a freshwater stream flows into the ocean as shown in the diagram which statement correctly describes how the stream affects these salinity of the ocean


A- salinity increases because the stream adds salt to the ocean.

B- salinity decreases because the stream adds freshwater to the ocean

C- salinity increases because of stream adds freshwater to the ocean

D- salinity Remains the Same because the stream adds freshwater to the ocean ​

Answer:

The elements can be classified as metals, nonmetals, or metalloids. ... Elements are further classified into metals, non-metals, and metalloids based on their properties, ... when they undergo chemical reactions They normally do not accept ... Most metal oxides are basic oxides and dissolve in water to form .

Explanation:

So, litmus paper is a qualitative tool for assessing the acidity or basicity of a substance (usually a solution). In general, blue litmus turns red in the presence of an acid, and red litmus turns blue in the presence of a base. They can't really tell you much more than that.

The solutions that are most likely acids are those that turn blue litmus red and do not evoke a color change in red litmus. A solution that turns red litmus blue or does not evoke a color change in blue litmus is likely not an acid. Using these criteria, solutions 4 and 7 are most likely acids since they both turn blue litmus red (and they cause no color change in red litmus).

The correct answer choice would thus be D.

Answer: Ba(NO3)2(aq) + H2O(l)

Explanation:

Answer:

133.34 g/moles

Explanation:

but to make life easy it could be 133.4 g/ moles as well

Answer:

15.4%

Explanation:

If Ka = 0.54 mM = 1.51x10⁻⁵

Then;

C₄H₈O₂               -------->            C₄H₇O₂⁻          +           H⁺

I                    0.54x10⁻³                             0                                0

E                   0.54x10⁻³(1-x)                      0.54x10⁻³x                0.54x10⁻³x

Recall that x is the percentage degree of dissociation

From the ICE table;

Ka = [C₄H₇O₂⁻] [ H⁺]/[C₄H₈O₂]

1.51x10⁻⁵=(0.54x10⁻³x) (0.54x10⁻³x)/ 0.54x10⁻³(1-x)  

1.51x10⁻⁵ = 0.54x10⁻³x^2/1-x

1.51x10⁻⁵(1-x) = 0.54x10⁻³x^2

1.51x10⁻⁵ - 1.51x10⁻⁵x = 0.54x10⁻³x^2

Hence;

0.54x10⁻³x^2 + 1.51x10⁻⁵x - 1.51x10⁻⁵=0

x^2 + 0.028x - 0.028 = 0

Solving the quadratic equation here;

x = 0.154 or −0.182

Ignoring the negative result, x = 0.154

Hence, fraction of butanoic acid that is in the dissociated form in this solution = 15.4%

Answer:

tissues,organs, organelles

a.

Initial moles of (CH₃CH₂)₃N = (0.1000 mol/L) × (20.00/1000 L) = 0.002 mol

Moles of HCl added = (0.1000 mol/L) × (13.00/1000 L) = 0.0013 mol

Addition of 1 mole of HCl reacts with 1 mole of (CH₃CH₂)₃N to 1 mole of (CH₃CH₂)₃NH⁺.

After addition of 13.00 mL of HCl:

Moles of (CH₃CH₂)₃N left unreacted = (0.002 - 0.0013) mol = 0.0007 mol

Moles of (CH₃CH₂)₃NH⁺ produced = 0.0013 mol

Hence, [(CH₃CH₂)₃NH⁺]/[(CH₃CH₂)₃N] = 0.0013/0.0007 = 13/7

Consider the dissociation of (CH₃CH₂)₃N:

(CH₃CH₂)₃N(aq) + H₂O(l) ⇌ (CH₃CH₂)₃NH⁺(aq) + OH⁻(aq) …… Kb = 5.2 × 10⁻⁴

Henderson-Hasselbalch equation:

pOH = pKb + log([(CH₃CH₂)₃NH⁺]/[(CH₃CH₂)₃N])

pOH = -log(5.2 × 10⁻⁴) + log(13/7) = 3.55

pH = pKw - pOH = 14.00 - 3.55 = 10.45

====

b.

Initial moles of (CH₃CH₂)₃N = 0.002 mol

Moles of HCl added = (0.1000 mol/L) × (20.80/1000 L) = 0.00208 mol

HCl is in excess.

Moles of HCl left unreacted = (0.00208 - 0.002) mol = 0.00008 mol

Volume of the final solution = (20.00 + 20.80) mL = 40.8 mL = 0.0408 L

In the final solution:

[H₃O⁺] = [HCl] = (0.00008 mol) / (0.0408 L) = 0.00196

pH = -log[H₃O⁺] = -log(0.00196) = 2.71

====

c.

Initial moles of (CH₃CH₂)₃N = 0.002 mol

Moles of HCl added = (0.1000 mol/L) × (29.00/1000 L) = 0.0029 mol

HCl is in excess.

Moles of HCl left unreacted = (0.0029 - 0.002) mol = 0.0009 mol

Volume of the final solution = (20.00 + 29.00) mL = 49 mL = 0.049 L

In the final solution:

[H₃O⁺] = [HCl] = (0.0009 mol) / (0.049 L) = 0.0184

pH = -log[H₃O⁺] = -log(0.0184) = 1.74

So, what's shown here is the ion product of pure water: that is, the product of the concentrations of hydronium and hydroxide ions in pure water at 25 °C. By this relation, if you know the [H₃O⁺], you can calculate the [OH⁻], and vice-versa.

Since [H₃O⁺] × [OH⁻] = 1.0 × 10⁻¹⁴, [OH⁻] = (1.0 × 10⁻¹⁴)/[H₃O⁺].

Substituting the given [H₃O⁺] as 1.25 × 10⁻² M:

[OH⁻] = (1.0 × 10⁻¹⁴)/(1.25 × 10⁻² M) = 8.0 × 10⁻¹³ M.

Answer:

It is clear from the above food chain that the grass occupies the first topic level which consists of producers. The second tropic level consist of primary consumers which is Insect. And the Frog assign the Third tropic level of food chain consisting of secondary consumers.Explanation:

Answer:

please your question is not understandable

Answer:

A

Explanation:

Just dissolve all three compounds in an organic solvent which not miscible with water (those two I have mentioned) in separatory funnel. Use aqueous sodium bicarbonate first to extract. If you use sodium hydroxide, both phenol and benzoic acid will be extracted as both can react with hydroxide

Answer:

I'm pretty sure its D

Explanation:

It says the best that explains. D states that when it has less energy that it the molecules will collide. And they would to make a liquid. So thats why its D.

Answer:dang

Explanation: