Answer:
a = 5 [m/s²]
Explanation:
To solve this equation we must use the following equation of kinematics.
[tex]v_{f} =v_{o} +a*t[/tex]
where:
Vf = final velocity = 25 [m/s]
Vo = initial velocity = 5 [m/s]
a = acceleration [m/s²]
t = time = 4 [s]
Note: The positive sign for the acceleration in the above equation means that the car is increasing its velocity.
25 = 5 +a*(4)
25 - 5 = 4*a
20 = 4*a
a = 5 [m/s²]
In a tug of war game, team A is very strong and is pulling team B with a speed of 1 foot per second. In this situation… *
A. Only team A is doing work
B.Only team B is doing work
C. Team A and team B are doing work
D. Neither team A nor team B is doing work
Compare the momentum of a 7160 kg truck moving at 5.00 m/s to the
momentum of a 2240 kg car moving at 15.0 m/s.
Answer:
2,200
Explanation:
truck=35800,car=33600
Which of the following is true about light with a single wavelength?
1) It can be refracted
II) It cannot be dispersed
III) It can be reflected *
Answer:
It can be refracted
Explanation:
When a single wavelength wave which is known as a monochromatic light is passed from one transparent medium to the other, it can refract. This refraction can only be seen if the light enter the medium at some angle.
A bus initially moving at 20 m/s with an acceleration of -4m/s² for 5
seconds. What is the displacement AND final velocity?
Answer:
50m; 0m/s.
Explanation:
Given the following data;
Initial velocity = 20m/s
Acceleration, a = - 4m/s²
Time, t = 5secs
To find the displacement, we would use the second equation of motion;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Substituting into the equation, we have;
[tex] S =20*5 + \frac{1}{2}*(-4)*5^{2}[/tex]
[tex] S =100 + (-2)*25[/tex]
[tex] S =100 - 50[/tex]
S = 50m
Next, to find the final velocity, we would use the third equation of motion;
[tex] V^{2} = U^{2} + 2aS [/tex]
Where;
V represents the final velocity measured in meter per seconds. U represents the initial velocity measured in meter per seconds. a represents acceleration measured in meters per seconds square.Substituting into the equation, we have;
[tex] V^{2} = 20^{2} + 2(-4)*50 [/tex]
[tex] V^{2} = 400 - 400[/tex]
[tex] V^{2} = 0[/tex]
V = 0m/s
Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.
Multiple Intelligences :
• are completely innate ( inborn)
•can be developed
•are not proven with scientific theory
•a and c
•all of the above
Which one is the answer?
Answer:
all of the above
PLS MARK ME AS BRAINLIAST
Whenever an action and reaction occur, momentum is what?
Answer:
I'm not sure what your asking for
reaction and law
Explanation:
the newton third law of motion
What type of substances is an alloy?
A) Moleclue?
B) Mixture?
C) Compound?
D) Element?
A boy on rollerskates is travelling along at 8 m/s. He has a mass of 60 kg and is carrying his
school bag of mass 10 kg. He throws the bag directly forward at 20 m/s relative to the
ground. Calculate the boy's speed after the 'explosion?
Answer:
6m/s
Explanation:
the original momentum = mass x velocity = 8x (60+10) = 560
momentum after = mass x velocity of the school bag + mass x velocity of the boy = 10x20 + 60x A
200+60A = 560
A=6
Just helping as usual what about you
Answer:
same i just love helping people out
god bless you have a blessed day
Explanation:
Answer:
I do too
Explanation:
I like to help others especially if it has been filled in by struggling in a certain concept of a subject.
Do u agree?
linear expansivity?
Linear expansivity, area expansivity and volume or cubic expansivity are
A force act on a bicycle for 2.4 sec, and changes its momentum from 20 kg m/s in the x positive direction to 40 Kg m/s in the Positive x direction, what is the magnitude of the force?
A. -10 N
B. 137.5 N
C. 8.33 N
D. -137.5 N
Answer:
Increased momentum =40-20=20
F=P/T=20/2.4=8.33N
Explanation:
F=(force)
P=(momentum)
T=(time)
The number of degrees of arc that your location is north or south of the Earth's equator is called your:
A. meridian
B. declination
C. latitude
D. longitude
Why this way of voting could benefit baboons
What force is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25?
