Two cars are moving with velocities 70 km/hr and west direction respectively.Find their relative velocity.
Answer:
Explanation:
To find the relative velocity of two cars moving in different directions, we need to subtract their velocities. In this case, one car is moving with a velocity of 70 km/hr and the other car is moving with a velocity in the west direction.
Let's assume that the velocity of the second car is also 70 km/hr. Since the car is moving in the west direction, we can represent its velocity as -70 km/hr (negative sign indicates motion in the opposite direction).
Now, we can find the relative velocity of the second car with respect to the first car by subtracting the velocity of the first car from the velocity of the second car:
Relative velocity = Velocity of the second car - Velocity of the first car
= (-70 km/hr) - (70 km/hr)
= -140 km/hr
Therefore, the relative velocity of the second car with respect to the first car is -140 km/hr, which means that the two cars are moving away from each other at a speed of 140 km/hr.
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The graph shows the decay of two different radioactive nuclei, Source A and Source B.
How long does it take Source B to complete two half-lives?
a. 10 s
b. 5 s
c. 40 s
d. 20 s
It takes source B 40 s to complete two half lives.
What is the half life?The half-life of a chemical is the amount of time it takes for half of the atoms in a sample to decay. This concept is widely used to describe how quickly a substance decays radioactively in nuclear physics and radiochemistry. Each radioactive substance has a unique half-life due to the properties of each atomic nucleus.
Looking at the graph, we can see that the half life of the source B is 20s .
Hence the time taken to complete two half lives = 2(20 s) = 40 s.
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You are an astronomer and are making observations about a
visible but faraway galaxy. In 2-3 sentences, describe what evidence you could gather to gain more information about (1) the galaxy's elemental
composition and (2) its motion relative to the Milky Way Galaxy.
To determine the elemental composition of the faraway galaxy, would use spectroscopy to analyze the light that is emitted or absorbed by the galaxy. This technique enables me to determine the types of atoms and molecules that are present in the galaxy, providing insights into its elemental composition.
To determine the galaxy's motion relative to the Milky Way, would use the Doppler effect to measure the galaxy's redshift or blueshift. This would enable me to determine whether the galaxy is moving away from or towards us, and at what speed, providing information about its motion relative to our galaxy.
It could also look for any gravitational lensing effects, which could indicate the presence of massive objects that are influencing the galaxy's motion.
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6.3 A probability found through quantum mechanics. In the test of Bells
theorem, experiment 6.2, what is the probability given by quantum
mechanics that, if the orientation settings are different, the two
detectors will flash different colors?
According to the given information, regardless of the orientation settings, the two detectors will flash different colors with probability . This prediction is based on quantum mechanics.
How to explain the experimentIn the experiment described, a pair of atoms are produced from a central source and detected by two detectors that are separated by a distance of nearly seven miles.
Each detector has the possibility of being oriented as A, B, or C, and is mounted with two colored lamps, a red lamp, and a green lamp.
According to the predictions of quantum mechanics, if the orientation settings of the two detectors are the same, then the two detectors always flash different colors.
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A woman weighs 100 kg and wants to know the force that the heels of her different shoes put on the new carpet by standing on one foot. The different shoes, A, B, C, D have heels of area 1cm, 4cm, 8cm and 64cm.
Which heel applies greater force to the carpet?
Answer: ALL EQUAL
^^^^^^^^^^^^^^^^^^^^^^^
^^^^^^^^^^^^^^^^^^^^^^^
Answer: ALL EQUAL
The heel of shoe D applies the greatest force to the carpet because it has the largest surface area in contact with it, and thus the largest force is distributed over that larger area.
Radar; atomic & molecular research, microwave ovens, cell phones are possible because of which type of wave? Pic attached below
Radar; atomic & molecular research, microwave ovens, cell phones are possible because of microwaves.
What are microwaves?Microwave is described as a form of electromagnetic radiation with wavelengths ranging from about one meter to one millimeter corresponding to frequencies between 300 MHz and 300 GHz respectively.
In conclusion, Microwave radiation has its effects as it can heat the body tissue the same way it heats food. Uneccessary exposure to high levels of microwaves can cause a painful burn.
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Which of the following statements regarding VDGS
Systems are true? (Select ALL that are true.)
You can guess what type of aircraft is being parked.
If the system stops the aircraft, you can just manually continue to park it.
