The domain of the linear function is (1.5, ∞) and the range of the linear function will be (40, ∞).
What are domain and range?The domain means all the possible values of x and the range means all the possible values of y.
A carpet installer charges a flat rate of $40 and $1.50 per square foot for labor.
So the total cost for the labor depends on the amount of carpet installed, the relationship between the total cost for labor and the amount of corporate installed.
Then the domain of the relation is the range of the relation will be
Let y be the total amount and x be the number of square foot.
y = 1.5x + 40
Then the domain of the linear function is (1.5, ∞) and the range of the linear function will be (40, ∞).
The graph is given below.
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Rick bought some tetra fish and goldfish for his fish tank. He bought twice as many goldfish as he did tetras. Each goldfish costs $1.50, and each tetra fish costs $2.00. He spent $20 on the fish. Which system can be used to represent x, the number of tetra fish, and y, the number of goldfish, he purchased?
x = 2 y. 2 x + 1.5 y = 20
2 x = y. 2 x + 1.5 y = 20
x = y. 2 x + 1.5 y = 20
x + y = 20. 2 x + 1.5 y
Answer:
B. 2x = y; 2x +1.5y = 20
Step-by-step explanation:
The two given relations can be written as two equations, one for the numbers of fish, and one for their cost.
__
number of fishThe number of goldfish (y) is twice the number of tetras (x), so one equation can be ...
2x = y
cost of fishThe tetras (x) are $2 each, and the goldfish (y) are $1.50 each. Their total cost is the sum of products of the number of fish and the cost of each. That total is given as $20, so the other equation could be ...
2x +1.5y = 20
Then the appropriate system of equations is ...
2x = y2x +1.5y = 20_____
Additional comment
The solution can be found by substituting for 2x to get ...
y +1.5y = 20 . . . . . . substitute for 2x
y = 20/2.5 = 8 . . . . divide by the coefficient of y
x = y/2 = 4 . . . . . . . find the number of tetras
Rick bought 4 tetras and 8 goldfish.
__
The wording "twice as many goldfish as tetras" easily causes confusion. It is helpful to reword it as "goldfish were twice the number of tetras."
Study each of the growing geometrical patterns. Then do the following for each pattern. (I) Give a verbal description of how the pattern is growing. (ii)Set up a table of values.(III) Write down a numerical description for each pattern (you must relate the number of the frame to the number of figures in the frame). (IV) For each pattern, write down a formula that can be used to calculate the number of building blocks in any term. (v) Write down the value of the 10th frame. Use your formula to determine how many building blocks there are in the 100th frame of each growing pattern. M M Δ Δ Δ 2 (6) (6) (8) [40]
A description of how the pattern is growing is that the pattern is growing by the addition of two blocks every time.
How to illustrate the pattern?A numerical description of the pattern is:
1 - 2 blocks.
2 - 4 blocks.
3 - 6 blocks
4 - 8 blocks.
The formula that can be used to calculate the number if building blocks in any term will be 2n. For example, the number of blocks for the 5th term will be:
= 2n = 2 × 5 = 10
The value for the 10th frame will be:
= 2n
= 2 × 10 = 20
The value for the 100th frame will be:
= 2n
= 2 × 100 = 200
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Given the data set (4,85),(7,92),(14,110), which of the following equation best represents a line of best fit
Select the correct answer from each drop-down menu.
Need helpp
(1st image of dropdown menu is the drop down menu on top an the second image is the second dropdown menu beneath it)
Triangle ABC and triangle XYZ are similar based on angle-side-angle criterion.
Triangle ABC and triangle RQP are similar based on side-angle-side criterion.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Two triangles are said to be congruent if they have the same shape and their corresponding sides are congruent.
Triangle ABC and triangle XYZ are similar based on angle-side-angle criterion.
Triangle ABC and triangle RQP are similar based on side-angle-side criterion.
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400g is what percent of 80kg?
You buy a CD for $9000 that earns $172.92 in interest every 2 months. What is the
annual yield on your investment?
