A. Directions:translate each problem into algebraic expression or equation and identify the variable/s.

1. Julie weighs c kilogram. After going to gym for six months, she lost 2. 5 kilograms. Express her weight algebraically.

2. Peter is m centimeter tall. Jhon's height is 5 more than twice the height of Peter. How tall is Jhon?

3. Ador is thrice older than Emy. If Emy is d years old less than 9,how old is ador?

4. Jupiter is n years old now. How old is Jupiter 7 years from now?

5. Anna's sister is p years old. Anna is 4 years older than thrice the age of her sister. How old is Anna?

guys please help me please
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Based on the information provided, Madeline and Ben invested $1500 for their son Peter's education on the day he was born at an interest rate of 6.7% compounded quarterly. Since Peter is now 19 years old and wants to go to college, we can calculate the current value of his education fund.

To do this, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:
A = the final amount
P = the principal (initial investment)
r = the annual interest rate (as a decimal)
n = the number of times the interest is compounded per year
t = the time in years

In this case, we have:

P = $1500
r = 6.7% = 0.067 (as a decimal)
n = 4 (since the interest is compounded quarterly)
t = 19 (since Peter is now 19 years old)

So, the current value of Peter's education fund is:

A = $1500(1 + 0.067/4)^(4*19)
A = $1500(1.01675)^76
A = $1500(2.4826)
A = $3,723.90

Therefore, the current value of Peter's education fund is $3,723.90. This should help Madeline and Ben determine how much more they need to save for Peter's college expenses.

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1. For the solid bounded by the panes 2 = 1 - x and z=1-y in the first octant, one triple integral that describes the volume of the solid. The region is bounded by the x-axis and the curve y = √(2x-x^2), which is the top half of a circle centered at (1,0) with radius 1.

One possible order of integration is:
∫0^1 ∫0^(1-x) ∫0^(1-y) dzdydx
This means we integrate over z first, then y, then x. Another order of integration could be:
∫0^1 ∫0^x ∫0^(1-x-y) dzdydx
Here we integrate over z first, then x, then y.
Another possible order of integration is:
∫0^1 ∫0^1-x ∫0^1-y dzdxdy
Here we integrate over z first, then x, then y. This order of integration can also be rewritten in polar coordinates as:
∫0^(π/4) ∫0^(secθ-1) ∫0^(cscθ-1) r dzdrdθ
2. Compute by switching the order of integration:
∫0^2 ∫0^√(2x-x^2) dydx

First, let's sketch the region of integration. The region is bounded by the x-axis and the curve y = √(2x-x^2), which is the top half of a circle centered at (1,0) with radius 1.
We can switch the order of integration to integrate over x first, then y:
∫0^1 ∫0^(2-2y^2) dxdy
To find the limits of integration for x, we set y = √(2x-x^2) and solve for x:
y^2 = 2x - x^2
x^2 - 2x + y^2 = 0
(x-1)^2 = 1 - y^2
x = 1 ± √(1-y^2)
Since the curve is the top half of the circle, we take the positive square root:
x = 1 + √(1-y^2)
So the limits of integration for x are 0 to 2-2y^2. Integrating with respect to x first gives:
∫0^1 ∫0^(2-2y^2) dxdy = ∫0^1 (2-2y^2)dy = 4/3
3. Write the following integral in polar coordinates, then solve:
arctan (dy/dx)
We can write dy/dx in terms of polar coordinates using the chain rule:
dy/dx = (dy/dr)(dr/dθ)(1/dx/dθ)
Using the relationships x = rcosθ and y = rsinθ, we have:
dx/dθ = -rsinθ
dy/dθ = rcosθ, So
dy/dx = (dy/dr)(dr/dθ)(1/dx/dθ) = (cosθ)/(sinθ) = cotθ
Therefore, the integral becomes:
∫arctan(cotθ) dθ

