To solve the given question, we need to use the distributive property and collect like terms. In summary, the distributive property is a useful tool in simplifying expressions.
First, we need to distribute the fraction 4/5 to the expression inside the parenthesis, which gives us 4/5 x 1/4c - 4/5 x 5. Then, we can simplify the expression by multiplying the two fractions and combining the terms. This gives us (1/5)c - 4.
Therefore, the simplified expression is (1/5)c - 4. We can use this expression to evaluate the given expression for any value of c. For example, if c = 15, then the expression becomes (1/5) x 15 - 4 = 3 - 4 = -1.
In summary, the distributive property is a useful tool in simplifying expressions.
By distributing a term to each term inside a set of parentheses, we can collect like terms and simplify the expression. In this case, we used the distributive property to simplify a fraction and a constant and then combined the like terms to obtain the final answer.
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what is x^2-3x=70 in standard form?
Answer: x^2 + 3x - 70 = 0
Step-by-step explanation:
Target INT1: I can correctly antidifferentiate basic functions and identify antiderivatives nd the most general antiderivatives of each function. 1. y = 1 - x^2 + x^2 + 3x^4
2. g(x) = cos x + x
3. h(x) = 5
The antiderivative of h(x) is 5x + C.
We can simplify the function y as y = 1 + 3x^4. Now, we can integrate term by term as:
∫ y dx = ∫ (1 + 3x^4) dx
= x + (3/5)x^5 + C
So, the antiderivative of y is x + (3/5)x^5 + C.
The antiderivative of cos(x) is sin(x) and the antiderivative of x is (1/2)x^2. Therefore, we can integrate term by term as:
∫ g(x) dx = ∫ (cos x + x) dx
= sin(x) + (1/2)x^2 + C
So, the antiderivative of g(x) is sin(x) + (1/2)x^2 + C.
The antiderivative of any constant is the constant times x. Therefore, we can integrate h(x) as:
∫ h(x) dx = ∫ 5 dx
= 5x + C
So, the antiderivative of h(x) is 5x + C.
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Use the random list of 100 numbers below and the assignations 0-4 to represent girls and 5-9 to represent boys to answer the question. Determine how many groups contain at least three girls and use the information to answer the questions below.
The example's random list had 25 groups containing three girls, a probability of 25 %. The amount of groups of this random list is (more or less than) ______ the example's random list. The probability of the this random list is therefore (lower or higher then) ________ the example's random list.
The probability of this random list is therefore the same as the example's random list, which is 25%.
What is the probability?To determine the number of groups containing at least three girls, we need to count the number of groups where there are at least 3 numbers between 0 and 4.
We can do this by counting the number of groups that have 0, 1, or 2 numbers between 0 and 4, and subtracting this from the total number of groups:
Number of groups with 0, 1, or 2 numbers between 0 and 4:
Number of groups with 0 numbers between 0 and 4 = 6 choose 0 * 94 choose 4 = 5,414,200
Number of groups with 1 number between 0 and 4 = 6 choose 1 * 94 choose 3 = 291,301,200
Number of groups with 2 numbers between 0 and 4 = 6 choose 2 * 94 choose 2 = 5,111,640
Total number of groups = 100 choose 5 = 75,287,520
Number of groups with at least 3 numbers between 0 and 4:
= Total number of groups - Number of groups with 0, 1, or 2 numbers between 0 and 4
= 75,287,520 - (5,414,200 + 291,301,200 + 5,111,640)
= 64,460,480
The amount of groups of this random list is the same as the example's random list (both have 100 groups).
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Emma has a wooden sculpture in the shape of a cuboid.
The sculpture is 2. 2 m high, 1. 1 m wide and 0. 55 m thick.
Emma plans to paint all the faces of the sculpture with
three coats of wood varnish.
a How many tins of wood varnish does Emma
need to buy?
b What is the total cost of the wood varnish?
varnish
$ 3. 99
(Size of tin: 100 ml)
20 m2 per litre
a) To find the total surface area of the cuboid, we need to find the area of each face and then add them up.