You do not need to investigate the reason for the stop.
Anyone can give the "Stop" signal if a threat to the safety of the aircraft is
observed.
You must power on and check the system before arrival.
A qualified agent must man the Emergency stop.
The true statements regarding VDGS Systems are you must power on and check the system before arrival and a qualified agent must man the Emergency stop.
What is VDGS?VDGS stands for Visual Docking Guidance System. It is a technology used in airports to assist pilots in parking their aircraft at the gate by providing visual cues and guidance through the use of lights and/or displays.
The following statements regarding VDGS Systems are true:
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What is the acceleration of a 650 kg racing camel that has a Ford net force of 897N
The acceleration of the racing camel is 1.38 m/s².
What is the acceleration of the racing camel?From Newton's second law, force is expressed as;
F = m × a
Where is mass of object and a is the acceleration
Given that:
Mass of the camel m = 650 kg Net force f = 897NAcceleration of the camel a = ?To determine the acceleration of the camel, pug the given values into the abovr formula and solve for a.
F = m × a
897N = 650 kg × a
Note that: Newton N is the same as kg·m/s²
Hence;
897kg·m/s² = 650 kg × a
Divide both sides by 650 kg
a = (897kg·m/s²) / (650 kg)
a = 1.38 m/s²
Therefore, the acceleration is 1.38 meters per second sqaure.
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An electric golf cart develops 1.25 kW of power while moving at a constant speed: (a) Express its power in horsepower: (b) If the cart travels 200 m in 35.0 %, what force is exerted by the cart?
a) The power of the electric golf cart is approximately 1.674 horsepower.
b) The force exerted by the electric golf cart is approximately 2182.5 Newtons.
Power and force in the Electric golf cart(a) To convert 1.25 kW to horsepower, we can use the conversion factor:
1 horsepower = 0.746 kW
So, 1.25 kW = (1.25/0.746) horsepower = 1.674 horsepower (approximately)
Therefore, the power of the electric golf cart is approximately 1.674 horsepower.
(b) To calculate the force exerted by the cart, we can use the following formula:
force = power / velocity
where power is in watts, velocity is in meters per second, and force is in Newtons.
First, we need to convert the power of the cart from 1.25 kW to watts:
1 kW = 1000 watts
So, 1.25 kW = 1250 watts
Now, we need to convert the distance traveled by the cart from meters to kilometers, and the time taken from seconds to hours:
200 m = 0.2 km
35.0% = 0.35 hours
Using the formula, we can calculate the force exerted by the cart as:
force = power / velocity
force = 1250 / (0.2/0.35)
force = 1250 / 0.5714
force = 2182.5 N (approximately)
Therefore, the force exerted by the electric golf cart is approximately 2182.5 Newtons.
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1.5 Find the center of gravity of a 100 mm x 150 mm x 30 mm T-section. H 150 mm -100 mm- G D BI 30 mm E -30 mm Figure 1.5 1.
Answer:
Explanation:
que ricos puntitos
what is screw guage how does it work
Answer:
A screw gauge, also known as a micrometer screw gauge, is a precision measuring instrument used to measure small distances with high accuracy. It consists of a calibrated screw and a calibrated thimble with a spindle and an anvil face. The spindle is attached to the screw, and the anvil face is fixed to the body of the instrument.
To use a screw gauge, the object being measured is placed between the spindle and the anvil face, and the screw is turned until the spindle makes contact with the object. The thimble is then turned, which moves the spindle and the screw, until the spindle is firmly in contact with the object. The reading on the scale of the thimble is then taken, which gives the distance between the spindle and the anvil face, with a high degree of precision.
Screw gauges are commonly used in a variety of fields, including engineering, machining, and scientific research, where accurate measurements are required.
Screw gauge measures diameter with high accuracy using a screw and nut mechanism. It has a pitch and graduated thimble.
A screw check is an estimating instrument used to gauge the width of items, particularly wires and chambers, with high exactness. It deals with the rule of a screw and nut component.The screw measure comprises of a U-molded outline with a screw toward one side and a thimble at the other.
The screw has a pitch, which is the distance gone by the screw in one complete turn. The pitch is as a rule of the request for 0.5 mm. The thimble is graduated into 50 or 100 equivalent parts. The roundabout scale on the thimble must be changed to such an extent that the zero of the scale matches with the zero of the pitch scale.
