A design engineer wants to construct a sample mean chart for controlling the service life of a halogen headlamp his company produces. He knows from numerous previous samples that when this service life is in control it is normally distributed with a mean of 500 hours and a standard deviation of 20 hours. On three recent production batches, he tested service life on random samples of four headlamps, with these results: Sample Service Life (hours) 1 495 500 505 500 2 525 515 505 515 3 470 480 460 470 What is the mean of the sampling distribution of sample means when the service life is in control

Answers

Answer 1

Answer:

[tex]$ \text {Sample mean} = \bar{x} = \mu = 500 \: hours $[/tex]

Step-by-step explanation:

What is Normal Distribution?

We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.  

For the given scenario, it is known from numerous previous samples that when this service life is in control it is normally distributed with a mean of 500 hours and a standard deviation of 20 hours.

On three recent production batches, he tested service life on random samples of four headlamps.

We are asked to find the mean of the sampling distribution of sample means when the service life is in control.

Since we know that the population is normally distributed and a random sample is taken from the population then the mean of the sampling distribution of sample means would be equal to the population mean that is 500 hours.

[tex]$ \text {Sample mean} = \bar{x} = \mu = 500 \: hours $[/tex]

Whereas the standard deviation of the sampling distribution of sample means would be

[tex]\text {standard deviation} = s = \frac{\sigma}{\sqrt{n} } \\\\[/tex]

Where n is the sample size and σ is the population standard deviation.

[tex]\text {standard deviation} = s = \frac{20}{\sqrt{4} } \\\\ \text {standard deviation} = s = \frac{20}{2 } \\\\ \text {standard deviation} = s = 10 \: hours \\\\[/tex]


Related Questions

Find the percent of decrease from $2.00 to $1.25

Answers

Answer:

37.5

Step-by-step explanation:z

2.0-1.25=0.75

0.75/2.00 x 100

37.5% decrease

A local cable company claims that the proportion of people who have Internet access is less than 63%. To test this claim, a random sample of 800 people is taken and its determined that 478 people have Internet access. The following is the setup for this hypothesis test: H0:p=0.63 Ha:p<0.63 Find the p-value for this hypothesis test for a proportion and round your answer to 3 decimal places.

Answers

Answer:

Step-by-step explanation:

For the null hypothesis,

H0 : p = 0.63

For the alternative hypothesis,

Ha : p < 0.63

This is a left tailed test

Considering the population proportion, probability of success, p = 0.63

q = probability of failure = 1 - p

q = 1 - 0.63 = 0.37

Considering the sample,

Sample proportion, P = x/n

Where

x = number of success = 478

n = number of samples = 800

P = 478/800 = 0.6

We would determine the test statistic which is the z score

z = (P - p)/√pq/n

z = (0.6 - 0.63)/√(0.63 × 0.37)/800 = - 1.76

From the normal distribution table, the area below the test z score in the left tail 0.039

Thus

p = 0.039

Answer:

-3.66

Step-by-step explanation:

can someone please help me it’s urgent!!!!!

Answers

Answer:

6/4

Explanation:

If Alex can file the papers in the cabinets for 6 hours and 4 hours with Millie, then the fraction to represent the papers filed with Millie would be 6/4.

Hope this helps!

Suppose Carol Danvers invested $1,000 into an account paying 6% annual interest compounded
annually.

How much is in her account at the end of one year?

Answers

Answer:

$ 1,060.00

Step-by-step explanation:

A = $ 1,060.00

A = P + I where

P (principal) = $ 1,000.00

I (interest) = $ 60.00

Compound Interest Equation

A = P(1 + r/n)^nt

Where:

A = Accrued Amount (principal + interest)

P = Principal Amount

I = Interest Amount

R = Annual Nominal Interest Rate in percent

r = Annual Nominal Interest Rate as a decimal

r = R/100

t = Time Involved in years, 0.5 years is calculated as 6 months, etc.

n = number of compounding periods per unit t; at the END of each period

An animal shelter has a 65% adoption rate for puppies. Of all puppies in the shelter, 75% live to be 7 years or older. Of the puppies who are adopted, 80% live to be 7 years or older. What is the probability that a randomly selected puppy in the shelter will get adopted and live 7 or more years

Answers

Answer:

52% probability that a randomly selected puppy in the shelter will get adopted and live 7 or more years

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: A puppy is adopted.

