Answer:
(a) The time taken for the plane to reach 50 km/hr is 811.97 s
(b) (i) the acceleration of the plane is 0.012 m/s²
(ii) The time taken for the plane to reach 50 km/hr is 1172.85 s
Explanation:
Given;
mass of the freight train, m = 3.8 x 10⁷ kg
force applied to pull the train, F = 6.5 x 10⁵ N
a. How long does it take the train to go from rest to 50 km/hr?
Given;
initial velocity, u = 0
final velocity, v = 50 km/hr = 13.889 m/s
Apply Newton's second law of motion to determine the time traveled by the train at the given speed;
[tex]F = ma = \frac{m(v-u)}{t}\\\\t = \frac{m(v-u)}{F}\\\\t = \frac{3.8*10^7(13.889-0)}{6.5*10^5}\\\\t = 811.97 \ s[/tex]
(b)
(i) the acceleration of the plane
Given;
air resistance, = 2.0 x 10⁵ N
Apply Newton's second law of motion;
∑F = ma
6.5 x 10⁵ N - 2.0 x 10⁵ N = ma
4.5 x 10⁵ N = ma
[tex]a = \frac{4.5 * 10^5 }{m}\\\\a = \frac{4.5 * 10^5 }{3.8*10^7}\\\\a = 0.012 \ m/s^2[/tex]
(ii) time taken for the plane to reach 50 km/hr is given by;
[tex]F = \frac{m(v-u)}{t}\\\\t = \frac{m(v-u)}{F}\\\\t = \frac{3.8*10^7(13.889-0)}{4.5*10^5}\\\\t = 1172.85 \ s[/tex]
Once a player catches the Frisbee they are only allowed to pivot like in
basketball.
True
False
A person applies a force of 200N to move an object initially at rest weighing 400N. What could be the coefficient of static friction between the object and the surface?
Answer:
[tex]\mu=0.5[/tex]
Explanation:
Given that,
Applied force, F = 200 N
Weight of the object, or the normal force, N = 400 N
We need to find the coefficient of static friction between the object and the surface.
The force of friction has the same magnitude as that of applied force. It can be given by :
[tex]F=\mu mg[/tex]
mg is weight of the object
[tex]\mu=\dfrac{F}{mg}\\\\\mu=\dfrac{200}{400}\\\\\mu=0.5[/tex]
So, the coefficient of static friction between the object and the surface is 0.5.
Someone help me please I got it wrong idk why please help
Answer:
not enough avidence is the correct answer
What are the differences between elastic and inelastic collisions when it comes to how momentum is conserved and spread between the balls after a collision?
Answer:
Collision can be classified as either elastic or inelastic. The main difference between elastic and inelastic collisions is that, in elastic collisions, the total kinetic energy of the colliding objects before the collision is equal to the their total kinetic energy after the collision. In inelastic collisions, the total kinetic energy of the objects after the collision is less than the total kinetic energy of the objects before the collision.
GIVE. BRAINLIEST
PLEASE
A basketball has a volume of 300 cm3. If Michael pumped 200 cm3 and Fandi pumped another 200 cm3 into it then the total volume of air in the basketball is 400 cm3.
Answer:
...
Explanation:
If a basketball has a volume of 300 cm³. If Michael pumped 200 cm³ and Fandi pumped another 200 cm³ into it then the total volume of air in the basketball would be 300 cm³.
What is the matter?Anything which has mass to keep the same when comparing the hardness of the solid and occupies space is known as matter, mainly there are four states of matter solid liquid gases, and plasma.
As given in the problem if a basketball has a volume of 300 cm³. If Michael pumped 200 cm³ and Fandi pumped another 200 cm³.
The volume of the basketball would remain the same as the gas pumped in the basketball compress would take the volume of the basketball.
Thus, If Michael pumped 200 cm³ and Fandi pumped another 200 cm³ into it then the total volume of air in the basketball would be 300 cm³.
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What is the main function of an earthworm organ
Answer:
brain
Explanation:
brain and blood
What is the proportionality constant between an object and
its acceleration by a given force?
Answer:
The net force acting on an object is proportional to the acceleration of that object with respect to an inertial frame of reference. The constant of proportionality in this, Newton's second law, is the classical mass of the object.
Explanation:
What unit is used to measure energy when calculating specific heat capacity? Give the abbreviation, not the full name.
The unit that should be used to measure energy when calculating specific heat capacity is Energy is in Joules ( J ).
What unit is used to measure energy?The specific heat capacity should be determined in joules per kilogram degree-celsius ( J k g − 1 ∘ C − 1 ).
