The distance travelled by the ball, given the data is 7.82 m
Data obtained from the questionInitial velocity (u) = 10 m/sAngle of projection (θ) = 25 degrees Time of flight (T) = 1.5 sAcceleration due to gravity (g) = 9.8 m/s²Range (R) = ?How to determine the rangeThe range (i.e distance) travelled by the ball can be obtained as illustrated below:
R = u²Sine(2θ) / g
R = 10² × Sine (2×25) / 9.8
R = 10² × Sine 50 / 9.8
R = 7.82 m
Thus, the distance travelled by the ball is 7.82 m
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An extraterrestrial civilisation lives on a planet with a very elliptical orbit. Additionally, thousands of large asteroids orbit their solar system. The civilisation uses the light from their home star to count the number of asteroids in the direct line between the star and their planet. For a first measurement, they count the asteroids for 60 days and detect 1000 objects. Several months later, they start a second measurement: This time, they count for 80 days. How many asteroids will they detect during the second measurement? Explain why. (Note: Assume that the asteroids are homogeneously distributed in their solar system.)
i will mark as a brainiest please help me as soon
For Kepler's third law this can be solved as normal ratios
1000/60=x/80100/6=x/806x=8000x=8000/6x=1333.34asteroidsThe number of asteroids which will be detected during the second measurement is 1333.34.
What is an Asteroid?These are referred to objects which revolve round the sun and are characterized by their small rocky shape.
Kepler's third law can be used to solved it using normal ratios
1000/60=x/80
100/6 = x/80
6x = 8000
x= 8000/6
x=1333.34asteroids
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Where will the strongest force be excerted by the scissor blades to cut through a piece of material? Explain your answer.
Answer:
in the thick part of the scissors ✂️
Explanation:
because in physics simple machine called wedge the force applied in this thick area it have thine side used to split or piece objects
You have a wooden bench in your living room. You set your backpack on the bench and lean your hand against the wall. Name two action-reaction pairs that are present in this situation
The action-reaction pairs in the given situation are:
the backpack and the bench the and and the wallWhat are action-reaction pairs?Action-reaction pairs are two forces which are equal but oppositely directed in their line of action.
Action-reaction pairs are according to Newton's third law of motion.
The action-reaction pairs in the given situation are:
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You are riding a bicycle you apply forward force of 50 n, and you and the bicycle have a combined mass of 100kg. What is the acceleration of the bicycle?
Answer:
a = 0.5m.s²
Explanation:
Fnet = m×a
50 = 100×a
a = 0.5
What change occurs to the mass of an object when an unbalanced force is applied to it
The actual mass of a sheet of copy paper is 4.5 g. What must be the actual mass of a 1 cm² plece of copy paper?
Show your calculations.
The actual mass of a 1 cm² piece of copy paper is determined as 0.0074 g.
Area of the sheet of paper in square centimetersArea = Length x Width
Area = (11 x 2.54 cm) x (8.5 x 2.54 cm)
Area = 603.22 cm²
Actual mass of the sheet of paperMass = area density/area
Mass = (4.5 gcm²)/(603.22 cm²)
Mass = 0.0074 g
The complete question is below:
A sheet of 8.5 inch by 11inch paper has a mass of 4.50 grams one square centimeter , 1cm2 of that sheet of paper will have a mass closets to ____grams ( (hint use 1inch = 2.54 centimeters and area = length times)
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Suppose the resistance of a copper wire is 1.05 ohms at 30°C. Find the temperature at which the resistance becomes 1.50 ohms.
Suppose the resistance of a copper wire is 1.05 ohms at 30°C. the temperature is mathematically given as
T=139.89
What is the temperature at which the resistance becomes 1.50 ohms.?Generally, the equation for the coefficient of change is mathematically given as
[tex]\mu_k= 0.2+(0.043)3\\\\\mu_k=0.2+(0.043)(4.343)[/tex]
[tex]\mu_k=0.387[/tex]
In conclusion, the Temperature of copper
[tex]R=R_0( 1+ \alpha(T-T1))[/tex]
1.5(1+0.005(T-30))
T=139.89
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Two cars, with the same mass and traveling at the same speed, hit large trees head-on. One car has a rigid body that undergoes little or no deformation in the collision. The other has ``crumple zones'': portions of the body designed to crumple and deform in such a collision. How does this improve the chances that the driver of the second car will survive the event
The crumple zones in the second car will improve the chance of survival of the driver because it will act as shock absorber, reducing the impact of the force on the driver.
Newton's third law of motion
According to Newton's third law of motion, action and reaction are equal and opposite.