To solve this integral, we use the identity arctan(x) + arctan(1/x) = π/2 for x > 0:
arctan(cotθ) = π/2 - arctan(tanθ)
So the integral becomes:
∫(π/2 - arctan(tanθ)) dθ
Integrating, we get:
(π/2)θ - ln|cosθ| + C
Where C is the constant of integration.
1. To find three other orders of integration for the solid bounded by the planes z = 1 - x, z = 1 - y, x = 0, y = 0, and z = 0 in the first octant, we can rearrange the given triple integral, which is given as:
∫∫∫_D dz dy dx
Now, we can find three other orders of integration:
a) ∫∫∫_D dx dz dy
b) ∫∫∫_D dy dx dz
c) ∫∫∫_D dy dz dx
2. To compute the volume of the solid by switching the order of integration, we can rewrite the given integral ∫∫ dy dx as: ∫∫ dx dy

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The answer is A. 1. We can use L'Hopital's rule to evaluate the limit:

limit x→9√(f(x))-3/√(x)-3 = limit x→9 (f(x)-9)/(x-9) / (√(f(x))-3)/(√(x)-3)

Now, we know that f(9) = 9 and f'(9) = 4, so we can use the definition of the derivative to write:

f(x) - f(9) = f'(9)(x-9) + o(x-9)

where o(x-9) represents a term that goes to 0 faster than x-9 as x approaches 9. Plugging this into the numerator, we get:

f(x) - 9 = 4(x-9) + o(x-9)

Plugging this into the denominator, we get:

√(f(x)) - 3 = √(4(x-9) + o(x-9)) = 2√(x-9) + o(1)

√(x) - 3 = √(x-9) + o(1)

Therefore, the limit becomes:

limit x→9 (4(x-9) + o(x-9))/(√(x-9) + o(1)) / (2√(x-9) + o(1))/(√(x-9) + o(1))

Simplifying this expression, we get:

limit x→9 2(4(x-9) + o(x-9))/(√(x-9) + o(1))^2

limit x→9 8 + 2o(1)/(x-9)

As x approaches 9, the o(1) term goes to 0, so the limit becomes:

8 + 2*0/0 = 8

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Mr. Mensah's total earnings at the end of the fifteenth year of service is €1920.00 + €2520.00 = €4440.00.

To calculate Mr. Mensah's salary in the fifteenth year of service, we need to determine the pattern of salary increase over the years.

We know that Mr. Mensah's salary starts at €6400.00 and increases by €240.00 every year for the first eight years. After that, he is promoted to a new post with an annual salary of €9500.00, which increases by €360.00 every year.

Let's break it down:

For the first eight years, the salary increases by €240.00 per year:

After 1 year: €6400.00 + €240.00 = €6640.00

After 2 years: €6640.00 + €240.00 = €6880.00

...

After 8 years: €6400.00 + (8 * €240.00) = €6400.00 + €1920.00 = €8320.00

From the ninth year onwards, the salary increases by €360.00 per year:

After 9 years: €9500.00 + €360.00 = €9860.00

After 10 years: €9860.00 + €360.00 = €10220.00

...

After 15 years: €9500.00 + (7 * €360.00) = €9500.00 + €2520.00 = €12020.00

Therefore, Mr. Mensah's salary in the fifteenth year of service is €12,020.00.

To calculate Mr. Mensah's total earnings at the end of the fifteenth year of service, we need to sum up his salaries from year 1 to year 15.

For the first eight years, the total earnings can be calculated as follows:

Total earnings = (Salary in year 1 + Salary in year 2 + ... + Salary in year 8) = 8 * €240.00 = €1920.00

From the ninth year onwards, the total earnings can be calculated as follows:

Total earnings = (Salary in year 9 + Salary in year 10 + ... + Salary in year 15) = 7 * €360.00 = €2520.00

Therefore, Mr. Mensah's total earnings at the end of the fifteenth year of service is €1920.00 + €2520.00 = €4440.00.

