Answer:
[tex]\boxed{\boxed{\sf x=4}}[/tex]
Step-by-step explanation:
[tex]\sf 5 = 2x -3[/tex]
1) Switch Sides:
[tex]\longmapsto\sf 2x-3=5[/tex]
2) Add 3 to both sides:
[tex]\longmapsto\sf 2x-3+3=5+3[/tex]
[tex]\longmapsto\sf 2x=8[/tex]
3) Divide both sides by 2:
[tex]\longmapsto\sf \cfrac{2x}{2}=\cfrac{8}{2}[/tex]
[tex]\longmapsto\sf x=4[/tex]
_____________________________
Given the two equations below, determine which statement best describes the graph of the equations.
y=x + 6
y = x+ 17
A.
The two lines given by the above equations intersect (but are not perpendicular).
B.
The two lines given by the above equations coincide.
C.
The two lines given by the above equations are perpendicular.
D.
The two lines given by the above equations are parallel.
Answer:
Graph.
y=x+6y=x+17
Step-by-step explanation:
If using the method of completing the square to solve the quadratic equation
x^2+2x – 31 = 0, which number would have to be added to "complete the
square"?
==
Answer:
See belowStep-by-step explanation:
Given equation:
x² + 2x - 31 = 0Complete square as follows:
x² + 2x + 1 - 31 = 1(x + 1)² = 32x + 1 = ± √32x = - 1 ± 4√2Step-by-step explanation:
We need to solve the equation using completing the square method .
=> x² - 2x - 31 = 0
=> x² -2*1*x + 1² - 1² - 31 = 0
=> ( x -1)² - 32 = 0
=> (x+1)² = 32
=> x +1 = ±√32
=> x = ±4√2 - 1
A bag contains 12 red marbles. The ratio of red marbles to blue marbles is 3:4. Find the number of blue marbles in the bag. blue marbles
Answer: 4
Step-by-step explanation:
since they are comparing it red to blue marbles and in 3:4 ratio 4 is the second one and it is comparing red to BLUE the second 1 is blue
Can you please help me
Answer:
63
Step-by-step explanation:
27/6=4.5
14*4.5=63
Please help i need to do this and study a different class later
Answer:
im not sure sorry
Step-by-step explanation:
An urn contains p black balls, q white balls, and r red balls; and n balls are chosen without replacement. a. Find the joint distribution of the numbers of black, white, and red balls in the sample. b. Find the joint distribution
The joint distribution of the numbers of the three colours in the sample without replacement is:
[tex]\mathbf{P(A=a,B=b,C=c) = \dfrac{\Big( ^{p}_{ A} \Big) \Big( ^{q}_{ B} \Big) \Big( ^{r}_{ C} \Big) }{ \mathbf{\Big( ^{p+q+r}_{ \ \ \ n} \Big) } }\ \ \ \ where; n = A+B+C}[/tex]
Let consider A, B, and C to denote the three variables that are black, white, and red balls in the sample.
i.e.
n = A + B + C
Now, the numbers of ways 'n' balls are chosen without replacement in an urn that comprises of p black balls, q white balls, and r red balls can be computed as follows:
[tex]\mathbf{\implies \Big( ^{p+q+r}_{ \ \ \ n} \Big) }[/tex]
Now, the number of ways whereby A black balls can be chosen from p black balls is expressed as:
[tex]\mathbf{\implies \Big( ^{p}_{ A} \Big) }[/tex]
The number of ways whereby B white balls can be chosen from q white balls is expressed as:
[tex]\mathbf{\implies \Big( ^{q}_{ B} \Big) }[/tex]
The number of ways whereby C red balls can be chosen from r red balls is expressed as:
[tex]\mathbf{\implies \Big( ^{r}_{ C} \Big) }[/tex]
Therefore, we can conclude that the joint distribution of the numbers of the three colours in the sample without replacement is:
[tex]\mathbf{P(A=a,B=b,C=c) = \dfrac{\Big( ^{p}_{ A} \Big) \Big( ^{q}_{ B} \Big) \Big( ^{r}_{ C} \Big) }{ \mathbf{\Big( ^{p+q+r}_{ \ \ \ n} \Big) } }\ \ \ \ where; n = A+B+C}[/tex]
Learn more about joint distribution here:
https://brainly.com/question/17283589?referrer=searchResults
The total number of public electric charging units available for hybrid vehicles has increased exponentially since 2005. The number of outlets A(t) at these alternative fueling stations t years after 2005 can be approximated by A(t)=233(2.08)t, where t=0 corresponds to 2005. How many outlets were available in 2007, in 2009, in 2010?
a.
