This is the inequality that represents all possible widths, w, in feet of the garden is W^2 + 2W - 120 ≥ 0
The area of a rectangle is given by the formula A = L x W, where A is the area, L is the length, and W is the width. In this problem, we are given that the garden is rectangular and that the length is 2 feet longer than the width, so we can write L = W + 2.
We are also told that the area of the garden is at least 120 square feet, so we can write:
A = L x W ≥ 120
Substituting L = W + 2, we get:
(W + 2) x W ≥ 120
expanding the left side, we get:
W^2 + 2W ≥ 120
Rearranging, we get:
W^2 + 2W - 120 ≥ 0
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Use the equations to find ∂z/∂x and ∂z/∂y. ez = 5xyz
The partial derivative of z with respect to x is 5xy + 5xz, and the partial derivative of z with respect to y is 5xz + 5yz.
To find the partial derivatives of z with respect to x and y, we use the chain rule. The chain rule allows us to find the rate of change of a function with respect to one of its independent variables while holding all other independent variables constant.
Using the chain rule, we can find the partial derivatives of z with respect to x and y as follows:
∂z/∂x = 5(yz) + 5x(1)(z)
∂z/∂x = 5xy + 5xz
∂z/∂y = 5(xz) + 5y(1)(z)
∂z/∂y = 5xz + 5yz
Therefore, the partial derivative of z with respect to x is 5xy + 5xz, and the partial derivative of z with respect to y is 5xz + 5yz.
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As a candle burns, its wick gets smaller over time. When first purchased, the wick is 150 mm in length. After 50 minutes, the wick is only 110 mm in length. Find the slope you would use in a linear model of mm per minute. 3 points Construct an equation that models the length of the wick over this time period. Your answer should be in the proper form using correct letters and numbers with no spaces. 2 points Use your linear model to predict the how many minutes it would take to have 74 mm remaining. 3 points
It would take approximately 95 minutes for the wick to have 74 mm remaining.
1) Finding the slope (mm per minute):
The wick was initially 150 mm in length and reduced to 110 mm after 50 minutes. To find the slope, we use the formula:
Slope = (change in length) / (change in time)
Slope = (110 mm - 150 mm) / (50 minutes - 0 minutes)
Slope = (-40 mm) / (50 minutes)
Slope = -0.8 mm/minute
2) Constructing the linear equation:
We now have the slope (-0.8) and the initial length (150 mm) to create a linear equation:
Length (L) = initial length + slope × time (t)
L = 150 - 0.8t
3) Predicting the time to have 74 mm remaining:
To find the time, plug in 74 mm for the length (L) in the equation and solve for t:
74 = 150 - 0.8t
76 = 0.8t
t = 95 minutes
So, it would take approximately 95 minutes for the wick to have 74 mm remaining.
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8-73.
For each diagram below, write and solve an equation for x
Answer:
a.x=100 equation: 540=(125·2)+90+(2x)
b. x=3 equation: 6x+18=2x+30
Step-by-step explanation:
a. We know that the interior angles of a pentagon have to equal 540 degrees.
So:
540=125+125+90 (hence the square) + x + x
simplify:
540=340+2x
simplify:
200=2x
x=100
b. Using the alternate exterior angles theorem we can say:
6x+18=2x+30
simplify:
4x+18=30
4x=12
x=3
Use linear approximation to approximate √125.04 as follows Let f(x) = ³√ x, and find the linearization of f(x) at x = 125 in the form y = mx+ b Note: The values of m and bare rational numbers which can be computed by hand. You need to enter expressions which give m and b exactly You should not have a decimal point in the answers to either of these parts m= b = Using these values, find the approximation Also, for this part you should be entering a rational number, not a decimal approximation ²√ 125.04≈
To approximate √125.04 using linear approximation, first find the linearization of f(x) = ³√x at x = 125. Then use the point-slope form of the equation to find the equation of the tangent line and plug in x = 125.04 to get the approximation.