To utilize the screw check, the item whose width is to be estimated is set between the iron block and the shaft. The screw is turned until the shaft simply contacts the item. The pitch scale perusing is noted.
The thimble is then turned until the zero of the thimble scale concurs with the middle line of the pitch scale. The thimble scale perusing is then noted. The breadth of the item is then determined by adding the pitch scale perusing and the thimble scale perusing.
Along these lines, a screw check can gauge widths to an exactness of 0.01 mm or better. It is broadly utilized in designing, fabricating, and logical applications.
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What force produces an extension of 2.5 cm?
A simple circuit exists with two identical light bulbs. The two light bulbs are in series with one another. If one light bulb is removed, which of the following would occur?
The current would increase.
The current would decrease.
The total resistance would increase.
The total voltage would decrease.
The current would decrease if one light bulb is removed from the circuit. Option B is correct.
If one light bulb is removed from a simple circuit with two identical light bulbs that are in series with one another, the total resistance in the circuit would increase. This is because the resistance of the circuit is proportional to the number of resistors in the circuit, and removing one bulb reduces the number of resistors in the circuit.
The total current in the circuit would decrease because the resistance has increased. This is because the current flowing through a circuit is inversely proportional to the resistance of the circuit according to Ohm's law. Option B is correct.
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2. Suppose the sled runs on packed snow. The coefficient of friction is now only 0.12. A person and sled weighing 650 N sits on the sled and it is pulled at a constant velocity across the snow.
A. Draw FBD.
B. What is the combined mass of the sled and person?
C. Determine the frictional force value.
D. What is the value of the force needed to pull the sled?
Answer:
Explanation:
B. W = mg m = W/g = (650 N)/(9.8 m/s²) = 66.33 kg
C. Ff = μN = (0.12)(650 N) = 78 N
D. F > 78 N
Note: Brainly doesn't provide drawing tools, so I can't help you with the FBD. But here's a try at it: N = normal force, F = applied force, W = weight of person + sled, Ff = force of friction, ⊕ (person and the sled)
N
↑
Ff← ⊕ →F
↓
W
Review the ray tracing provided.
A thin lens is located centered over a 14 cm ruler at the 7 cm mark. A black dot is located at 5.5 cm on the left side of the lens and at 8.5 cm on the right side of the lens. An arrow is located at the 6 cm mark. Rays appear to go from the head of the arrow towards the lens, and then extend backwards to the tip of an arrow located at 4 cm.
Which of the following best describes the image?
Inverted, smaller, and real
Upright, smaller, and virtual
Upright, larger, and real
Upright, larger, and virtual
The best description of the image is (B) upright, smaller, and virtual is correct option.
To determine the characteristics of the image, we can use the thin lens equation:
1/f = 1/do + 1/di
where f is the focal length of the lens, do is the object distance (distance of the object from the lens), and di is the image distance (distance of the image from the lens).
We can also use the magnification equation:
m = -di/do
where m is the magnification.
First, we need to determine the focal length of the lens. We can use the fact that the lens is centered over the 14 cm ruler at the 7 cm mark, which means the lens is 7 cm from both the left and right sides of the ruler. Since the ruler has a total length of 14 cm, the lens must be in the middle, and the distance from the lens to the ruler is 7 cm. Therefore, the lens has a focal length of 7 cm.
Next, we can use the thin lens equation to find the image distance for the arrow located at the 6 cm mark:
1/7 = 1/(6 - 7) + 1/di
di = -7 cm
The negative sign indicates that the image is inverted.
We can also use the magnification equation to find the magnification of the image:
m = -di/do = -(-7)/(-6) = 7/6
The positive magnification indicates that the image is upright.
Finally, we can use the image distance and magnification to determine the characteristics of the image. Since the image distance is negative, the image is virtual. Since the magnification is less than 1, the image is smaller.
Therefore, the best description of the image is upright, smaller, and virtual.
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Answer:
upright, smaller virtual
Explanation:
2.
How did Robert Boyle demonstrate that sound needs a medium through which to travel?
He found that an alarm watch in a vacuum did not make a
sound.
He found that the speed of sound varied under different
conditions.
MacBook Air
He found that an alarm watch under water did not make a
sound.
He recorded the time that distant pistol fire was heard.
