A 10-cm long pencil is placed upright 50 cm from a concave mirror with focal length 0.50 m. What will be
the characteristics of any image that is formed?

Answers

Answer 1

A virtual and erect image is formed by concave mirror.

What is focal length?

The focal length of the mirror is the distance between the lens and the image sensor.

It is also defined as the distance from a lens or mirror to the focal point.

It is also stated by the formula

[tex]\frac{1}{y} +\frac{1}{u} = \frac{1}{f}[/tex]

u = -50 cm and f = 0.50 m (50cm)

[tex]\frac{1}{v} +\frac{1}{-50} =\frac{1}{50}[/tex]

v= -50 cm

where - sign shows that image is virtual.

Magnification  m= [tex]\frac{v}{u}[/tex]

m = -50/50

m = 0

hence, virtual and erect image will be formed.

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Related Questions

If you separate vector B into its components. How many components will it have? Those components will be called?

Answers

The vector B will have two components and those components will be called resultant vectors.

What is a component vector?

A component vector is a unit vector that represents a given vector in a particular direction.

A vector can be represented in x - direction and y - direction.

x - component of the vector = Bcosθy - component of the vector = Bsinθ

Thus, the vector B will have two components and those components will be called resultant vectors.

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Refer to the attached image!!!​

Answers

The time of motion of the track star is determined as 0.837 s.

Time of motion of the track star

The time of motion of the track star is calculated as follows;

T = (2u sinθ)/g

where;

T is time of motiong is acceleration due to gravityθ is angle of projection

T = (2 x 12 x sin20)/9.8

T = 0.837 s

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Against the park ranger's advice, a visitor at a national park throws a stone horizontally off the edge of a 83 m high cliff and it lands a distance of 93 m from the edge of the cliff, narrowly missing a visitor below.
What was the initial horizontal velocity of the rock, in m/s? You can round your answer to the hundredths place and use g ≈ 10 m/s2.

Answers

Answer:

20.37m/s

Explanation:

For this problem, we'll need a basic kinematic equation for both directions


Vertical direction:

[tex]y(t)=\frac{1}{2}a_{y}t^{2}+v_{o_y}t+y_{o}[/tex]

Knowing that the acceleration in the y-direction is due to gravity, and is constant near the surface of the Earth, where the rock is being thrown, we get [tex]a_{y}=g=-10m/s^{2}[/tex].  We're also given that the initial vertical height is 83m, so [tex]y_o=83m[/tex].  Additionally, we're given that the stone is thrown horizontally, and thus initially, it has no vertical velocity.  Only velocity in the x-direction.  Thus, [tex]v_{o_y}=0m/s[/tex].  Substituting known values into our equation:

[tex]y(t)=\frac{1}{2}(-10)t^{2}+(0)t+(83)[/tex]

[tex]y(t)=-5t^{2}+83[/tex]

This equation is true for all times until the acceleration changes (isn't constant... i.e. when it hits the ground).

What now?

We want to find the specific time when it does hit the ground.  Why?  Because this is the point in time where we know some extra information about what is happening in the x direction, and that will help us deal with the x-direction equation.  

When the stone does hit the ground, the output of this function (measuring the height of the stone) is zero, which leaves only one unknown value, t... the time associated with that y:  the time that it takes to hit the ground:

[tex]0=-5(t_{ground})^{2}+83\\-83=-5(t_{ground})^{2}\\\frac{-83}{-5}=(t_{ground})^{2}\\16.6=(t_{ground})^{2}\\\sqrt{16.6}=\sqrt{(t_{ground})^2}\\4.074309757seconds=t_{ground}[/tex]

Again, this is the time that the stone hits the ground.  Knowing how special this time is, one might give it a special subscript to keep track of it.  

[tex]t_{ground}=4.074309757seconds[/tex]

Horizontal direction

Reusing the basic kinematic equation for the horizontal direction:

[tex]x(t)=\frac{1}{2}a_{x}t^{2}+v_{o_x}t+x_{o}[/tex]

Note that in the horizontal direction, there is no acceleration (after the rock is released), so [tex]a_{x}=0[/tex].  Also, if we define the base of the cliff as our origin, then at the top of the cliff where the rock is released, the initial x-position is still zero, aka, [tex]x_{o}=0[/tex]

[tex]x(t)=\frac{1}{2}(0)t^{2}+v_{o_x}t+(0)\\x(t)=v_{o_x}t[/tex]