To approximate √125.04 using linear approximation and the function f(x) = ³√x, first find the linearization of f(x) at x = 125 in the form y = mx + b. Calculate f(125) and f'(x).Calculate f'(125): Use the point-slope form of the equation
1: Calculate f(125) and f'(x).
f(125) = ³√125 = 5
f'(x) = (1/3)x^(-2/3)
2: Calculate f'(125).
f'(125) = (1/3)(125)^(-2/3) = 1/15
3: Use the point-slope form of the equation y - y1 = m(x - x1) to find the equation of the tangent line.
y - 5 = (1/15)(x - 125)
4: Rearrange to find y in terms of x.
y = (1/15)(x - 125) + 5
5: Determine the values of m and b.
m = 1/15
b = (1/15)(-125) + 5
6: Plug in x = 125.04 to approximate √125.04.
²√125.04 ≈ (1/15)(125.04 - 125) + 5
The linearization of f(x) at x = 125 is y = (1/15)x + b, with m = 1/15 and b = (1/15)(-125) + 5. Using these values, the approximation of √125.04 is (1/15)(125.04 - 125) + 5.
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The cost to produce x cases of Thingamabobs is given by the function C = 50x + 1000 where Cis in hundreds of dollars. If production is growing at a rate of 20 cases per day when the production level is x= 50 cases, find the rate at which the cost of production is changing.
The rate at which the cost of production is changing is 1000 hundred dollars per day or $100,000 per day.
To find the rate at which the cost of production is changing, we'll use the given cost function C = 50x + 1000, and the information that production is growing at a rate of 20 cases per day when x = 50 cases.
First, differentiate the cost function with respect to x to get the rate of change of the cost with respect to the number of cases produced (dC/dx):
dC/dx = 50
The derivative, 50, tells us that the cost increases by 50 hundred dollars for each additional case produced.
Now, we're given that dx/dt = 20 cases per day when x = 50 cases. To find dC/dt, the rate at which the cost of production is changing, multiply the rate of change of the cost with respect to the number of cases (dC/dx) by the rate of change of the number of cases with respect to time (dx/dt):
[tex]dC/dt = (dC/dx) × (dx/dt) = 50 × 20[/tex]
dC/dt = 1000
So, the rate at which the cost of production is changing is 1000 hundred dollars per day or $100,000 per day.
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When solving the equation 6x² - 2x = -3 with the quadratic formula.
If a = 6, what are the values of b and c?
b =
C =
A/
A cylinder has a base area of 64π m2. Its height is equal to twice the radius. Identify the volume of the cylinder to the nearest tenth
The volume of the cylinder is approximately 1024π cubic meters.
We are given the base area of the cylinder as 64π square meters, which means that the radius of the cylinder is 8 meters (since the area of a circle is given by πr^2). We are also given that the height of the cylinder is twice the radius, which means that the height is 16 meters.
The volume of a cylinder is given by the formula V = πr^2h, where r is the radius and h is the height. Substituting the given values, we get V = π(8^2)(16) = 1024π cubic meters. Therefore, the volume of the cylinder is approximately 1024π cubic meters.
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Answer:
[tex]3217.0 m ^{3}[/tex]
Step-by-step explanation:
Use the following for #5-6 A middle school science teacher wants to conduct some experiments. There are 15 students in the class. The teacher selects the students randomly to work together in groups of five. 5) In how many ways can the teacher combine five of the students for the first group if the order is not important? 6) After the first group of five is selected, in how many ways can the teacher combine five of the remaining students if the order is not important?
Answer:
5) 3003 ways;6) 252 ways.---------------------------------
5) Use the combination formula:
C(n, r) = n! / (r!(n-r)!)In this case, n = 15 (total students) and r = 5 (students in a group).
Substitute and calculate:
C(15, 5) = 15! / (5!(15-5)!) C(15, 5) = 15! / (5!10!) C(15, 5) = 3003The teacher can combine the students in 3003 ways for the first group.
6) After the first group of five is selected, there are 10 students remaining.
Again use the combination formula, with n = 10 and r = 5:
C(10, 5) = 10! / (5!(10-5)!) C(10, 5) = 10! / (5!5!) C(10, 5) = 252The teacher can combine the remaining students in 252 ways for the second group.
