Question:
A ball has a 17 J of kinetic energy and lB mechanical energy is 25 Joule
a. Find the gravitational potential energy of the ball.
b. if the ball has a mass of 3.2 kg, what is its height above the ground?
c. What is the speed of the ball?
Answer:
a. = 85
b. h = 0.25 m
c. = 3.26 m/s
Explanation:
Part A
PEgrav = m ו g • h
In the above equation, m represents the mass of the object, h represents the height of the object and g represents the gravitational field strength (9.8 N/kg on Earth) - sometimes referred to as the acceleration of gravity. So, to find:
GPE = ME - KE = 25 - 17 = 85
Part B
The formula simplifies to: h max = h + V₀² / (2 × g) and the time of flight is the longest.
The vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.
The equation may be written as:
GPE = mgh
8 = 3.2 × 10 × h
h = 0.25 m
Part C
The ball speed is calculated by dividing the distance by the time. If the time was 3 seconds, the average speed will be 60/3 = 20 feet per second (6.1 m/sec). KE = 1/2 MV²
17 = 1/2 × 3.2 x V²
V = 17 ÷ 1.6
Note, this is only the average ball speed, the speed of the ball at the time of release would be greater.
A 5 kg object experiences a horizontal force, which
causes it to accelerate at 2 m/s2, moving it a distance of
10 m horizontally. How much work is done by the force
on the object?
Answer:
The work is done by the force 100 NM.
Explanation:
=5kg * 2 m/s^2
=5* 2 N (kg*m/s^2=N)
=10N
Work done = force* distance
=10N* 10
= 100 NM
For an object of mass 5 kg accelerating at the rate of 2 m/s², then the work done by the force on the object will be 100 Nm.
What is Work?In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.
The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.
As per the given information in the question,
Mass of the object, m = 5 kg
Acceleration, a = 2 m/s²
Distance, d = 10 m
W = f × d
W = m × a × d
W = 5 × 2 × 10
W = 100 Nm
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What force can be seen when North Pole is brought near to South Pole
Answer:
Explanation:
The answer is magnetic force
Answer:
Magnetic forces which causes attraction between the two poles
PLEASE HELP ASAP
Dry ice changes state directly from a solid to a gas at room temperature, in a process called sublimation. What does sublimation demonstrate?
Answer:
changing from a solid to a gas without changing into a liquid. :)
What variables must be known to determine the observed frequency of a wave?
Answer:
The frequency, 'f', of a wave is given by the speed, 'v' of the wave and the wavelength, λ, of the wave
f = v/λ
The frequency, 'f', of a wave is also given by the inverse of the period, 'T', of the wave which is the time it takes the wave to complete an oscillation or a cycle
f 1/T
Therefore, the variables to be known to determine the frequency of a wave includes either, the velocity and the wavelength of the wave or the period of oscillation (the wave cycle) of the wave
Explanation:
A stone is thrown horizontally from a 50m high cliff with an initial speed of 15 meters per second. How far will the stone have travelled from the cliff when it strikes the ground?
a. 45.92m/s
b. 47.85 m
c. 58.2 seconds
d. 35.85 m/s/s
This is a classic case of 'velocity components.'
Imagine a vector for velocity. Now, consider that this vector could be the hypotenuse of a right triangle, with two other sides going along the x and y-axis. These sides of the triangle will have values, and adding them up using the pythagorean theorem will prove that the sum of their squares equals the square of the original vector.
Well, okay, that's nice and all, you may be saying - but how do we solve the actual question?
Let's apply this thought to the question. This vector can have both an x component and y component (essentially, parts of the vector that travel along the x and y-axis).
Now, what could these components be? We know that the stone is thrown perfectly horizontally, meaning that the x-component is quite literally the velocity.
How about the y-component? Since it's thrown at a perfect horizontal, there isn't really any vertical velocity whatsoever. There's only horizontal velocity.
"Great, fantastic! So, what's the importance of figuring out the horizontal and vertical velocities?"
When a stone is in free fall, it experiences a gravitational acceleration. This acceleration from gravity, though, only affects the vertical velocity. Since gravity is vertical as well, it's essentially impossible for the horizontal velocity to be changed at all.