Area of one face = length x width
Area of top and bottom faces = 1.1 m x 0.55 m = 0.605 m² (2 faces)
Area of front and back faces = 2.2 m x 0.55 m = 1.21 m² (2 faces)
Area of side faces = 2.2 m x 1.1 m = 2.42 m² (2 faces)
Total surface area = (2 x 0.605) + (2 x 1.21) + (2 x 2.42) = 7.7 m²
Each tin of varnish covers 20 m², so Emma needs:
Number of tins = (total surface area x number of coats) / coverage per tin
Number of tins = (7.7 x 3) / 0.02 = 1155
Emma needs to buy 1155 tins of wood varnish.
b) The cost of each tin of varnish is $3.99 for 100 ml. To find the cost of 1155 tins, we first need to convert the volume of varnish needed into liters.
Volume of varnish needed = (total surface area x number of coats) / coverage per litre
Volume of varnish needed = (7.7 x 3) / 20 = 1.155 liters
The number of tins required to make up 1.155 liters of varnish is:
Number of tins = (1.155 / 0.1) = 11.55
So Emma needs to buy 12 tins of varnish. The total cost is:
Total cost = cost per tin x number of tins
Total cost = $3.99 x 12 = $47.88
The total cost of the wood varnish is $47.88.
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Determine the critical points and the linearizations for the following systems: = (a) x' = (1 + x) sin y, y' = 1 – X – cos y (b) x = 1 - xy, y' = 2 - 43 x – =
a) The critical points are x = -1 and y = nπ, where n is an integer. The linearization of the system near the center is x' = ky, y' = -kx
b) The critical points are (1, 1) and (-1, -1). The linearization of the system near the degenerate critical point is x' = y, y' = 2x + 2y
(a) To find the critical points of the system, we need to solve the equations:
1 + x = 0 and sin y = 0 for x and y, respectively. This gives us x = -1 and y = nπ, where n is an integer. We can also find the linearizations near each critical point by computing the Jacobian matrix:
J(x, y) = [cos y, (1 + x)cos y - sin y; -1, sin y]
At the critical point (-1, nπ), the Jacobian matrix becomes:
J(-1, nπ) = [(-1)^n, 0; -1, 0]
The eigenvalues of this matrix are 0 and (-1)^n, which means that we have a center at (-1, nπ) when n is even, and a saddle point when n is odd. The linearization of the system near the center is:
x' = ky, y' = -kx
where k is a constant determined by the Jacobian matrix. The linearization near the saddle point is:
x' = -y, y' = -x
(b) To find the critical points of the system, we need to solve the equations:
1 - xy = 0 and x - y^3 = 0 for x and y, respectively. This gives us two critical points: (1, 1) and (-1, -1).
We can find the linearizations near each critical point by computing the Jacobian matrix:
J(x, y) = [-y, -x; 1, 3y^2]
At the critical point (1, 1), the Jacobian matrix becomes:
J(1, 1) = [-1, -1; 1, 3]
The eigenvalues of this matrix are -1 - √5 and -1 + √5, which means that we have a saddle point at (1, 1). The linearization of the system near the saddle point is:
x' = (-1 - √5)x - y, y' = x + (3 - √5)y
At the critical point (-1, -1), the Jacobian matrix becomes:
J(-1, -1) = [1, 1; 1, 3]
The eigenvalues of this matrix are 2 and 2, which means that we have a degenerate critical point at (-1, -1). The linearization of the system near the degenerate critical point is:
x' = y, y' = 2x + 2y
This system has infinitely many solutions, since the eigenvalues are equal.
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Alexandra rolls a standard six-sided die, numbered from 1 to 6. which word or phrase describes the probability that she will roll a number between 1 and 6 ( including 1 and 6)?
The probability that Alexandra will roll a number between 1 and 6, including 1 and 6, on a standard six-sided die can be described as "certain" or "100%."