Event B: The puppy lives 7 or more years.

An animal shelter has a 65% adoption rate for puppies

This means that [tex]P(A) = 0.65[/tex]

Of the puppies who are adopted, 80% live to be 7 years or older.

This means that [tex]P(B|A) = 0.8[/tex]

What is the probability that a randomly selected puppy in the shelter will get adopted and live 7 or more years

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

[tex]P(A \cap B) = P(A)*P(B|A)[/tex]

[tex]P(A \cap B) = 0.65*0.8[/tex]

[tex]P(A \cap B) = 0.52[/tex]

52% probability that a randomly selected puppy in the shelter will get adopted and live 7 or more years

What is the square root of x if x = 25?

Answers

Answer:

5 is your answer

Step-by-step explanation:

The [tex]\sqrt{25}[/tex] will equal to 5, because [tex]5^2[/tex] = 25

Answer:

5

Step-by-step explanation:

5 x 5 =25, so it is the square root of 25

The drama club is selling candles for a fundraiser. They spend $100 on the candles and sell them for $4.50 each. How many candles must they sell to make more than $125 profit?

Let x represent the number of candles sold. Which inequality can you use to find x?

Answers

So I try to help

Step-by-step explanation:

I don't no sorrry

Answer:

the first one!!

Step-by-step explanation:

According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, 23% of all complaints in 2007 were for identity theft. In that year, Alaska had 321 complaints of identity theft out of 1,432 consumer complaints (Consumer fraud and, 2008). (7.1.2)

State the random variable, population parameter, and hypotheses.

Answers

Answer:

Random variable: for this case represent the number of complaints in 2007

Population parameter: represent the real proportion of complaints in 2007 p

Hypothesis to verify

We want to check if the true proportion of complaints in 2007 is equal to 0.23, the system of hypothesis are.:  

Null hypothesis:[tex]p=0.23[/tex]  

Alternative hypothesis:[tex]p \neq 0.23[/tex]  

Step-by-step explanation:

Information provided

n=1432 represent the random sample taken

X=321 represent the number of complaints

[tex]\hat p=\frac{321}{1432}=0.224[/tex] estimated proportion of complaints in 2007

[tex]p_o=0.23[/tex] is the value to verify

z would represent the statistic

Random variable: for this case represent the number of complaints in 2007

Population parameter: represent the real proportion of complaints in 2007 p

Hypothesis to verify

We want to check if the true proportion of complaints in 2007 is equal to 0.23, the system of hypothesis are.:  

Null hypothesis:[tex]p=0.23[/tex]  

Alternative hypothesis:[tex]p \neq 0.23[/tex]  

In two sample surveys 125 people were asked about their favorite fruit in the survey 40 people chose apples 64 choose oranges and 21 chose bananas in the second 34 chose apples 63 chose oranges 19 Joe’s banana marine inferred before is this a French trooper by us on the data explain

Answers

Answer:

Marianne made an inference that is true based on the data. More than half of the people surveyed in each sample chose oranges as their favorite fruit. Since most people in each sample chose oranges, it is likely that oranges are the favorite fruit of the entire population.

hope it help please mark me as brainliest

Which equation can be used to find mMN

Answers

Answer:

Its depending on the angle

Find the first 4 terms and the 10th one n+5

Answers

Answer: First 4 terms of n + 5  = 6,7,8,9

10th term = 15

Hope this is right

Step-by-step explanation:

By putting n = 1 , 2, 3 , 4 we can find first 4 terms

When n = 1

n + 5 = 1 + 5 = 6

When n = 2

n + 5 = 2 + 5 = 7

When n = 3

n + 5 = 3 + 5 = 8

When n = 4

n + 5 = 4 + 5 = 9

When n = 10

n + 5 = 10 +5 = 15

A new post-surgical treatment is being compared with a standard treatment. Seven subjects receive the new treatment, while seven others (the controls) receive the standard treatment. The recovery times, in days, are given below.