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Based on the given information, Yasmina should use Sally's Saddles if she expects to give 200 rides and wants to make the most profit.

To determine which company Yasmina should use to offer horseback rides at her school's Spring Fair, we need to compare the costs and revenues associated with each option.

First, let's consider Polly's Ponies. They charge $100 for a small pony and Yasmina can charge children $2 for a ride. To break even with this option, Yasmina would need to give 50 rides ($100 / $2 per ride). If she expects to give 200 rides, she would earn $400 in revenue ($2 per ride x 200 rides) and have a profit of $300 ($400 revenue - $100 rental fee).

Next, let's consider Sally's Saddles. They charge $240 for a larger horse and Yasmina can charge children $3 for a ride. To break even with this option, Yasmina would need to give 80 rides ($240 / $3 per ride). If she expects to give 200 rides, she would earn $600 in revenue ($3 per ride x 200 rides) and have a profit of $360 ($600 revenue - $240 rental fee).

Therefore, if Yasmina wants to make the same amount of profit regardless of which company she uses, she would need children to take a total of 125 rides ((($240 rental fee for Sally's Saddles - $100 rental fee for Polly's Ponies) / ($3 per ride - $2 per ride)). If she expects to give 200 rides, she should use Sally's Saddles since she will make a higher profit of $360 compared to $300 with Polly's Ponies.

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0.180 is the sample mean weight of grapes, and what is the margin of error

The sample mean weight is the midpoint of the confidence interval:

sample mean = (lower limit + upper limit) / 2 = (15.875 + 16.595) / 2 = 16.235

Therefore, the sample mean weight of grapes is 16.235 ounces.

The margin of error is half of the width of the confidence interval:

margin of error = (upper limit - sample mean) = (16.595 - 16.235) / 2 = 0.180

Therefore, the margin of error is 0.180 ounces.

So the correct answer is: "The sample mean weight is 16.235 ounces, and the margin of error is 0.180 ounces."

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To find the unique function f(x) satisfying the given conditions, we will use the method of undetermined coefficients.

Assume that f(x) is a polynomial of degree n. Then, f"(x) is a polynomial of degree n-2. Therefore, x^2 f(x) is a polynomial of degree n+2.

Let's first find the second derivative of f(x):

f''(x) = (d^2/dx^2) f(x)

Since we assumed that f(x) is a polynomial of degree n, we can write:

f''(x) = n(n-1) a_n x^(n-2)

where a_n is the leading coefficient of f(x).

Now, let's substitute the given values of f(1) and f(2):

f(1) = a_n

f(2) = a_n 2^n

Therefore, we have two equations:

n(n-1) a_n = x^2 f(x)

a_n = 4

a_n 2^n = 1

Solving for n and a_n, we get:

n = 3/2

a_n = 4/3^(3/2)

Thus, the unique function f(x) that satisfies the given conditions is:

f(x) = (4/3^(3/2)) x^(3/2) - (4/3^(3/2)) x^2 + 1/2
It seems that your question is incomplete or contains some errors. However, based on the information provided, I understand that you are looking for a function f(x) that satisfies given conditions involving its second derivative and specific values of f(1) and f(2).

To assist you properly, please provide the complete and correct version of the question with all the necessary conditions.

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Tina received $12.30 for recycling her cans last week.

To find how much money Tina got for her cans last week, we need to find the total number of cans she collected and then multiply that by 0.05 (since she gets 5 cents per can).

On Wednesday and Thursday, Tina collected 37 cans each day, for a total of 2 x 37 = 74 cans.

On Tuesday, Friday, Saturday, and Sunday, she collected 43 cans each day, for a total of 4 x 43 = 172 cans.

The total number of cans collected is 74 + 172 = 246 cans.

To find the total amount of money Tina received, we multiply 246 by 0.05, which gives us:

246 x 0.05 = $12.30

Therefore, Tina received $12.30 for recycling her cans last week.