Here's a step-by-step explanation:
1. A standard six-sided die has six faces, numbered from 1 to 6.
2. When rolling the die, each face has an equal chance of landing face up.
3. The question asks for the probability of rolling a number between 1 and 6, which includes all the possible outcomes (1, 2, 3, 4, 5, and 6).
4. Since all outcomes are covered, the probability of this event occurring is 100% or certain.
Therefore, the word or phrase that describes this probability is "certain" or "100%."
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A building is 210 m tall. A scale model is built using a scale factor of 0. 5.
a) Determine the height of the model to the nearest centimeter, if necessary.
b) What are the actual dimensions of the bed, couch, and desk?
a) The height of the scale model is 105 m. b) The actual dimensions of the bed, couch, and desk are twice as large as their corresponding dimensions in the scale model.
a) To determine the height of the scale model, we multiply the height of the actual building by the scale factor of 0.5:
Height of scale model = 0.5 x 210 m = 105 m.
b) Since the scale factor is 0.5, the actual dimensions of the bed, couch, and desk are twice as large as their corresponding dimensions in the scale model.
For example, if the length of the couch in the scale model is 10 cm, then the actual length of the couch is 2 x 10 cm = 20 cm. Similarly, if the width of the desk in the scale model is 8 cm, then the actual width of the desk is 2 x 8 cm = 16 cm.
Therefore, to find the actual dimensions of the bed, couch, and desk, we simply multiply the corresponding dimensions in the scale model by 2.
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Problem
Yoshi is a basketball player who likes to practice by attempting the same three-point shot until he makes the shot. His past performance indicates that he has a
30
%
30%30, percent chance of making one of these shots. Let
X
XX represent the number of attempts it takes Yoshi to make the shot, and assume the results of each attempt are independent.
Is
X
XX a binomial variable? Why or why not?
Choose 1 answer:
Choose 1 answer:
(Choice A)
A
Each trial isn't being classified as a success or failure, so
X
XX is not a binomial variable.
(Choice B)
B
There is no fixed number of trials, so
X
XX is not a binomial variable.
(Choice C)
C
The trials are not independent, so
X
XX is not a binomial variable.
(Choice D)
D
This situation satisfies each of the conditions for a binomial variable, so
X
XX has a binomial distribution
There is no fixed number of trials, so X is not a binomial variable. (Choice B) B is the right response.
Discrete random variables are within the category of binomial random variables. A binomial random variable keeps track of how frequently an event occurs over a predetermined number of trials. ALL of the following prerequisites have to be satisfied for a variable to qualify as a binomial random variable:
A predetermined sample size (number of trials) is used.
The relevant occurrence either takes place or doesn't in every trial.
On each trial, the likelihood of occurrence (or not) is the same.
Trials run separately from one another.
While Yoshi has a 30% chance of success for each shot and the trials are independent, the number of attempts is not fixed, as he continues until he makes the shot.
Thus, the correct answer is (Choice B) B. There is no fixed number of trials, so X is not a binomial variable.
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A cable hangs between two poles 12 yards apart. The cable forms a catenary that can be modeled
by the equation y = 12 cosh(x/12) - 5 between x =- 6 and x = 6. Find the area under the
12 catenary.
Round your answer to four decimal places.
The area under the catenary between the two poles is approximately 51.3224 square yards.
To find the area under the catenary between two poles 12 yards apart, with the equation y = 12cosh(x/12) - 5 between x = -6 and x = 6.
We can find the area by using integration.
The equation for the catenary.
y = 12cosh(x/12) - 5
Set up the integral to find the area under the curve between x = -6 and x = 6.
Area = ∫ (-6 to 6)[12cosh(x/12) - 5]dx
Integrate the function with respect to x.
Since we are dealing with the hyperbolic cosine function, we know that the integral of cosh(x/12) is 12sinh(x/12).
Therefore, the integral becomes:
Area = [12 (12sinh(x/12)) - 5x] evaluated from -6 to 6
Evaluate the integral at the bounds.