Robert Boyle demonstrated that sound needs a medium through which to travel by observing that an alarm watch in a vacuum did not make a sound. Option 1 is the answer.
Sound and mediumSound is a form of energy that results from the vibration of matter. When an object vibrates, it creates sound waves that travel through a medium and can be perceived by the human ear.
A medium is a substance or material through which waves can travel. In the case of sound, air, water, and solids such as metal or wood can serve as a medium. Without a medium, sound cannot propagate because there are no molecules to vibrate and transmit the waves.
Robert Boyle demonstrated that sound needs a medium through which to travel by observing that an alarm watch in a vacuum did not make a sound. This led him to conclude that sound requires a medium, such as air or water, to propagate.
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are physical quantities and fundamental quantities same
Answer:
The physical quantities are the quantities that are the base quantities of the measurement. They are known as the fundamental quantities. The units of those units are known as the fundamental units. The derived physical quantities are dependent on the fundamental quantities.
What is the force of gravity between two 70.0kg masses that are separated by 2.50m?
Answer:
F = 5.2324 x 10⁻⁸ N
Explanation:
F = G(m₁ · m₂) / r²
where F is the gravitational force, G is the gravitational constant (6.674 x 10⁻¹¹ N·m²/kg²), m1 and m2 are the masses of the two objects, and r is the distance between them.
Plugging in the given values m1 = m2 = 70.0 kg, r = 2.5 m:
F = (6.674 x 10⁻¹¹)(70.0 kg)² / (2.50 m)²
F = 5.2324 x 10⁻⁸ N
Therefore, the gravitational force between the two 70.0 kg masses separated by 2.50 m is approximately 5.2324 x 10⁻⁸ N.
As the pendulum swings from position A to position B, what is the relationship of kinetic energy to potential energy (neglect friction)? (5 points)
The kinetic energy increase is equal to the potential energy decrease.
The potential energy increase is equal to the kinetic energy decrease.
The kinetic energy and potential energy remain the same.
The kinetic energy increase is more than the potential energy decrease.
As the pendulum swings from position A to position B, the potential energy decreases while the kinetic energy increases. According to the law of conservation of energy, the total energy in a system remains constant, neglecting friction. Therefore, the potential energy lost by the pendulum is converted into kinetic energy. The correct relationship of kinetic energy to potential energy as the pendulum swings from position A to position B is:
The potential energy decrease is equal to the kinetic energy increase.
So, the answer is option B.
Answer:
The potential energy increase is equal to the kinetic energy decrease.
2.
How did Robert Boyle demonstrate that sound needs a medium through which to travel?
He found that an alarm watch in a vacuum did not make a
sound.
He found that the speed of sound varied under different
conditions.
MacBook Air
He found that an alarm watch under water did not make a
sound.
He recorded the time that distant pistol fire was heard.
In the 1600s, a scientist by the name of Robert Boyle made the first known demonstration of the fact that a sound cannot pass through void space. Boyle placed the clock in a glass jar with a tight lid.
How can an experiment demonstrate that sound travels through a medium?Pump out the air from the sealed bell jar while putting an electrical bell inside. Set the electric bell to ringing. We cannot hear the sound that the bell makes with our ears. This indicates that sound waves require a material environment for propagation because they cannot move through a vacuum.
What justifies the notion that sound travels via a medium?Since sound waves are carried from one location to another by the molecules of solids, liquids, and gases, sound requires a physical medium for propagation, such as a solid, liquid, or gas. Since there are no molecules in the vacuum that can vibrate and convey sound waves, sound cannot travel through it.
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6.
Sonography uses infrasonic waves to create images of objects found inside other objects.
True
False
Sonography uses infrasonic waves to create images of objects found inside other objects.-False
Sonography, commonly known as ultrasound imaging, creates pictures of structures and organs inside the body using high-frequency sound waves (rather than infrared rays). These sound waves are emitted by a transducer, a portable device put on the skin and deliver sound waves through the body. The waves reverberate off internal organs and structures and are picked up by the transducer, which generates a visual representation on a computer screen. Ultrasonic imaging is widely used in obstetrics to monitor fetal development and in other medical specialties to diagnose and treat various disorders.
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Two objects, one with a mass of 75.0kg and the other with a mass of 60.0kg experience a gravitational force of attraction of 8.50x10-9N. How far apart are their
centers of mass?
