6
E
Right triangle ABC is reflected over AC, then dilated by
a scale factor of to form triangle DEC. Which
statements about the two triangles must be
true? Select three options.
DAABC-ADEC
OZB ZE
3BC= 2EC
3DE = 2AB
3mzA= 2mzD
25:04
2mzA=3m2D

If a plane including pints p,q, and r cuts through the cube, the shape that will be gotten is a triangle.

A triangle is a polygon with three edges and three vertices. The sum of the internal angles of a triangle is equal to 180 degrees.

In this case, when a plane including pints p,q, and r cuts through the cube, the shape that will be gotten is a triangle.

The diagram is attached.

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The value of cos θ is 3/5.

Trigonometric ratios can be used to determine the ratios of any two sides out of a total of three sides of a right-angled triangle in terms of the respective angles.

Here, given point on circle is (0.6, 0.8) or (3/5 , 4/5)

x - axis (base) = 3/5

y - axis (Perpendicular) = 4/5

Radius (Hypotenuse) = 1

Now, we know

cos θ = Base / Hypotenuse

cos θ = 3/5

Thus, the value of cos θ is 3/5.

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Answer: True: The graph of y=3x²-3 opens up

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Up

Vertex: (0,−3)(0,-3)

Focus: (0,−35/12)

Axis of Symmetry: x=0

Directrix: y=−37/12

X={-2, -1, 0, 1, 2}

Y={9, 0, -3, 0, 9

Step-by-step explanation:

Answer: A. The function has two distinct real zeros.

Answer:

C. The function has four distinct real zeros.

Step-by-step explanation:

The function intersects y=0 at x=1/2, 4, and 6 twice. It has two solutions at 6 twice as it is a behavior of polynomial or rational functions

Answer:

false

Step-by-step explanation:

so D(2) is equal to how much money he has after 2 years while D(7) is after 7 years. since he earns 3% interest each year he will have more money after 7 years than 2 years

Answer:

Step-by-step explanation:

We got two shapes in the given figure,on the right we got a rectangle and on the left we have a square.

Area of rectangle:-

Area of square :-

Total area :-

Answer:

Step-by-step explanation:

you have two rectangles, the bigest has the base of 6cm and the height of 4cm, the area is 6 * 4 = 24cm ^ 2, the other rectangle has the base of 6 - 4 = 2 and the height of 5 - 4 = 1, 2*1=2.

we add the dimensions and we have the area of ​​the complete figure 24 + 2 =

26 cm ^ 2

The option that best describes the experiment is accurate and reproducible.

All the values from the experiment are close in value to the accepted value. This indicates that the experiment is accurate. Two experiments yield the same values. This indicates that the experiment is reproducible.

Here is the table used in answering the question:

Accepted Value: 130

Experiment 1 129

Experiment 2 131

Experiment 3 129

Experiment 4 132

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Answer:

(A)They are precise and reproducible

Step-by-step explanation:

Answer:

putting the values of coordinates in equation to check for the solution.

For A

2x + y < 10

2(-5) + 4 < 10.

-10 - 4 < 10

-14 < 10 ( true)

2x - 4y > 8

2(-5) - 4(4) > 8

-10 - 16 > 8

-26 > 8

false..

it is not the solution of the equation.

similarly we can find for other coordinates.

E is the solution

Answer:

11 + 5√5

Step-by-step explanation:

6 + 3√5 +2√5 + 5

11 + 5√5

root n * root n = n , which is why there is a 5 at the end

Answer:

the answer is 11+5√5

Step-by-step explanation:

Answer:

$26

Step-by-step explanation:

Let blueberry pies = x and lemon pies = y.

4x + 13y = 230

4x + 2y = 76

Using elimination, we see that 11y = 154. Therefore, y = 14.

4x + 2(14) = 76

4x + 28 = 76

4x = 48

x = 12

x + y = 12 + 14 = 26.

$26 is your answer.