At x = 6: 12 (12sinh(6/12)) - 5(6) = 12 (12sinh(0.5)) - 30
At x = -6: 12 (12sinh(-6/12)) - 5(-6) = 12 (12sinh(-0.5)) + 30
Subtract the lower bound result from the upper bound result.
Area = [12(12sinh(0.5)) - 30] - [12(12sinh(-0.5)) + 30]
Calculate the numerical values and round to four decimal places.
Area = 51.3224
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These cones are similar. find the volume
of the smaller cone. round to the
nearest tenth.
2cm 3 cm
volume = [ ? ] cm3
volume = 66 cm3
The volume of the smaller cone is approximately [tex]5.5 cm^3[/tex], rounded to the nearest tenth
If the cones are similar, then the ratio of the corresponding dimensions of the cones is the same.
Let's denote the height and radius of the smaller cone as h and r, respectively. Then, the height and radius of the larger cone are 3h and 2r, respectively.
Since the volumes of the cones are proportional to the cube of their radii and heights, we can write:
(volume of smaller cone) / (volume of larger cone) = [tex](r^2 * h) / ((2r)^2 * 3h)[/tex]
Simplifying this expression, we get:
(volume of smaller cone) / (volume of larger cone) = 1/12
Since we are given that the volume of the larger cone is [tex]66 cm^3[/tex], we can solve for the volume of the smaller cone as follows:
(volume of smaller cone) =[tex](1/12) * (66 cm^3) = 5.5 cm^3[/tex]
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Find the ordered pair (s,t) that satisfies the system
s/2+5/t=3
3t-6s=9
The ordered pair (s,t) that satisfies the system are (1/2,4) and (1,5).
We can use the second equation to solve for one of the variables in terms of the other. Let's solve for t:
3t - 6s = 9
3t = 6s + 9
t = (2s + 3)
Now we can substitute this expression for t into the first equation and solve for s:
s/2 + 5/t = 3
s/2 + 5/(2s + 3) = 3
Multiplying both sides by the denominator (2s + 3) gives:
s(2s + 3)/2 + 5 = 3(2s + 3)
Simplifying and collecting like terms yields:
2s^2 + 3s + 10 = 6s + 9
2s^2 - 3s + 1 = 0
This quadratic equation can be factored as:
(2s - 1)(s - 1) = 0
So s = 1/2 or s = 1.
Now we can substitute these values for s into the equation we derived for t:
If s=1/2 then t=2(1/2)+3=4
If s=1 then t=2(1)+3=5
Therefore, the ordered pairs that satisfy the system are (1/2,4) and (1,5).
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Rectangle ABCD is graphed in the coordinate plane. The following are
the vertices of the rectangle: A(-6,-4), B(-4,-4), C(-4,-2), and
D(-6, -2).
What is the perimeter of rectangle ABCD?
units
Stuck? Review related articles/videos or use a hint.
Report a problem
Answer:
The perimeter of rectangle ABCD can be calculated by adding up the lengths of its sides. Using the distance formula, we can find that AB has a length of 2 units, BC has a length of 2 units, CD has a length of 2 units, and AD has a length of 4 units. Therefore, the perimeter of rectangle ABCD is 10 units.
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17. Which is D = 2zv solved for v? (1 point)
Ov=
2z
D
2z
Ov=D-2z
Ov=
AN
Ov=1
The equation D = 2zv when solved for v is D/2z = v
Which is D = 2zv solved for v?To solve D = 2zv for v, we need to isolate the variable v on one side of the equation. We can do this by dividing both sides of the equation by 2z:
D = 2zv
So, we have
D/2z = v
So the solution for v is v = D/2z.
This equation tells us that v is equal to the ratio of D divided by 2z. In other words, v is proportional to D, and inversely proportional to 2z.
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Sheri wrote the following entries in her checkbook:-$13.52,-$15.88,
+$500,-$451.57. +$275, $244.58. + $2,516. what is the total of her
deposits? what is the average amount of her checks? what overall
change in her balance would occur as a result of these 7
transactions?