While we don't know the initial horizontal velocity, we do know an output of the function for one specific input... we know that when the stone hits the ground, that the stone's horizontal distance is 93m from the cliff.  So, if we input [tex]t_{ground}[/tex] into this function, it will give an output of 93.  The only remaining unknown is the initial velocity in the x direction.  One equation, one unknown, we can solve this:

[tex]x(t_{ground})=v_{o_x}t_{ground}\\83=v_{o_x}(4.074309757)\\\frac{83}{4.074309757} =v_{o_x}\\20.37154879m/s =v_{o_x}\\[/tex]

If there were a component of initial velocity in the y direction, we would need to use the Pythagorean theorem to combine them.  However, as the initial y component of velocity is zero, the initial velocity is simply the initial x velocity.

Paying attention to directions, round to the answer to the nearest hundredth:

[tex]20.37m/s =v_{o}\\[/tex]

it is easier to drag a stone than to kick it for the same distance. why​

Answers

Answer:

it is easier to kick a stone than to drag a stone.

Explanation:

the science behind the question is fairly simple.

when you kick and object for say a (rock) you have inertia which is made from you clocking your leg back and swinging it full force forward. when you kick with inertia, you will have a much further travel distance of the object rather than dragging it which is almost set at a certain rate of how fast you are moving (m) and how much inertia you are using by pulling (p)

so m+p=i for inertia. hope this  helped

A downward force of magnitude 5 n is exerted on the book by the force of.

Answers

Answer:

A downward force of magnitude 5 N is exerted on the book by the force of ... Do the downward force in Part A (gravity) and the upward force in Part B ...

Newton's second law of motion states that Choose one: A. the force of gravity is proportional to the masses of the two objects and the inverse of the square of the distance. B. the acceleration of an object is proportional to the net force acting on it. C. objects have inertia. D. every action has an equal and opposite reaction.

Answers

Answer:

B

Explanation:

two examples of hydraulic brake​

Answers

Answer:

1). Brake pedal or lever

2). A pushrod also called an actuating rod

Question 1 of 10
What is the magnitude of the vector described below?
"13 m/s to the east"
A. Meters per second
B. Meters
C. East
D. 13 m/s

Answers

Answer:

D

Explanation:

The magnitude is 13 m/s

   the direction is east    the   units  are  m/s

Type the correct answer in each box. Round your answers to the nearest hundredth.
An illustration depicts a ball tied with a rope and hanged at a position labeled A. The ball is then pulled to a position labeled B with a height of 0 point 5 meters.
A ball with a mass of 1.5 kilograms is tied to the end of a rope. The ball is pulled to a height of 0.5 meters above the ground and released.
The ball has
joules of potential energy at position B. At position A, all of the energy changes to kinetic energy. The velocity of the ball at position A is
meters/second. Assume there’s no air resistance. Use g = 9.8 m/s2 , PE = m × g × h, and .

Answers

The velocity of the ball at position A is 3.13 m/s.Since all energy is converted to KE.

What is potential energy?

The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule.

A person has the most potential energy due to her position. when he is sitting on the highest point.

Given data;

Mass,m = .5 kg

Height,H = 0.5 m

Acceleration due to gravity,g = 9.8 m/s²

H is the height

The potential energy is found as;

The potential energy is mainly dependent upon the height of the object.

Potential energy = mgh

The potential energy at point B;

PE = mgh

PE = ( 1.5 kg) ( 9.8 m/s2) (0.5 m)

PE = 7.35 J

Since all energy is converted to KE, the kinetic energy at point B;

KE = 0.5mv^2

KE = PE

7.35 = 0.53(1.5) v^2

V = 3.13 m/s

Hence, the velocity of the ball at position A is 3.13 m/s.

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2) A ball is thrown forward horizontally from the top of a cliff
with a velocity of 10m/s as shown in the figure below. The
height of the cliff above the ground is 4.5m. Calculate
0218
R
i for position coordinates p(x, y), prove that the path of
horizontal projectile is parabolic.
[3]
ii. the time to reach the ground
[1]
iii. the distance from the cliff of the ball on hitting the ground [1]
iv. the velocity with which the ball hits the ground
[2]
v. the direction of the ball to the horizontal just before it hits the
ground.
[1]

Answers

(i) For position coordinates p(x, y),  the path of horizontal projectile is parabolic.

(ii)  The time to reach the ground is 0.96 s.

