( 8 x 10^4) - ( 4 x 10^2) give the answer in standard form

Answer:

angles X = 45°

angles Y = 45°

angles Z = 90°

Step-by-step explanation:

Given:

angles X = angles Y = x°

angles Z = 2 angles Y = 2x°

Find:

Each angle

Computation:

Using angle sum property

angles X + angles Y + angles Z = 180

x + x + 2x = 180

4x = 180

x = 45°

So,

angles X = 45°

angles Y = 45°

angles Z = 90°

Answer:

area of the parallelogram=6

area of the rectangle=20

total area=26 square units

Answer:

-6

Step-by-step explanation:

h(x) = -3x – 12 becomes h(-2) =  -3(-2) – 12 = -6

Answer:  

Your efficiency is 80%. N is 400

Step-by-step explanation:

I hope I helped :)

Would appreciate Brainliest ;)

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Have a lovely day and good luck with your school work!

I believe the answer is 400, 80%

have a blessed day!

Step-by-step explanation:

Clearly, there is a common difference between the monthly employment rates:

8.7% - 8.9% = -0.2%

8.5% - 8.7% = -0.2%

8.3% - 8.5% = -0.2%

a) So, for every month x, the percentage will go down 0.2%, starting at 8.9%. So, we can make this equation:

y = -0.2x + 9.1, where x = 1 would be October 2011.

January 2013 is 16 months after October 2011, so:

y = -0.2(16) + 9.1

y = 5.9%

b) To find when the unemployment rate will be zero, we set the equation equal to zero:

0 = -0.2x + 9.1

-0.2x = -9.1

x = 45.5 months

So, rounding up, the U.S. would reach a zero unemployment rate in 46 months or around September 2014? Not completely sure.

Slope = change in Y / change in x

Slope = (-7 - 2) / (-3 - -3)

Slope = -9/0

Because the change in x = 0, the slope is undefined.

The answer is the slope is  undefined.

The total Judy saved was £200. Moreover, if she spends £172 on Christmas presents, she will have £28 left.

If you observe the pictogram, two squares are equivalent to £20. This means one square is equivalent to £10. Based on this, let's determine the total she saved every month.

To find out the total money she will have in this situation is equivalent to the total of money she saved - £172 she spent.

Note: This question is incomplete because the pictogram is missing, here I attach the missing section.

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Answer:

The answer to your question is Dependent Variable.

In a linear regression model, the variable that is being predicted or explained is known as Dependent Variable . It is denoted by y and is often referred to as the response variable

Step-by-step explanation:

I don't really know how to explain sorry.

Brainliest pls! :)

Answer:Dependent Variable

Answer:

240cm

Step-by-step explanation:

Answer:

1.3/20   2.4/20 or 1/5   3.9/27 or 1/3

Step-by-step explanation:

I hope this helped!

The geometric sequence is a sequence with a common ratio. The common ratio is the ratio between the succeeding term and the preceding term of a sequence and must be equal to a constant k.

Given a sequence 2, 4, 8, 16... This sequence is geometric in nature because of a constant common ratio of 2.'

Common ratio = 4/2 = 8/4 = 2

Hence a geometric sequence is characterized by its common ratio

Answer:

21 beads

Step-by-step explanation:

15.75 divided by 0.75 = 21

sorry im late hope this helps out :) <3

Answer:

$7194

Step-by-step explanation:

Given the following

Principal = $6600

Time = 9months = 9/12 year

Rate R = 12%

Interest = PRT/100

Interest = 6600*9/12 * 12/100

Interest = 66*9

Interest = $594

Amount on the borrowers check  = principal + interest

Amount on the borrowers check = 6600 + 594

Amount on the borrowers check = $7194

Answer:

[tex]t = 4b + 10c[/tex]

Step-by-step explanation:

Given

1 bag = 4 doughnuts

1 carton = 10 doughnuts

Required

Determine the amount of doughnuts in b bags and c cartons

If 1 bag contains 4 doughnuts, then b bags contain 4b doughnuts

If 1 carton contains 10 doughnuts, then c cartons contain 10b doughnuts

So, the total (t) is calculated by adding up the amount of doughnuts in the cartons and the bags:

i.e.

[tex]t = 4b + 10c[/tex]

Answer:

your answer will be

A)(6,10)

B)(2,12)

C)(4,4)

Step-by-step explanation:

hope this helps

have a nice day/night ^_^

Answer:

the estimated area of the fountain is 147.58 square yards and the estimated area of the path is 28.26 square yards

Step-by-step explanation:

#platolivesmatter

your welcome!!!

The area of the fountain is 147.58 square yards, and the area of the path is 28.25 square yards.

A circle is a closed, two-dimensional object where every point in the plane is equally spaced from a central point. The line of reflection symmetry is formed by all lines that traverse the circle. Additionally, every angle has rotational symmetry around the center.