3. let f be a differentiable function on an open interval i and assume that f has no local minima nor local maxima on i. prove that f is either increasing or decreasing on i.
Shown that if f has no local minima nor local maxima on i, then f is either increasing or decreasing on i.
Since f has no local minima nor local maxima on i, it means that for any point x in i, either f is increasing or decreasing in a small interval around x. In other words, either f'(x) > 0 or f'(x) < 0 for all x in i.
Now suppose there exist two points a and b in i such that a < b and f(a) < f(b). We want to show that f is increasing on i.
Consider the interval [a,b]. By the Mean Value Theorem, there exists a point c in (a,b) such that f'(c) = (f(b) - f(a))/(b - a). Since f(a) < f(b), we have (f(b) - f(a))/(b - a) > 0, which implies f'(c) > 0. Since f'(x) > 0 for all x in i, it follows that f is increasing on [a,c] and on [c,b]. Therefore, f is increasing on i.
A similar argument can be made if f(a) > f(b), which would imply that f is decreasing on i.
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Select the correct answer from each drop-down menu.
The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i.
The length of the hypotenuse is
units, and the area of the triangle is
square units. (Hint: Use the Pythagorean theorem.)
The area of the triangle is 6 square units.
How to solveOnce you have the points they make a 3-4-5 triangle.
The two legs are 3 and 4, so the hypotenuse has to be 5.
Or you could use the Pythagorean theorem a² + b² = c² 3² + 4² = c² 25 = c² c = 5
then find area
A=1/2bh
1/2(3*4)
6
Thus, the area of the triangle is 6 square units.
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Display numerical data in plots on a number line, including dot plots, histograms, and box plots.
The dot plot that most accurately displays Miss Little's class data is illustrated below.
To create a dot plot, we first need to determine the range of the data, which is the difference between the highest and lowest values. In this case, the range is from 8 to 16. We then draw a number line that spans the range, and mark each data point along the line with a dot.
Let's take a look at the first data set: 13, 14, 9, 12, 16, 11, and 10. The range is from 9 to 16, so we draw a number line from 9 to 16. We then mark each data point with a dot above its corresponding value on the number line. So, there will be one dot above 13, one dot above 14, two dots above 9, one dot above 12, one dot above 16, one dot above 11, and one dot above 10.
We repeat this process for the second data set: 9, 8, 10, 10, 11, 15, and 10. The range is from 8 to 15, so we draw a number line from 8 to 15. We then mark each data point with a dot above its corresponding value on the number line. So, there will be one dot above 9, one dot above 8, three dots above 10, one dot above 11, one dot above 15, and zero dots above 14.
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Complete Question:
Miss. Little wants to know how many pairs of shoes each of her students owns. She decides to ask each of her students to write the number of pairs of shoes that he or she owns. This data is displayed in the provided chart. Plot the dot plot that most accurately displays Miss Little's class data.
13 14 9 12 16 11 10
9 8 10 10 11 15 10
please help i need this asap
All the value of angles are,
⇒ ∠a = 118°
⇒ ∠b = 62°
⇒ ∠q = 84°
⇒ ∠v = 84°
Given that;
Two parallel lines t₁ and t₂ are shown in image.
Here, we have;
Apply the definition of corresponding angles,
∠d = 180 - 62
∠d = 118°
Hence, By definition of vertically opposite angles,
⇒ ∠a = 118°
And,
∠b = 180 - 118°
∠b = 62°
Apply the definition of corresponding angles,
∠q = 180 - 96
∠q = 84°
Hence, By definition of vertically opposite angles,
⇒ ∠v = 84°
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145 student are in the auditorium. Of the students in the auditorium, about 86% of the students play a sport. About 45% of the students are in the school play. How many students play a sport? How many students are in the play? Round your answer to the nearest whole
About 125 students play a sport and about 65 students are in the play.
To find the number of students who play a sport and those who are in the play, we need to use the given percentages and round the answers to the nearest whole.
Find the number of students who play a sport:
Multiply the total number of students (145) by the percentage of students who play a sport (86%).