Answer:

Step-by-step explanation:

Let B be the price of a blueberry pie.  Let L be the price of a lemon meringue pie.

We are told that Shreya makes a total of $76 by selling 4 blueberry and 2 lemon meringue pies.  This can be made into an equation:

Shreya:  4B + 2L = $76

We also learn that Shanice is doing particularly well:

Shanice:  4B + 13L = $320

We want to determine the prices for each type of pie, B and L.  We have two equations and two unknowns.  That means we should be able to find the answers by substitution.

Rearrange Shreya's equation to isolate B:

Shreya:  4B + 2L = $76

               4B   = $76 - 2L

                 B = ($76-2L)/4

Now use this definition of B in Shanice's equation:

Shanice:  4B + 13L = $320

                4( ($76-2L)/4) + 13L = $320

                     ($76-2L) + 13L = $320

            11L = 244

                L = $22.18

Use L = $22.18 in either equation and solve for B:

4B + 2L = $76

4B + 2*($22.18) = $76

4B = $31.64

B = $7.91

---

Blueberry pies are $7.91 each.

Lemon meringue pies are $22.18 each

=========

CHECK:  Do these prices provide the correct sales for each person?

            Price($/pie)        Shreya     Shanice

Blueberry          7.91               4            4

Lemon Mer.    22.18                2           13

Blueberry Sales ($)                    31.64        31.64

Lemon Mer. Sales ($)               44.3       288.36

Total Sales                              $76        $320

YES - These prices account for each person's sales.

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: a_{33} = 1\degree[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

In a matrix, [tex] \sf a_{ij} [/tex] represents an element in " i " th row and " j " th column.

Henceforth, element [tex] \sf a_{33} [/tex] represents element in 3rd row and 3rd column.

[tex]\qquad \tt \rightarrow \:a_{33} = 1[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Using the normal distribution, it is found that:

a) The pilot is at the 72th percentile.

b) 19.13% of pilots are unable to fly.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation are given, respectively, by:

[tex]\mu = 72.6, \sigma = 2.7[/tex].

Item a:

The percentile is the p-value of Z when X = 74.2, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{74.2 - 72.6}{2.7}[/tex]

Z = 0.59

Z = 0.59 has a p-value of 0.7224.

72th percentile.

Item b:

The proportion that is able to fly is the p-value of Z when X = 78 subtracted by the p-value of Z when X = 70, hence:

X = 78:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{78 - 72.6}{2.7}[/tex]

Z = 2

Z = 2 has a p-value of 0.9772.

X = 70:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{70 - 72.6}{2.7}[/tex]

Z = -0.96

Z = -0.96 has a p-value of 0.1685.

0.9772 - 0.1685 = 0.8087 = 80.87%.

Hence the percentage that is unable to fly is:

100 - 80.87 = 19.13%.

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Answer:

First Option i.e 5/3 > 3/2 , the slope of Climbing equipment at Gym is greater is Correct

Step-by-step explanation:

This question deals with Slope of a line.

Slope tells how vertical a line is.

The more the slope is, the more the line is vertical. When slope is zero, the line is horizontal.

To find the slope, we take the ratio of how much the line's height increases as we go forward or backward on the horizontal axis.

For first climbing equipment rise = 6 feet, run(horizontal) = 4 feet

Thus, slope =  6/4 = 3/2 ≈ 1.5

For second climbing equipment rise = 10 feet, run(horizontal) = 6 feet

Thus, slope=   10/6 = 5/3 ≈ 1.66

Thus,

Slope of first climbing equipment = 3/2 < slope of second climbing equipment = 5/3

Thus, First Option i.e 5/3 > 3/2 , the slope of Climbing equipment at Gym is greater is Correct

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y = x⁴- 5x² + 4 represents the first graph.

y = x(x + 3)(x - 2) represents the second graph.