Answer:
$4,000.343
Step-by-step explanation:
Divided the months of the year and caculate the intrest.
HELP STAT:
Graph the function F(x)= -sec (x/4) +3 on the interval [-2pi,6pi]
Answer:
Step-by-step explanation:
find the measure of angle ACB
Answer:
angle ACB=45º
Step-by-step explanation:
angle 135º lies on a straight line
a straight line = 180º
thus, angle ACB= 180-135=45º
Find the prime factorization of the composite number 10692
When decomposing into prime factors, it is when a number is taken out of its half, third, fifth and seventh, and it is also possible for the same number number.
[tex]\large\displaystyle\text{$\begin{gathered}\sf \left.\begin{matrix} \blue{10692 }\\ \ 5346\\ \ 2673\\ \ \ \ 891\\ \ \ \ 297\\ \ \ \ \ 99\\ \ \ \ \ 33\\ \ \ \ \ 11\\ \ \ \ \ 1 \end{matrix}\right|\begin{matrix} 2\\ 2\\ 3\\ 3\\ 3\\ 3\\ 3\\ 11\\ \: \end{matrix} \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf 10692=2\cdot2\cdot3\cdot3\cdot3\cdot3\cdot3\cdot11=\bf{2^{2}\cdot3^{5}\cdot11 } \end{gathered}$}[/tex][tex]\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]
Identifying an Error
Identify the error in the student solution shown
below. Find the correct answer.
2ln(x)= In(3x) - [In(9) - 2ln(3)]
In(x²) In(3x)-[In(9) - In(9)]
In(~2) 1/25)
The incorrect step is ln(x²) = ln(3x/0) because ln(x/y) = lnx - lny and the solutions are x = 0, 3
What is a logarithm?It is another way to represent the power of numbers, and we say that 'b' is the logarithm of 'c' with base 'a' if and only if 'a' to the power 'b' equals 'c'.
[tex]\rm a^b = c\\log_ac =b[/tex]
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have:
2ln(x) = In(3x) - [In(9) - 2ln(3)]
In(x²) = In(3x) - [In(9) - In(9)]
ln(x²) = ln(3x) - 0
ln(x²) = ln(3x/0) (incorrect step)
ln(x²) = ln(3x)
x² = 3x (correct step)
x² - 3x =0
x(x - 3) = 0
x = 0, 3
Thus, the incorrect step is ln(x²) = ln(3x/0) because ln(x/y) = lnx - lny and the solutions are x = 0, 3
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if p = (-1,-1) find the image of p under the following rotation. 90 degrees counterclockwise about the origin
Answer:
( 1, - 1 )
Step-by-step explanation:
I need help with question 12
The value of the integral over limit is 20, the average is 1.73
The signed area is shown in the graph attached.
What is a Function ?A function is a mathematical statement used to find a relation between two variable.
To Evaluate the definite integral between
f(x) = 5 if 4≤x ≤9
f(x) = -1 if 9≤x≤14
[tex]\rm \int_{4}^{14}f(x) dx = \int_{4}^{9} 5 dx +\int_{9}^{14} (-1)dx\\\\\int_{4}^{14}f(x) dx = (5x)^{9}_{4} -(x)^{14}_{9}\\\\\int_{4}^{14}f(x) dx = 5*(9-4) - (14-9)\\\\\int_{4}^{14}f(x) dx = 20[/tex]
The average value of the interval is
= (5+5+5+5+5-1-1-1-1-1-1)/ 11 = 1.73
Therefore the average is 1.73.
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What does the ratio 6 to 8 represent in the situation?
Answer:
its 80
Step-by-step explanation:
the ratio is 80 hope this helps!
Briana monitors the number of E. coli infections reported in a certain
neighborhood in a given week. The recent numbers are shown in
this table:
According to her reports, the reported infections are growing at a
rate of 50%.
If the number of infections continues to grow exponentially,what
will the number of infections be in week 6?
An equation is formed of two equal expressions. The number of infections in 6 weeks is 456.