145 × 0.86 = 124.7
Round the answer to the nearest whole number:
Approximately 125 students play a sport.
Find the number of students who are in the play:
Multiply the total number of students (145) by the percentage of students who are in the play (45%).
145 × 0.45 = 65.25
Round the answer to the nearest whole number:
Approximately 65 students are in the play.
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9. define a relation r on the integers, ∀m, n ∈ z, mean if m n is even. is r a partial order relation? prove or give counterexample.
No, the relation r is not a partial order relation.
To prove this, we need to show that r is not reflexive, not antisymmetric, or not transitive.
r is reflexive if ∀a∈Z, a a holds, which means that any integer is related to itself. This is true for r since a a = 2 × a = even.r is antisymmetric if whenever a b and b a, then a = b. This is not true for r since, for example, 2 6 and 6 2, but 2 ≠ 6.r is transitive if whenever a b and b c, then a c. This is not true for r since, for example, 2 6 and 6 4, but 2 is not related to 4.Since r fails to satisfy the antisymmetric property, it is not a partial order relation.
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A fisherman kept records of the weight in pounds of the fish caught on the fishing trip 10, 9, 2, 12, 10, 12, 8, 14, 11, 3, 6, 9, 7, 15. What does the shape of the distribution in the histogram tell you about the situation
The shape of the distribution in the histogram can tell us about the distribution of weights of fish caught by the fisherman.
Looking at the given data set, we can see that the weights of the fish caught vary from as low as 2 pounds to as high as 15 pounds. The histogram of this data set can help us to fantasize the distribution of these weights. Grounded on the shape of the histogram, we can see that the distribution is kindly slanted to the right, with a long tail extending towards the advanced end of the weights.
This suggests that there were further fish caught that counted lower than the mean weight of the catch, with smaller fish caught that counted further than the mean weight. also, the presence of a many outliers( similar as the fish that counted 15 pounds) suggests that there may have been some larger or unusual fish caught on the trip.
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Let f(x) = 2 sqrt(x)/8x^2 + 3x – 9
Evaluate f’(x) at x = 4.
The derivative of the function f(x) = 2 \sqrt(x) / (8x² + 3x - 9) evaluated at x = 4.
To find f'(x), we need to differentiate the given function f(x) using the power rule and the chain rule of differentiation.
First, we can rewrite the function f(x) as:
f(x) = 2x^{1/2} / (8x² + 3x - 9)
Next, we can differentiate f(x) with respect to x:
f'(x) = d/dx [2x^{1/2} / (8x² + 3x - 9)]
Using the quotient rule of differentiation, we have:
f'(x) = [ (8x² + 3x - 9) d/dx [2x^{1/2}] - 2x^{1/2} d/dx [8x² + 3x - 9] ] / (8x² + 3x - 9)²
Applying the power rule of differentiation, we have:
f'(x) = [ (8x² + 3x - 9)(1/2) - 2x{1/2}(16x + 3) ] / (8x² + 3x - 9)²
Now we can evaluate f'(x) at x = 4 by substituting x = 4 into the expression for f'(x):
f'(4) = [ (8(4)² + 3(4) - 9)(1/2) - 2(4)^(1/2)(16(4) + 3) ] / (8(4)² + 3(4) - 9)²
f'(4) = [ (128 + 12 - 9)(1/2) - 2(4)^(1/2)(67) ] / (128 + 12 - 9)^2
f'(4) = [ 131^(1/2) - 2(4)^(1/2)(67) ] / 12167
Therefore, f'(4) = [ 131^(1/2) - 134(2)^(1/2) ] / 12167.
This is the value of the derivative of f(x) at x = 4.
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This question: 1 pt
15 of 30
identify the type 1 error. the epa claims that fluoride in children's drinking water should be at a mean level of less than 1. 2 ppm, or parts per million, to reduce the number of dental cavities.
The type 1 error in this scenario would be rejecting the null hypothesis that the mean level of fluoride in children's drinking water is less than 1.2 ppm, when in reality it is true.