1) The first polynomial is;

y = x⁴- 5x² + 4

Simplifying this gives us;

y = x⁴- 4x² - x² + 4

y = x²(x² - 4) - 1(x²- 4)

y = (x² - 1)(x² - 4)

y = (x - 1)(x + 1)(x - 2)(x + 2)

Thus, the zeros of this polynomial are; x = -2, -1, 1, 2

From the given graphs attached, first graph has the zeros (x-intercepts) as x = -2, -1, 1, 2.

So graph (1) represents the polynomial  y = x⁴- 5x² + 4

2). The second graph shows the x-intercepts at x = -3, 0, 2

Since, y = x(x + 3)(x - 2) is the polynomial with x-intercepts at x = -3, 0, 2

Therefore, y = x(x + 3)(x - 2) represents the second graph.

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Answer:

20%

Step-by-step explanation:

Half of 2 = 1

Half of 1.6 = 0.8

1 - 0.8 = 0.2

0.2 × 100 = 20%

Answer:

the first equation could be something along the lines of [tex]y=3x^{2}[/tex] then the second is [tex]y=3x^{2} -3\\[/tex]

Step-by-step explanation:

this is how shifting works

Answer:

[tex]\huge\boxed{\sf x - 3 }[/tex]

Step-by-step explanation:

Let the certain number be x

So,

Sum is to add so we'll use the sign +

= x + (-3)

We know that + and - makes - because - sign will flip the + sign and make it negative, So:

= x - 3

[tex]\rule[225]{225}{2}[/tex]

Solution: c-3

[tex]\searrow[/tex]

Detailed explanation:

[tex]\searrow[/tex]

This problem tells us to convert the verbal phrase (in words) "the sum of a certain number and -3" into an algebraic expression, which is written in numbers.

Let's start by taking a look at our problem.

"the sum of a certain number and -3". We can first write this "certain number" as one letter (any letter you want). Let it be c.

Our expression already looks a little easier: "the sum of c and -3".

Now, the word "sum" tells us to add. So we should add c and -3.

[tex]--\mapsto\boldsymbol{c+-3}[/tex]

Which is the exact same thing as [tex]\boldsymbol{c-3}[/tex].

Voila! There's our answer.

______________________

Hope I helped! Best wishes.

Reach far. Aim high. Dream big.

_______________________

[tex]3x ^{2} \: + \: {6x}^{3} \: - \: 9 {x}^{2} y[/tex]

[tex] \boxed{ \bold{3 {x}^{2} \: \times \: (1 \: + \: 2x \: - \: 3y)}}[/tex]

Answer:

[tex]\boxed{3x²(1 + 2x - 3y)}[/tex]

Step-by-step explanation:

3x squared + 6 x cube - 9x squared y

To factor

Solution:

A process when algebraic expression is expressed as a product of two or more expressions is factorisation.

ATP,

Square = a²

Cube = a³

We can see that 3x^2 is common in this expression.

So rewrite as:

Done!

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:y-6 = 3(x + 2) [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

Equation of line in point - slope form :

[tex]\qquad \tt \rightarrow \:y-y_1 = m(x - x_1)[/tex]

Here :

[tex]\qquad \tt \rightarrow \:y - 6 = 3(x - ( - 2))[/tex]

[tex]\qquad \tt \rightarrow \:y - 6 = 3(x + 2)[/tex]

The number of primes less than 190 using the principle of inclusion-exclusion are 42

The principle of inclusion-exclusion is known as a counting technique that computes the number of elements satisfying at least one of several properties and guaranteeing that the numbers are not counted twice.

Prime numbers are numbers only divisible by 1 and itself.

Prime numbers less than 190 are:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181

They are 42 in number

Therefore, the number of primes less than 190 using the principle of inclusion-exclusion are 42

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Answer:

50

Step-by-step explanation:

if last year 100% of the tomatoes were produced and this year 40% less were produced then that would mean 60% of tomatoes were produced this year.

if 60% = 30 then

100% = ?