Given

a circular fountain,

radius of fountain  = √47 yards

area of  fountain = πr²

area = π(√47)²

area = 147.58 square yards.

and fountain surrounded by a circular path,

which form a concentric circle with fountain,

the radius of the circular path from center of the fountain = √56 yards

area of the path = total area with radius √56 - an area of fountain

area of the path = π(√56)² - 147.58

area of the path = 175.84 - 147.58

area of the path = 28.26 square yards

Hence the area of the fountain is 147.58 square yards,

area of path = 28.25 square yards.

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Answer:

7:50

Step-by-step explanation:

Mr. Wellborn arrives 50 minutes before 8:40 so that means you subtracts 50 minutes from 8:40. 8:40-50=7:50

Therefore, the answer is 7:50

Hope this helps

Answer:

The answer is 7:50 A.M

Step-by-step explanation:

First we know that 50 is less than 40 so we subtract one hour. that get 50 so the answer is 7:50!

By the way, the person who answered this is a 3rd grader!  If the answer is worng am sorry i tried my best.

Answer:

184 in.^2

Step-by-step explanation:

The cross section through the center of a sphere is a circle whose radius is equal to the radius of the sphere.

area of circle

[tex]A_{circle} = \pi r^2[/tex]

[tex] \pi r^2 = 46 [/tex]

[tex] r^2 = \dfrac{46}{\pi} [/tex]

[tex] r = \sqrt{\dfrac{46}{\pi}} [/tex]

[tex] r = 3.83 ~in.[/tex]

surface area of sphere

[tex] SA = 4 \pi r^2 [/tex]

[tex] SA = 4 \times \pi \times (3.83)^2 [/tex]

[tex] SA = 184~in.^2 [/tex]

Answer:

d. y = 3x + 5

Step-by-step explanation:

plug x = 2 in the equation y = 3x +5

y = 3*2 + 5

y = 11

so x = 2, y = 11

we know d is the correct statement

Answer:

your question and is d option

Answer: One solution

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

they intersect at 1 point

Answer:

20

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

Delta math

The measure of K to the nearest degree is 4°.

The law of cosines, commonly referred to as the cosine rule or the cosine formula, in trigonometry essentially connects the length of the triangle to the cosines of one of its angles. It claims that we can determine the length of the third side of a triangle if we know the length of the first two sides and the angle between them.

Given ΔJKL,

j = 7.9 inches, k = 2 inches, l = 9.8 inches

to find the measure of angle K,

we can calculate the angle by cosine law,

cosK = (j² + l² - k²)/(2.j.l)

cosK = (7.9² + 9.8²  - 2²)/(2*7.9*9.8)

cosK = 154.45/154.81

K = cos⁻¹(0.99748)

K = 4.067⁰ ≈ 4°

Hence angle K is 4°.

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Answer:

Determine the null and alternative hypotheses :  STEP 1

Draw a conclusion about the unknown  population using what is known about the sample :  STEP 4

Determine the probability at which you will conclude that the sample outcome is very unlikely :  STEP 2

Draw a random sample and calculate the sample statistic : STEP 3

Step-by-step explanation:

The correct order of the steps are :

Determine the null and alternative hypotheses :  STEP 1

Draw a conclusion about the unknown  population using what is known about the sample :  STEP 4

Determine the probability at which you will conclude that the sample outcome is very unlikely :  STEP 2

Draw a random sample and calculate the sample statistic : STEP 3

Answer:

165

Step-by-step explanation:

In 165 ways i can select 3 books to bring on vacation from a group of 11 books.

A combination is when you choose data from a group without any order or sequence. If the group of data is relatively lesser, you can calculate the number of possible combinations.

According to the question

Select 3 books to bring on vacation from a group of 11 books.

By using combinations formula

[tex]^{n} C _{r}=\frac{n!}{r!(n-r)!}[/tex]

[tex]^{11} C_{3}[/tex] = [tex]\frac{11!}{3!(11-3)!}[/tex]

= [tex]\frac{11.(10)(9)(8!)}{3!.8!}[/tex]

Cancelling out 8! from denominator and numerator

= [tex]\frac{11(10)(9)}{3(2)(1)}[/tex]

= 165

Thus, In 165 ways i can select 3 books to bring on vacation from a group of 11 books.

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Answer:

The total surface area of a regular pyramidis the sum of the areas of its lateralfaces and its base. The general formula for thelateral surface area of a regular pyramidis where p represents the perimeter of thebase and SI the height of inclination.

Answer:

its the second and third option

Step-by-step explanation:

I took the test

In order to multiply a matrix by another matrix, we multiply the rows in the first matrix by the columns in the other matrix (How this is done is shown below)

To determine the pairs of matrices that AB=BA, we will determine AB and BA for each of the options below.

