6.
Suppose that a new class is opened for enrollment and currently
has 7 students. Is this class an outlier if it is added to the data set?

#First u find the gradient first, remember that the formula of equation of the line is y=mx + c

y = 3x - 3

so the gradient (m) is 3

#Now u find the equation of the line

y - y1 = m(x - x1)

y - 4 = 3(x - 6)

y - 4 = 3x - 18

y = 3x - 18 + 4

y = 3x - 14

Answer:

-x² - 2y² + 2xy - 8y

Step-by-step explanation:

Answer:

[tex]\bar x =2.53[/tex] -- Mean

[tex]Median= 2[/tex]

[tex]Mode = 2[/tex]

[tex]Range = 8[/tex]

[tex]Q_1 = 1[/tex]

[tex]Q_3 = 3[/tex]

[tex]IQR = 2[/tex]

Step-by-step explanation:

Given

n = 30

Data: 2 3 1 2 6 4 2 1 5 3 2 3 1 2 2 1 3 1 2 2 4 2 1 2 9 3 2 1 1 3

Solving (a): The mean

This is calculated as:

[tex]\bar x =\frac{\sum x}{n}[/tex]

[tex]\bar x =\frac{2 +3 +1 +2 +6 +4 +2 +1 +5 +3 +2 +3+ 1+ 2 +2 +1 +3 +1 +2 +2 +4 +2 +1 +2 +9 +3 +2 +1 +1 +3}{30}[/tex]

[tex]\bar x =\frac{76}{30}[/tex]

[tex]\bar x =2.53[/tex]

Solving (b): The median

First arrange the given data

Arranged: 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 4 4 5 6 9

[tex]Median =\frac{1}{2}(n+1)[/tex]

[tex]Median =\frac{1}{2}(30+1)[/tex]

[tex]Median =\frac{1}{2}(31)[/tex]

[tex]Median = 15.5th[/tex]

This implies that the median is the average of the 15th and 16th item

[tex]Median = \frac{2+2}{2}[/tex]

[tex]Median = \frac{4}{2}[/tex]

[tex]Median= 2[/tex]

Solving (c): The mode

From the given data; 2 has the highest frequency of 11.

So,

[tex]Mode = 2[/tex]

Solving (d): The Range

[tex]Range = Highest\ Data - Lowest\ Data[/tex]

The highest is 9 and the lowest is 1,

So:

[tex]Range = 9 - 1[/tex]

[tex]Range = 8[/tex]

Solving (e): Lower (Q1) and Upper (Q3) quartile.

Q1 is calculated as:

[tex]Q_1 = \frac{1}{4}(n+1)th[/tex]

[tex]Q_1 = \frac{1}{4}(30+1)th[/tex]

[tex]Q_1 = \frac{1}{4}(31)th[/tex]

[tex]Q_1 = 7.75th[/tex]

[tex]Q_1 = 8th\ item[/tex]

[tex]Q_1 = 1[/tex] -- from the arranged data

Q3 is calculated as:

[tex]Q_3 = \frac{3}{4}(n+1)th[/tex]

[tex]Q_3 = \frac{3}{4}(30+1)th[/tex]

[tex]Q_3 = \frac{3}{4}(31)th[/tex]

[tex]Q_3 = 23.25th[/tex]

[tex]Q_3 = 23rd\ item[/tex]

[tex]Q_3 = 3[/tex] -- from the arranged data

Solving (f): The interquartile range (IQR)

[tex]IQR = Q_3 - Q_1[/tex]

[tex]IQR = 3-1[/tex]

[tex]IQR = 2[/tex]

Answer:

A) c(x)=2x+60

$74

Step-by-step explanation:

A) c(x)=2x+60

$74

Answer:

They are in conflict.

Step-by-step explanation:

for statement (a) we have child gunshot deaths doubling every year. So if it was 1 death in 1950, it is 2 in 1951, 4 in 1952, 8 in 1953, 16 in 1954. That would make the deaths in 1994 = (deaths in 1950) x 2 x 2 x 2 x 2 ... with 44 factors of 2. That number is over a trillion.

for statement (b) we have child gunshot deaths doubling over a period of 44 years, which might even be true

Answer:

[tex]\displaystyle d = 2\sqrt{13}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Algebra II

Step-by-step explanation:

Step 1: Define

Point (11, 4) → x₁ = 11, y₁ = 4

Point (5, 8) → x₂ = 5, y₂ = 8

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Answer:

f(3) = 10

Step-by-step explanation:

f(3) = 2(3)^2 - (3) - 5

f(3) = 2(9) - (3) - 5

f(3) = 18 - 3 - 5

f(3) = 10

Answer:a

Step-by-step explanation:

Answer:

99miles is more likely correct

or 114miles as knots is usually higher mileage

Step-by-step explanation:

70^2 + 70^2 = c^2

sqrt 4900 + sqrt 4900 = c^2

sq rt 9800 = c^2 = 98.9949494

99 x 1.1507794480225 = 113.927165 = 114miles if converted to 80.6m/ph

70 Knots is equivalent to 80.554561361578 Miles/Hour. How to convert from Knots to Miles/Hour The conversion factor from Knots to Miles/Hour is 1.1507794480225. To find out how many Knots in Miles/Hour, multiply by the conversion factor or use the Velocity converter.