(iii) The distance from the cliff of the ball on hitting the ground is 9.6 m.

(iv) The velocity with which the ball hits the ground is 9.4 m/s.

(v) The direction of the ball to the horizontal just before it hits the

ground is 90 degrees.

What is projectile?

When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion.

Given is a ball is thrown forward horizontally from the top of a cliff

with a velocity of 10m/s.  The height of the cliff above the ground is 4.5m.

(i) The equation formed by the ball is at point (x,y) given by

y =yo + Voy x t - 1/2gx²

The equation is in the form of parabola.

Thus, the ball follows parabolic path.

(ii) The time to reach the ground is

t = √2h/g

t =  √(2x 4.5)/9.81

t= 0.96 s

iii) Horizontal distance traveled

R = u x t

R = 10 x 0.96

R = 9.6 m

Thus, the distance from the cliff of the ball on hitting the ground is 9.6 m.

(iv) The velocity with which the ball hits the ground.

v = √2gh

Plug the values, we get

v = √(2 x 9.81 x 4.5)

v = 9.4 m/s

(v) The direction of the ball to the horizontal will be 90 degrees just before it hits the ground.

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If m = 2,000, p = 2. 25, and y= 6,000, what is velocity?

Answers

The velocity is 6.75



The velocity in the equation stated above can be calculated as follows

m= 2,000
p= 2.25

y= 6000

velocity= 2.25 × 6000/ 2000
= 13500/2000
= 6.75


Hence the velocity is 6.75

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Find the momentum of a body of mass 5kg moving with velocity of 4.5m/s

Answers

Momentum= mass × velocity

momentum= P

P= m×v

P= 5×4.5

P=22.5

I hope this helps.

this stationary wave is what we call the first harmonic of the first normal mode of the system. in units of l, the length of the wire, what is λ1, the wavelength of the first harmonic?

Answers

The wavelength of the first harmonic of the standing wave is 2L.

What is a standing wave?

A standing wave is one in which the obvious points remain fixed as the vibration continues. A standing wave occurs in a wind instrument such as a trumpet, saxophone etc.

We know from  the formula of the first harmonic that the wavelength of the first harmonic of the standing wave is 2L.

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4. T or F X-rays, ultraviolet light, and gamma rays all can travel through interplanetary space, so they are examples of waves.
5. What happens to the amplitude of water waves as you get farther from the disturbance that caused them? Why?

Answers

4. The X-rays, ultraviolet light, and gamma rays all can travel through interplanetary space, so they are examples of waves is a False.

5. The amplitude of water waves as you get farther from the disturbance that caused them decreases.

What is electromagnetic spectrum?

The electromagnetic spectrum consists of the range of all types of EM radiation. Radiation is packet of energy that travels and spreads out. It has radio waves, infrared waves, visible light waves, ultraviolet rays and microwaves.

They possess high energy even to penetrate deep within the material. The electromagnetic spectrum has longer wavelength and less frequency.

4. The Earth's environment is thick an adequate number of that for all intents and purposes no X-beams can come through from space the entire way to the Earth's surface. This is great as far as we're concerned yet in addition terrible for stargazing. We need to put X-beam telescopes and identifiers on satellites.

Thus, X-rays, ultraviolet light, and gamma rays all can travel through interplanetary space, so they are examples of wave is a False statement.

5. The amplitude of the wave decreases as the time period increases. But when we get far from the disturbance, the amplitude increases.

Thus, the amplitude of water wave increases as we get farther from the disturbance.

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Al 26.98 and S 32.06 calculate the number of formula units in 62.2 g sample of aluminum sulfide

Answers

The number of formula units would be  2.5 x  [tex]10^2^3[/tex]

Formular unit

This is mathematically given as: mole x Avogadro number

Molar mass of the aluminum sulfide (Al2S3) sample = 26.98 x 2 + 32.06 x 3

= 53.96 + 96.18 = 150.14 g/mole

Mole of 62.2 g aluminum sulfide = 62.2/150.14 = 0.4143 moles

Formular unit = 0.4143 x 6.023 x [tex]10^2^3[/tex] = 2.5 x  [tex]10^2^3[/tex]

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What is the crosswind component for a landing on runway 18 if the tower reports the wind as 220° at 30 knots?

Answers

From the head wind component charts,  the crosswind component for a landing on runway 18 is 19 knots.

What is crosswind component?