This means that to solve the horizontal distance, we simply need to find the time it takes for the rock to hit the ground and multiply said time by the horizontal velocity.
Since the vertical velocity is the only thing changed by gravity, we can write out an equation that can solve for the time:
∆Y = [tex]v_{i}[/tex]t + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]
We know that initial vertical velocity is zero, so:
∆Y = [tex]v_{i}[/tex]t + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]
∆Y = 0t + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]
∆Y = [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]
We need to solve for t, so let's isolate the variable. Multiply both sides by 2 to get rid of the fraction:
∆Y * 2 = [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex] * 2
2∆Y = g[tex]t^{2}[/tex]
Divide both sides by g:
(2∆Y)/g = [tex]\frac{gt^{2} }{g}[/tex]
Square root both sides:
[tex]\sqrt{(2Y)/g}[/tex] = [tex]\sqrt{t^{2} }[/tex]
t = [tex]\sqrt{(2Y)/g}[/tex]
Input our values for Y and g (Y is the height of the cliff, and g is gravitational acceleration):
t = [tex]\sqrt{(2*50)/9.80}[/tex]
Solve:
t = [tex]\sqrt{(2*50)/9.80}[/tex]
t = 3.194 (s)
Whew! That was a lot of steps to find the time! Now that we have the time, we can find the horizontal distance the rock travels:
∆x = [tex]v_{i}[/tex]t + [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]
The horizontal velocity has no acceleration (gravity is vertical!), so:
∆x = [tex]v_{i}[/tex]t + [tex]\frac{1}{2}[/tex]*0*[tex]t^{2}[/tex]
∆x = [tex]v_{i}[/tex]t
The horizontal velocity is 15 m/s, and the time is 3.194:
∆x = [tex]v_{i}[/tex]t
∆x = 15 * 3.194
∆x = 47.91 (m)
Since we rounded the time, it makes sense that our final answer's a little bit off to the options. The closest one is option B, which is only 0.6m off, a tiny difference that may have come from the test maker's use of '10 m/[tex]s^{2}[/tex]' as the gravitational acceleration (while we stayed as accurate as possible with 9.80) as well as our rounding of the final time.
Option B, the stone will have travelled 47.85 meters.
If you have any questions on how I got to the answer or if you're still confused on any topic I attempted to explain, just ask in the comments and I'll try to answer it to the best of my ability! Good luck!
- breezyツ
please see the picture
Answer:
t.f. are you sure that's english? it looks like not a real thing
Explanation:
Which would take more force to stop in 10 seconds: an 8.0-kilogram ball rolling in a straight line at a speed of 0.2 m/sec or a 5.0-kilogram ball rolling along the same path at a speed of 1.0 m/sec?
Answer:
Higher force would be required to stop 5 kg of ball
Explanation:
The force required to stop a moving object depends on its momentum.
The momentum for 8 kg of rolling ball is = 8 kg * 0.2 m/s = 1.6 kgm/s
The momentum for 5 kg of rolling ball is = 8 kg * 1.0 m/s = 5 kgm/s
Hence, momentum of 5 Kg ball is higher than the momentum of 8 Kg of ball
Hence, higher force would be required to stop 5 kg of ball
which are the upthrust forces?
Explanation:
An object that is partly or completely submerged experiences a greater pressure on its bottom surface than on its top.
Answer:
upthrust force is an upward force exerted by a fluid that opposes the weight of a partially or fully immersed object
A 1.2 kg block is held at rest against the spring with a force constant k= 730 N/m. Initially, the spring is compressed a distance d. When the block is released, it slides across a surface that is frictionless except for a rough patch of width 5.0 cm that has a coefficient of kinetic friction = 0.44. Find d, such that the block's speed after crossing the rough patch is 2.3 m/s.