Treatment: 12 13 15 19 20 21 24
Control: 18 23 24 30 32 35 39

Required:
Find a 98% confidence interval for the difference in the mean recovery times between treatment and control.

Answers

Answer:

[tex] (17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745[/tex]

[tex] (17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255[/tex]

Step-by-step explanation:

For this case we have the following info given:

Treatment: 12 13 15 19 20 21 24

Control: 18 23 24 30 32 35 39

We can find the sample mean and deviations with the the following formulas:

[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]

[tex] s =\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}[/tex]

And repaplacing we got:

[tex] \bar X_T = 17.714[/tex] the sample mean for treatment

[tex] \bar X_C = 28.714[/tex] the sample mean for treatment

[tex] s_T= 4.461[/tex] the sample deviation for treatment

[tex] s_C= 7.387[/tex] the sample deviation for control

[tex]n_T= n_C= 7[/tex] the sample size for each sample

The degrees of freedom are given by:

[tex] df= 7+7-2= 12[/tex]

The confidence interval for the difference of means is given by:

[tex] (\bar X_T -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_T}{n_T} +\frac{s^2_C}{n_C}}[/tex]

The confidence is 98% so then the significance is [tex]\alpha=0.02[/tex] and [tex] \alpha/2 =0.01[/tex]. Then the critical value would be:

[tex] t_{\alpha/2}=2.681[/tex]

And replacing we got:

[tex] (17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745[/tex]

[tex] (17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255[/tex]

If 9x+2y^2−3z^2=132 and 9y−2y^2+3z^2=867, then x+y =

Answers

Answer:

[tex]x + y = \frac{1000}{9}[/tex]

Step-by-step explanation:

Step 1: Identify the approach:

With this problem, the general solution is to try manipulate given data and transform data into a new form, in which, the desired value [tex](x + y)[/tex] is on the left side and all of other components which do not contain [tex]x[/tex] or [tex]y[/tex] are on the right side.

Step 2: Analyze:

[tex]9x + 2y^{2} - 3z^{2} = 132\\9y - 2y^{2} + 3z^{2} = 867[/tex]

Realize that in both equations, the [tex]2y^{2}[/tex] and [tex]3z^{2}[/tex] are in form of different signs. Then adding up corresponding sides of both equation can help eliminate these undesired components.

Step 3: Perform manipulation:

[tex]9x + 2y^{2} - 3z^{2} + 9y - 2y^{2} - 3z^{2} = 132 + 867[/tex]

Rearrange:

[tex](9x + 9y) + (2y^{2} - 2y^{2}) +(3z^{2} - 3z^{2}) = 132 + 867[/tex]

Simplify:

[tex]9(x + y) + 0 + 0 = 1000[/tex]

Simplify:

[tex]x + y = \frac{1000}{9}[/tex]

Hope this helps!

:)

Running times for 400 meters are Normally distributed for young men between 18 and 30 years of age with a mean of 93 seconds and a standard deviation of 16 seconds. How fast does a man have to run to be in the top 1% of runners?

Answers

Answer:

To be in the top 1% of the runners, the man has to run the 400 meters in at most 55.768 seconds.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 93, \sigma = 16[/tex]

How fast does a man have to run to be in the top 1% of runners?

The lower the time, the faster they are. So the man has to be at most in the 1st percentile, which is X when Z has a pvalue of 0.01. So he has to run in at most X seconds, and X is found when Z = -2.327. Then

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-2.327 = \frac{X - 93}{16}[/tex]

[tex]X - 93 = -2.327*16[/tex]

[tex]X = 55.768[/tex]

To be in the top 1% of the runners, the man has to run the 400 meters in at most 55.768 seconds.

Please help me extra points for 1 math question. Please help before my time is up. Five times a number, added to -3, is 37. Find that number.