Answer:

x + x + x

Step-by-step explanation:

We have 3y and are asked to express it equivalently with the answers provided.

I will go over the flaws of each answer and single it down to the correct one.

x * x * x would equal x^3, since this is being multiplied.

x^3 is equal to x * x * x, therefore it is not correct.

x + 3 is not correct because you cannot add numbers or variables that are not like terms, so it would not equal to 3y.

x + x + x would equal to 3y because they are all like terms and do not form exponents.

Answer:

Step-by-step explanation:

50(1+7.25/100)

50(107.25/100)

50(1.0725)

53.625

$53.63

Answer:

Apigy 60918370927710 paojzob pour ta life yzs 029282728

Answer:

The answer is 137,280

Step-by-step explanation:

5280 ft. = 1 mile

So....

26 x 5280 = 137,280

Answer:

Use long subtraction to evaluate.

6.84

Step-by-step explanation:

Answer:

The answer is A 21

Step-by-step explanation:

Answer:

D) 5/13

Step-by-step explanation:

Sin x = Opposite / Hypotenuse

Opposite side length = 5 cm

Hypotenuse length = 13 cm

Sin x = 5/13

Answer:

Fountain= 147.65 square yards

path= 28.28 square yards

Step-by-step explanation:

pi*47 <---square root cancels out the square

=147.65

pi*56=175.93

175.93-147.65=28.28

Answer:

77

Step-by-step explanation:

77/11=7

Answer:

k=77 because 77/11 is 7

Step-by-step explanation:

Answer:

the correct answer is option C) 0

Hope that helps! :)

Answer:

D. no solution

Step-by-step explanation:

substitute y = 2x + 3 in

2y = 4x + 10

gives 2(2x+3) = 4x + 10

4x - 4x = 10 - 6

therefore the equation has no solution

Answer:

1/4

Step-by-step explanation:

Answer:

11.7

Step-by-step explanation:

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Answer:

B (11.7)

Step-by-step explanation:

if you add the whole numbers (4, 4, 3) it would be 11 and then you add the decimal part which is 7 so it would be 11.7

Answer:

Step-by-step explanation:

(5, 38) (6, 39)

(39 - 38)/(6 - 5) = 1/1= 1

y - 38 = x - 5

y = x + 33

Answer:

I think d is the answer

Answer:

Step-by-step explanation:

No it isn't. 140/100 is NOT a whole number so 140 isn't a multiple of 100.

Answer:

Looking at graphs we count the distance at the side for every change point, imagine a distance going 10miles and then staying at 10 miles on the second hour we keep 10 miles and pick the next new number as the linear graph moves up.

We do not count any horizontal lines twice as this shows stationary journeys meaning constant time, we know time is always at the bottom of graphs and just count the points by matching each point to the distance until you get from 0-7 hrs across the graph.

We show the numbers also as they descend as this counts as positive hours too. A descent in miles is not a descend in hours so the mileage gets bigger if we are reading it left to right and slopes descend.

Step-by-step explanation:

y = 350 miles

count to see if they are more than 350miles on the line as it goes up across and down, counting only once if it stays straight, and count again if its straight at any other point. always count from a to b to c etc.

y = 455 miles

count to see if they are more than 455miles on the line as it goes up across and down, counting only once if it stays straight, and count again if its straight at any other point. always count from a to b to c etc.

y = 140 miles

count to see if they are more than 140miles on the line as it goes up across and down, counting only once if it stays straight, and count again if its straight at any other point. always count from a to b to c etc.

y = 280 miles

count to see if they are more than 280 miles on the line as it goes up across and down, counting only once if it stays straight, and count again if its straight at any other point. always count from a to b to c etc.

Answer:

C

Step-by-step explanation:

The possible value of the machine at the end of each year will be $3200

Depreciation in economics is a measure of the amount of value an asset loses from influential factors affecting its market value.

Given that, the value of a machine is decreasing by a constant percent rate each year, we need to find the possible value of the machine at the end of each year,

So, we can say that this is a case of depreciation,

Since, the values are not given, let us consider the rate be 20% and the initial price of the machine be $16000.

We know that, the depreciation, formula is given by :

A = P(1-r)ⁿ

Where, A = final amount, P = initial amount, r = rate and n = time.

Since, the value is decreasing by a constant percent rate each year,

Therefore, every year the amount decreased will be same,

Finding for 1 year,

A = 16000(1-0.2)¹

A = 16000(0.8)

A = 12800

The amount decreased = 16000-12800 = $3200

Therefore, after each year the decreased amount will be $3200

Hence, the possible value of the machine at the end of each year will be $3200

Learn more about depreciation, click;

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Answer:

10.5 cm

Step-by-step explanation:

took the test

Answer:

x=0

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.