A company earns $150 a week for 9 weeks. It then has a loss of 565 a week for 25 weeks. At the end of the 34 weeks what is the company's
balance?

that is a rational number.

Answer:

200 17/23

Step-by-step explanation:

Mathxway.....

Answer:

[tex]\frac{61}{99}[/tex]

Step-by-step explanation:

let x = 0.616161 (etc.)

make a second equation because you multiply by 100:

100x = 61.616161 (etc.)

subtract from each other

100x = 61.616161

     x =  0.616161

you get

99x = 61

solve for x

[tex]\frac{61}{99}[/tex]

Answer:

1.60x=32.00

Step-by-step explanation:

Since you do not how much gallons of gas he bought you would use the variable x.

Answer:

1.60x=32

Step-by-step explanation:

Answer:

-1

Step-by-step explanation:

g(1) = -2*1^2 - 4*1 + 5

Hi

a+b > a-b

<=> a+b-a = b > a-b-a=-b ** subtract a **

<=> b+b > 0 ** add b **

<=> 2b > 0 ** divide by 2 **

<=> b > 0

so (E) is the right answer

Thanks

Answer: it should be 11.infinite 6

Step-by-step explanation:7x2=14+21=35

35/3 = 11.infinite 6

So basically 11.6

Answer:

there are 32 bottles needed

Step-by-step explanation:

Thanks

Answer:

I'm pretty sure it's increasing

Step-by-step explanation:

because the linear parent function is x=y, no negative signs

Answer:

Increasing

Step-by-step explanation:

Answer: 30 cents

Step-by-step explanation:

1/20 of a dollar is 5 cents

Then we multiply by the numerator (6) to get our answer....

5x6= 30

Hoped this helps! :)

Answer:

60

Step-by-step explanation:

percentage=18

rate=30%

base=_____

p/r=b

18/0.30=60

Answer:

60

Step-by-step explanation:

18=30%

6=10%

6x10=60

10x10=100%

Answer: x=8

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

2/3*12=24/3=8

easy way:

2/3*12/1=24/3=8

Answer:

Step-by-step explanation:

Answer:

The answer is 35%

Answer:

Maggie is 7 years old

Step-by-step explanation:

Attached is an image that explains the question. Hope this helps!

Answer:

[tex]n=5/2[/tex]

Step-by-step explanation:

We have the equation:

[tex]5^{2n-2}=125[/tex]

Notice that 125 is the same as 5³. So:

[tex]5^{2n-2}=5^3[/tex]

Since they have the same base, the exponents must be equal. Therefore:

[tex]2n-2=3[/tex]

Solve for n. Add 2 to both sides:

[tex]2n=5[/tex]

Divide both sides by 2:

[tex]n=5/2=2.5[/tex]

So, the value of n is 5/2.

And we're done!

Answer:

N = 2.5

Step-by-step explanation:

Ok, so try this.

125 is 5^3, right?

And in this equation, we have 5 to the power of 2n-2 is equal to 125.

You need to make sure that the exponent ends up as 3.

How would you do this?

Try substituting N for 3.

That's too big.

Try Substituting N for 2.

That's a bit too small.

What number is in between 2 and 3?

2.5 is.

N = 2.5

Check your work, and see if you came up with the same answer

Work:

2.5 x 2 = 5

5 - 3 = 2

5^3 = 125

Answer:

The answer would be -12x^2-4x+6

Step-by-step explanation:

This is the simplest form it could get since you subtract the two x^2 together.

Answer: (z + 2)(z - 3)

Step-by-step explanation:

First, we have 1 as a coefficient on z², so we multiply that by -6, which gives us -6. Now we must find out what two numbers when multiplied, give us -6, and when added together, give us -1 (z's coefficient). Going through -6's factors, I got -3 and 2 since we need a negative one when they are added together. Now we can input our values:

(z - 3)(z + 2).

Double checking, we get the starting equation, which means our factorization was correct, and so is the solution.

Note: it does not matter which binomial comes first because you will get the same answer regardless of its position.

The 1st term is 60.

Add 50 to this to get the 2nd term, 60 + 50 = 110.

Add 50 to that to get the 3rd term, 110 + 50 = 160.

Add 50 to that to get the 4th term, 160 + 50 = 210.

And so on...