Answer:
Compression distance: [tex]d \approx 0.102\,m[/tex]
Explanation:
According to this statement, we know that system is non-conservative due to the rough patch. By Principle of Energy Conservation and Work-Energy Theorem, we have the following expression that represents the system having a translational kinetic energy ([tex]K[/tex]), in joules, at the expense of elastic potential energy ([tex]U[/tex]), in joules, and overcoming work losses due to friction ([tex]W_{l}[/tex]), in joules:
[tex]K + W_{l} = U[/tex] (1)
By definitions of translational kinetic and elastic potential energies and work losses due to friction, we expand the equation described above:
[tex]\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2} \cdot k \cdot d^{2}[/tex] (2)
Where:
[tex]m[/tex] - Mass of the block, in kilograms.
[tex]v[/tex] - Final velocity of the block, in meters per second.
[tex]\mu[/tex] - KInetic coefficient of friction, no unit.
[tex]g[/tex] - Gravitational acceleration, in meters per square second.
[tex]s[/tex] - Width of the rough patch, in meters.
[tex]k[/tex] - Spring constant, in newtons per meter.
[tex]d[/tex] - Compression distance, in meters.
If we know that [tex]m = 1.2\,kg[/tex], [tex]v = 2.3\,\frac{m}{s}[/tex], [tex]\mu = 0.44[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]s = 0.05\,m[/tex] and [tex]k = 730\,\frac{N}{m}[/tex], then the compression distance of the spring is:
[tex]\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2} \cdot k \cdot d^{2}[/tex]
[tex]m\cdot v^{2} + 2\cdot m\cdot g \cdot s = k\cdot d^{2}[/tex]
[tex]d = \sqrt{\frac{m\cdot (v^{2}+2\cdot g\cdot s)}{k} }[/tex]
[tex]d \approx 0.102\,m[/tex]
Once a player has stopped dribbling, how many steps are they allowed to take at maximum?
Answer:
2 steps
Explanation:
:)
this makes basketball interesting
Answer:
2 steps tops. If it is more that is called "traveling".
Explanation:
state the Newton's law of cooling
Explanation:
Newton's law of cooling (or heating) states that the temperature of a body changes at a rate proportional to the difference in temperature between the body and its surroundings. It is a reasonably accurate approximation in some circumstances. dTdt=−k(T−T0), where k is a positive constant.
Answer:
Q=h.A.(T(t)-Tenu)
Explanation:
10) Challenge: A student is pushing a 50 kg cart, with a force of 600 N. Another student measures the speed
of the cart, and finds that the cart is only accelerating at 3 m/s2. How lar is the force pushing back on the car?
Hint: Draw a diagram showing the cart, and the two forces acting on it.
The explanation is shown in the picture. Hope it helps!
Edit: where I wrote "m/s" , I should have wrote m/s^2
Please help....
Genetics Practice Problems
1. AA = HoD Ee = He Ii = He Mm = He
Bb = He ff = HoR Jj = He nn = HoR Cc = He
GG = HoD kk = HoR OO = HoD Dd = He
HH = HoD Ll = He Pp = He
Which is the graph of the polar equation r = 4 cos3 theta
Answer:
B
Explanation:
The correct answer is B on edge
(Looks like a flower with 3 petals with the most right petal covering the x-axis.)
Answer: Just pray for me, thank you.
4.3.11 QC
100% correct
1. Use the image to answer the question.
Select the equation that represents the graph.
Which table best represents the graph of the equation θ = 45°
Answers:
1. r= 4 which is C
2. A table
3. D (4.24, pi/4)
4. D Radius 1 and center (1,0)
5. B symmetrical about the vertical axis
Explanation: I did it!
Which of the following statements correctly describes sound waves? Select all that apply.
a) Sound waves travel as transverse waves.
b)Sound waves travel as longitudinal waves.
c)Sound waves travel at a speed of 3×108 m/s.
d)Sound waves can travel through the vacuum of space.
e)Sound waves typically move faster through solids than gases.
Answer:
a
Explanation:
transverse waves travel at a right angle to the direction of the wave motion and the examples of transverse waves are water waves and radio waves of which radio produces sound.
Answer:
The correct option is A.
Sound waves travel as transverse waves.
Explanation:
Sound waves is a type of compression or mechanical vibrations that travel through a medium such as water, air and the energy of the medium through which it's travel cause the vibrations.
Sound travel as transverse waves because it move through a right angle direction of the wave movement and it travel through a medium such as air.