The EPA claims that fluoride in children's drinking water should have a mean level of less than 1.2 ppm to reduce the number of dental cavities. A type 1 error occurs when we reject the null hypothesis when it is actually true. In this case, the null hypothesis (H0) would be that the mean fluoride level is less than or equal to 1.2 ppm, and the alternative hypothesis (H1) would be that the mean fluoride level is greater than 1.2 ppm.
A type 1 error would occur if we incorrectly conclude that the mean fluoride level is greater than 1.2 ppm when, in reality, it is less than or equal to 1.2 ppm. This could lead to unnecessary actions being taken to reduce fluoride levels when they are already at an acceptable level.
In other words, falsely concluding that the mean level of fluoride in the water is above 1.2 ppm and therefore causing harm to the children's dental health by not reducing the number of dental cavities.
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ASAP THX!!! ANSWER GETS BRAINLIEST
Rachel went to the grocery store and spent $68. She now has only $23 to get gasoline with before she returns home. How much money did Rachel have before she went grocery shopping? Create an equation to represent the situation. Make sure to identify and label your variable. Solve for the variable and describe your answer. Show your work and prove your solution to be correct
The solution is correct, as both sides of the equation are equal.
To find out how much money Rachel had before she went grocery shopping, we can create an equation using a variable.
Let x represent the amount of money Rachel had before grocery shopping.
The equation for the situation would be: x - $68 = $23
Now, let's solve for x:
Step 1: Add $68 to both sides of the equation:
x = $23 + $68
Step 2: Calculate the sum:
x = $91
So, Rachel had $91 before she went grocery shopping.
To prove the solution is correct, we can plug the value of x back into the equation:
$91 - $68 = $23
$23 = $23
Hence, both are equal.
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An experiment involving learning in animals requires placing white mice and rabbits into separate, controlled environments: environment I and environment II. The maximum amount of time available in environment I is 420 minutes, and the maximum amount of time available in environment II is 600 minutes. The white mice must spend 10 minutes in environment I and 25 minutes in environment II, and the rabbits must spend 12 minutes in environment I and 15 minutes in environment II. Find the maximum possible number of animals that can be used in the experiment and find the number of white mice and the number of rabbits that can be used.
We find that the maximum possible number of animals is 37, with 17 white mice and 20 rabbits.
Let's use the following variables:
x be the number of white mice
Let y be the number of rabbits
Based on the given information, we can create the following system of linear inequalities:
10x + 12y ≤ 420 (maximum time available in environment I)
25x + 15y ≤ 600 (maximum time available in environment II)
We also have the constraints that x and y must be non-negative integers.
To solve this problem, we can use a graphing approach. We can graph each inequality on the same coordinate plane and shade the region that satisfies all the constraints. The feasible region will be the region that is shaded.
However, since x and y must be integers, we need to find the corner points of the feasible region and test each one to see which one gives us the maximum value of x + y.
To find the corner points, we can solve each inequality for one variable and then substitute into the other inequality:
For the first inequality: 12y ≤ 420 - 10x, so y ≤ (420 - 10x)/12
For the second inequality: 15y ≤ 600 - 25x, so y ≤ (600 - 25x)/15
Since y must be a non-negative integer, we can use the floor function to round down to the nearest integer:
For the first inequality: y ≤ ⌊(420 - 10x)/12⌋
For the second inequality: y ≤ ⌊(600 - 25x)/15⌋
We can then plot these two expressions on the same graph and find the points where they intersect. We can then test each point to see if it satisfies all the constraints and if it gives us the maximum value of x + y.
After doing all the calculations, we find that the maximum possible number of animals is 37, with 17 white mice and 20 rabbits.