Answer:
Any force greater than 24.5 N
Explanation:
To find the frictional force is the 1st step. this can be found by multiplying the coefficient of friction and the normal force. normal force can be found by multiplying gravity (we will say 9.8 m/s/s) and the mass which is 10. You then multiply the result by the coefficient of friction which is 0.25 and it leads us to an answer to 24.5 N. This means that if you pull with exactly 24.5 N, the sled wouldnt move. So you need a force greater than 24.5 N and we have our answer.
I hope I helped correct me if im wrong
A force of 25 N is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25.
First, we will calculate the normal force (N), which, in a horizontal surface, has the same magnitude and opposite sense as the weight (W) of the sled.
[tex]|N| = |W| = m \times g = 10 kg \times \frac{9.8m}{s^{2} } = 98 N[/tex]
where,
m: mass of the sledg: Earth's gravityThen, we will calculate the friction force (f) using the following expression.
[tex]f = \mu \times N = 0.25 \times 98 N = 25 N[/tex]
According to Newton's first law of motion, for the sled to move at a constant velocity, the sum of the force exerted (F) on the sled and the friction force (f) must be zero.
[tex]F + f = 0\\F = -f\\F = -25 N\\|F| = 25 N[/tex]
A force of 25 N is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25.
You can learn more about friction here: https://brainly.com/question/18754989
I need help asap!!!!!!! FVLS CIVICS
Step 2:
Brainstorm an idea for a new amendment to the Constitution. Answer the following questions about your new amendment idea.
What will this amendment do?
Whom will it benefit and how?
Answer:
Amendment (whatever you call it), but it would be amendment 28 if passed, lol
Explanation:
This amendment will be term limits for all members of House and Senate for Congress
How this amendment would benefit is that it would be more structured in Congress.
A tough kid on a tricycle has combined mass 32 kg. She starts from rest and travels 3.5 m in 2.5 s. What is the net force used to accelerate. (Hint: d=(1/2)at2)
Answer:
F = 35.84NExplanation:
Force = mass * acceleration (Newton's second law of motion)
Given
Mass = 32kg
Get the acceleration using the expression d = 1/2at^2
3.5 = 1/2 (a)2.5^2
3.5 = 3.125a
a = 3.5/3.125
a = 1.12m/s^2
Get the net force;
F = 3.2 * 1.12
F = 35.84N
Hence the net force used to accelerate is 35.84N
how much would a person whose mass is 60kg weight on the moon
Why are recessive traits not seen even though they are present in the alleles?
Answer:
Explanation:. The vending machine holds 10 bags of pretzels and 8 packs of cheese crackers. Both the pretzels and crackers dispenseat 2 bags per hour. How many hours will elapse when there is the same number of snacks remaining in the vending machine? How many of each item will there be at this point?Equation1______________________________Equation2_______________________________Hours: ___________________________ Items: ____________________________What does each equation have n common? ______________________How does this affect the solution?
You have an oxygen atom that is looking to bond. How many atoms of one element from column 1 would need to bond with that oxygen to form an ionic bond? Why?
A balloon is launched straight upward and has a hang time of 14 s. (wow)
A.) What was the launching velocity of the balloon?
B.) How high did the balloon travel?
C.) How far did the balloon travel between t = 3 and t = 4 s?
Answer:
A) Vo = 137.34 [m/s]
B) Y = 961.38 [m]
C) y = 367.8[m] for t = 3 [s] and y = 470.88[m] for t = 4[s]
Explanation:
To solve this problem we must use the following equation of kinematics. We must keep in mind that the negative sign of the equation means that the acceleration of gravity acts in the opposite direction to the movement of the balloon.
A)
[tex]v_{f} =v_{o} -g*t[/tex]
where:
Vf = final velocity = 0 (the maximum hang time, maximum elevation)
Vo = initial velocity [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time = 14 [s]
0 = Vo - (9,81*14)
Vo = 137.34 [m/s]
B)
Now we use the following equation.
[tex]y=y_{o}+v_{o} *t -(\frac{1}{2} )*g*t^{2}[/tex]
where:
Yo = initial position = 0
Y = final position [m]
Vo = initial velocity = 137.34 [m/s]
Now replacing
Y = (137.34*14) - (0.5*9.81*14²)
Y = 961.38 [m]
C)
With the above equation, we can calculate the distances between t = 3 and t = 4 [s]
[tex]y=y_{o} +v_{o} *t - (1/2)*g*t^{2}[/tex]
y = (137.34*3) - (0.5*9.81*3²)
y = 367.8[m] for t = 3 [s]
for t = 4[s]
y = (137.34*4) - (0.5*9.81*4²)
y = 470.88[m]
If the density of water is 1000 kg/m², what is the pressure at the bottom of a swimming pool 2m
deep when it is full of water?