What is an equation?An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
The general equation of an exponential function is written as,
y = A(B)ˣ
Since the infection is increasing at a rate of 50%, therefore, the rate of growth will be,
B = 1.50
Substitute any value then we will get,
40 = A(1.50)⁰
A = 40
Thus, the exponential equation of the growth will be,
y = 40(1.50)ˣ
Now, the number of infections in 6 weeks will be,
y = 40(1.50)⁶
y = 455.625 ≈ 456
Hence, the number of infections in 6 weeks is 456.
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Consider a triangle ABC like the one below. Suppose that B=129°, a=7, and c=42. (The figure is not drawn to scale.) Solve the triangle.
Carry your intermediate computations to at least four decimal places, and round your answers to the nearest tenth.
If there is more than one solution, use the button labeled "or".
4-C-b-0
DOD
X
No
solution
5
?
The angles are: A =24.7° ; B = 40.6° ; C =114.7°.
What is Cosine law?
The law of cosine helps in establishing a relationship between the lengths of sides of a triangle and the cosine of its angles. The cosine law in trigonometry generalizes the Pythagoras theorem, which applies to a right triangle.
Cosine Law
a² = b²+c²-2bc cos A
b² = c²+a² -2ca cos B
Sum of three angles of a triangle is 180°.
a = 34 ; b= 53; c = 74
Substituting the given values in the cosine law, we have
34² = 53² + 74² - 2*53 *74 * cos A
7844 cos A = 2809 + 5476 - 1156 = 7129
cos A = 7129/7844 = 0.9088
A = cos⁻¹ (0.9088) = 24.6600° = 24.7°
53² = 74² + 34² - 2 (74)(34) cos B
5032 cos B = 5476 + 1156 - 2809 = 3823
cos B = 3823/5032 = 0.7597
B = cos⁻¹ (0.7597) = 40.5622° = 40.6°
Also, A + B + C = 180°
24.7 + 40.6 + C =180
C =180 - 65.3 = 114.7°
Thus, the angles are: A =24.7° ; B = 40.6° ; C =114.7°
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Here are the first five numbers in a sequence.
47 41
(a) Find the first negative number in the sequence.
35
29
23
Answer:
- 1
Step-by-step explanation:
note there is a common difference of 6 between consecutive terms , that is
23 - 29 = 29 - 35 = 35 - 41 = 41 - 47 = - 6
by subtracting 6 from the previous term we get
23 - 6 = 17
17 - 6 = 11
11 - 6 = 5
5 - 6 = - 1
the first negative number in the sequence is - 1
Given that (1, 0, 1) is a solution to a system of three linear equations, which of the following is true about the system?
The true option about the system of linear equation is that the system can only be independent and consistent.
How to illustrate the equation?It should be noted that the system is consistent as it can illustrate more than a solution.
Also, it can't be independent and dependent at the same time as depicted in some of the option given.
In this case, true option about the system is that the system can only be independent and consistent.
The complete question is:
Given that (1, 0, 1) is a solution to a system of three linear equations, which of the following is true about the system?
The system can be either inconsistent or consistent.
The system can be either independent or dependent.
The system can only be independent and consistent.
The system can only be dependent and inconsistent.
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Use two different methods to find an explain the formula for the area of a trapezoid that has parallel sides of length a and B and height H. Consider these ideas or others: combine two copies of a trapezoid to make a parallelogram. Subdivide the trapezoid into two triangles one with base b and one with base a.
Answer:
Formula of Trapezoid:
A = (a + b) × h / 2
The formula can be derived in different ways. for now, we have discussed two ways:
1. By using the formula of a triangle
2. By dividing into different sections
Step-by-step explanation:
1. By using the formula of a triangle
One of the ways to explain a formula for an area of a trapezoid using a formula for a triangle can be as follows.
Assume a trapezoid PQRS with lower base SR and upper base PQ (they are parallel) and sides PS and QR.
The image is attached below.
Connect vertices P and R with a diagonal.
Consider triangle ΔPQR as having a base PQ and an altitude from vertex R down to point M on base PQ (RM⊥PQ).