The number of outlets in 2007 are 1008 outlets
Since the number of outlets A(t) at these alternative fueling stations t years after 2005 is [tex]A(t) = 233(2.08)^{t}[/tex] with t = 0 corresponding to 2005.
To find the number of outlets in 2007, we substitute t = 2 into the equation.
So,
[tex]A(t) = 233(2.08)^{t}\\A(2) = 233(2.08)^{2}\\A(2) = 233(4.3264)\\A(2) =1008.0512[/tex]
A(2) ≅ 1008 outlets (we round down to the nearest whole number since we can only have a whole number of outlets).
So, the number of outlets in 2007 are 1008 outlets
b.
The number of outlets in 2009 are 4361 outlets
To find the number of outlets in 2009, we substitute t = 4 into the equation.
So,
[tex]A(t) = 233(2.08)^{t}\\A(4) = 233(2.08)^{4}\\A(4) = 233(18.72)\\A(4) =4361.23[/tex]
A(4) ≅ 4361 outlets (we round down to the nearest whole number since we can only have a whole number of outlets).
So, the number of outlets in 2009 are 4361 outlets
c.
The number of outlets in 2010 are 9071 outlets
To find the number of outlets in 2010, we substitute t = 5 into the equation.
So,
[tex]A(t) = 233(2.08)^{t}\\A(5) = 233(2.08)^{5}\\A(5) = 233(38.93)\\A(5) = 9071.36[/tex]
A(5) ≅ 9071 outlets (we round down to the nearest whole number since we can only have a whole number of outlets).
So, the number of outlets in 2010 are 9071 outlets
Learn more about exponential increase here:
https://brainly.com/question/18261561
The number of students in a chess club decreased from 26 to 15. What is the percent decrease? Round your answer to the nearest percent.
Answer:
42%
Step-by-step explanation:
26 - 15 = 11
Take your decrease and divide it by the original price:
11/26 = 0.4230
Multiply 0.4230 by 100 to find the percent:
42.3
Round your answer and you would get -
42%
Answer:
42%
Step-by-step explanation:
You divide 15 by 26 and get 0.5769 and it continues with other numbers. to the nearest percent is 58. Then you subtract it from 100 and get 42%.
Please help!!! Due today!! Will mark brainliest!!!!
Answer:
$231Step-by-step explanation:
Given:
A = 44000i = 0.375% or 0.00375n = 12*12 = 144 (12 years and 12 periods per year)d = ?Use the given formula and find d:
[tex]44000 = d(\frac{(1+0.00375)^{144}-1}{0.00375})[/tex][tex]44000 = d*190.47[/tex][tex]d = 44000/190.47[/tex][tex]d = 231[/tex]express the recurring decimal 0.034 as a fraction in its simplest form
Answer:
It's 17/500
Step-by-step explanation:
I took the same test and I got it right!<3 pLeAsE gIvE bRaInLiEsT tYsM<3 HaVe A wOnDeRfUl... WeEkEnD
Find the volume of the sphere.
6
Answer 35
A sum of 2 integers is 41 and their difference is 5. Find the integers.
Answer:
A = 22
B = 19
Explanation:
Numbers one and two will be a variable A and B respectively.
A + B = 41 Equation one
A + B = 5 Equation two
Isolate one of the variables. Let's use A
A + B = 41 = A = 41 - B
Now replace the A in Equation two.
(41 - B) - B = 5
Simplify: 41 - 2B = 5
Isolate variable: 38 = 2B --> B = 19
Use the value of B to find A
A = 41 - B = 41 - 19 = 22
So the answer is A = 22 and B =19
what is 32,020.20 rounded to the nearest tenths
Answer:
32,020
Explanatiojn:
Which is the quotient for
2
.
21
÷
0
.
34
?
A.
0.65
B.
6.05
C.
6.5
D.
65
Answer:
The answer is 6.5
Step-by-step explanation:
A car renting agency charges a fixed rate of $8 per day plus 8 cents per mile. If a family paid the agency $260 for the use of a car on a 2,450 mile trip, how many days was the car use
Answer: 8 days your welcome (:
Answer:
8 days
1day = $8.08
$8.08 * 8 = $64.64 so this is wrong.
$260/$8.08= about 31 days.
WILL MARK BRAINLIEST!!