Example include Radio waves and water waves.
Therefore, Sound waves travel as transverse waves.
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DNA ___ occurs during the s phase of Interphase.
A. division
B. modification
C. replication
D. multiplication
Answer:
c
Explanation:
Answer:
c
Explanation:
the DNA replication happens in the s phase of interphase
The diagram shows how Earth is tilted on its axis as it revolves around the Sun. What is the season in the United States when Earth is in position C
Winter
It is winter because the Northern Hemisphere is not facing the sun.
In which direction is the magnetic field in the center of the solenoid?
Answer:direction A
Explanation:
Took test
The direction is the magnetic field in the center of the solenoid will be towards A. The direction of the magnetic field is toward the A.
What is a solenoid?A coil of wire that carries an electric current is a solenoid. A solenoid is an electromagnet formed by a helical coil of wire. Which generates a magnetic field when an electric current is passed through the coil .
A solenoid is a form of coil that produces a magnetic field when the electric current is passed through it. A solenoid is created when a conductive wire is used to make a loop.
Use your understanding of the magnetic field's form to determine the direction of the magnetic field along the middle of the solenoid.
Because the current wraps around the core of the solenoid in this scenario, it may be controlled with your fingertips. It goes with your thumb since the magnetic field is straight down the inside.
To learn more about the solenoid, refer to the link ;
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A 97.3 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.67 rad/s . A monkey drops a 9.67 kg bunch of bananas vertically onto the platform. They hit the platform at 45 of its radius from the center, adhere to it there, and continue to rotate with it. Then the monkey, with a mass of 21.9 kg , drops vertically to the edge of the platform, grasps it, and continues to rotate with the platform. Find the angular velocity of the platform with its load. Model the platform as a disk of radius 1.73 m
Answer:
w = 1.14 rad / s
Explanation:
This is an angular momentum exercise. Let's define a system formed by the three bodies, the platform, the bananas and the monkey, in such a way that the torques during the collision have been internal and the angular momentum is preserved.
Initial instant. The platform alone
L₀ = I w₀
Final moment. When the bananas are on the shelf
we approximate the bananas as a point load and the distance is indicated
x = 0.45m
L_f = (m x² + I ) w₁
angular momentum is conserved
L₀ = L_f
I w₀ = (m x² + I) w₁
w₁ = [tex]\frac{I}{m x^2 + I} \ w_o[/tex]
Let's repeat for the platform with the bananas and the monkey is the one that falls for x₂ = 1.73 m
initial instant. The platform and bananas alone
L₀ = I₁ w₁
I₁ = (m x² + I)
final instant. After the crash
L_f = I w
L_f = (I₁ + M x₂²) w
the moment is preserved
L₀ = L_f
(m x² + I) w₁ = ((m x² + I) + M x₂²) w
(m x² + I) w₁ = (I + m x² + M x₂²) w
we substitute
w = [tex]\frac{m x^2 +I}{I + m x^2 + M x_2^2} \ \frac{I}{m x^2 + I} \ w_o[/tex]
w = [tex]\frac{I}{I + m x^2 + M x_2^2} \ w_o[/tex]
the moment of inertia of a circular disk is
I = ½ m_p x₂²
we substitute
w = [tex]\frac{ \frac{1}{2} m_p x_2^2 }{ \frac{1}{2} m_p x_2^2 + M x_2^2 + m x^2} \ \ w_o[/tex]
let's calculate
w =[tex]\frac{ \frac{1}{2} \ 97.3 \ 1.73^2 }{ \frac{1}{2} \ 97.3 \ 1.73^2 + 21.9 \ 1.73^2 + 9.67 \ 0.45^2 } \ \ 1.67[/tex]
w = [tex]\frac{145.60 }{145.60 \ + 65.54 \ + 1.958} \ \ 1.67[/tex]
w = 1.14 rad / s
What do you call the material or "stuff" that a wave travels through
A medium
B wave
C decibel
D doppler
The expansion of a liquid is _____ than a solid
A. less
B. greater
Answer:
B.Greater
Explanation:
Smack that thanks button pleasee.