The pressure at the bottom when the given tank is full of water will be 19600 Pa.
Pressure can be calculated by the formula,
[tex]\bold {P = \rho h g}[/tex]
Where,
P- pressure = ?
[tex]\bold {\rho}[/tex] - density of water = 1000 kg/m²
h - height of water = 2 m
g - gravity acceleration = 9.8 m/s
Put the values in the formula
[tex]\bold {P = 2 \times 1000 \times 9.8} \\\\\bold {P = 19600\ Pa}[/tex]
Therefore, the pressure at the bottom when the given tank is full of water will be 19600 Pa.
To know more about pressure,
https://brainly.com/question/23603188
Two positively charged particles are 0.03 m apart. The first
particle has a charge of 8.1 C, and the second a charge of 2.6
C. Which change would lead to the smallest increase in the
- electric force between the two particles?
A. Reduce the charge on the first particle by one half.
O B. Double the distance between the particles.
O C. Double the charge on the second particle.
OD. Reduce the distance between the particles by one
half
The correct option is option C.
Doubling the charge on the second particle produces the smallest increase in force.
Electrostatic force:Let the given charges be Q and q such that:
Q = 8.1C and q = 2.6C
separated by a distance of R = 0.03m
Now, we have to calculate the minimum increase in electric force.
The electrostatic force is given by:
F = kQq/R²
Option A is wrong since reducing the charge will reduce the force.
Option B is wrong since the force is inversely proportional to the distance, so increasing the distance will decrease the force.
Option C ⇒ Double the charge on the second particle:
F = 2kQq/R²
Option D ⇒ Reduce the distance between the particles by one half:
So, the new distance between the charges is R/2, then
F = kQq/(R/2)²
F = 4kQq/R²
Clearly, the operation in option C gives the smallest increase in the force.
Learn more about Electrostatic force:
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A 10kg mass is moving to the right with a velocity of 15 m/s. A 13kg mass
is moving to the left with a velocity of 6.0 m/s. Assuming that these two
masses have a head on collision and stick together, what would be the
final velocity and to what direction? *
Answer:
M1u1+(-m2u2) = (m1+m2) V. By using this equation you can find the final velocity of that. It would be 3.13ms-1. And the direction is right side.
What is the acceleration of car if it goes from 60 m/s to a stop in 6 seconds?
Answer:
[tex]\boxed {\boxed {\sf a= -10 \ m/s^2}}[/tex]
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
[tex]a=\frac{v_f-v_i}{t}[/tex]
The car came to a stop, so it's final velocity is 0 m/s.
The initial velocity of the car is 60 m/s.
The time is 6 seconds.
[tex]v_f=0 \ m/s\\v_i=60 \ m/s\\t= 6 \ s[/tex]
Substitute the values into the formula.
[tex]a=\frac{0 \ m/s-60 \ m/s}{6 \ s }[/tex]
Solve the numerator.
0 m/s-60 m/s= -60 m/s[tex]a\frac{-60 \ m/s}{ 6 \ s }[/tex]
Divide.
[tex]a= -10 \ m/s^2[/tex]
The acceleration of the car is-10 meters per square second. The negative acceleration indicates it is slowing down/stopping.
runnin reggie ran up a mountain from an elevation of 915 m to 4095 m in 62.25 min. If Reggie has a mass of 70 kg, how much power did Reggie generate during his run?
Answer:
....................
The target heart rate zone is:
a
the level your recovery heart rate should reach.
b
where you want your exercise heart rate.
c
where you want your resting heart rate.
d
your maximum heart rate.
The target heart rate zone is where you want your exercise heart rate to be. Option B is correct.
The target heart rate zone is a specific range of heart rates that you should aim to achieve during exercise to maximize the benefits of your workout. This range is typically calculated based on a percentage of your maximum heart rate. For example, if your maximum heart rate is 180 beats per minute, your target heart rate zone might be between 120 and 150 beats per minute.