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Two different box-filling machines are used to fill cerealboxes on the assembly line. The critical measurement influenced bythese machines is the weight of the product in the machines. Engineers are quite certain that the variance of the weight ofproduct is σ^2=1 ounce. Experiments are conducted using bothmachines with sample sizes of 36 each. The sample averages formachine A and B are xA=4. 5 ounces and xB =4. 7 ounces. Engineers seemed surprisedthat the two sample averages for the filling machines were sodifferent.
a. Use the central limit theorem to determine
P(XB- XA >= 0. 2)
under the condition that μA=μB
b. Do the aforementioned experiments seem to, in any way,strongly support a conjecture that the two population means for thetwo machines are different?
a. By central limit theorem, P(XB- XA >= 0. 2) is approximately 0.0228 under the condition that μA=μB.
b. Yes, we can conclude that the observed difference in sample means does provide evidence that the two population means for the two machines are different.
a. Using the central limit theorem, we know that the sampling distribution of the difference in means (XB - XA) is approximately normal with mean (μB - μA) and standard deviation (σ/√n), where σ is the population standard deviation (σ=1 ounce) and n is the sample size (n=36 for both machines).
So, P(XB - XA >= 0.2) can be calculated by standardizing the difference in means:
Z = (XB - XA - (μB - μA)) / (σ/√n)
Z = (4.7 - 4.5 - 0) / (1/√36)
Z = 2
Looking up the probability of Z being greater than or equal to 2 in a standard normal distribution table, we find P(Z >= 2) = 0.0228.
Therefore, P(XB - XA >= 0.2) is approximately 0.0228 under the condition that μA=μB.
b. The difference in sample means (XB - XA = 0.2) is relatively small compared to the population standard deviation (σ=1 ounce). However, the calculated probability in part a (0.0228) suggests that the observed difference in sample means is statistically significant at a significance level of 0.05 (since P(XB - XA >= 0.2) < 0.05).
Therefore, we can conclude that the observed difference in sample means does provide evidence that the two population means for the two machines are different. However, further testing or analysis may be necessary to confirm this conclusion.
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In May, the cost for a child is not changed. The cost for an adult is reduced by p % to $22.10. (i) Calculate p.
The cost for an adult is reduced by approximately 26.33% to $22.10.
How to solveThe original cost for an adult ticket (X) = $30
The reduced cost for an adult ticket = $22.10
We need to find the percentage decrease (p) from the original cost to the reduced cost:
p = ((Original cost - Reduced cost) / Original cost) * 100
p = (($30 - $22.10) / $30) * 100
p = ($7.90 / $30) * 100
p ≈ 26.33 %
The fee for an adult has notably decreased by approximately 26.33%, now costing a mere $22.10.
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In May, the cost for a child is not changed. The cost for an adult is reduced by p % to $22.10. If the original cost of an adult ticket is $X, (i) calculate p, given that the original cost for an adult ticket is $30.
What is the volume of the prism, measured in cubic inches
Answer:
360 cubes
Step-by-step explanation:
Sushi corporation bought a machine at the beginning of the year at a cost of $39,000. the estimated useful life was five years and the residual value was $4,000. required: complete a depreciation schedule for the straight-line method. prepare the journal entry to record year 2 depreciation.
Entry debits the Depreciation Expense account for $7,000 and credits the Accumulated Depreciation account for the same amount, reflecting the decrease in the value of the machine over time.
To calculate deprecation using the straight- line system, we need to abate the residual value from the original cost of the machine and also divide the result by the estimated useful life. Using the given values, we have
Cost of machine = $ 39,000
Residual value = $ 4,000
Depreciable cost = $ 35,000($ 39,000-$ 4,000)
Estimated useful life = 5 times
To calculate the periodic deprecation expenditure, we divide the depreciable cost by the estimated useful life
Periodic deprecation expenditure = $ 7,000($ 35,000 ÷ 5)
Depreciation Expense $7,000
Accumulated Depreciation $7,000
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The journal entry is as given in figure:
Shannon's net worth is $872. 17 and her liabilities are $15,997. If she pays off a credit card with a balance of $7,698, what is her new net worth?
Answer:
To calculate Shannon's new net worth after paying off her credit card, we need to subtract the credit card balance from her total liabilities, and then subtract the result from her net worth:
New liabilities = $15,997 - $7,698 = $8,299
New net worth = $872.17 - $8,299 = -$7,426.83
Based on these calculations, Shannon's new net worth would be -$7,426.83 after paying off her credit card. This indicates that her liabilities still exceed her assets, and she would need to continue working towards reducing her debt and increasing her net worth over time.