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To find the moment of inertia about the y-axis of the first-quadrant area bounded by the curve y=9−x^2 and the coordinate axes, we can use the formula:

I = ∫y² dA

where I is the moment of inertia, y is the distance from the y-axis to the infinitesimal element of area dA, and the integral is taken over the first-quadrant area.

To set up the integral, we need to express y in terms of x for the curve y=9−x². Solving for y, we get:

y = 9 - x²

The area element dA is given by:

dA = y dx

Substituting y in terms of x, we get:

dA = (9 - x²) dx

Now we can express the moment of inertia as an integral:

I = ∫y² dA
 = ∫(9 - x²)² dx     (limits of integration: x = 0 to x = 3)

To evaluate the integral, we can expand the integrand using the binomial theorem:

I = ∫(81 - 36x² + x⁴) dx
 = 81x - 12x³ + (1/5)x⁵     (limits of integration: x = 0 to x = 3)

Finally, we can substitute the limits of integration and simplify:

I = (81(3) - 12(3)³ + (1/5)(3)⁵) - 0
 = 243 - 108 + 27
 = 162

Therefore, the moment of inertia about the y-axis is 162 units^4.
To find the moment of inertia (Iy) about the y-axis for the first-quadrant area bounded by the curve y = 9 - x^2 and the coordinate axes, we need to integrate the expression for the moment of inertia using the limits of the region.

The curve intersects the x-axis when y = 0, so:

0 = 9 - x²
x² = 9
x = ±3

Since we're in the first quadrant, we're interested in x = 3.

The moment of inertia about the y-axis is given by the expression Iy = ∫x²dA, where dA is the area element. In this case, we'll use a vertical strip with thickness dx and height y = 9 - x². Therefore, dA = y dx.

Now, let's integrate Iy:

Iy = ∫x²(9 - x²) dx from 0 to 3

To solve this integral, you may need to use polynomial expansion and integration techniques:

Iy = ∫(9x² - x⁴) dx from 0 to 3
Iy = [3x³/3 - x⁵/5] from 0 to 3
Iy = (3(3)³/3 - (3)⁵/5) - (0)
Iy = (81 - 243/5)
Iy = (405 - 243)/5
Iy = 162/5

So the moment of inertia about the y-axis for the first-quadrant area bounded by the curve y = 9 - x^2 and the coordinate axes is Iy = 162/5.

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The function h(x) can be represented by -3x-9 .

An equation can be represented by a linear function. The standard form for the linear equation is: y= mx+b , for example, y=7x+6. Where:

m= the slope.

b= the constant term that represents the y-intercept.

For the given example: m=7 and b=6.

The question gives two linear equations that represent two functions: f(x)=-2x+7 and g(x)=5x-16.

For solving this you should sum both equations. See below

h(x)=f(x)+g(x)

h(x)=-2x+7 +5x-16

h(x)=-3x-9

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The angles on the north side of the intersection are complementary angles because complementary angles are two angles whose measures add up to 90 degrees. At the intersection of Madison Street and Peachtree Street, the north side of the intersection forms a right angle (90 degrees).

Any angle on the north side of the intersection must be complementary to the right angle, meaning its measure must be less than 90 degrees.

For example, if we consider the angle formed by Madison Street and the north side of the intersection, it is less than 90 degrees and therefore complementary to the right angle formed by the intersection. Similarly, if we consider the angle formed by Peachtree Street and the north side of the intersection, it is also less than 90 degrees and complementary to the right angle formed by the intersection.
Therefore, all angles on the north side of the intersection are complementary to the right angle formed by the intersection.

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The quotient of the given division is 0.4082, under the condition that dividend is 4.082 and divisor is 10,000.

The count of zeros in 10,000 is 4, then we have to transfer the decimal point four places to the left to divide by 10,000. Here, we have to relie on the basic principles involved in division.

Then, in order to find the quotient of 4.082 and 10,000, we have to divide 4.082 by 10,000. To perform this, we expand the number by moving the decimal point forward of 4.082.