The car with rigid body will exert maximum force to the driver while the car with crumple zone will exert lesser force to the driver since the crumple zone will act as shock absorber, reducing the impact of the force on the driver.
Thus, the crumple zones in the second car will improve the chance of survival of the driver because it will act as shock absorber, reducing the impact of the force on the driver.
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The Voyager spacecraft is moving at 17 000 m/s. How far will it travel in one year? Give your answer in km.
Explanation:
first change m/s to km/hr and time 1 year to hour b/c we are asked the to give in km. so,
v=17,000 m/s = 17000×3600/1000 = 61,200 km/hr
t= 1 year= 365 days =365day×24 hr/day = 8,760hr
therefore, V = s/t from this s = v×t =61200×8760 =536,112,000 Km
what is the angular displacement of a minute hand of a clock after 3 minutes?
Answer:
π/10 rads
Explanation:
It takes an hour (60 minutes) for the minute's hand to turn a full circle or achieve an angular rotation of
2πl rad.
Now, number of periods of 3 minutes in an hour is;
Number of periods = 60/3 = 20 periods
Thus, 3 minutes rotation accounts for 1/20 of 2π the rotation of the minute's hand in an hour.
Thus;
Angular displacement = (1/20) * 2π = π/10 rads
Many medicines started out as natural products. Aspirin was originally made from _______________
A. The bark of the willow tree
B. Poppies
C. Mold
D. The foxglove flower.
Answer:
A
Explanation:
ASA was found in the bark of willow trees.
the 12-lead ecg shows st-segment elevation in leads v2 and v3 of ≥ 0.2 mv. what is this finding indicative of?
The 12-lead ECG test that shows st-segment elevation in leads v2 and v3 of ≥ 0.2 mv, could be a diagnostic for myocardial infarction.
What is 12 - lead ECG test?
A 12-lead electrocardiogram (ECG) is a medical test that is recorded using leads, or nodes, attached to the body.
Electrocardiograms, sometimes referred to as ECGs, capture the electrical activity of the heart and transfer it to graphed paper.
When a 12-lead ECG shows st-segment elevation in leads v2 and v3 of ≥ 0.2 mv, it could be a diagnostic for myocardial infarction.
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a note of frequency 200Hz has a velocity of 400m/s. what is the wavelength of the note
Answer:
[tex]\huge\boxed{\sf \lambda = 2 m}[/tex]
Explanation:
Given data:Frequency = f = 200 Hz
Velocity = v = 400 m/s
Required:Wavelength = λ = ?
Formula:v = fλ
Solution:Put the givens in the formula
400 = (200)λ
Divide 200 to both sides
400/200 = λ
2 m = λ
λ = 2 m
[tex]\rule[225]{225}{2}[/tex]
What is bioluminescence?
A. It is when living creatures absorb light.
B. It is when living creatures reflect light.
C. It is when living creatures produce light.
D. It is when living creatures destroy light.
Answer:
C.
Explanation:
Bioluminescence is the fascinating natural phenomenon by which living creatures produce light.
A proton moves in the negative x-direction through a uniform magnetic field in the negative y-direction what is the direction of the magnetic force acting on the proton?
out of the page
into the page
in the positive y-direction
in the negative y-direction
i will give you full point and mark you as brainiest if you help me please i need it sooner.
The energy of the sun Is a response for the life on earth The planet might take a seat down withinside the liveable radius starting from 0. eighty-five AU to two AU.
Why large planets rotates faster?The large the planet quicker will be the rotation speed, and therefore shortest the time to take rotate across the axis. The large planets are exceedingly greater solid whilst as compared to the small planet system.
The hazards are
• With improved size, the quantity of gravitational enchantment posed via way of means of the planet might additionally increase. This might cause attracting outer area asteroids and consequential crater impact.
• The large the size, the farther it'd be from the big name to atone for the hydrostatic balance, hence reducing the possibilities for it being an inhabitable area.
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We have an Atwood device, two blocks connect by a string strung over a pulley, but the twist this time is that both blocks are on perfectly smooth inclines. The upper block is on an incline 15 degrees to the horizontal and has a mass of 7kg. The lower block is on an incline of 65 degrees to the horizontal and has a mass of 11kg. Find the acceleration of the system?
The Acceleration of the system is 6.41 m/s².
Given,
α= 15°, m₁ = 7kg
β= 65°, m₂ = 11 kg
Let, a be the acceleration and T is the tensions at the end it's the cord.
Let, the mass m₂ be coming down along the inclined plane along the inclined surface towards downward m₂g sin β and the tension in the upward direction,
Resultant force, m₂a=m₂g sin β -T
11a=((11) ×g sin 65°) -T ...(i)
Now, considering the motion of m₁ which moves downwards, the forces are m₁g sinα, and T both are acting downwards.