For the first option

[tex]A= \left[\begin{array}{cc}1&0&-2&1&\end{array}\right]; B= \left[\begin{array}{cc}5&0&3&2&\end{array}\right] \\[/tex]

[tex]AB= \left[\begin{array}{cc}(1\times5)+(0\times3)&(1\times0)+(0\times 2)&(-2\times5)+(1\times3)&(-2\times0)+(1\times2)&\end{array}\right]\\AB= \left[\begin{array}{cc}5+0&0+0&-10+3&0+2&\end{array}\right]\\AB = \left[\begin{array}{cc}5&0&-7&2&\end{array}\right] \\[/tex]

and

[tex]BA= \left[\begin{array}{cc}(5\times1)+(0\times-2)&(5\times0)+(0\times 1)&(3\times1)+(2\times-2)&(3\times0)+(1\times2)&\end{array}\right]\\BA= \left[\begin{array}{cc}5+0&0+0&3+-4&0+2&\end{array}\right]\\BA = \left[\begin{array}{cc}5&0&-1&2&\end{array}\right] \\[/tex]

∴ AB≠BA

For the second option

[tex]A= \left[\begin{array}{cc}1&0&-1&2&\end{array}\right]; B= \left[\begin{array}{cc}3&0&6&-3&\end{array}\right] \\[/tex]

[tex]AB= \left[\begin{array}{cc}(1\times3)+(0\times6)&(1\times0)+(0\times -3)&(-1\times3)+(2\times6)&(-1\times0)+(2\times-3)&\end{array}\right]\\AB= \left[\begin{array}{cc}3+0&0+0&-3+12&0+-6&\end{array}\right]\\AB = \left[\begin{array}{cc}3&0&9&-6&\end{array}\right] \\[/tex]

and

[tex]BA= \left[\begin{array}{cc}(3\times1)+(0\times-1)&(3\times0)+(0\times 2)&(6\times1)+(-3\times-1)&(6\times0)+(-3\times2)&\end{array}\right]\\BA= \left[\begin{array}{cc}3+0&0+0&6+3&0+-6&\end{array}\right]\\BA = \left[\begin{array}{cc}3&0&9&-6&\end{array}\right] \\[/tex]

Here AB = BA

For the third option

[tex]A= \left[\begin{array}{cc}1&0&-1&2&\end{array}\right]; B= \left[\begin{array}{cc}5&0&3&2&\end{array}\right] \\[/tex]

[tex]AB= \left[\begin{array}{cc}(1\times5)+(0\times3)&(1\times0)+(0\times 2)&(-1\times5)+(2\times3)&(-1\times0)+(2\times2)&\end{array}\right]\\AB= \left[\begin{array}{cc}5+0&0+0&-5+6&0+4&\end{array}\right]\\AB = \left[\begin{array}{cc}5&0&1&4&\end{array}\right] \\[/tex]

and

[tex]BA= \left[\begin{array}{cc}(5\times1)+(0\times-1)&(5\times0)+(0\times 2)&(3\times1)+(2\times-1)&(3\times0)+(2\times2)&\end{array}\right]\\BA= \left[\begin{array}{cc}5+0&0+0&3+-2&0+4&\end{array}\right]\\BA = \left[\begin{array}{cc}5&0&1&4&\end{array}\right] \\[/tex]

Here also, AB=BA

For the fourth option

[tex]A= \left[\begin{array}{cc}1&0&-2&1&\end{array}\right]; B= \left[\begin{array}{cc}3&0&6&-3&\end{array}\right] \\[/tex]

[tex]AB= \left[\begin{array}{cc}(1\times3)+(0\times6)&(1\times0)+(0\times -3)&(-2\times3)+(1\times6)&(-2\times0)+(1\times-3)&\end{array}\right]\\AB= \left[\begin{array}{cc}3+0&0+0&-6+6&0+-3&\end{array}\right]\\AB = \left[\begin{array}{cc}3&0&0&-3&\end{array}\right] \\[/tex]

and

[tex]BA= \left[\begin{array}{cc}(3\times1)+(0\times-2)&(3\times0)+(0\times 1)&(6\times1)+(-3\times-2)&(6\times0)+(-3\times1)&\end{array}\right]\\BA= \left[\begin{array}{cc}3+0&0+0&6+6&0+-3&\end{array}\right]\\BA = \left[\begin{array}{cc}3&0&12&-3&\end{array}\right] \\[/tex]

Here, AB≠BA

Hence, it is only in the second and third options that AB = BA

[tex]A= \left[\begin{array}{cc}1&0&-1&2&\end{array}\right] B= \left[\begin{array}{cc}3&0&6&-3&\end{array}\right] \\[/tex] and [tex]A= \left[\begin{array}{cc}1&0&-1&2&\end{array}\right]B= \left[\begin{array}{cc}5&0&3&2&\end{array}\right] \\[/tex]

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