Answers

Answer:

your number should be 8

Step-by-step explanation:

5x+(-3)=37

5x-3=37

+3       +3

5x=40

÷5  ÷5

x=8

hope this helps

Answer:

The answer is 8.

5x-3=37

5x=37+3

5x=40

x=40/5

x=8

HOPE IT HELPS!!

NFL player Gerald Sensabaugh recorded a 46 inch standing vertical jump at the 2005 NFL Combine, at that time the highest for any NFL player in the history of the Combine. Sensabaugh weighed about 200 lb when he set the record. Part A What was his speed as he left the floor

Answers

Answer:

His speed as he left the floor is 4.83 m/s.

Step-by-step explanation:

Given: 46 inches = 1.1684 m and mass = 200 lb = 90.7185 Kg.

From the third equation of motion under free fall,

  [tex]V^{2}[/tex] = [tex]U^{2}[/tex] - 2gs

Where; V is the final velocity (0), U is the initial velocity (unknown), g is the value of gravity - 10 m/[tex]s^{2}[/tex] and s is the distance = 1.1684 m.

Then;

0 = [tex]U^{2}[/tex] - 2gs

[tex]U^{2}[/tex] = 2gs

   = 2 × 10 × 1.1684

  = 23.368

⇒ U = [tex]\sqrt{23.368}[/tex]

       = 4.8340 m/s

The initial velocity, U = 4.83 m/s.

Therefore, his speed as he left the floor is 4.83 m/s.

Answer:

His speed as he left the floor is 4.83 m/s.

Step-by-step explanation:

What is the value of Y ? I’ll give you a brainslist !!!

Answers

[tex]answer \\ = 5 \sqrt{3} \\ please \: see \: the \: attached \: picture \: for \: \: full \: solution \\ hope \: it \: helps[/tex]

Answer:

[tex]5 \sqrt{3} [/tex]

First answer is correct

Step-by-step explanation:

[tex] \frac{5}{x} = \cos(60) \\ \frac{5}{x} = \frac{1}{2} \\ x = 10 \\ \frac{y}{x} = \sin(60 ) \\ \frac{y}{10} = \frac{ \sqrt{3} }{2} \\ 2y = 10 \sqrt{3} \\ y = \frac{10 \sqrt{3} }{2} \\ y = 5 \sqrt{3} [/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

helpppppppppppppppppppppppppppppppppp

Answers

Answer:

answer is 2/3

Step-by-step explanation:

probability it is an eclair is 1/15=3/(3+2x+6+x)= 1/(x+3)

so x+3=15 and then x = 12

so the probability it is a humbug is (2*12+6)/(3*12+9) = 30/45 = 2/3

List the steps taken and find the area of the figure below
6cm
6 CM
6 cm
6 cm

Answers

Answer:

36 cm

Step-by-step explanation:

Since all measurements of the figure are the same, that means that this figure is a square.  To find the area of a figure multiply length by width.  Since this figure is a square and all sides are equal, we multiply 6 by 6 for an area of 36 cm.

Triangle JKL was dilated using the rule D Subscript M, one-third. The image, triangle J'K'L', is the result of the dilation. Point M is the center of dilation. Triangle J K L is dilated to form smaller triangle J prime K prime L prime. The length of M L prime is 2.5. What is L'L? 5 units 7.5 units 10 units 12.5 units

Answers

Answer: the answer is A 5 units

The length of L'L in the dilated figure is 5 units.

What is transformation?

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, translation, reflection and dilation.

Dilation is the increase or decrease in size of a figure.

Triangle JKL was dilated by 1/3 with M as the center of dilation to form J'K'L'.

Given that ML' = 2.5 units, hence:

L'L = (2.5 * 3) - 2.5 = 5 units

The length of L'L in the dilated figure is 5 units.

Find out more on transformation at: https://brainly.com/question/1620969

Express the following in usual form ​

Answers

Answer:

52300

Step-by-step explanation:

When you multiply by ten the decimal dot moves one space to the right, so here you multiply by ten four times, so you move the dot four spaces to the right and you get 52300

5.23 x 10000 is the answer

There are 20 pieces of fruit in a bowl and 5 of them are apples. What percent of the fruit are apples?