It is to be supplied for the substance with respect to mass and it increased the temperature.
Hence, The unit that should be used to measure energy when calculating specific heat capacity is Energy is in Joules ( J ).
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The unit used to measure energy when calculating specific heat capacity is the joule (J).
The joule (J), a unit used to quantify energy, is used to calculate specific heat capacity. In the International System of Units (SI), the joule serves as the default unit of energy.
It is described as the quantity of energy that is delivered when one newton of force is exerted across a one-meter distance.
Thus, the quantity of heat energy needed to increase the temperature of a particular substance by a specific amount is measured as specific heat capacity. J/kg°C, or joules per kilogramme per degree Celsius, is the unit of measurement.
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Why is creativity important in constructing scientific explanations?
A. There are very few scientists who are creative people.
B. Science works when scientists make up their data.
C. The results of some experiments might not be explained by any
known theories.
D. Scientists all think in exactly the same way.
WHICH OF THE FOLLOWING IS
you need to attach a picture so I can answer it
5) A forklift raises a box 1.2 m doing 7,000 J of work on it. What is the mass of the box?
Answer:
The answer is 5833.3 kgExplanation:
To find the mass of the box we use the formula
[tex]m = \frac{w}{d} \\ [/tex]
w is the workdone
d is the distance
From the question we have
[tex]m = \frac{7000}{1.2} \\ = 5833.3333...[/tex]
We have the final answer as
5833.3 kgHope this helps you
How many electrons are in the third energy level?
2
8
18
20
Answer:
B)8
Explanation:
In the first energy level you can have, at most, 2. Every energy level after that wants to have 8 electrons. Valence electrons I believe.
Hope this helps, have a nice day! (^-^)
Romeo is a 68 kg astronaut. Juliet is a beautiful cosmonaut who is standing on the balcony of a 4.58 x 10^5kg space station that is at rest and out of gas. Romeo is floating 25 meters away from the space station’s center of mass, how strong is the force between Romeo and Juliet?
Answer:
F = 3.32 x 10⁻⁶ N
Explanation:
The force of attraction between two masses is given by Newton's Law of Gravitation, as follows:
F = Gm₁m₂/r²
where,
F = Force between Romeo and Juliet = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
m₁ = mass of Romeo = 68 kg
m₂ = mass of space station = 4.58 x 10⁵ kg
r = distance = 25 m
Therefore,
F = (6.67 x 10⁻¹¹ N.m²/kg²)(68 kg)(4.58 x 10⁵ kg)/(25 m)²
F = 3.32 x 10⁻⁶ N
answer please urgent
Answer:
equal and unlike charges
Explanation:
Answer:
[tex]\huge\boxed{\sf Equal \ and \ unlike \ charges}[/tex]
Explanation:
When two bodies are rubs against each other, Charges of equal magnitude are induced in them. However, they are of equal magnitude but the charges are opposite and unlike.
For Example:
If we rub an iron rod with a cotton cloth, a positive charge will be induced in the iron rod and a negative charge will be induced in the cotton cloth. Note that the charges will be of equal magnitude.
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
Let me know if you have any q's regarding this!
~AnonymousHelper1807Which describes Hans Oersteds work with electricity and magnetism
Hans Oersteds works with electricity and magnetism is that he developed electromagnetism when he observed compass needle that was deflected when electric current flow through it.
What is electromagnetism?Electromagnetism is a type of electromagnetic force that occur between electric field and magnetic field and the interaction that exhaust between them and charged particles.
Therefore, Hans Oersteds works with electricity and magnetism is that he developed electromagnetism.
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1.The
across each resistor is
the same in a series circuit.
) voltage
current
Answer:
The answer is Current.
Explanation:
In a series circuit, every component will have the same current.
In parallel circuit, all voltage of component remains the same.
Answer:
In a series circuit, each resistor has the same charge flowing through it.
Explanation:
If you have resistors arranged in a chain, the current only has one path to take which results in an equal charge in each resistor.
Zookeepers carry a stretcher that holds a sleeping lion. The total mass of the stretcher and lion is 175 kg. The lion's forward acceleration is 2 m/s2. What is the force necessary to produce this acceleration?
Answer:
350 N
Explanation:
Newton's second law:
∑F = ma
∑F = (175 kg) (2 m/s²)
∑F = 350 N
Suppose that 5 J of work is needed to stretch a spring from its natural length of 36 cm to a length of 45 cm.
Required:
a. How much work is needed to stretch the spring from 38 cm to 43 cm? (Round your answer to two decimal places.) J
b. How far beyond its natural length will a force of 45 N keep the spring stretched? (Round your answer one decimal place.