Total deposits of Sheri are $3,535.58 and Average check amount $160.32 and Change in balance is $3,055.61.
As the change in balance is positive, we can say that her overall balance increased as a result of these transactions.
To find the total of Sheri's deposits, we add up all the positive values in her checkbook:
Total deposits = $500 + $275 + $244.58 + $2,516 = $3,535.58
To find the average amount of her checks, we first need to find the total value of all her checks:
Total checks = -$13.52 - $15.88 - $451.57 = -$480.97
Then we can divide this total by the number of checks to get the average amount:
Average check amount = -$480.97 ÷ 3 = -$160.32
Note that the negative sign indicates that these are payments she made, rather than deposits.
To find the overall change in her balance, we add up all the entries in her checkbook:
Change in balance = -$13.52 - $15.88 + $500 - $451.57 + $275 + $244.58 + $2,516 = $3,055.61
Since this value is positive, we can say that her overall balance increased as a result of these transactions.
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According to a simple physiological model, an athletic adult male needs 20 calories per day per pound of body weight to maintain his weight. If he consumes more or fewer calories than those required to maintain his weight, his weight changes at a rate proportional to the difference between the number of calories consumed and the number needed to maintain his current weight; the constant of proportionality is 1/3500pounds per calorie. Suppose that a particular person has a constant caloric intake of HH calories per day. Let W(t)be the person's weight in pounds at time t (measured in days).
(a) What differential equation has solution W(t)? dWdt=
(Your answer may involve W, H and values given in the problem.)
(b) If the person starts out weighing 180 pounds and consumes 3200 calories a day. What happens to the person's weight as t→[infinity]? W→?
(a) The differential equation that has solution W(t) is:
dW/dt = (1/3500) * (HH - 20W)
This is because the rate of change of weight with respect to time is proportional to the difference between the person's constant caloric intake and the number of calories needed to maintain their current weight, which is 20 calories per day per pound of body weight. The constant of proportionality is 1/3500 pounds per calorie.
(b) To find out what happens to the person's weight as t→[infinity], we can look at the long-term behavior of the solution to the differential equation. As t gets very large, the weight W(t) approaches a limiting value W∞ such that dW/dt = 0. This means that the person's weight is no longer changing, and is therefore at a steady state.
To find this steady state weight, we set dW/dt = 0 in the differential equation:
(1/3500) * (HH - 20W∞) = 0
Solving for W∞, we get:
W∞ = HH/20
So as t→[infinity], the person's weight approaches W∞ = HH/20.
This means that if the person starts out weighing 180 pounds and consumes 3200 calories a day, their weight will eventually stabilize at W∞ = 3200/20 = 160 pounds.
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Unit v performance task: percents (7. Rp. A. 3)
black friday deals
holy stone drone with live video and
adjustable wide-angle camera.
best buy
best buy is offering this drone for 20% off for
black friday.
pc richard and son
pc richard and son is offering the same drone
for 10% off plus an extra $20 off to the first 100
customers.
you only have time to go to one store. Which store will give you the
cheaper price? (assume that you are one of the first 100 customers at pc
richard and son. )
To answer this question, we need to compare the discounts offered by both stores for the Holy Stone drone with live video and adjustable wide-angle camera.
Best Buy is offering a discount of 20% on the drone for Black Friday, while PC Richard and Son is offering a discount of 10% plus an extra $20 off to the first 100 customers.
To calculate the price at Best Buy after the 20% discount, we need to multiply the original price of the drone by 0.8 (100% - 20%). Let's assume the original price of the drone is $200. So, the price at Best Buy after the discount will be:
Price at Best Buy = $200 x 0.8 = $160
To calculate the price at PC Richard and Son after the discount, we need to first calculate the 10% discount and then subtract the extra $20 off. Let's assume the original price of the drone is still $200. So, the price at PC Richard and Son after the 10% discount will be:
Price after 10% discount = $200 x 0.9 = $180
Then, we need to subtract the extra $20 off for the first 100 customers:
Price at PC Richard and Son = $180 - $20 = $160
So, both stores are offering the drone at the same price of $160 after the discounts. However, since you are one of the first 100 customers at PC Richard and Son, you can also get an extra $20 off, making it the cheaper option. Therefore, you should go to PC Richard and Son to get the cheaper price.