Resultant force m₁a = m₁g sin α+T
7a =7g sin 15°+T ...(ii)
Solving both the equations by adding them,
18a=11gsin 65°+7g sin 15°-T+T
18a=11gsin 65°+7g sin 15°=115.45
a=115.45/18=6.41 m/s²
Hence, the Acceleration of the system is 6.41 m/s².
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What do we generally avoid in a many-to-many junction table?
It is important to avoid an autoincrement primary key column in a many-to-many junction table.
What is a many-to-many junction table?A many-to-many junction table is a junction table which links multiple data in one table to multiple data in another table.
Generally in a many-to-many junction table, it is important to avoid an autoincrement primary key column.
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Use the drop-down menus to complete the sentence.
A. object spins around its own axis, while a
object moves around another object.
Object spins around its own axis, while the object moves around another object.
What is Earth's revolution?
Earth's rotation or Earth's spin is the rotation of planet Earth around its own axis, as well as changes in the orientation of the rotation axis in space.
The continuous rotation of the Earth about its axis gives rise to the revolution of earth around the sun.
Thus, object spins around its own axis, while the object moves around another object.
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answer: rotating, revolving
The strength of a magnetic field around a wire carrying a current of 20 A is 0.004 T. What is the strength of the magnetic field if the current is changed to 40 A ?
Given the increased current, the strength of the magnetic field around the wire carrying the current increases to 0.008T
What is the strength of the magnetic field if the current is changed to 40 A ?Given that;
First scenario
Strength of magnetic field B = 0.004TCurrent A = 20ASecond scenario
Strength of magnetic field B' = ?Current I' = 40AFirst, we determine the strength of the magnetic field.
B/I = B'/I'
0.004T/20A = B'/40A
B' = ( 0.004T × 40A ) / 20A
B' = 0.16AT / 20A
B' = 0.008T
Given the increased current, the strength of the magnetic field around the wire carrying the current increases to 0.008T
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When water vapor (a gas) starts to cool, it can
become a liquid. What causes this change in the
state of matter in water?
Answer:
This process is CONDENSATION
Explanation:
Condensation occurs when water vapour loses some of its kinetic energy to a colder body and changes into liquid state.
which of the following best decribes
26.6 00
Fig. E26.6 both meters are ide-
alized, the battery has no appre-
ciable internal resistance, and the
ammeter reads 1.15 A. (a) What
does the voltmeter read? (b) What
is the emf & of the battery?
26.7 For the circuit shown
For the circuit shown in Figure E26.6
V
45.0 Ω
25.0 Ω
ww(A)
|15.0 Ω
www
|15.0 Ω
W
www
ww
4+
35.0 = ?
10.0 Ω
a. The voltmeter reads 0.053 volts
b. The electromotive force, emf of the battery is 0. 106 volts
How to determine the voltmeter reading
a. Given the current = 1. 15A
Voltmeter reads the voltage = V
Resistance could be gotten from the diagram = R
V = IR
To find the resistance from the structure
First, find the resistance in parallel
Resistance in parallel = 1/R1 = 1/R2 + 1/R3 = 1/25 + 1/15 + 1/15 = 0. 17 Ohms
Now, find the resistance in series
Resistance in series = R1 + R2 + R3 = 45 + 0. 17 + 10 = 55. 17 Ohms
Finally, the resistance in parallel = 1/35 + 1/55. 17 = 0. 028 + 0. 018 = 0. 046 Ohms
Substitute values into the equation
V = IR
V = 1. 15 * 0. 046
V = 0. 053 Volts
b. To find the Emf, use the formula
Emf = V + Ir
Substitute the values into the formula
Emf = 0. 053 + 1.15 * 0.046
Emf = 0. 053 + 0. 0529
Emf = 0. 106 volts
Therefore, the voltmeter reads 0.053 volts and the electromotive force of the battery us 0. 106 volts
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Looking at the wave diagram which best describes the wave
Answer:
B describes the best ...
An Object weighs 600N on Earth. What would its weight be on on another planet of gravitational acceleration 8N/kg?
Answer:
Correct option is A)
Weight on earth = 600N
Let g= 10m/s2 on earth
Mass on earth = 10600=60 kg
Now, since mass is a constant quantity so, it will remain 60 kg on the moon also.
Now, weight on moon = mg′
m= mass =60 kg
g′ = acc. due to gravity on moon = 61th the value on earth
So, Weight on moon = 61th of the weight on earth
⇒ Weight on the moon =600×61=100 N
What did johannes kepler contribute to the study of planets? he formulated the universal law of gravitation. he identified the first moons of jupiter. he collected detailed data that led to the proposal of the heliocentric model. he provided mathematical support for the heliocentric model.