Answer:
2.78J
3.64cm
Explanation:
Natural length is 36 and stretches to 45. 5 J of work is needed
5 = 1/2k(0.45-0.36)²
5 = 1/2k(0.09)²
5 = 0.0081k/2
10 = 0.0081k
K = 1234.568
X1 = 0.38-0.36 = 0.02
X2 = 0.43-0.36 = 0.07
Work done
W = 1/2k(x2²-x1²)
W = 1/2(1234.568)(0.007²-0.02²)
W = 1234.568(0.0049-0.0004)/2
W = 2.78j
F = 45N
F = kx
X = f/k
= 45/1234.568
= 0.0364
= 3.64cm
The answer to A is 2.78j
The answer to b is 3.64cm
is power a vector quantity
Answer:
Power is a scalar quantity and has a unit,a magnitude(a numerical value) but no direction.
Explanation:
What becomes V if we use 2 resistors of 4W in parallel?
A. 2.66 V
B. 6 V
C. 12 V
D. 24 V
Explanation:
The question is incomplete. To get the voltage V across the resistors, we need to total current flowing in the circuit.
Let the current I = 6 A
According to ohms law, V = IRt
V is the total voltage
I is the total current
Rr is the total effective resistance
Since the 2 4ohms resistors are connected in parallel;
1/Rt = 1/4 + 1/4
1/Rt = 2/4
Cross multiply
2Rt = 4
Rt = 4/2
Rt = 2 ohms
Get the voltage V.
V = IRt
V = 6(2)
V = 12V
Hence the required voltage will be 12V
Note that the value of the current used was assumed. The same calculation can be employed for any value of the current
What does a switch in an electrical circuit do?
O A. It concentrates negative charges on one side of the circuit when it
is open.
B. It concentrates negative charges on one side of the circuit when it
is closed.
C. It allows electrons to flow from one part of the circuit to another
when it is open.
D. It allows electrons to flow from one part of the circuit to another
when it is closed.
Answer:
It allows electrons to flow from one part of the circuit to another
when it is closed.
Explanation:
hope this helps <3 !!
Answer: D
Explanation:
draw a force body diagram represnting various forces on book
Explanation:
thanks me and dont forget to mark mi as brainlist
A 12 volt car battery pushes charge through the headlight resistance of 10 ohms. How much current is passing through the circuit
Answer:50
Explanation:
The current flowing through the given circuit is 0.12 A.
The given parameters;
voltage of the battery, V = 12Vresistance of the headlight, R = 10 OhmsThe current passing through the headlight is calculated by applying Ohms law as shown below;
V = IR
where;
I is the current flowing the circuitR is the resistance to the flow of current in the circuitSubstitute the given parameters and solve the current flowing in the circuit;
[tex]V = IR\\\\I = \frac{V}{R} \\\\I = \frac{12}{10} \\\\I = 0.12 \ A[/tex]
Thus, the current flowing through the given circuit is 0.12 A.
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A rock is sitting at the edge of a flat merry-go-round at a distance of 1.6 meters from the center. The coefficient of static friction between the rock and the merry-go-round is 0.70. What is the minimum angular velocity of the merry-go-round that would cause the rock to begin sliding off?
Answer:
ω = 2.1 rad/sec
Explanation:
As the rock is moving along with the merry-go-round, in a circular trajectory, there must be an external force, keeping it on track.This force, that changes the direction of the rock but not its speed, is the centripetal force, and aims always towards the center of the circle.Now, we need to ask ourselves: what supplies this force?In this case, the only force acting on the rock that could do it, is the friction force, more precisely, the static friction force.We know that this force can be expressed as follows:[tex]f_{frs} = \mu_{s} * F_{n} (1)[/tex]
where μs = coefficient of static friction between the rock and the merry-
go-round surface = 0.7, and Fn = normal force.
In this case, as the surface is horizontal, and the rock is not accelerated in the vertical direction, this force in magnitude must be equal to the weight of the rock, as follows:Fn = m*g (2)This static friction force is just the same as the centripetal force.The centripetal force depends on the square of the angular velocity and the radius of the trajectory, as follows:[tex]F_{c} = m* \omega^{2}*r (3)[/tex]
Since (1) is equal to (3), replacing (2) in (1) and solving for ω, we get:[tex]\omega = \sqrt{\frac{\mu_{s} * g}{r} } = \sqrt{\frac{0.7*9.8m/s2}{1.6m}} = 2.1 rad/sec[/tex]
This is the minimum angular velocity that would cause the rock to begin sliding off, due to that if it is larger than this value , the centripetal force will be larger that the static friction force, which will become a kinetic friction force, causing the rock to slide off.Describe the difference between simply taking measurements and doing a scientific experiment.