Notice that in the 2nd term, we added 1 copy of 50 to the 1st term.

In the 3rd, we ultimately added 2 copies of 50 to the 1st term.

In the 4th, we added 3 50s.

And so on... If the pattern continues, then the n-th term can be obtained by adding (n - 1) copies of 50 to the first term.

So, the 100th term is

60 + (100 - 1) * 50 = 5010

Answer:

I wanna say its Hence n (Q) =7

I may be mistaken

Answer:

6

Step-by-step explanation:

The set is made up of 6 elements. Therefore, the cardinal number is 6.

Answer:

The total number of sets is 2,640.

Step-by-step explanation:

The number of marbles in the bag are:

S = {3R, 5G, 1L, 2Y and 6O}

There are a total of N = 17 marbles in the bag.

Four marbles are randomly selected.

Assume that the selection was without replacement.

It is provided that two of the marbles are green.

And the remaining two are non-green.

A sample of the selection is as follows:

G, G, _, _

The two green marbles can be selected in 5 × 4 = 20 ways.

So, the remaining two marbles cannot be green.

That leaves us with: 3R, 1L, 2Y and 6O = 12 marbles.

The third marble can be selected in 12 ways.

And the fourth marble can be selected in 11 ways.

So the number of combinations of selecting 4 marbles such that 2 are green and 2 are non-green is:

Total number of sets = 5 × 4 × 12 × 11 = 2640

Thus, the total number of sets is 2,640.

Answer:

80

Step-by-step explanation:

Answer:

The width is 34.6

Step-by-step explanation:

You have to assume that the cut is a straight cut.

Givens

c = 41

a = 22

b = ?

Formula

a^2 + b^2 = c^2

Solution

22^2 + b^2 = 41^2

484 + b^2 = 1681                   Subtract 484 from both sides

484-484 + b^2 = 1681-484   Combine

b^2 = 1197                              Take the square root of both sides.

sqrt(b^2) = sqrt(1197)

b = 3*sqrt(133)

b = 34.598  

b = 34.6

Answer:

[tex]\boxed{2^{\frac{802}{27}} \cdot 3^9}[/tex]

Step-by-step explanation:

I will try to give as many details as possible.

First of all, I just would like to say:

[tex]\text{Use } \LaTeX ![/tex]

Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! （＊＾Ｕ＾）人（≧Ｖ≦＊）/

[tex]$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$[/tex]

Note that

[tex]\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }[/tex]

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

[tex]\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3[/tex]

Also,

[tex]\boxed{a^{0} = 1, a\neq 0 }[/tex]

[tex]\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27[/tex]

Note

[tex]\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}[/tex]

[tex]\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27[/tex]

[tex]\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)[/tex]

[tex]\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)[/tex]

[tex]\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)[/tex]

Note

[tex]\boxed{\dfrac{1}{\dfrac{1}{a} } = a}[/tex]

[tex]9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)[/tex]

[tex]\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)[/tex]

Once

[tex]9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6[/tex]

[tex]\boxed{(a \cdot b)^n=a^n \cdot b^n}[/tex]

And

[tex]$4^{\frac{4}{27}} = 2^{\frac{8}{27} $[/tex]

We have

[tex]\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)[/tex]

Also, once

[tex]\boxed{\dfrac{c^a}{c^b}=c^{a-b}}[/tex]

[tex]2^{30-\frac{8}{27}} \cdot 3^6\cdot 27[/tex]

As

[tex]30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}[/tex]

[tex]2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3[/tex]

[tex]2^{\frac{802}{27}} \cdot 3^9[/tex]

Answer:

The derivative is [tex]\frac{dR}{dM} = CM - M^2[/tex]

Step-by-step explanation:

From the question we are told that

The equation representing the reaction is [tex]R = M^2 (\frac{C}{2} - \frac{M}{3} )[/tex]

Generally this equation can be represented as

[tex]R = \frac{C M^2}{2} - \frac{M^3}{3}[/tex]

Generally [tex]\frac{dR}{dM}[/tex] as a function of M is mathematically represented as

[tex]\frac{dR}{dM} = 2 * \frac{C M^{2 - 1 }}{2} + 3 * \frac{M^{3-1}}{3}[/tex]

=> [tex]\frac{dR}{dM} = CM - M^2[/tex]