Answers

Step-by-step explanation:

20fruits=100%

5fruits=?

5x100/20 5fruitsx5%

=24%

evaluate the formula of A=lw, for l=10.8 cm and w=2.5 cm​

Answers

Answer:

A = 27 cm²

Step-by-step explanation:

[tex]A = lw\\Where, l=10.8 cm , w = 2.5 cm\\[/tex]

Putting in the above formula

A = (10.8)(2.5)

A = 27 cm²

Someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi. We think the actual amount is lower than that and want to run the test at an alpha level of 5%. What would our sample size need to be if we want to reject the null hypothesis if the sample mean is at or below 1,997.2956?

Answers

Answer:

The sample size must be greater than 37 if we want to reject the null hypothesis.

Step-by-step explanation:

We are given that someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi.

Also, we are given a level of significance of 5%.

Let [tex]\mu[/tex] = mean breaking strength of their climbing rope

SO, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 2,000 psi       {means that the mean breaking strength of their climbing rope is 2,000 psi}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < 2,000 psi      {means that the mean breaking strength of their climbing rope is lower than 2,000 psi}

Now, the test statistics that we will use here is One-sample z-test statistics as we know about population standard deviation;

                         T.S.  =  [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]  ~ N(0,1)

where, [tex]\bar X[/tex] = ample mean strength = 1,997.2956 psi

            [tex]\sigma[/tex] = population standard devaition = 10 psi

            n = sample size

Now, at the 5% level of significance, the z table gives a critical value of -1.645 for the left-tailed test.

So, to reject our null hypothesis our test statistics must be less than -1.645 as only then we have sufficient evidence to reject our null hypothesis.

SO,  T.S. < -1.645   {then reject null hypothesis}

         [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < -1.645[/tex]

         [tex]\frac{1,997.2956-2,000}{\frac{10}{\sqrt{n} } } < -1.645[/tex]

         [tex](\frac{1,997.2956-2,000}{10}) \times {\sqrt{n} } } < -1.645[/tex]

          [tex]-0.27044 \times \sqrt{n}< -1.645[/tex]

               [tex]\sqrt{n}> \frac{-1.645}{-0.27044}[/tex]

                 [tex]\sqrt{n}>6.083[/tex]

                  n > 36.99 ≈ 37.

SO, the sample size must be greater than 37 if we want to reject the null hypothesis.

Find the radius of a circle given that the area is three times its circumference





Answers

Answer:

Radius of the circle = 6 units

Step-by-step explanation:

Let the radius of the circle be r

According to the given condition:

Area of the circle = 3 times the circumference of the circle

[tex]\therefore \pi r^2 =3\times 2\pi r\\\therefore r^2 = \frac{3\times 2\pi r}{\pi}\\\therefore r^2 = 3\times 2r\\\therefore r = 6\: units\\[/tex]

Roxie is picking out some movies to rent, and she is primarily interested in horror films and documentaries. She has narrowed down her selections to 66 horror films and 1515 documentaries. Step 2 of 2 : How many different combinations of 33 movies can she rent if she wants at least two documentaries?

Answers

Answer:

1,085

Step-by-step explanation:

The calculation of  number of different combinations of 3 films she can rent if she needs at least two documentaries is shown below:-

[tex]= N\times (2 \times documentaries\ and\ 1\ horror \ movies)+N\times (3\ documentaries)[/tex]

[tex]=(6C_1)\times (15C_2)+(6C_0)\times (15C_3)[/tex]

= 630 + 455

= 1,085

Therefore for calculating the number of different combinations of 3 films she can rent if she needs at least two documentaries we simply applied the above formula and here we consider one number in the question as it shows the double number.