In 2-3 sentences
Draw the resultant of each set of vectors. Indicate if you used the parallelogram or head-to-tail method.
Answer:
Explanation:
See attached file.
A robot probe drops a camera off the rim of a 239 m high cliff on Mars, where the free-fall acceleration rate is -3.7m/s². Find the velocity with which the camera hits the ground.
Answer:
42.1m/s
Explanation:
Given parameters:
Height of cliff = 239m
Free fall acceleration = -3.7m/s²
Unknown:
Final velocity of the camera = ?
Solution:
When the body is falling under free fall, the acceleration = 3.7m/s² ;
The appropriate motion equation is:
V² = U² + 2gH
V = final velocity
U = initial velocity
g = free fall acceleration
H = height of the fall
Insert the parameters and solve;
U = 0
V² = 0² + 2 x 3.7 x 239
V² = 1768.6
V = 42.1m/s
A 30kg boxed is pushed with a force of 20N. What is the boxes acceleration. Please show work
Answer:
The answer is 0.67 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass
From the question we have
[tex]a = \frac{20}{30} = \frac{2}{3} \\ = 0.6666666...[/tex]
We have the final answer as
0.67 m/s²Hope this helps you
Three persons wants to push a wheel cart in the direction marked x in Fig. The two person push with horizontal forces F1 and F2 as F1 = 45 N 70degree And F2 = 75 N , 20 Degree (a) Find the magnitude and direction of the force that third person should exert to stop this cart. You can ignore the effects of friction. (b) If the third person exerts the force found in part (a), the cart accelerates at 200 m/S2 in the (+) x-direction. What is the weight of the cart
Answer:
I had to search the Figure on Google to solve this question.
a) The magnitude of the force F₃ is:
[tex] F_{3} = 87.47 N [/tex]
And the direction of F₃:
[tex] \alpha = 79.04 ^{\circ} [/tex] (with respect to the y-direction, in the third quadrant)
b) P = 4.22 N
Explanation:
I had to search the Figure on Google to solve this question.
a) We can find the force of the third person as follows:
[tex] \Sigma F_{x} = F_{1x} + F_{2x} + F_{3x} = 0 [/tex]
[tex] \Sigma F_{y} = F_{1y} - F_{2y} + F_{3y} = 0 [/tex]
So, in x-direction we have:
[tex] \Sigma F_{x} = 45 N*cos(70) + 75 N*cos(20) + F_{3x} = 0 [/tex]
[tex] F_{3x} = -85.87 N [/tex]
In y-direction we have:
[tex] \Sigma F_{y} = 45 N*sin(70) - 75 N*sin(20) + F_{3y} = 0 [/tex]
[tex] F_{3y} = -16.63 N [/tex]
The magnitude of the force F₃ is:
[tex] F_{3} = \sqrt{F_{3x}^{2} + F_{3y}^{2}} = \sqrt{(-85.87 N)^{2} + (-16.63 N)^{2}} = 87.47 N [/tex]
To find the direction of F₃ we need to calculate its angle with respect to the y-direction (in the third quadrant):
[tex] tan(\alpha) = \frac{|F_{3x}|}{|F_{3y}|} = \frac{85.87 N}{16.63 N} [/tex]
[tex] \alpha = 79.04 ^{\circ} [/tex]
b) If the third person exerts the force found in part (a) the car will stop, so the only way for the cart to accelerate at 200 m/s² is that the third person does not exert the force found in a.
To find the weight of the cart when it accelerates at 200 m/s², we need to consider: F₃ = 0.
First, we need to find the cart's mass. Since the car is moving in the x-direction we have:
[tex] \Sigma F_{x} = F_{1x} + F_{2x} = ma [/tex]
[tex] 45 N*cos(70) + 75 N*cos(20) = m*200 m/s^{2} [/tex]
[tex] m = \frac{45 N*cos(70) + 75 N*cos(20)}{200 m/s^{2}} = 0.43 kg [/tex]
Now, the weight of the cart is:
[tex] P = mg = 0.43 kg*9.81 m/s^{2} = 4.22 N [/tex]
I hope it helps you!
What would happen if one of the four-stroke combustion cycle parts never worked?
Answer:
An internal-combustion engine goes through four strokes: intake, compression, combustion (power), and exhaust. As the piston moves during each stroke, it turns the crankshaft.
Answer:
The engine will not work causing no movement in the wheels .
Explanation:
Remember the four stroke combustion cycle powers the wheels and if one of these parts do not work, then the car will not move .