Answer:
Approximately [tex]5.94\; {\rm N}[/tex].
Explanation:
The gravitational force between two objects of uniform mass is:
[tex]\displaystyle F = \frac{k\, M\, m}{r^{2}}[/tex],
Where:
[tex]k \approx 6.67 \times 10^{-11}\; {\rm m^{3}\, kg^{-1}\, s^{-2} }[/tex] is the gravitational constant,[tex]M[/tex] and [tex]m[/tex] are the mass of the two objects, and[tex]r[/tex] is the distance between the center of mass of the two objects.Rearrange this equation to find [tex]r[/tex]:
[tex]\begin{aligned} r &= \sqrt{\frac{k\, M\, m}{F}} \\ &= \sqrt{\frac{(6.67 \times 10^{-11})\, (75.0)\, (60.0)}{8.50 \times 10^{-9}}}\; {\rm kg} \\ &\approx 5.94\; {\rm kg}\end{aligned}[/tex].
What is the acceleration of a 650 kg racing camel that has a forward net force of 897N
Answer:
a = 0.724 m/s2
Explanation:
Known:
m = 650 kg
F = 897 N
a = ?
Use this formula:
F = ma
a = F/m
a = 650/897
a = 0.724 m/s2
When a 102 g mass is hung on a spring it stretches 4.0 cm. The spring is then set in SHM by stretching it a further 6.0 cm and then releasing it.
a) Calculate the force required to stretch the spring 6.0 cm.
Answer:
1.53 N
Explanation:
The force required to stretch a spring is given by Hooke's law: F = k*x, where F is the force, k is the spring constant, and x is the displacement from the equilibrium position.
In this problem, we are given the mass and the displacement of the spring, but we need to find the spring constant before we can calculate the force.
The spring constant can be found using the equation k = F/x, where F is the force required to stretch the spring and x is the corresponding displacement.
Given that the 102 g mass stretches the spring by 4.0 cm, we have:
k = F/x = (mg)/x = (0.102 kg)(9.8 m/s^2)/(0.04 m) = 25.5 N/m
where g is the acceleration due to gravity.
Now, to calculate the force required to stretch the spring by 6.0 cm, we use the same equation with the new displacement:
F = kx = (25.5 N/m)(0.06 m) = 1.53 N
Therefore, the force required to stretch the spring by 6.0 cm is 1.53 N.
HELP ASAP
The specific heat capacity of solid copper metal is 0.385 J/g-K. How many joules of heat are needed to raise the temperature of a 1.55-kg block of copper from 33.0 °C to 99.9 °C?
3.71 × 10^−6J
39.9 J
3.99 × 10^4J
0.00371 J
2.69 × 10^5 J
IT IS A CHEMISTRY QUESTION BUT WAS PUT WITH PHYSICS BY MISTAKE SORRY
Answer: 3.99•10⁴ J
Explanation:
The Heat Formula is: Q = m • C • ΔT
Your given C, m, T₀, and T
C = 0.385 J/g•K
m = 1.55 kg or 1,550 g
T₀ = 33.0 °C
T = 99.9 °C
(ΔT = T - T₀)
Your only remaining variable is Q, heat, so you can now plug in your values to solve.
Q = (1550)(0.385)(99.9 - 33.0)
(ΔT(°C) = ΔT(K) because the conversion is linear)
Q = 39,922.575 J
or
3.99•10⁴ J
define boiling point
Answer: boiling point is when the object of a liquid is hot enough to start to boil and create bubbles, and even start to evaporate into gas.
Explanation:
You decide to go skiing but fall over. As you are attempting to get back up, you see a child start to head down the hill straight for you. If the coefficient of friction between the child and the snow is assumed to be 0, and the child appears to be 20 m above you when they start down the mountain, and the incline of the mountain is 31 degrees, how long do you have to get up and out of the way before you and the child collide?
The time taken to get up and out of the way before you and the child collide is 2.82 s.