Section 1: Write the following times in 24-hour clock time:
a) 7:15 a.m -
b) 1:05 am
c) 2:01 p.m
d) 9:22 p.m
e) 12:25 am



Section 2: Write the following times in 12-hour clock time.
a) 1155 hours
b) 1005 hours
c) 1714 hours
d) 0756 hours
e) 1345 hours​

Answers

Answer:

Section 1:

a) 7:15 a.m - 19:15

b) 1:05 am - 01:05

c) 2:01 p.m - 14:01

d) 9:22 p.m - 21:22

e) 12:25 am- 24:25

Section 2:

a) 1155 hours - 11:55am

b) 1005 hours -10:05am

c) 1714 hours - 5:14pm

d) 0756 hours - 7:56am

e) 1345 hours- 1:45pm ​

Answer:

12:25 am= 00:25

Step-by-step explanation:

The average number of children a Japanese woman has in her lifetime is 1.37. Suppose that one Japanese woman is randomly chosen. a. In words, define the random variable X. b. List the values that X may take on. c. Give the distribution of X.X~ _____(_____,_____) d. Find the probability that she has no children. e. Find the probability that she has fewer children than the Japanese average.

Answers

Answer:

a. X: amount of children that a Japanese woman has in her lifetime.

b. X can take natural numbers (all positive integers) as values.

c. X~Poi(1.37).

d. P(X=0)=0.2541

e. P(X<1.37)=0.6022

Step-by-step explanation:

a) This can be modeled with a Poisson distribution.

We let the variable X be the amount of children that a Japanese woman has in her lifetime.

The parameter of the Poisson distribution is λ=1.37.

This is also the value of the mean and the standard deviation.

b) X can take all positive integer values.

c) X is modeled as a Poisson variable with λ=1.37.

d) This can be calculated as:

[tex]P(0)=\lambda^ke^{-\lambda}/k!=1.37^{0} \cdot e^{-1.37}/0!=1*0.2541/1=0.2541\\\\[/tex]

e) Having fewer children than the average means that she has one or none children.

This can be calculated as:

[tex]P(X<1.37)=P(0)+P(1)\\\\\\P(0)=1.37^{0} \cdot e^{-1.37}/0!=1*0.2541/1=0.2541\\\\P(1)=1.37^{1} \cdot e^{-1.37}/1!=1.37*0.2541/1=0.3481\\\\\\P(X<1.37)=0.2541+0.3481=0.6022[/tex]

Combine these radicals. -3sqrt(of81)+sqrt(of16)

Answers

I just hold on......

Answer:

-23

Step-by-step explanation:

Directly above center court, the Yakima SunDome in Yakima, Washington, rises to its maximum height of 92 ft. The angle of elevation from justins parking spot at a Yakama sun kings home to the top of the dome is 11. To the nearest fooot how far from the center court is Justin Parked?

Answers

Answer:

473 feet.

Step-by-step explanation:

Let's look at the image below. We have that the angle of elevation from Justin parking spot is 11º and the height of the building is 92 feet and we need to know how far from the building is Justin parked, in other words, we need to find x in the image.

We can see that to find x we can use a trigonometric function (in this case is tan since we have the Opposite side (92 feet) and we need the Adjacent side (x)

Thus we have:

[tex]Tan11= \frac{92}{x} \\0.1943=\frac{92}{x}\\ x=\frac{92}{0.1943}\\ x=473.49\\x=473[/tex]

Thus, Justin is parked 473 feet away from the center court.