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Larray bought roses at the flower shop for $4.50 per dozen with a 90% markup. what is the final retail price
A markup refers to the amount that is added on top of the cost price of a product to arrive at the selling price. In this case, the cost price of the roses was $4.50 per dozen. Therefore, a 90% markup would mean that the selling price is 90% more than the cost price.
To calculate the markup, we can use the following formula:
Markup = Cost Price x Markup Percentage
Markup Percentage = 90% = 0.9 (in decimal form)
Markup = $4.50 x 0.9 = $4.05
This means that the markup on the roses is $4.05 per dozen.
To calculate the final retail price, we simply need to add the markup to the cost price:
Retail Price = Cost Price + Markup
Retail Price = $4.50 + $4.05 = $8.55
Therefore, the final retail price for the roses that Larray bought at the flower shop is $8.55 per dozen.
In conclusion, Larray bought roses at the flower shop for $4.50 per dozen with a 90% markup, which resulted in a final retail price of $8.55 per dozen. The markup was calculated by multiplying the cost price by the markup percentage of 90%, and then adding it to the cost price to arrive at the selling price.
This is a common practice in the flower industry, where flower shops add a markup to the cost of their products to make a profit.
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Dado y = 1 / 3x3 +7x dy encontrar dy/dx
To find dy/dx for y = 1/3x³ + 7x, we need to take the derivative with respect to x using the power rule and the sum rule, which gives dy/dx = x² + 7.
The given equation is y = 1/3x³ + 7x. To find dy/dx, we need to take the derivative of y with respect to x. We can do this by using the power rule and the sum rule of differentiation.
Using the power rule, the derivative of x³ is 3x². Using the sum rule, the derivative of 7x is 7. Therefore, the derivative of y with respect to x is:
dy/dx = d/dx (1/3x³ + 7x)
= d/dx (1/3x³) + d/dx (7x)
= (1/3) d/dx (x³) + 7 d/dx (x)
= (1/3) (3x²) + 7
= x² + 7
Hence, we have found that the derivative of y with respect to x is x² + 7.
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A model airplane flew the distance of 330 feet in 15 seconds. Select ALL the unit rates that are equivalent to the speed of the model airplane.
All of the unit rates that are equivalent to the speed of the model airplane are 22 feet per second, 1320 feet per minute, and 0.25 miles per minute.
To calculate the speed of the model airplane, we need to use the formula:
Speed = Distance / Time
Given that the distance covered by the model airplane is 330 feet, and the time taken is 15 seconds, we can substitute these values in the above formula to get:
Speed = 330 feet / 15 seconds
Simplifying this, we get:
Speed = 22 feet per second
To convert this unit rate to other equivalent unit rates, we need to use conversion factors. For example, to convert feet per second to feet per minute, we can multiply the unit rate by 60 (since there are 60 seconds in a minute):
22 feet per second x 60 seconds per minute = 1320 feet per minute
Similarly, to convert feet per minute to miles per minute, we can use the conversion factor 1 mile = 5280 feet:
1320 feet per minute / 5280 feet per mile = 0.25 miles per minute
Therefore, all of the unit rates that are equivalent to the speed of the model airplane are 22 feet per second, 1320 feet per minute, and 0.25 miles per minute.