Johannes Kepler contributed to the study of planets : He provided mathematical support for the heliocentric model.
What is Kepler's first law of planetary motion?Kepler's first law of planetary motion states that the planets revolve around the Sun in orbits elliptical in shape with the Sun at its one of the focus.
As the planets rotate around the Sun, the relative distance between the Sun and planets increases and decreases.
The heliocentric model in which the Earth and planets revolve around the Sun at the center of the universe. Johannes gave the mathematical calculations of this model.
Thus, last option is correct.
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Answer:
D
Explanation:
a lunar probe is moving 1670 m/s at a 73.0 angle. it needs to land on the moon 3.71 x 10^8 m away in a 46.0 direction in 8.64 x 10^4 s. what is the magnitude of the acceleration that the engine must produce?
The magnitude of the acceleration that the engine must produce is 0.065 m/s².
What is acceleration?Acceleration is given by the ratio of Resultant or total force acting on any object and the its mass.
It can also be defined as the rate change of velocity with time.
acceleration a = (Δv) / (Δt)
Given is a lunar probe is moving 1670 m/s at a 73° angle. it needs to land on the moon 3.71 x 10⁸ m away in a 46° direction in 8.64 x 10⁴ s.
The initial velocity will be
1670 x cos (73°-46°) = 1487.981 m/s
Using the second equation of motion, we have
s = ut + 1/2 at²
The final velocity will be zero after landing on Moon.
Substituting the values, we have
3.71 x 10⁸= 1487.981 x 8.64 x 10⁴ + 1/2 a ( 8.64 x 10⁴)²
Solving the equation, we get
acceleration, a = 0.065 m/s²
Thus, the magnitude of the acceleration that the engine must produce is 0.065 m/s²
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Answer:
The direction is 30.6
Explanation:
A boater is accompanied by a person at least 16 years of age. In michigan, what is the youngest age that this person can be and legally operate a boat powered by a motor of more than 35 hp?.
The youngest age that this person can be and legally operate a boat powered by a motor of more than 35 hp will be 12 years of age.
What is electric power?It is the rate of the electric work done. Its unit is the watt. Horsepower is the unit of power.
A person under the age of 12 may only legally operate a boat with a motor that has more than 6 horsepower but no more than 35 horsepower
if they meet two requirements: they have a boating safety certificate, which they must have on board; and they are being closely watched by an adult who is at least 16 years old.
Hence the youngest age that this person can be and legally operate a boat powered by a motor of more than 35 hp will be 12 years of age.
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A force of 5N produces an acceleration of 8m/s2 on mass m1, and an acceleration of 24m/s2 on a mass m2. What acceleration would the same force provide if both the masses are tied together.
The acceleration that the same force will provide if both masses are tied together is; 6.0 m/s².
How to find the Acceleration?We are given;
Force; F = 5 N
Acceleration of the first mass, a₁ = 8.0 m/s²
Acceleration of the second mass, a₂ = 24 m/s²
Formula for force is;
F = ma
Let us find both masses; m₁ and m₂.
m₁ = F/a₁
m₂ = F/a₂
Thus;
m₁ = 5/8 kg
m₂ = 5/24 kg
Total mass is; m = m₁ + m₂
m = 5/8 + 5/24
m = 15 + 5/24
m = 20/24 kg
Thus, acceleration if they are both tied together is;
a = F/m
a = 5/(20/24)
a = 6.0 m/s².
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A flywheel is rotating at 30 rev/s. What is the total angle, in radians, through which a point on the flywheel rotates in 40 s?
The total angle, in radians, through which a point on the flywheel rotates is 7540 radians
Angular motionFrom the question, we are to determine the total angle in radians
Using the formula,
[tex]\omega = \frac{\theta}{t}[/tex]
Where [tex]\omega[/tex] is the angular velocity
[tex]\theta[/tex] is the angle
and t is the time
From the given information,
[tex]\omega = 30 \ rev/s[/tex]
Convert to rad/s
[tex]\omega = 30 \times 2\pi \ rad/s[/tex]
[tex]\omega = 188.496 \ rad/s[/tex]
and t = 40 s
From the formula
[tex]\omega = \frac{\theta}{t}[/tex]
[tex]\theta = \omega t[/tex]
∴ [tex]\theta = 188.496 \times 40[/tex]
θ = 7539.822 rad
θ ≅ 7540 rad
Hence, the total angle, in radians, through which a point on the flywheel rotates is 7540 radians
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