Answer:
C = (A*P - 8.4Y -330T + 200I) / 100
Step-by-step explanation:
P = (8.4Y + 330T + 100C -200I ) / A
now we have to calculate completed passes C for given P, Y, T, I, A
A*P = 8.4Y + 330T -200I +100C
100C = A*P - 8.4Y - 330T + 200I
C = (A*P - 8.4Y -330T + 200I) / 100
I just solved the equation for C
HELP ASAP DO NOT SPAM YOU WILL BE REPORTED 15 POINTS I WILL MARK BRAINIEST Graph the solution to this inequality on the number line. w – 0.7 > -1.1 First select the correct ray. Then select the location of the endpoint to plot the inequality on the number line.
There are 24 red cars to every 96 blue cars. How many blue cars are there if there are 96 red cars?
Dividing the ratio of red and blue cars:
96 /24 = 4
There are 4 times as many blue cars as red cars.
Multiply the number of red cars by the scale factor:
96 red x 4 = 384 blue cars
Answer:
384 blue cars
Step-by-step explanation:
Here's how I do all of this in my head:
Divide 96 by 24:
96 ÷ 24 = 4
Now that we know that the number we need is 4, all we have to do is multiply both factors by 4.
96 × 4 = 384
24 × 4 = 96 (which is the number we're looking for)
So now that we have 96 red cars, we can see that there's 384 blue cars, which will be your answer.
I hope I helped, and a Branliest is always appreciated! ☺
Matt bought a 12-pack of water for $10.32. What was the unit rate?
We want to find the unit rate of the bottles of water given that we know that the cost of 12 bottles is $10.32, we will find that the unit rate is:
r = 1.16 (bottles/$)
The unit rate is defined as the rate of change per unit, in this particular case, the unit rate would be the cost of every single bottle of water.
Here, we do know that for $10.32, you get 12 bottles.
The unit rate is just given by the quotient between these two values:
(12 bottles)/($10.32) = 1.16 (bottles/$)
Meaning that the cost of every single bottle is $1.16
If you want to learn more, you can read:
https://brainly.com/question/18065083
Juanita borrowed $600 to purchase a new computer. She was charged 7% interest for two years. She used the simple interest formula to find the interest.
I = 600(7)(2)
What error did Juanita make and how will her error affect the interest she calculates? Explain.
please help
Answer:
The error she made was multiplyng by 7. This would affect her calculations as 7 in percentage form is represented as 700%. The 700% interest would basically mean she owes 7 times the amount she borrowed. The correct number would be 0.07 because 0.07 represents 7% which is the interest. Another error that was made was multiplying 2 to the entire equation. The only thing that needs to be doubled is the interest as every year the interest takes 7%. The correct way would be to put 0.07*2 in paranthesis. The correct equation is
I = 600(0.07*2)
1) A survey asked the question, “Do you think a vaccination should be mandatory to enter
shopping areas?!” to a random sample of 1068 Jordanians. The results showed that 71.2%
responded that vaccination should mandatory. Determine which of the following is an
observation, a variable, a sample statistic (value calculated based on the observed sample), or a
population parameter.
(a) A Jordanian that was asked the question.
(b) The response of the Jordanian (Yes: vaccination should be mandatory. No: vaccination
should not be mandatory).
(c) 71.2%.
(d) The percentage of all Jordanians who agreed with the statement that vaccination should
be mandatory to enter shopping areas.
Given that a survey asked the question, "Do you think a vaccination should be mandatory to enter shopping areas?" to a random sample of 1068 Jordanians, and the results showed that 71.2% responded that vaccination should mandatory, to determine which of the following is an observation, a variable, a sample statistic (value calculated based on the observed sample), or a population parameter, the following statistical reasoning must be performed:
(a) A Jordanian that was asked the question.
-An observation, as the person questioned is part of the study and therefore, it is an individual observation that makes up the trend.
(b) The response of the Jordanian.
-A variable, since it is one of the two possible answers that the survey has.
(c) 71.2%.
-A population parameter, because it represents a specific percentage with respect to the total population.
(d) The percentage of all Jordanians who agreed with the statement that vaccination should be mandatory to enter shopping areas.
-A sample statistic, since it is a statistical element that arises from the survey.
Learn more in https://brainly.com/question/17716064
Lines A and B are parallel
Answer:
dddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
Step-by-step explanation:
Answer:
....................
6. (a) Find a recurrence relation for the number of n-digit binary sequences with no pair of consecutive 1s. (b) Repeat for n-digit ternary sequences
(a) There are 2 sequences of length 1 that fit the bill: 0 and 1. So if [tex]b_n[/tex] is the number of permissible sequences, then [tex]b_1=2[/tex].