100x30÷60

Answer:

Given:

Let, the slope of the line passing through the point ( m) = -2

The line passing through the point M(-1,-3)= (x1 , y1)

The equation of the line passing through the point M(-1,-3) is

y-y1 = m (x-x1)

or, y-(-3) = -2 (x-(-1))

or, y+3 = -2 (x+1)

or, y+3 = -2x-2

or, 2x+y = -2-3

Hence, 2x+y =-5 is the required equation.

(a) is the correct answer .

Answer:

[tex]\boxed {\frac{dy}{dx}= 2x}[/tex]

Step-by-step explanation:

Solving :

⇒ log y = log (x²)

⇒ log y = 2 log x

⇒ [tex]\mathsf {\frac{1}{y} \frac{dy}{dx} = \frac{1}{x} \times 2}[/tex]

⇒ [tex]\mathsf {\frac{dy}{dx}= 2x}[/tex]

Answer:

y’ = 2x

Step-by-step explanation:

Let y = f (x), take the natural logarithm of both sides ln (y) = ln (f (x))

ln (y) = ln (x²)

Differentiate the expression using the chain rule, keeping in mind that y is a function of x.

Differentiate the left hand side ln (y) using the chain rule.

y’/y = 2 In (x)

Differentiate the right hand side.

Differentiate 2 ln (x)

y’/y = d/dx = [ 2 In (x) ]

Since 2 is constant with respect to xx, the derivative of 2 ln (x) with respect to x is 2 d/dx [ln (x)]

y’/y = 2 d/dx [In (x)]

The derivative of ln (x) with respect to x is 1/x.

y’/y = 2 1/x

Combine 2 and 1/x

y’/y = 2/x

Isolate y' and substitute the original function for y in the right hand side.

y’ = [tex]\frac{2}{x}[/tex] x²

Factor x out of x².

y’ = [tex]\frac{2}{x}[/tex] (x * x)

Cancel the common factor.

y’ = [tex]\frac{2}{x}[/tex] (x * x)                     (The x that is under 2 and the other x that I have underlined are the ones that cancel out)  

Rewrite the expression.

y’ = 2x

So therefore, the answer would be 2x.

Answer:

Period = 4 units

Step-by-step explanation:

Standard form of a tangent function:

[tex]f(x)=\sf A \tan(B(x+C))+D[/tex]

The tangent function has a vertical asymptote whenever cos(x) = 0

The tangent function does not have an amplitude because it has no maximum or minimum value.

Given function:

[tex]y=\tan \left(\dfrac{\pi}{4}\left(x-\dfrac{\pi}{3}\right)\right)[/tex]

Therefore:

Answer: 4 units

Step-by-step explanation:

Using the graph attached, If g(x) = 2f(x-1), the graph of the function will be:  g(x) = x - 7.

Using the graph, the function is:

f(x-1) =1/2 (x-1) - 3

f(x-1) = 1/2x - 1/2 - 3/1

f(x-1) = 1/2x - 7/2

So:

g(x) = 2f(x-1)

g(x) = 2 (1/2x - 7/2)

g(x) = x - 7

Therefore,:

At  x = 0,  y = -7

y = 0, x = -7

Thus, Using the graph attached, If g(x) = 2f(x-1), the graph of the function will be:  g(x) = x - 7.

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Got it right on Plato/Edmentum UωU <3

Answer: [tex]2x^2+2x-4-\frac{4}{x+1}[/tex]

Not a factor because there is a remainder.

Step-by-step explanation:

Let's use synthetic division to solve this..

-1  ║ 2 | 4 | -2 | -8

   ║    | -2| -2 |  4

   ║ 2 | 2|  -4 |  -4

[tex]2x^2+2x-4-\frac{4}{x+1}[/tex]

PS: if anyone knows a better way to do a synthetic division chart please let me know.

Answer+Step-by-step explanation:

[tex]f^{-1}\left( x\right) =\frac{1}{7} x^{2}+3 \ ,\text{where}\ x\geq 0[/tex]