5. Carla babysits and tutors to make extra money. She babysits for $5 an hour and tutors for $10 an hour.
She can only work at most 15 hours a week. She wants to go on a trip with her friend and needs to
make $95 dollars this week to cover the cost of the trip. Graph a system of linear inequalities that
represents this situation. Using this graph, identify at least one combination of hours that will NOT be a
solution to this system of inequalities.
I

Answer:

-2090

Step-by-step explanation:

1)  Remove parentheses.

-2 -8 -32 -2048

2) Simplify - 2 - 8 to -10.

-10 - 32 - 2048

3) Simplify -10-32 to -42.

-42 - 2048

4) Simplify.

-2090

The slope and y-intercept will be the negative 5/2 and 4.

The complete question is attached below.

The equation of line is given as

y = mx + c

Where m is the slope and c is the y-intercept.

The equation is given below.

y > -(5/2)x + 4

The slope and y-intercept will be the negative 5/2 and 4.

The graph is also attached below.

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Answer:

Option C:

Step-by-step explanation:

Hello!

The sum of all angles in a triangle is 180°.

Add up all the angles and solve for x by setting the equation to 180°.

Now that we solved for x, we can plug it back into each equation to solve for each angle.

The answer is Option C:

Answer:

I believe you're trying to say 5+x= 3/4

Subdivide the interval [0, 3] into 6 subintervals of equal length, ∆x = (3 - 0)/6 = 1/2. Then the partition is

[tex]\left[0,\dfrac12\right] \cup \left[\dfrac12,1\right] \cup \left[1,\dfrac32\right] \cup \cdots \cup \left[\dfrac52,3\right][/tex]

The right endpoint of the [tex]i[/tex]-th subinterval is

[tex]r_i = \dfrac12 + (i-1)\times\dfrac12 = \dfrac i2[/tex]

with [tex]i\in\{1,2,3,\ldots,6\}[/tex].

Then the area under the [tex]y=x^2[/tex] on the interval [0, 3] is approximately

[tex]\displaystyle \int_0^3 x^2 \, dx \approx \sum_{i=1}^6 (r_i)^2 \Delta x = \frac18 \sum_{i=1}^6 i^2[/tex]

Recall that

[tex]\displaystyle \sum_{n=1}^N n^2 = \frac{N(N+1)(2N+1)}6[/tex]

Then the approximate value of the area is

[tex]\displaystyle \int_0^3 x^2 \, dx \approx \frac{6\times7\times13}{48} = \boxed{\frac{91}8}[/tex]

The actual value of the area is 9, so this approximation is an overestimation, as is always the case when using a right endpoint sum for an increasing function.

Answer:

11

Step-by-step explanation:

(f + g)(x)

= f(x) + g(x)

= x² - 6x - 4 +5x + 3 ← collect like terms

= x² - x - 1

then

(f + g)(- 3) = (- 3)² - (- 3) - 1 = 9 + 3 - 1 = 11

Answer:

11

Step-by-step explanation:

F(–3)=(–3)²–6(–3)–4===> 9+18–4=23

g(–3)=5(–3)+3=‐15+3=–12

23–12=11

The length of the diagonal LN would be 8.60 units.

To find the distance between the two coordinates, We use distance formula ;

[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}[/tex]
Lets put the values of L and N,
d= [tex]\sqrt{(0 - -5)^2 + (-3-4)^2}[/tex]

d =[tex]\sqrt{25+49}[/tex]

d= [tex]\sqrt{74}[/tex]

d= 8.60 units

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Answer:

Bricks for 1 wall= 405

If there are 5 rooms with 4 walls,

Walls= 5 x 4= 20

Bricks= 405 x 20

= 8100

Mark me the brainliest pleeeeeaseee :)

Answer:

(5,18)  & (-5 , 38)

Step-by-step explanation:

  A linear equation represented by a line in a graph intersect the quadratic equation represented by a parabola zero, one or two times.

f(x) = x² - 2x + 3   -------------------(I)  

f(x) = -2x + 28   ---------------------(II)

x² - 2x + 3 = -2x + 28

x² - 2x + 2x + 3 - 28 = 0

x² - 25 = 0

x²         = 25

         x = √25 = √5*5

        x = ± 5

Plugin x = 5 in equation (II),

                    f(5) = -2*5 + 28

                          = -10 + 28

                          = 18

(5 , 18)

Plugin x = -5 in equation (II),

 f(-5) = -2*(-5) + 28

         = 10 + 28

         = 38

(-5, 38)

Answer:

(5, 18) and (-5, 38)

Step-by-step explanation:

Given system of equations:

1) f(x) = x² - 2x + 3 ⇒ y = x² - 2x + 3

2) f(x) = -2x + 28 ⇒ y = -2x + 28

Solve using the Substitution Method:

Step 1: Substitute the the first equation into the second equation.

⇒ x² - 2x + 3 = -2x + 28

Step 2: Solve for x.

x² - 2x + 3 = -2x + 28 [ Add 2x to both sides. ]

x² - 2x + 2x + 3 = -2x + 2x + 28

⇒ x² + 3 = 28 [ Subtract 28 from both sides. ]

x² + 3 - 28 = 28 - 28

⇒ x² - 25 = 0 [ Factor using the following rule: a² - b² = (a - b)(a + b). ]  

(x - 5)(x + 5) = 0

⇒ x - 5 = 0, x + 5 = 0 [ Solve for the values of x. ]

x - 5 + 5 = 0 + 5, x + 5 - 5 = 0 - 5

⇒ x = 5, x = -5

Step 3: Solve for y.