To the sequence 0, we can attach either 0 or 1 at the end, while the sequence 1 must be followed by 0. Then the permissible sequences of length 2 are 00, 01, and 10, so [tex]b_2=3[/tex].
Now consider a sequence of length n + 1, of which there are [tex]b_{n+1}[/tex].
• If the last digit is 0, then we got this sequence by simply joining 0 to one of [tex]b_n[/tex] sequences. In other words, there are [tex]b_n[/tex] permissible sequences of length n + 1 that end in 0.
• If the last digit is 1, then the previous digit must have been 0. Put another way, we join 01 to a permissible sequence of length n - 1 (there are [tex]b_{n-1}[/tex] of them). So there are [tex]b_{n-1}[/tex] permissible sequences of length n + 1 that end in 1.
These cases are mutually exclusive, so the number of (n + 1)-length permissible sequences is given by
[tex]\begin{cases}b_1 = 2 \\ b_2 = 3 \\ b_{n+1} = b_n + b_{n-2} & \text{for }n\ge2\end{cases}[/tex]
(b) The reasoning for a permissible ternary sequence is similar. Let [tex]t_n[/tex] be the number of sequences of length n not containing 11.
We first note that [tex]t_1 = 3[/tex], since we can have 0, 1, or 2; and [tex]t_2 = 8[/tex], since we can have 00, 01, 02, 10, 12, 20, 21, or 22.
Consider a sequence of length n + 1 ([tex]t_{n+1}[/tex] of these).
• If the last digit is 0, then we joined 0 to a permissible sequence of length n. So there are [tex]t_n[/tex] permissible sequences of length n + 1 ending in 0.
• If the last digit is 1, then the last two digits must be either 01 or 21. Since there are 2 choices for the n-th digit, there are [tex]2t_{n-1}[/tex] permissible sequences of length n + 1 ending in 1.
• If the last digit is 2, then we essentially have the same situation as if the sequence ended in 0, so there are [tex]t_n[/tex] sequences of length n + 1 ending in 2.
Then the recurrence for ternary permissible sequences is
[tex]\begin{cases}t_1 = 3 \\ t_2 = 8 \\ t_{n+1} = 2t_n + 2t_{n-1} & \text{for }n\ge2\end{cases}[/tex]
Which one is this. I don't really understand
Answer:
i need points and this is a long question from before
thanks for the points
Step-by-step explanation:
It’s for pre college
Answer:
answer is I do'not no I am sorry
x divide 5 =20 solve equation for x
Answer:
x = 100
Step-by-step explanation:
[tex]\frac{x}{5}=20[/tex]
[tex]5*\frac{x}{5} =20*5[/tex]
x = 20 * 5
x = 100
Hope This Helps
Sophia's bank account
statement said she had -$25.
She deposited $47 into her
account. What is Sophia's
balance after she made the
deposit?
Answer:
22
Step-by-step explanation:
10.
Which equation is represented by the graph?
A. y = 1/2x^2 - 2x + 1
B. y = x2 − 4x + 1
C. y = -1/2x^2 - 2x + 1
D. y = −x2 − 4x + 1
Answer:
D. y = −x2 − 4x + 1
Step-by-step explanation:
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Down
Vertex: ( − 2 , 5 )
Focus: ( − 2 , 19 /4 )
Axis of Symmetry: x= − 2
Directrix: y = 21 /4
x y
− 4 1
− 3 4
− 2 5
− 1 4
0 1
6/23 divided by 1/5 plz help
Answer:
30 / 23
Step-by-step explanation:
to divide two fractions, multiply by the reciprocal.
The reciprocal of 1/5 is 5/1. We will rewrite the equation as:
[tex]\frac{6}{23}[/tex] times [tex]\frac{5}{1}[/tex]
6 x 5 = 30
23 x 1 = 23
the answer is 30 / 23
The Quotient is 30/23.
What is Division?One of the four fundamental mathematical operations, along with addition, subtraction, and multiplication, is division. Division is the process of dividing a larger group into smaller groups so that each group contains an equal number of things.
Given:
6/23 divided by 1/5
As, division is not possible in fraction so we will perform the multiplication
= 6/23 ÷ 1/5
= 6/23 x 5
= 30/ 23
Learn more about Division here:
https://brainly.com/question/21416852
#SPJ5
$4.95 marked up 80%
Answer:
$8.91
Step-by-step explanation:
Multiply $4.95 times 0.80 ( convert 80% to a decimal ) and that will equal 3.96 .
Then , since you're marking it up , you're gonna add the 3.96 to 4.95 which will equal $8.91 .
:)