When winds are not parallel to or directly with  the line of travel, the wind is said to have a crosswind component.

From the head wind component charts, at 220° at 30 knots, the corresponding crosswind component is 19 knots.

Thus, from the head wind component charts,  the crosswind component for a landing on runway 18 is 19 knots.

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Pls help me i have to submit this due tomorrow :'D

Answers

[tex]\textsf {a) As there is no change in the initial and final positions, the displacement is}\\\textsf {equal to 0.}[/tex]

b) Finding total distance :

Distance travelled from 0 s to 5 s :

1/2 x 5 x 30 = 75 m

Distance travelled from 5 s to 10 s :

5 x 30 = 150 m

Distance travelled from 10 s to 15 s :

150 + 1/2 x 5 x 5150 + 12.5 = 162.5 m

Distance travelled from 15 s to 20 s :

36 x 5 + 1/2 x 5 x 4180 + 10 = 190 m

Distance travelled from 20 s to 25 s :

45 x 5 + 1/2 x 5 x 5225 + 12.5 = 237.5 m

Distance travelled from 25 s to 30 s :

40 x 5 + 1/2 x 10 x 5200 + 25 = 225 m

Distance travelled from 30 s to 35 s :

20 x 5 + 1/2 x 20 x 5100 + 50 = 150 m

Distance travelled from 35 s to 40 s :

1/2 x 20 x 550 m

Total = 75 + 150 + 162.5 + 190 + 237.5 + 225 + 150 + 50

Total = 1240 m

c) velocity at t = 15 s

36/1512/52.4 m/s

d) average velocity

0 m/s (as displacement is equal to 0)

e) average speed

1240/4031 m/s

f) Part d uses displacement whereas part e uses distance

Henry shot a down tennis ball and a cricket ball of the same size to window glass. Which one will have more impact? Justify.​

Answers

Answer: The cricket ball bc of the material

Explanation:

define density and give its SI unit​

Answers

Answer:

Density is defined as mass per unit volume. its SI unit is: kg/m³

Explanation:

Answer:

Density is defined as mass per unit volume. its SI unit is: kg/m³

Explanation:

from answer above

What is a characteristic of a catamaran hull? tends to pitch in waves only recommended on calm inland waters planes at low speed a stable ride

Answers

A Stable Ride is the main characteristic of a catamaran hull.

What is catamaran hull?

Catamaran Hull is a multi-hulled watercraft, which have two parallel hulls of equal size.

The characteristic of a catamaran hull are as follows:

A catamaran hull has less volume than an equal size monohull.Catamaran hulls are distinguished by lighter displacement and shallower draft when compared to monohulls of the same length. Catamarans can be used in shallow waters as well. This feature makes catamarans quite flexible and versatile.Catamaran has multiple hulls, usually two parallel hulls of equal size. This geometric feature gives the craft an increased stability.Catamarans derives extra stability from its wide beam, in the place of a ballasted keel employed in a regular monohull sailboat.

Therefore, Catamarans has a stable ride, according to their characteristic.

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one of the rare galaxies that is isolated in space is likely to be a(n) ____.

Answers

The rarest type of galaxies is the elliptical double-ringed galaxy.

What is the rarest type of galaxy?

elliptical double-ringed galaxy is considered as the rarest type of galaxy because of its small number. The example of such type of galaxy is PGC 1000714. Scientists suggest that about 0.1% of galaxies are of this type.

So we can conclude that the rarest type of galaxies is the elliptical double-ringed galaxy.

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The amount of kinetic energy an object has depends on which feature of the object?
A) its motion
B) its position
C) its gravity
D) its height

Answers

Motion (but also Mass).

What does that mean about the densities of the phases of water?

The solid state is the most dense, followed by the liquid state, then the gas state.
The solid state is more dense than the liquid state.
The liquid state is more dense than the solid state.
The gas state is the most dense, followed by the liquid state, then the solid state

Answers

The correct option is 2. The solid state is more dense than the liquid state.

The solid form of most substances is denser than the liquid phase so a block of most solids will sink in the liquid but a block of ice floats in liquid water because ice is less dense. Upon freezing the density of water decreases by about 9%. This is due to cooling of intermolecular vibrations allowing the molecules to form steady hydrogen bonds and locking into positions of hexagonal packing upon freezing to ice. These bonds are shorter in the crystal than in the liquid.

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A car is moving at a rate of 72km/hr . How far does the car move when it stops after 4 seconds?

step by step asap pls​

Answers

Answer:

The car will stop after 4 seconds after moving the distance of 0.08km.