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What is the meaning of a relative frequency of 0. 56
A relative frequency of 0.56 means that out of the total number of observations in a given sample or population, 56% of those observations belong to a particular category or have a certain characteristic.
In other words, it is the proportion or fraction of the observations that fall into that particular category or have that characteristic, relative to the total number of observations. For example, if we had a sample of 100 people and 56 of them had brown hair, then the relative frequency of brown hair would be 0.56 or 56%.
To calculate relative frequency, you divide the frequency of a specific event or category by the total number of observations. In this case, the specific event or category occurs 56% as often as the total events or categories observed.
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4 km 20) Determine the distance across the lake? 6 km Lake 6
hope this helps you
Question 3
3.1 simplify the following ratios:
3.1.1 500g : 3 kg
3.1.2 12cm : 1m
The simplified ratios are: 1:6 & 3:25
To simplify the first ratio, we need to convert the units so they are the same. We can either convert 500g to kilograms or 3kg to grams. Let's convert 3kg to grams since it will be easier to compare with 500g.
3 kg = 3000g
Now the ratio becomes:
500g : 3000g
We can simplify this ratio by dividing both sides by 500:
500g/500 = 1 and 3000g/500 = 6
So the simplified ratio is:
1 : 6
For the second ratio, we need to convert either 12cm to meters or 1m to centimeters. Let's convert 1m to centimeters since it will be easier to compare with 12cm.
1m = 100cm
Now the ratio becomes:
12cm : 100cm
We can simplify this ratio by dividing both sides by 4:
12cm/4 = 3 and 100cm/4 = 25
So the simplified ratio is:
3 : 25
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Last question :) btw if u can’t tell the equation there is 6x+68
Answer:
The answer for x is 2
z is 100°
Step-by-step explanation:
80=6x+68
6x=80-68
6x=12
divide both sides by 6
6x/6=12/6
x=2
z=?(empty space)
?(empty space)=z
80+z+z+6x+68=360
Note:6x+68=80
80+80+2z=360
160+2z=360
2z=360-160
2z=200
divide both sides by 2
2z/2=200/2
z=100°
2. A social media company claims that over 1 million people log onto their app daily. To test this claim, you record the number of people who log onto the app for 65 days. The mean number of people to log in and use the social media app was discovered to be 998,946 users a day, with a standard deviation of 23,876. 23. Test the hypothesis using a 1% level of significance.
The hypothesis test suggests that there is not enough evidence to reject the claim made by the social media company that over 1 million people log onto their app daily, as the t-value (-1.732) is less than the critical value (-2.429).
Null hypothesis, The true mean number of people who log onto the app daily is equal to or less than 1 million.
Alternative hypothesis, The true mean number of people who log onto the app daily is greater than 1 million.
Level of significance = 1%
We can use a one-sample t-test to test the hypothesis.
t = (X - μ) / (s / √n)
where X is the sample mean, μ is the hypothesized population mean, s is the sample standard deviation, and n is the sample size.
Substituting the values, we get
t = (998,946 - 1,000,000) / (23,876 / √65)
t = -1.732
Using a t-distribution table with 64 degrees of freedom and a one-tailed test at a 1% level of significance, the critical value is 2.429.
Since the calculated t-value (-1.732) is less than the critical value (-2.429), we fail to reject the null hypothesis. There is not enough evidence to support the claim that more than 1 million people log onto the app daily.
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A bracelet is now reduced to £420.this is 70% of the original price. what is the original price?
Answer:
.70p = £420, so p = £600
The original price of the bracelet is £600.
The original price of the bracelet was £600.
To find the original price of the bracelet, we need to use the information that the current price is 70% of the original price. We can use algebra to solve for the original price:
Let X be the original price of the bracelet.
70% of X is equal to £420.
We can write this as:
0.7X = £420
To solve for X, we can divide both sides of the equation by 0.7:
X = £420 ÷ 0.7
Evaluating the right-hand side gives us:
X = £600
Therefore, the original price of the bracelet was £600.
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