} + 8[/tex]

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Answer:

Step-by-step explanation:

Solution

17 = a + b

b =  a + 1                    Substitute b into the top equation

17 = a + a+1                Combine

17 = 2a + 1                  Subtract 1 from both sides

17-1 = 2a+1-1               Combine

16 = 2a                       Divide both sides by 2

16/2 = 2a/2

a = 8

b = 8 + 1 = 9

Answer

a = 8

b = 9

Answer:

its $95 dollars

Step-by-step explanation:

The function g(x) is obtained by the transformation of the function f(x) is translated towards left by 1 unit.

A statement, principle, or policy that creates the link between two variables is known as a function.

The function f(x) is given below.

f(x) = 2ˣ

Then the function g(x) is given as

[tex]\rm g(x) = 2^{x + 1}[/tex]

The function g(x) is obtained by the transformation of the function f(x) is translated towards left by 1 unit.

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A percentage is a way to describe a part of a whole. The relative change from last year to this year is 3.7%.

A percentage is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25 which is equal to 25%.

To convert a fraction to a percentage, convert the fraction to decimal form and then multiply by 100 with the '%' symbol.

28.6% of city employees ride the bus to work, therefore, the final value is 28.6. While Last year, 29.7% of city employees rode the bus to work, therefore, the initial value is 29.7.

Since relative change means change with respect to some value. Thus, the relative value with respect to last year is,

Relative value = (29.7-28.6)/29.7 = 0.037 = 3.7%

Hence, the relative change from last year to this year is 3.7%.

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The ranges of batting averages were least common among the players is 0.320-0.329 and 0.360-0.369 , Option D is the correct answer.

Average is the middle value of a set of data points , calculated by summing all the data points and then dividing by the number of points.

It is given that , 30 best batting averages for a semi-pro baseball league.

The ranges of batting averages were least common among the players

To find this , it has to be observed that which range has the lowest frequency

The range 0.320-0.329 and 0.360-0.369 has frequency of 1 which is the least among all

Hence Option D is the correct answer.

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Answer:

The answer is C. Hope it helps

Answer: 72

Step-by-step explanation:

[tex]\sum^{3}_{t=0} (6t^{2}-3)=(6(0)^{2}-3)+(6(1)^{2}-3)+(6(2)^{2}-3)+(6(3)^{2}-3)=\boxed{72}[/tex]

Answer:

The area for the trapezoid is

A=h/2(a+b)

A=8/2(10+15)

A=100 cm square

Hope it helps!

Answer:

Two functions which satisfies the H(x) are f(x) = 2x - 4, (x)    = x⁵  and

f(x)  = 2x,  g(x)  = x⁵ - 2

Step-by-step explanation:

The given question is based on the decomposition of a given function into two functions

Decomposition of a function :- functional decomposition is the process of resolving a functional relationship into its constituent parts in such a way that the original function can be reconstructed from those parts by function composition

so the function given in the question is H(x) = 2x⁵ - 4

now by using the concept of decomposition of a function we can find two functions f and g

therefore,

f(x) = 2x - 4

and    g(x)    = x⁵

similarly we can find another pair which satisfies the function H(x)

f(x)  = 2x

and g(x)  = x⁵ - 2

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The two types of transformations that can be used to transform f(x) to g(x).  g (x) = f(x) + 16 and g (x) = f(x + 8)

ABC has vertices at A (12, 8), B (4, 8)

f(x)= 0, -1 ,5,14

g(x)= -6, -1, -1, 14

g(x)=f(x)+k

-6= 0+k

k= -6

A) g (x) = f(x) + 16 and

g(x) = f(x + 8)

B) g(x)=f(x)+k

-1= -1+ k

k= -1+1=0

g(x)=f(x)+k

-1= 5+k

k= -1-5=-6

g(x)=f(x)+k

14= 14+k

k= 0

k= -6,0,-6,0

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The cost of goods sold is $10,258 million and the Cash paid to supplier is $10,447 million.

a. Cost of goods sold

Cost of Goods Sold=Beginning Inventories + Purchases – Ending Inventories

Cost of goods sold = $1,997 + $10,392 - $2,131

Cost of goods sold = $10,258

b. Cash paid to supplier

Cash paid=2015 Beginning balance  + Purchases - 2015 Ending balance

Cash paid = $1,181 + $10,392 - $1,126

Cash paid = $10,447

Therefore the cost of goods sold is $10,258 million and the Cash paid to supplier is $10,447 million.

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Using Chebyshev's Theorem, the minimum percentage of commuters in has a commute time within 2 standard deviations of the​ mean is of 75%.

When we have no information about the population distribution, Chebyshev's Theorem is used. It states that:

Hence, the minimum percentage of commuters in has a commute time within 2 standard deviations of the​ mean is of 75%.

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Answer:

A = { x:x >3 ,where x --> R}

B = { x:x <4, where x --> R}

Y = { x:x is month of year with more than 30 days}

W = { x:x is all days of a week}

should i create the world problem with 12 3 and 9?

Part 1: Finding [tex](g\circ h)(x)[/tex]

Note that [tex](g\circ h)(x)=g(h(x))[/tex]

In this case, it is [tex]g(\sqrt{x+4})=(\sqrt{x+4})^{2}-3=x+4-3=\boxed{x+1}[/tex]

Part 2: Domain

For the domain, we need to make sure the radicand of h(x) is greater than or equal to 0, so we get [tex]x+4 \geq 0 \longrightarrow \boxed{x \geq -4}[/tex]

The composition (g ο h) = x+ 1 and the domain of the composition (g ο h) is = (-∞ , ∞).

The composition (g ο h) means that the function g(x) composes of h(x) that is g(h(x)). So we have to put the the values of h(x) in the function g(x).

Now here it is given that

g(x) = [tex]x^{2} -3[/tex] and h(x) = [tex]\sqrt[2]{x + 4}[/tex]

so to get (g ο h) we have to replace the x with the value of h(x)

That gives :

g(h(x)) = [tex]\sqrt[2]{x+4} ^{2} - 3[/tex]

g(h(x)) = x + 4 - 3 = x +1

So the composition (g ο h) = x+ 1

The domain of the function is the values of x for which the function is defined.

so the domain of the composition (g ο h) is :

g(h(x)) = x+ 1

This function is undefined for no value of x .

So its domain is (-∞ , ∞).

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Answer:

3.8918

round the 1 from the 8 to get 2

3.892

Answer:

4 r^3

Step-by-step explanation:

sqrt ( 16 r^6 )    = sqrt ( 4^2 * (r^3)^2  )    =   4 r^3