Its area is
S1=[tex]\frac{1}{2} *PQ*RM[/tex]
Consider triangle ΔPRS as having a base SR and an altitude from vertex P up to point N on-base SR (PN⊥SR).
Its area is
S2=[tex]\frac{1}{2} *SR*PN[/tex]
Altitudes RM and PN are equal and constitute the distance between two parallel bases PQ and SR.
They both are equal to the altitude of the trapezoid h.
Therefore, we can represent areas of our two triangles as
S1=[tex]\frac{1}{2}*PQ*h[/tex]
S2=[tex]\frac{1}{2}*SR*h[/tex]
Adding them together, we get the area of the whole trapezoid:
S=S1+S2=[tex]\frac{1}{2} (PQ+SR)h,[/tex]
which is usually represented in words as "half-sum of the bases times the altitude".
2. By dividing into different sections
Trapezoid PQRS is shown below, with PQ parallel to RS.
Figure 1 - Trapezoid PQRS with PQ parallel to RS(image is attached below.)
We are going to derive the area of a trapezoid by dividing it into different sections.
If we drop another line from Q, then we will have two altitudes namely PT and QU.
Figure 2 - Trapezoid PQRS divided into two triangles and a rectangle. (image is attached below.)
From Figure 2, it is clear that Area of PQRS = Area of PST + Area of PQUT + Area of QRU. We have learned that the area of a triangle is the product of its base and altitude divided by 2, and the area of a rectangle is the product of its length and width. Hence, we can easily compute the area of PQRS. It is clear that
=> [tex]A_{PQRS} = (\frac{ah}{2}) + b_{1}h + \frac{ch}{2}[/tex]
Simplifying, we have
=>[tex]A= \frac{ah+2b_{1+C} }{2}[/tex]
Factoring we have,
=> [tex]A_{PQRS} = (a+ 2b_{1} + c)\frac{h}{2} \\= > {(a+ b_{1} + c) + b_{1} }\frac{h}{2}[/tex]
But, [tex]a+ b_{1} + c[/tex] is equal to [tex]b_{2}[/tex], the longer base of our trapezoid.
Hence, [tex]A_{PQRS}= (b_{1} + b_{2} )\frac{h}{2}[/tex]
We have discussed two ways by which we can derive area of a trapezoid.
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A company makes paper labels for paint cans. As shown below, each can is in the shape of a cylinder
with a height of 7 cm and a radius of 2 cm. The paper label is wrapped around the can and covers only
the side of the can (not the top or bottom). The company uses, on average, 3612.64 cm² of paper
each minute making these labels. How many labels does the company make, on average, each
minute?
For your calculations, do not round any intermediate steps, and use the button on a calculator. Round
your answer to the nearest hundredth.
The company needs 41 labels on average, each minute.
What is the circumference of a circle?The perimeter of a circle (circumference): 2 π radius
Replacing with the values given:
C = 2 (3.14) 2 = 12.56 cm
So, the area of one label is:
Area of a rectangle: length x width = 12.56 x 7 = 87.92 cm sq.
Now, the number of label be n
87.92 x n = 3612.64 cm2
n = 3612.64 / 87.92
n = 41.09
Hence, The company needs 41 labels on average, each minute.
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Express cos S as a fraction in simplest terms.
Answer: Read attachment.
Step-by-step explanation: Attached below is my work. Hope it helps!
A billboard designer has decided that a sign should have 4-ft margins at the top and bottom and 1-ft margins on the left and right sides. Furthermore, the billboard should have a total area of 3600 ft2 (including the margins).
If x denotes the left-right width (in feet) of the billboard, determine the value of x that maximizes the area of the printed region of the billboard.
An equation is formed of two equal expressions. The value of x that maximizes the area of the printed region of the billboard is 9.655 ft.