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cos 14° -sin 14°/ cos 14° + sin 14° = cot 59
Answer:
To solve this trigonometric identity, we need to use the definitions of the trigonometric functions and some algebraic manipulation. Here's how we can do it:
cos 14° - sin 14°/ cos 14° + sin 14°
= (cos 14°/cos 14°) - (sin 14°/cos 14°)/(cos 14°/cos 14°) + (sin 14°/cos 14°) (multiplying the numerator and denominator of the second term by cos 14°)
= 1 - tan 14°/1 + tan 14° (using the definitions of cosine and sine, and dividing both terms by cos 14°)
= (1 - tan²14°)/(1 + tan 14°) (using the identity 1 + tan²θ = sec²θ)
= 1/cot 14° - cot 14° (using the definition of cotangent and simplifying the numerator)
= cot 90° - cot 14° (using the identity cot(90° - θ) = tan θ)
= cot (90° + 14°) (using the identity cot(θ + 90°) = -tan θ)
= cot 104°
Since cot(104°) = cot(180° - 76°) = -cot 76°, we can also write the final answer as -cot 76°.
Therefore, the given identity is true, and we have shown that:
cos 14° - sin 14°/ cos 14° + sin 14° = cot 59 = -cot 76°.
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Find the inverse for each relation: 4 points each
1. {(1,‐2), (2, 3),(3, ‐3),(4, 2)}
2. {(4,2),(5,1),(6,0),(7,‐1)}
Find an equation for the inverse for each of the following relations.
3. Y=-8x+3
4. Y=2/3x-5
5. Y=1/2x+10
6. Y=(x-3)^2
Verify that f and g are inverse functions.
7. F(x)=5x+2;g(x)=(x-2)/5
8. F(x)=1/2x-7;g(x)=2x+14
The inverse relation is {(‐2,1), (3, 2),(‐3, 3),(2, 4)}, {(2, 4),(1, 5),(0, 6),(‐1, 7)}, the inverse equation is: y = (-x + 3)/8, y = (3/2)x - (15/2), y = (1/2)x + 10,
x = sqrt(y) + 3 or x = -sqrt(y) + 3 and f(g(x)) = g(f(x)) = x, f and g are inverse functions.
1.To find the inverse of the relation, we need to switch the x and y values of each point and solve for y:
{(‐2,1), (3, 2),(‐3, 3),(2, 4)}
2. Following the same process as above:
{(2, 4),(1, 5),(0, 6),(‐1, 7)}
So the inverse relation is {(2, 4),(1, 5),(0, 6),(‐1, 7)}.
3.To find the equation of the inverse, we can solve for x:
y = -8x + 3
x = (-y + 3)/8
So the inverse equation is: y = (-x + 3)/8.
4. Following the same process as above:
y = (2/3)x - 5
x = (3/2)y + 5
So the inverse equation is: y = (3/2)x - (15/2).
5. Following the same process as above:
y = (1/2)x + 10
x = 2(y - 10)
So the inverse equation is: y = (1/2)x + 10.
6.To find the inverse equation, we need to solve for x:
y = (x-3)^2
x = sqrt(y) + 3 or x = -sqrt(y) + 3
So the inverse equation is: x = sqrt(y) + 3 or x = -sqrt(y) + 3.
7,To verify that f and g are inverse functions, we need to show that f(g(x)) = x and g(f(x)) = x.
f(x) = 5x + 2
g(x) = (x-2)/5
f(g(x)) = 5((x-2)/5) + 2 = x - 2 + 2 = x
g(f(x)) = ((5x + 2)-2)/5 = x/5
Since f(g(x)) = g(f(x)) = x, f and g are inverse functions.
8.Following the same process as above:
f(x) = (1/2)x - 7
g(x) = 2x + 14
f(g(x)) = (1/2)(2x+14) - 7 = x
g(f(x)) = 2((1/2)x - 7) + 14 = x
Since f(g(x)) = g(f(x)) = x, f and g are inverse functions.
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At the craft store, Stefan bought a bag of yellow and brown marbles. The bag contained 40 marbles, and 10% of them were yellow. How many yellow marbles did Stefan receive?
The number of yellow marbles Stefan received is 4.
To find out how many yellow marbles Stefan received, we need to calculate 10% of the total number of marbles, which is 40.
