A balloon is launched straight upward and has a hang time of 14 s. (wow)
A.) What was the launching velocity of the balloon?
B.) How high did the balloon travel?
C.) How far did the balloon travel between t = 3 and t = 4 s?

Answers

Answer 1

Answer:

A) Vo = 137.34 [m/s]

B) Y = 961.38 [m]

C) y = 367.8[m] for t = 3 [s] and y = 470.88[m] for t = 4[s]

Explanation:

To solve this problem we must use the following equation of kinematics. We must keep in mind that the negative sign of the equation means that the acceleration of gravity acts in the opposite direction to the movement of the balloon.

A)

[tex]v_{f} =v_{o} -g*t[/tex]

where:

Vf = final velocity = 0 (the maximum hang time, maximum elevation)

Vo = initial velocity [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time = 14 [s]

0 = Vo - (9,81*14)

Vo = 137.34 [m/s]

B)

Now we use the following equation.

[tex]y=y_{o}+v_{o} *t -(\frac{1}{2} )*g*t^{2}[/tex]

where:

Yo = initial position = 0

Y = final position [m]

Vo = initial velocity = 137.34 [m/s]

Now replacing

Y = (137.34*14) - (0.5*9.81*14²)

Y = 961.38 [m]

C)

With the above equation, we can calculate the distances between t = 3 and t = 4 [s]

[tex]y=y_{o} +v_{o} *t - (1/2)*g*t^{2}[/tex]

y = (137.34*3) - (0.5*9.81*3²)

y = 367.8[m] for t = 3 [s]

for t = 4[s]

y =  (137.34*4) - (0.5*9.81*4²)

y = 470.88[m]


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Answer:

We show added energy to a system as +Q or -W

Explanation:

The first law of thermodynamics states that, in an isolated system, energy can neither be created nor be destroyed;

Energy is added to the internal energy of a system as either work energy or heat energy as follows;

ΔU = Q - W

Therefore, when energy is added as heat energy to a system, we show the energy as positive Q (+Q), when energy is added to the system in the form of work, we show the energy as minus W (-W).

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The unit of the electric resistance is ???​

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Ohms

Step-by-step-explanation :

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Squared mass per time cubed , that is , electric current squared.

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Answer:

....................

What force is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25?

Answers

Answer:

Any force greater than 24.5 N

Explanation:

To find the frictional force is the 1st step. this can be found by multiplying the coefficient of friction and the normal force. normal force can be found by multiplying gravity (we will say 9.8 m/s/s) and the mass which is 10. You then multiply the result by the coefficient of friction which is 0.25 and it leads us to an answer to 24.5 N. This means that if you pull with exactly 24.5 N, the sled wouldnt move. So you need a force greater than 24.5 N and we have our answer.

I hope I helped correct me if im wrong

A force of 25 N is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25.

First, we will calculate the normal force (N), which, in a horizontal surface, has the same magnitude and opposite sense as the weight (W) of the sled.

[tex]|N| = |W| = m \times g = 10 kg \times \frac{9.8m}{s^{2} } = 98 N[/tex]

where,

m: mass of the sledg: Earth's gravity

Then, we will calculate the friction force (f) using the following expression.

[tex]f = \mu \times N = 0.25 \times 98 N = 25 N[/tex]

According to Newton's first law of motion, for the sled to move at a constant velocity, the sum of the force exerted (F) on the sled and the friction force (f) must be zero.

[tex]F + f = 0\\F = -f\\F = -25 N\\|F| = 25 N[/tex]

A force of 25 N is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25.

You can learn more about friction here: https://brainly.com/question/18754989

All elements are composed of extremely small particles called

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Answers

Answer:

it was given the name Newton (N). from this, the derived unit of energy (or work) is defined ,as the work produced when the unit of force causes a displacement equal to the unit of length of its point of application along its direction . It was given the name Joule (J).

Explanation:

Suppose an object has a velocity of -7 m/s at t=0. What will the velocity be after 4 seconds if the acceleration of the object is +1 m/s^2?

Answers

Answer:

Vf = - 3 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f} =v_{o} +a*t[/tex]

where:

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Vo = initial velocity = - 7 [m/s]

a = acceleration = 1 [m/s²]

t = time = 4[s]

Now replacing:

Vf = -7 + (1*4)

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Is it possible to generate emf without rotating the coil explain

Answers

Answer:

It's not possible.

Explanation:

It's not possible.

This is because when a coil is rotated in a magnetic field about a line which is not the axis of the coil, the magnetic coil with a link going through the coil will change and thus an EMF will be produced.

Now, this EMF produced is gotten as a result of cutting action through lines of magnetic flux gotten through rotation (physical movement) of the coil through space.

Faraday's law allows finding the result for whether it is possible to create induced electromotive force (emf) without rotating the coil are:  

Producing a pulsating voltage is possible change the magnetic field the area of ​​the loop. Producing constant voltage is not possible since a uniform change of some parameter is required and the only one that can change is the angle constantly.

Faraday's Law states that by varying the magnetic flux an electromotive force is produced.

           [tex]emf = - \frac{d \Phi_B }{dt} \\\Phi_B = B . A[/tex]

Where emf is the induced voltage, Ф the magnetic flux, B the magnetic field and A the area of ​​the loop

We can write the flow explicitly.

          Ф =  B A cos θ.

Therefore we see that there is some form of having this changing flow:

Changing the magnitude of the magnetic field. Changing the area of ​​the loop. Changing the angle between the normal to the area and the magnetic field direction.

The first two methods are used in pulsating fields, that is, a voltage is obtained for a short period of time.

The last method is used in equipment that can give indicated voltage in a constant way, it is the method used to produce electricity, it consists of an external system that rotates the loop with a constant speed and produces an output voltage.

In conclusion using Faraday's law we can find the result for whether it is possible to create induced electromotive force (emf) without rotating the coil are:  

Producing a pulsating voltage is possible change the magnetic field the area of ​​the loop Producing constant voltage is not possible since a uniform change of some parameter is required and the only one that can change is the angle constantly.

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Explanation:

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Hope this helped, Have a Great Day!!

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