An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
Given x is the left-right width of the billboard and y is the height of the billboard. Therefore,
The total area of the billboard, A= x·y
The total printed area of the billboard, [tex]A_p=(x-2)(y-8)[/tex]
Given in problem that the area of the billboard is 3600 ft².
x·y = 3600
y = (3600)/x
Substituting the value of y in the equation of the total printed area of the billboard,
[tex]A_p = (x-2)(\dfrac{3600}{x}-8)\\\\A_p = 3600 -8x -\dfrac{7200}{x} + 16\\\\A_p =3616-8x - \dfrac{7200}{x}[/tex]
Now, the value of x is needed to be minimum, therefore, differentiating the given function,
[tex]\dfrac{d}{dx}A_p =\dfrac{d}{dx}3616-8x - \dfrac{7200}{x}\\\\\dfrac{d}{dx}A_p =-8 - \dfrac{7200}{x^2}[/tex]
Equate the differentiated function with 0,
[tex]0=-8x - \dfrac{7200}{x^2}\\\\8x = - \dfrac{7200}{x^2}\\\\x^3 = 900\\\\x = 9.655 ft.[/tex]
Hence, the value of x that maximizes the area of the printed region of the billboard is 9.655 ft.
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Amy and Laura recorded the average gas mileage (MPG) of their vehicles each week for four weeks. What can be concluded about the relationships shown in the graph and table?
Amy and Laura recorded the same gas mileage each week.
Both Amy and Laura increased their gas mileage in the first two weeks.
Amy had greater gas mileage than Laura.
Laura had a constant gas mileage in the first four weeks of data.
Who runs fastest?
When do Andy and Berta cross paths?
Who is closest to the 1.5 mile mark after 6 minutes?
Both Amy and Laura increased their gas mileage in the first two weeks.
Option B is the correct answer.
The missing graph is attached with the answer.
What is a Graph ?A graph is a statistical way of showing data , it is used to show relation between the points.
A graph is useful in understanding the nature of a function.
From the data given in the question
The statements that can be concluded is , Option B
Both Amy and Laura increased their gas mileage in the first two weeks.
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dollars per pint
pints per dollar.
▼
Find the unit rates. If necessary, round your answers to the nearest hundredth.
$6.79 for 16 pints
Answer:
0.42 dollar per pint
2.36 pints per dollar
Circle O is shown. Line segment J E is a diameter and line segment O B is a radius. A line is drawn from point J to point B to form a chord. Tangents B D and E D intersect at point D outside of the circle.
Use the diagram to complete the statements.
The measure of angle EJB is
the measure of angle BOE.
The measure of angle BDE is
the measure of angle BOE.
The measure of angle OED is
✔ equal to
the measure of angle OBD.
The measure of angle OED is the measure of angle OBD. Then the correct option is C.
What is a circle?It is the center of an equidistant point drawn from the center. The radius of a circle is the distance between the center and the circumference.
Circle O is shown.
Line segment JE is a diameter and line segment OB is a radius.
A line is drawn from point J to point B to form a chord.
Tangents BD and ED intersect at point D outside the circle.
The radius and tangent are orthogonal to each other.
∠OED = ∠OBD = 90°
Then the correct option is C.
The complete question is given below.
Circle O is shown. Line segment J E is a diameter and line segment O B is a radius. A line is drawn from point J to point B to form a chord. Tangents B D and E D intersect at point D outside of the circle.
Use the diagram to complete the statements.
The measure of angle EJB is the measure of angle BOE.
The measure of angle BDE is the measure of angle BOE.
The measure of angle OED is the measure of angle OBD.
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Answer:
one-half, 180 minus, equal to
Step-by-step explanation:
Step 1: Choose the lowest common denominator.
02 03 04 05 06 08 010 012
3/4
50/80
O
Find the sum: -and
The expression written in equivalent form with a
common denominator is
The sum is
The expression written in equivalent form with a common denominator is -1/6
Adding fractionsFractions are written as ratio of two integers. For instance a/b is a fraction.