3) El motor de una moto le imprime una velocidad de 90 km/h al aplicar sobre ella una fuerza de 240 N. ¿Cuál es la potencia de la moto en vatios?
Answer:
P = 6000 W
Explanation:
The given question is "The motor of a motorcycle gives it a speed of 90 km / h when a force of 240 N is applied to it. What is the power of the motorcycle in watts?"
Given that,
Speed of a motorcycle, v = 90 km/h = 25 m/s
Force applied to the motorcycle, F = 240 N
We need to find the power of the motorcycle. We know that,
Power = Fv
So,
P = 240 N × 25 m/s
= 6000 W
So, the required power of the motorcycle is equal to 6000 W.
Out in the ocean, a wave crest 3.2 m high meets a wave trough from another direction which is 2.6 m deep. How high is the resulting wave??
Answer:
Height of resulting wave = 0.6 meters
Explanation:
Let the higher wave (wave crest) be A while the lower wave (wave trough) be B.
Given the following data;
A = 3.2m
B = 2.6m
To find the height of the resulting wave;
Height = A + B
But the lower wave becomes negative because it is below i.e on the lower trough.
Height = 3.2 + (-2.6)
Height = 3.2 - 2.6
Height of resulting wave = 0.6 meters
Explain why gases are more compressible than solid
Answer:
If we put pressure on a solid or a liquid, there is essentially no change in volume. ... The kinetic-molecular theory explains why gases are more compressible than either liquids or solids. Gases are compressible because most of the volume of a gas is composed of the large amounts of empty space between the gas particles.
Explanation:
This is the molecule in cells that forms part of the protein.
A. rRNA
B. mRNA
C .tRNA
D. DNA
According to the graph, how much Potassium bromide can be dissolved in 100 g of warer at 40C?
Answer:
77.8 g potassium bromide can be dissolved in 100 grams of water at 40°C.
Explanation:
In a given a line of KBr is straight.
A certain fm radio wave has a frequency of 1.31*10^8 he given that radio waves travel at 2.99*10^8 m/s what is the wavelength of this fm radio wave
Answer:
The answer is "[tex]3.92 \times 10^{16} \ m[/tex]"
Explanation:
Given:
[tex]\to v= 1.31 \times 10^8 \\\\\\to f=2.99\times 10^8 \ \frac{m}{s}\\\\[/tex]
Using formula:
[tex]\lambda=vf\\\\[/tex]
[tex]=2.99\times 10^8 \times 1.31\times 10^8\\\\=2.99\times 1.31\times 10^{16}\\\\=3.9169 \times 10^{16} \ m[/tex]
[tex]=3.92 \times 10^{16} \ m[/tex]
A runner slows down after completing works her deceleration is 0.25m/s after 5 sec she is traveling at 4m/s determine her initial velocity
Answer:
vi = 5.25 m/s
Explanation:
We can determine the initial velocity of the runner by using the first equation of motion, as follows:
[tex]v_f = v_i + at\\[/tex]
where,
vf = final speed of the runner = 4 m/s
vi = initial speed of the runner = ?
a = deceleration of the runner = - 0.25 m/s²
t = time taken = 5 s
Therefore,
[tex]4\ m/s = v_i + (-0.25\ m/s^2)(5\ s)\\v_i = 4\ m/s + 1.25\ m/s\\[/tex]
vi = 5.25 m/s
AWARDING BRAINLIEST (～￣▽￣)～
The thread around a screw is a lever.
Please select the best answer from the choices provided
T
F
The magnetic field at point P due to a 2.0-A current flowing in a long, straight, thin wire is 8.0 μT. How far is point P from the wire?
Answer:
r = 0.05 m = 5 cm
Explanation:
Applying ampere's law to the wire, we get:
[tex]B = \frac{\mu_oI}{2\pi r}\\\\r = \frac{\mu_oI}{2\pi B}[/tex]
where,
r = distance of point P from wire = ?
μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²
I = current = 2 A
B = Magnetic Field = 8 μT = 8 x 10⁻⁶ T
Therefore,
[tex]r = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(2\ A)}{2\pi(8\ x\ 10^{-6}\ T)}\\\\[/tex]
r = 0.05 m = 5 cm