That is,

[tex] \frac{4.082 }{10000} [/tex]

= 0.4082

The quotient is 0.4082

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The baker bought approximately 17.5 pounds of flour.

Let's use algebra to solve the problem. Let x be the number of pounds of flour that the baker bought. We know that the cost of the flour is $15.05 and the price per pound is $0.86. So we can set up the equation:

$15.05 = $0.86 x

To solve for x, we can divide both sides by $0.86:

x = $15.05 ÷ $0.86

x ≈ 17.5

Therefore, the baker bought approximately 17.5 pounds of flour.

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The linear equation is y = 4x + 2, the quadratic equation is y = 4x² - 2x + 2 , and the exponential equation is y = 2(3ˣ).

Let's use the first two points on the table: (0, 2) and (1, 6).

The slope is (6 - 2) / (1 - 0) = 4.

To find the y-intercept, we can plug in one of the points and solve for b in the equation y = mx + b.

Let's use (0, 2): 2 = 4(0) + b, so b = 2.

Therefore, the linear equation is y = 4x + 2.

We need to find the values of a, b, and c. Let's use the first three points on the table: (0, 2), (1, 6), and (2, 18).

We can create a system of equations by plugging in these points:

2 = a(0)² + b(0) + c,

6 = a(1)² + b(1) + c, and

18 = a(2)² + b(2) + c.

Simplifying these equations, we get

c = 2, a + b + c = 6, and 4a + 2b + c = 18.

Solving this system of equations, we get

a = 4, b = -2, and c = 2.

Therefore, the quadratic equation is y = 4x² - 2x + 2.

We can use the formula for exponential growth, which is y = abˣ, where a is the initial value and b is the growth factor. Let's use the first two points on the table: (0, 2) and (1, 6).

The initial value is 2, so the equation is y = 2bˣ.

To find the growth factor, we can divide the y-values: 6/2 = 3 = b¹, so b = 3. Therefore, the exponential equation is y = 2(3ˣ).

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By calculations, Colleen's photo is smaller than Ali's photo

From the question, we have the following parameters that can be used in our computation:

Area of Ali's photo = 91 square inches.

For Colleen's photo, we have

9 inches by 7 inches

This means that

Area of Colleen's photo = 9 * 7 square inches.

Evaluate

Area of Colleen's photo = 63 square inches.

63 square inches is lesser than 91 square inches

This means that Colleen's photo is smaller than Ali's photo

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Thus, the volume of cone for the given slant height and radius is found as:  314 cu. cm.

The distance from a cone's apex to its outer rim is referred to as the segment's slant height. It is corresponding to the hypotenuse's length of a right triangle that creates the cone.

Given data:

slant height of cone  l =  13 cm

radius r =  5 cm

Let h be the height

So, using Pythagorean theorem, find height.

l² = h² + r²

h² = l² - r²

h²= 13² - 5²

h² = 169 - 25

h = 12 cm

volume of a cone = 1/3 *π*r²*h

volume of a cone = 1/3 *3.14*5²*12

volume of a cone = 3.14*25*4

volume of a cone = 314 cu. cm

Thus, the volume of cone for the given slant height and radius is found as:  314 cu. cm.

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The expression that is equivalent to the one Shea wrote is b 5 x y x 5 x 2 +4

From the question, we have the following parameters that can be used in our computation:

5(y + 2) + 2 shows the amount of money five friends paid for snacks at a basketball game

This means that

Amount = 5(y + 2) + 2

When expanded, we have

Amount = 5 * y + 5 * 2 + 2

Using the above as a guide, we have the following:

The expression that is equivalent to the one Shea wrote is b 5 x y x 5 x 2 +4

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The recursive formula for this sequence is f(n) = f(n-3) + 6n - 18.

We can use the method of finite differences to find a possible recursive formula for this sequence.