Given the sum of the fractions shown;
-3/4 and 5/8
Sum = -3/4 + 5/8
Sum = 5/8 - 3/4
Sum = 5-6/8
Sum = -1/8
Hence the sum of the given fraction -1/3 and 5/8 is -1/6
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A jackrabbit can run at the speed of 1.35 kilometers per minute . How fast can the jackrabbit run in miles per hour ? First fill in the two blanks on the left side of the equation using two of the ratios . Then write your answer rounded to the nearest hundredth on the right side of the equation
The speed of the rabbit in miles per hour is 50.33 mi/h.
How fast can the jackrabbit run in miles per hour?We know that the speed of the jackrabbit is:
1.35 km/min.
Now we need to use the relations:
1 hour = 60 minutes.
So, in one hour, the rabit runs 60 times the distance that it runs in one minute, then:
1.35 km/min = 60*(1.35 km/h) = 81km/h
Now we need to change kilometers for miles.
1km = 0.6214 mi
Then we can rewrite:
81km/h = 81*0.6214mi/h = 50.33 mi/h
The speed of the rabbit in miles per hour is 50.33 mi/h.
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evaluate question 4 only
Substitute [tex]y = \sqrt x[/tex], so that [tex]y^2 = x[/tex] and [tex]2y\,dy = dx[/tex]. Then the integral becomes
[tex]\displaystyle \int \frac{dx}{\sqrt{1 + \sqrt x}} = 2 \int \frac y{\sqrt{1+y}} \, dy[/tex]
Now substitute [tex]z=1+y[/tex], so [tex]dz=dy[/tex]. The integral transforms to
[tex]\displaystyle 2 \int \frac y{\sqrt{1+y}} \, dy = 2 \int \frac{z-1}{\sqrt z} \, dz = 2 \int \left(\sqrt z - \frac1{\sqrt z}\right) \, dz[/tex]
The rest is trivial. By the power rule,
[tex]\displaystyle \int \left(\sqrt z - \frac1{\sqrt z}\right) \, dz = \frac23 z^{3/2} - 2z^{1/2} + C = \frac23 \sqrt z (z - 3) + C[/tex]
Put everything back in terms of [tex]y[/tex], then [tex]x[/tex] :
[tex]\displaystyle 2 \int \frac y{\sqrt{1+y}} \, dy = \frac43 \sqrt{1+y} (y - 2) + C[/tex]
[tex]\displaystyle \int \frac{dx}{\sqrt{1+\sqrt x}} = \boxed{\frac43 \sqrt{1+\sqrt x} (\sqrt x - 2) + C}[/tex]
Write each of the following numerals in base 10. For base twelve, T and E represent the face values ten and eleven, respectively.
a. 421 five
b. 11101 two
c. 13Ttwelve
(a)
421₅ = 4×5² + 2×5¹ + 1×5⁰
… = 100 + 10 + 1
… = 111
(b)
11101₂ = 1×2⁴ + 1×2³ + 1×2² + 0×2¹ + 1×2⁰
… = 16 + 8 + 4 + 0 + 1
… = 29
(c)
13T₁₂ = 1×12² + 3×12¹ + 10×12⁰
… = 144 + 36 + 10
… = 190
f(a)=3a^2+2a+7 find the value of f(a)
Answer:
Step-by-step explanation:
If a = 0, f(a) = f(0) = 0 + 0 + 7 = 7;
If a = 1, f(1) = 3(1^2) + 2(1) + 7 = 12;
and so on. Normally an 'a' value would be given as part of this problem.
Actually, the value of f(a) is given and is f(a) = 3a^2+2a+7 for input value a.
PLEASE HELP
Natalie invests $6,680 in a savings account with an interest rate of 2% compounded continuously.
How long will it take for the account balance to reach $8,838.51?
The time it will take the money to reach $8,838.51 is 14years
Compound interestThe formula for calculating compound interest is expressed as:
A = P(1+r)^t
where
P = $6,680
A = $8,838.51?
r = 2% = 0.02
Substitute and calculate the time 't"
8,838.51 = 6680(1+0.02)^t
1.3231 = 1.02^t
t = ln1.3231/ln1.02
t = 14years
Hence the time it will take the money to reach $8,838.51 is 14years
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