What is the time taken to get up?The time taken to get up and out of the way before you and the child collide is calculated as follows;
s = v + ¹/₂at²
s = v + ¹/₂(g sin (31)t²
where;
v is the initial velocitys is the displacementt is the time of motionThe time taken to get up is calculated as;
20 = 0 + ¹/₂(9.8 sin (31)t²
20 = 2.524t²
t² = 20/2.524
t² = 7.925
t = 2.82 s
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Consider a ring, sphere and Solidey clinder all with the same mass. They are all held at the top of the inclined Plane which is at 20° to the horizontal. the top of the inclined Plane is Im high. The shapes are released simultaneously and allowed to roll down the inclined plane. Assume the abjects roll with out slipping and that they are all made from the same material. Assume the coefficient of static friction bin the objects and the plane is 0-3-
a) worklout what order
they would get to the bottom of the slope.
b) How long will it take each shape to reach the bottom of the Slope ?
c) which shapes have the greater moment of inertia ?
d) determine the linear acceleration(a)
e) calculate the tangential (linear) Veloci ty of each shapes-
Answer:
a) The order in which the shapes reach the bottom of the slope will be the sphere, solid cylinder, and ring.
b) The time it takes for each shape to reach the bottom of the slope can be calculated using the following equation:
t = (2d / g)^(1/2)
Where t is the time, d is the height of the inclined plane (1m in this case), and g is the acceleration due to gravity (9.8 m/s^2).
For the sphere:
t = (2 x 1 / 9.8)^(1/2) = 0.45 seconds
For the solid cylinder:
t = (2 x 1 / 9.8)^(1/2) x (5/7) = 0.36 seconds
For the ring:
t = (2 x 1 / 9.8)^(1/2) x (2/5) = 0.28 seconds
c) The moment of inertia depends on the shape of the object and how the mass is distributed around its axis of rotation. For a solid sphere, the moment of inertia is given by I = (2/5)MR^2, for a solid cylinder it is I = (1/2)MR^2, and for a ring it is I = MR^2. Therefore, the order of increasing moment of inertia is the ring, the solid cylinder, and the sphere.
d) The linear acceleration of each shape can be calculated using the following equation:
a = gsinθ / (1 + I / MR^2)
Where a is the linear acceleration, g is the acceleration due to gravity (9.8 m/s^2), θ is the angle of the inclined plane (20° in this case), I is the moment of inertia, M is the mass, and R is the radius.
For the sphere:
a = (9.8 x sin20) / (1 + (2/5)) = 2.34 m/s^2
For the solid cylinder:
a = (9.8 x sin20) / (1 + (1/2)) = 3.29 m/s^2
For the ring:
a = (9.8 x sin20) / (1 + 1) = 4.16 m/s^2
e) The tangential (linear) velocity of each shape at the bottom of the slope can be calculated using the following equation:
v = ωR
Where v is the tangential velocity, ω is the angular velocity, and R is the radius.
The angular velocity can be calculated using the following equation:
ω = (2a / R)^(1/2)
For the sphere:
ω = (2 x 2.34 / 0.05)^(1/2) = 21.8 rad/s
v = 21.8 x 0.05 = 1.09 m/s
For the solid cylinder:
ω = (2 x 3.29 / 0.05)^(1/2) = 30.7 rad/s
v = 30.7 x 0.05 = 1.53 m/s
For the ring:
ω = (2 x 4.16 / 0.05)^(1/2) = 36.4 rad/s
v = 36.4 x 0.05 = 1.82 m/s
mark me brilliant
Answer:
c
Explanation:
The boy biked 600 m at a speed of 10 m/s, how long did it take him to bike the total distance?
Answer:60 seconds
Explanation: Since we have the boy's initial location si (0m), final location sf (600m) and his velocity v, we can have our position equation like so:
sf = si + vt
600 = 0 + 10t
Solve for t by dividing 600 by 10 and your time t = 60s
The length of the Achilles tendon increases 0.500 cm when the force exerted on it by the muscle increases from 3230 N to 4787 N.
How much work is done by the muscle in stretching the tendon?
The work done by the muscle in stretching the Achilles tendon is 20.04 joules.
To calculate the work done by the muscle in stretching the Achilles tendon, we can use the formula:
Work = Force × Distance
We know that the force exerted on the tendon by the muscle increased from 3230 N to 4787 N, causing the tendon to stretch by 0.500 cm.
converting the distance from centimeters to meters:
Distance = 0.500 cm = 0.005 m
Now we can calculate the work done by the muscle:
Work = Force × Distance
Work = (4787 N + 3230 N)/2 × 0.005 m
Work = 4008.5 N × 0.005 m
Work = 20.04 J
Therefore, the work done by the muscle in stretching the Achilles tendon is 20.04 joules.
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