The objective pulse is 50 to 85 percent of your greatest pulse. It is the level at which your heart is pulsating with moderate to extreme focus. To decide your greatest pulse, take 220 and deduct your age. Supporting an exercise at this speed works on cardiorespiratory perseverance.
Know more about target heart zone:
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A package is dropped from the height of 100 m and falls freely. How fast will the package be traveling when it hits the ground?
Answer:
The package will be traveling at 44.3 m/s when it hits the ground
Explanation:
Free Fall Motion
A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.8 m/s^2[/tex].
The final velocity of a free-falling object after a time t is given by:
vf=g.t
The distance traveled by a dropped object is:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
If we know the height h from which the object was dropped, we can find the time it takes fo hit the ground:
[tex]\displaystyle t=\sqrt{\frac{2h}{g}}[/tex]
The package was dropped from h=100 m, thus the time taken to reach the ground is:
[tex]\displaystyle t=\sqrt{\frac{2(100)}{9.8}}[/tex]
[tex]t = 4.52~s[/tex]
The final speed is now calculated:
[tex]vf=9.8*4.52[/tex]
[tex]vf=44.3~m/s[/tex]
The package will be traveling at 44.3 m/s when it hits the ground
Who was the first professor who implemented a scientific approach in order to investigate a problem, and who is referred to the the father of scientific mythology
Answer:
1. Aristotle
2. Thales of Miletus
Explanation:
1. Answer: The first professor who implemented a scientific approach in order to investigate a problem was Aristotle(384-322 BC)
Aristotle was a student under Plato, he pioneered the scientific method in ancient Greece.
2. Answer: The father of scientific mythology was
Thales of Miletus (c. 624/623-c. 548/545 BC)
Thales was a Greek mathematician, astronomer, and pre-socratic philosopher, Asia minor.
The unit of the electric resistance is ???
Answer:
OhmsStep-by-step-explanation :
Electric resistance
Dimension length :
Squared mass per time cubed , that is , electric current squared.
The SI derived unit of electric resistance is the ohm,(volt per ampere).
A race is held between a sports car and a motorcycle. The sports car can accelerate at 5.0 m/s^2 and the motorcycle can accelerate at 8.0 m/s^2. The two vehicles start the race at the same time and accelerate from rest. After 5.0 s, how fast is the sports car going? After 6.0 s, how distance will the motorcycle have gone? To make the race fair, the sports car starts 50.0 m ahead of the motorcycle. If the course is 200.0 m long, which vehicle wins the race?
Answer:
Vf₁ = 30 m/s
s₂ = 90 m
car wins the race.
Explanation:
To find the speed of car after 5 s, we use 1st equation of motion:
Vf₁ = Vi₁ + a₁t₁
where,
Vf₁ = Final Speed of Car = ?
Vi₁ = Initial Speed of Car = 0 m/s
a₁ = acceleration of car = 5 m/s²
t₁ = time = 5 s
Therefore,
Vf₁ = 0 m/s + (5 m/s²)(5 s)
Vf₁ = 25 m/s
To find the distance of motorcycle after 6 s, we use 2nd equation of motion:
s₂ = Vi₂ t₂ + (1/2)a₂t₂²
where,
s₂ = distance covered by the motorcycle = ?
Vi₁ = Initial Speed of motorcycle = 0 m/s
a₂ = acceleration of motorcycle = 8 m/s²
t₂ = time = 6 s
Therefore,
s₂ = (0 m/s)(6 s) + (1/2)(5 m/s²)(6 s)²
s₂ = 90 m
We can use 2nd equation of motion to find time taken by each car and motorcycle to reach the finish point:
For Car:
s₁ = Vi₁ t₁ + (1/2)a₁t₁²
where,
s₁ = 200 m - 50 m = 150 m (since, car starts 50 m ahead)
Therefore.
150 m = (0 m/s)(t₁) + (1/2)(5 m/s²)t₁²
t₁ = √60 s²
t₁ = 7.74 s
For Motorcycle:
s₂ = Vi₂ t₂ + (1/2)a₂t₂²
where,
s₁ = 200 m
Therefore.
200 m = (0 m/s)(t₂) + (1/2)(5 m/s²)t₂²
t₂ = √80 s²
t₂ = 8.94 s
Since, the car takes less time to reach finish line.
Therefore, car wins the race.