First, let's compute the first few differences:

f(4) - f(1) = 6

f(7) - f(4) = 6

Since the second differences are zero, we can assume that the sequence is a quadratic sequence. Let's write it in the form f(n) = an^2 + bn + c. We can solve for the coefficients using the given values:

f(1) = a(1)^2 + b(1) + c = 6

f(4) = a(4)^2 + b(4) + c = 12

f(7) = a(7)^2 + b(7) + c = 18

Solving for a, b, and c, we get:

a = 1

b = 5

c = 0

Therefore, the recursive formula for this sequence is f(n) = f(n-3) + 6n - 18.

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Answer:

16

Step-by-step explanation:

4y = 2.6

y = 0.65

20y + 3

= 20 × 0.65 + 3

= 13 + 3

= 16

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The calculated value of the length of segment KM is 11.83

From the question, we have the following parameters that can be used in our computation:

JM = 10

LM = 14

Using the similar triangle ratio, we have

JM/KM = KM/LM

substitute the known values in the above equation, so, we have the following representation

10/KM = KM/14

So, we have

KM^2 = 10 * 14

Evaluate

KM^2 = 140

This gives

KM = 11.8321595662

As a decimal rounded to the nearest hundredth, we have

KM = 11.83

HEnce, the value of KM is 11.83

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Lillian would have approximately $14,599 in her account after 3 years, to the nearest dollar.

To find out how much Lillian would have in her account after 3 years, we need to use the future value of a series formula, which is:

[tex]FV = P \frac{(1 + r)^nt - 1)}{r}[/tex]

where:
FV = future value of the series
P = monthly deposit ($430)
r = monthly interest rate (annual interest rate / 12)
n = number of times interest is compounded per year (12)
t = number of years (3)

First, we need to find the monthly interest rate by dividing the annual interest rate (4.5%) by 12:
[tex]r =\frac{0.045}{12} = 0.00375[/tex]

Now we can plug the values into the formula:
[tex]FV = 430 \frac{(1 + 0.00375)^{12x3}  - 1)}{0.00375}[/tex]

Calculating the future value:
[tex]FV = 430\frac{(1.127334 - 1) }{0.00375} = 430 \frac{0.127334}{ 0.00375} = 430 (33.955)[/tex]
[tex]FV =14,598.65[/tex]

So, Lillian would have approximately $14,599 in her account after 3 years, to the nearest dollar.

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Let's use the variables "a" for the cost of an apple, "b" for the cost of a banana, and "o" for the cost of an orange.

From the first transaction:

- 3a + 5b + 4o = 8.85

From the second transaction:

- 8a + b + 3o = 8.10

From the third transaction:

- 2a + 2b + 2o = 4.40

We can now solve for one variable and substitute into another equation until we have found all three. Let's solve for "a" in the third equation:

- 2a + 2b + 2o = 4.40

- 2a = 4.40 - 2b - 2o

- a = 2.20 - b - o

Now we can substitute "a" into the first equation:

- 3a + 5b + 4o = 8.85

- 3(2.20 - b - o) + 5b + 4o = 8.85

- 6.60 - 3b - 3o + 5b + 4o = 8.85

- 2b + o = 0.75  (Equation A)

Next, we can substitute "a" into the second equation:

- 8a + b + 3o = 8.10

- 8(2.20 - b - o) + b + 3o = 8.10

- 17.60 - 8b - 8o + b + 3o = 8.10

- -7b - 5o = -9.50  (Equation B)

Now we have two equations with two variables, so we can solve for one variable and substitute into the other equation. Let's solve for "o" in Equation A:

- 2b + o = 0.75

- o = 0.75 - 2b

Now we can substitute "o" into Equation B:

- -7b - 5o = -9.50

- -7b - 5(0.75 - 2b) = -9.50

- -7b - 3.75 + 10b = -9.50

- 3b = -5.75

- b = -1.92 (rounded to the nearest cent)

Finally, we can substitute "b" into Equation A to find "o":