Substitute the found x-values into one of the given equations.

y = x² - 2x + 3 ⇒ y = (5)² - 2(5) + 3 ⇒ y = 25 - 10 + 3 ⇒ y = 18

y = x² - 2x + 3 ⇒ y = (-5)² - 2(-5) + 3 ⇒ y = 25 + 10 + 3 ⇒ y = 38

The solutions to the system of equations are:

⟹ x₁ = 5, y₁ = 18 ⇒ (5, 18)

⟹ x₂ = -5, y₂ = 38 ⇒ (-5, 38)

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72

x varies directly as y

hence x=k y

k=6

y=12

x=6×12

x=72

12 will be opposite to 24. Then the number of the people are sitting at the table will be 24.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

The several people are sitting evenly spaced around a circular table and the positions are labelled 1, 2, 3 and so on.

The people at positions 3 and 15 are directly opposite each other.

Then the number of the people are sitting at the table will be

1 is opposite to 13

2 is opposite to 14

3 is opposite to 15

Similarly, 12 will be opposite to 24.

Then the number of the people are sitting at the table will be 24.

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Answer:

2nd box, 4th box and  5th box

Step-by-step explanation:

The correct answer is option A which is the value a₃₂ = 7.

A matrix is a specific arrangement of items, particularly numbers. A matrix is a row-and-column mathematical structure. The a_{ij} element in a matrix, such as M, refers to the i-th row and j-th column element.

In the given matrix the value of a₃₂ means that the element of the third row and the second column.

So the value of a₃₂ will be 7. which is present in the third row and the second column.

Therefore the correct answer is option A which is the value a₃₂ = 7.

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Answer:

[tex]x = -\frac{15}{2}[/tex]

Step-by-step explanation:

Hello!

The formula for the AOS is given to you, and you simply have to plug in the information given by the equation.

Equation of a Parabola (Standard): [tex]y = ax^2 + bx + c[/tex]

Comparing it to our equation:

Plug it in to the AOS formula:

You only have to input 15 in to the correct box since the negative sign is already placed for you.

Answer:

3. Definition of Midpoint

4. VAT, Vertical Angles Theorem

5. ASA, Angle-Side-Angle Theorem

Answer:

8 + 7.

Step-by-step explanation: It is absolute value.

Answer: 14

Step-by-step explanation:

because 8 +4 is 14

£36

20+25=45          Take away 13 and it's 32.   32+4 (the shipping charge) is 36. So Ruth pays 36 pounds.

Answer:

b I think.

Step-by-step explanation:

sorry if im wrong

Answer:

what?????????????????

The height of the volume of the container is 93.898cm.

We have given that,

An oatmeal container has a volume of 269 cubic inches.

Volume=269 cubic inches.

Radius=3cm

[tex]V=\pi r^2h[/tex]

[tex]269=\pi (3)^2h\\\269=9\pi h\\\h=\frac{269\pi }{9}\h=93.89871[/tex]

The height of the volume of the container is 93.898cm.

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Answer:

This point is not on the line, NOT TRUE

Step-by-step explanation:

The equation of the line is written in the slope-intercept form,

y = mx + b

where m represents the slope

           b represents the y-intercept

where the format of a point is (x, y)

Given: y = 7x (6/7, -1/4)

we can plug in the point (6/7, -1/4)

-1/4 = 7(6/7)

-1/4 = 6

-1/4 does not equal 6 so this point is not on the line

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Answer:

-x+4, 4+-x

Step-by-step explanation:

Obtain these answers by moving the X and 4 around and multiplying the equation by -1

Answer:

[tex]y=-8x+5[/tex]

Slope-intercept form:

[tex]\implies y=mx+b[/tex] [tex](\text{m=slope};\text{b=y-intercept})[/tex]

Using the slope-intercept form, let's identify the other slopes:

Option A:

[tex]y=-8x+5[/tex]  

[tex]\text{slope}=-8[/tex]

Option B:

[tex]y-9=-2(x+1)[/tex] (This equation is in point-slope form, the slope it too the left, making it -9)

[tex]\text{slope}=-9[/tex]

Option C:

[tex]y=7x-3[/tex]

[tex]\text{slope}=7[/tex]

Option D:

[tex]y+2=6(x+10)[/tex]

[tex]\text{slope}=2[/tex]  (Using point-slope terms, we can find the slope.)

⇒ A 'steep'est slope is closest to almost having a vertical slope or pitch, or  relatively high gradient, as a hill, an ascent, stairs, etc.

[tex]\text{This could be a line }[/tex] ⇒ ([tex]\text{positive or negative}[/tex])

Hence, the linear function with the steepest slope is Option A: [tex]y=-8x+5[/tex].

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Answer: 1

Step-by-step explanation:

[tex]2x-\sqrt{5}=2x^{1}-\sqrt{5}[/tex], and thus the highest exponent of x is 1

Answer:

Range: (-10 , 14)

Step-by-step explanation:

Given information:

Range: (x , y)?

Plug in domain of x = -4 and x = 4 into equation to find range.

f(-4) = 3 * -4 + 2 = -10

f(4) = 12 + 2 = 14

Range: (-10 , 14)