Explanation:

The reading above it clearly states that a car is moving at a speed of 72Km/hr. And it asking for the distance the car move when it stops after 4 seconds.

Looking at speed formula , speed=distance÷time.

But in this problem we I finding distance, so in speed formula make distance the subject.

Therefore distance = speed × time

Before going ahead you should have this in mind the unit for distance is Km and m . Our speed is in Km/hr but our time is in second. In this case change 4 seconds to hour which is 0.00111 hr .you change second to hour because hr will cancel hr when solving for distance giving distance unit Km

Distance = speed × time

Distance= 72km/hr × 0.00111 hr

hour cancel hour

Distance= 72km × 0.00111

Distance = 0.08km

Therefore the car will stop after 4 seconds after moving the distance of 0.08km.

Please mark brainliest.

conversion :

72 km/h = 72 × (1000/3600) = 20 m/s

so, in 4 seconds it travel

4 × 20 = 80 meters = 0.08 km

A 25-kg piece of equipment can be hung by steel wires of length 1.00 m, 2.00 m, or 3.00 m. If all the wires have the same diameter, which one will stretch the greatest distance

Answers

If all the wires have the same diameter, they will all stretch by the same percent. The elasticity does not depend upon the length.

What is the distance?

Distance is a numerical representation of the distance between two locations. The distance can refer to a physical length or an estimate based on other factors in physics or common use.

|AB| is a symbol for the distance between two points A and B.

A physiological method for identifying far-off or unseen items using sound waves that the objects reflect back to the source, such as a bat. Each one will enlarge by the same percentage.

Hence, they will all stretch by the same percentage.

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Use wave equation calculate the speed of sound in the air if frequency of 110 hz has a wave length of 3 m

Answers

Answer = 330 m/s

The wave equation is as follows:

Wave speed = wavelength x frequency

The known values are:
Wavelength = 3m
Frequency = 110 Hz

Substitute the known values into the wave equation to find the wave speed.

Wave speed = 3 x 110

Wave speed = 330 m/s

The ball is in contact with the bat for 0.001s use the equation in the box to caluclate the force exerted by the bat on the ball

Answers

Answer:

Force = 9600N

Explanation:

If this is the right question, there should have been a question before about the what the change in the momentum of the ball was. The answer to that was 9.6kg m/s. For this part, we divide this by the time taken which was 0.001s which give us the resultant force.

resultant force = change in momentum ÷ time

= 9.6kgm/s ÷ 0.001s

= 9600N

Question 16 of 25
Which of the following best describes an alternating current?
A. A circuit that has both series and parallel components
B. Charge that moves in a single direction
C. Charge that jiggles back and forth very quickly
D. A circuit that has only series or only parallel components
SUBMIT

Answers

The answer is B because trust me

Answer:

it is c

Explanation: i just did it

Trivia Time!! At what velocity does light move?

Answers

Explanation:

Light Light from a moving source travels at 300,000 km/sec (186,000 miles/sec).

Note:

The Speed of Light Is Constant.

Explanation:

LIGHT TRAVELS AT A CONSTANT VELOCITY OF 300,000 km/sec.

what is projectile motion?Give 3 applications of it in our daily life.​

Answers

Answer:

Motion of an object that travels in a curved path under the influence of Earth's gravitational field. Examples include throwing a ball, javelin throw, and golf ball.

Explanation:

Answer:

1. In sports.

2. In programming or Animation.

3. In home appliances.

4. In military.

Explanation:

1. In sports. Being common in sports, projectile motion is applied in motion of a projectile which is usually a ball. This is because we are able to calculate the angle of the flight developed by a ball to maximize its distance or velocity. For example in baseball and basketball.

2. In programming or Animation. Considering that there is a challenge for animators and programmers in modern world, physics is applied in televisions or video games. For example a baseball being hit by a player in video game or TV, it should look real. Hence the application of projectile motion.

3. In home appliances. Appliances for example hose or water gun uses an application of projectile motion. As the water exits the hose or water gun, the angle over which the water travels depends on the distance moved and force that is being applied.

4. In military. Bullets being shot from the barrel of the gun is a projectile in air. The speed of the bullet is higher than that of the water exiting the hose therefore it will travel a longer distance. The manufacturers of weapons such as a gun tries to maximize the speed while minimizing gun's recoil.

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