- 2b + o = 0.75

- 2(-1.92) + o = 0.75

- o = 4.59 (rounded to the nearest cent)

We can now find "a" by substituting "b" and "o" into one of the original equations. Let's use the first equation:

- 3a + 5b + 4o = 8.85

- 3a + 5(-1.92) + 4(4.59) = 8.85

- 3a - 9.60 + 18.36 = 8.85

- 3a = -0.09

- a = -0.03 (rounded to the nearest cent)

Since the cost of a piece of fruit cannot be negative, we made a mistake somewhere in our calculations. It's possible that we made a mistake in rounding at some point. To be sure, let's check our answers by substituting the values we found back into the original equation.

2(-0.0737) + 2(-0.0528) + 2o = 4.40

-0.1474 - 0.1056 + 2o = 4.40

2o = 4.6529

o = 2.3264 (rounded to 4 decimal places)

Therefore, each apple costs approximately $0.0737, each banana costs approximately $0.0528, and each orange costs approximately $2.3264.

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The volume of the cone is 117.3 (Round to the nearest tenth).

To find the volume of this cone with a height of 7 inches and a radius of 4 inches, and round to the nearest tenth, follow these steps:
1. Use the formula for the volume of a cone: V = (1/3)πr²h, where V is the volume, r is the radius, and h is the height.
2. Plug in the given values: V = (1/3)π(4²)(7)
3. Calculate the volume: V = (1/3)π(16)(7) = (1/3)(112π)
4. Multiply and round to the nearest tenth: V ≈ 117.3 cubic inches

So, the volume of this cone is approximately 117.3 cubic inches.

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Answer:

Step-by-step explanation:

We know that when you have this data, you can proceed with calculating the confidence intervals to determine IMM Thai's lead.

Hi there! The survey results seem to indicate that IMM Thai is indeed ahead of the other Thai restaurants among the voters.

To determine a range of likely values for IMM Thai's true lead over Lucky House, Thai Temple, and Thai Basil combined, you would need to calculate confidence intervals.

Unfortunately, I cannot provide specific calculations without the necessary data (sample size, mean, standard deviation, etc.).

Once you have this data, you can proceed with calculating the confidence intervals to determine IMM Thai's lead.

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Answer:

h = 30 cm

Step-by-step explanation:

Given:

V (volume) = 69,120π cm^3

d (diameter) = 96 cm (r (radius) = 0,5 × 96 = 48 cm

Find: h (height) - ?

[tex]v = \frac{1}{3} \times \pi {r}^{2} \times h[/tex]

[tex] \frac{1}{3} \times \pi \times {48}^{2} \times h = 69120\pi[/tex]

Multiply the whole equation by 3 to eliminate the fraction:

[tex]2304\pi \times h = 69120\pi[/tex]

[tex]h = 30[/tex]

Answer:

what integer?

Step-by-step explanation:

more detail please?

(a) State the null and alternative hypotheses.

Null Hypothesis: The mean monthly residential electricity consumption in the region is less than or equal to 880 kWh.

Alternative Hypothesis: The mean monthly residential electricity consumption in the region is greater than 880 kWh.

(b) Determine the test statistic.

We need to use a one-tailed t-test because the alternative hypothesis is one-tailed.

t = (x - μ) / (σ / √n) = (900 - 880) / (124 / √64) = 2.581

(c) Find the p-value.

Using a t-table or a calculator, we can find the p-value associated with a t-value of 2.581 and 63 degrees of freedom: p-value = 0.007

(d) State the conclusion.

The p-value is less than the significance level of 0.01, which means that we reject the null hypothesis. We have enough evidence to support the claim that the mean monthly residential electricity consumption in the region is more than 880 kWh.

(e) Interpret the conclusion in the context of the problem.

Based on the sample data, we can conclude that the mean monthly residential electricity consumption in the region is likely to be greater than 880 kWh. However, we cannot say for sure whether this conclusion would hold true for the entire population.

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