Other Questions
What is 2 less than a number The distance between the Sun and the Earth is 1 .496 x 1O^8km and distance between the Earth and lhe Moon is 3.84 x 10^8m. During solar eclipse. The Moon comes in between the Earth and the Sun. What is the distance between the Moon and the Sun at that particular time? How is Percys point of view of Gabe influenced by their interactions pages 39-40? *A. By showing how Gabes actions bring comfort to Percy and his mother.B. By showing how much Percy appreciates Gabe as his stepdad through his actions.C. By developing feelings of frustration due to Gabes behavior towards Percy and his mother.D. By making Percy feel powerful in their conversations. The area of a circle is 153.86 square meters. What is the diameter of the circle? Use 3.14 for . Was President Roosevelt advocating for neutrality or involvement in WWII? Question 18 of 202 PointsWhat is the Bill of Rights?O A. Rights that were approved by the presidentO B. Amendments that protect individual rightsO C. Rights that were opposed by the EnlightenmentO D. Laws that came from the Articles of Confederation an=(3n+4)n(4n8)n In this problem you must attempt to use the Root Test to decide whether the series converges. Compute L=limn[infinity]|an|n Enter the numerical value of the limit L if it converges, INF if it diverges to infinity, MINF if it diverges to negative infinity, or DIV if it diverges but not to infinity or negative infinity. L= Which of the following statements is true? A. The Root Test says that the series converges absolutely. B. The Root Test says that the series diverges. C. The Root Test says that the series converges conditionally. D. The Root Test is inconclusive, but the series converges absolutely by another test or tests. E. The Root Test is inconclusive, but the series diverges by another test or tests. F. The Root Test is inconclusive, but the series converges conditionally by another test or tests. Enter the letter for your choice here: Which of the following best describe the object relations school of personality development? (Check all that apply) A. requires a constant adjustment to separations and losses B. emphasizes the importance of an infants first two years of life and a baby's formative relationships. C. People are motivated not only by past conflicts, but future goals and their desire to fulfill themselves. D. identifies the central problem of personality as the balance between the need for independence and the need for others The five triangle congruence are sss, sas, aas, asa and hl criteria. Fully explain why aaa is not a triangle congruence criteria An oil company fills 1/10of a tank in 1/5, hour. At this rate, which expression can be used to determine how long it will take for the tank to fill completely?1010 hours01. 5 hours10.110hour55-10 hours [tex]( {8x}^{2} + 4x + 4) - (7x + 9)[/tex]Solve. Give reasons for the following.2. Energy is the fuel of life.1. Diamond and coal are basically different forms of carbon. You are doing an experiment and plated E. coliin different medias. Media A has onlyglucose, B has only lactose, and media C has both glucose and lactose.You notice that some of the cultures grown in media C are metabolizinglactose. Which type(s) of mutation(s) could cause this to occur What is the solution set of the quadratic inequality 6x^2+10? Please help meeee !! RST is dilated with the rule DT,1/3 (x, y), where the center of dilation is T(3, 2). The distance between the x-coordinates of R and T is . The distance between the y-coordinates of R and T is . R' is from T, so the coordinates of R' are . Tiptop Flight School offers flying lessons at a small municipal airport. The school's owner and the manager have been attempting to evaluate performance and control costs using a variance report that compares the planning budget to actual results. A recent variance report appears below: Tiptop Flight School Variance Report For the Month Ended July 31 Actual Results Planning Budget Variances Lessons 155 150 Revenue $33,900 $33,000 $900 F Expenses: Instructor wages 9,870 9,750 120 U Aircraft depreciation 5,890 5,700 190 U Fuel 2,750 2,250 500 U Maintenance 2,450 2,330 120 U Ground facility expenses 1,540 1,550 (10) F Administration 3,320 3,390 (70) F Total expense 25,820 24,970 850 U Net operating income $8,080 $8,030 $50 F After several months of using such variance reports, the owner has become frustrated. For example. she is quite confident that instructor wages were very tightly controlled in July. but the report shows an unfavorable variance. The planning budget was developed using the following formulas, where q is the number of lessons sold: Cost Formulas Revenue $220 q Instructor wages $65 q Aircraft depreciation $38 q Fuel $15 q Maintenance $530 + $12 q Ground facility expenses $1,250 + $2 q Administration $3,240 + $1 q Required: 1. Should the owner feel frustrated with the variance reports? Explain. 2. Prepare a flexible budget performance report for the school for July. 3. Evaluate the school's performance for July. Find the length of a. The length of the of the unknown leg is? Monique made several batches of soup for a potluck supper. Each batch required 3/4 of a pound of potatoes, and she used a total of 6 1/2 pounds of potatoes. How many batches of soup did Monique make?Which division and multiplication problems could represent this scenario? Check all the apply.A)3/4 divided by 13/2B)13/2 divided by 3/4C)3/4(13/2)D)13/2(3/4)E)13/2(4/3) 1. Find the volume of the cylinder height: 8mradius: 3 mwith the explanation if possible