Percentage calculations involve finding a part of a whole, and in this case, we are looking for the part that represents the yellow marbles. To find 10% of 40 marbles, you simply multiply the total number of marbles (40) by the percentage value (10%) as a decimal. To convert 10% to a decimal, you divide by 100, giving you 0.1.
Now, multiply the total marbles by the decimal value:
40 marbles * 0.1 = 4 marbles
So, Stefan received 4 yellow marbles in the bag he bought from the craft store.
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A culture of bacteria has an initial population of 65000 bacteria and doubles every 2
hours. Using the formula Pt = Po 2a, where Pt is the population after t hours, Po
is the initial population, t is the time in hours and d is the doubling time, what is the
population of bacteria in the culture after 13 hours, to the nearest whole number?
.
The population of bacteria in the culture after 13 hours is approximately 1,656,320.
What is the equation?An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.
We have the initial population, Po = 65000, and the doubling time, d = 2 hours. To find the population after 13 hours, we need to use the formula:
[tex]Pt = Po * 2^{(t/d)[/tex]
where Pt is the population after t hours, Po is the initial population, t is the time in hours, and d is the doubling time.
Substituting the given values, we get:
Pt = 65000 x [tex]2^{(13/2)[/tex]
Pt ≈ 1,656,320
Rounding this to the nearest whole number, we get:
The population of bacteria in the culture after 13 hours is approximately 1,656,320.
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840x - x2 A company's revenue for selling x (thousand) items is given by R(x) = x2 +840 Find the value of x that maximizes the revenue and find the maximum revenue. X= maximum revenue is $ 2
The value of x that maximizes revenue is x 28.99 and maximum revenue is $1680 (thousand).
The revenue function for a company that sells x (thousand) items is R(x) = x² + 840. To find the value of x that maximizes revenue, we need to differentiate the revenue function, set it equal to zero and solve for x. The maximum revenue can then be calculated by substituting the value of x into the revenue function.
Revenue function: R(x) = x² + 840
To find the value of x that maximizes revenue, we differentiate the revenue function with respect to x:
dR/dx = 2x
Setting this equal to zero, we get:
2x = 0
x = 0
However, this value does not make sense in the context of the problem, as the company cannot sell 0 items. Therefore, we need to consider the critical points of the function, which occur when dR/dx = 0 or is undefined.
dR/dx = 0 when 2x = 0, so x = 0 is a critical point.
dR/dx is undefined when x = ±√840, so these are also critical points.
We can use the second derivative test to determine which critical point corresponds to a maximum. The second derivative of the revenue function is:
d²R/dx² = 2
At x = 0, d²R/dx² = 2 > 0, so this critical point corresponds to a minimum.
At x = ±√840, d²R/dx² = 2 > 0, so these critical points correspond to a minimum.
Therefore, the value of x that maximizes revenue is x = √840 ≈ 28.99 (thousand items).
To find the maximum revenue, we substitute x = √840 into the revenue function:
R(√840) = (√840)² + 840 = 1680
So the maximum revenue is $1680 (thousand).
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What’s the answer? I need help:)
Answer:
x=180-90-54, y=180-x,z=90
Step-by-step explanation:
the sum of the degree of a triangle will equal 180. the sum of the degree of a line will equal 180.
Find ln 0. 732 to four decimal places
A.
-0. 5227
B.
-0. 3120
C.
-0. 4624
D.
-0. 4719
Using a calculator, we can evaluate ln 0.732 to four decimal places. The correct answer is option D, -0.4719.
The natural logarithm of a number is the logarithm to the base e (approximately 2.71828), and ln 0.732 is the natural logarithm of the number 0.732.
To find the value of ln 0.732, we simply input the number into the calculator and hit the ln key.
The result is approximately -0.4719, rounded to four decimal places. Therefore, the correct answer is D, -0.4719.
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Simplify 3y(y^2-3y+2)
Step-by-step explanation:
if this factorisation because I think you alr simplified, but here's the answer for factorisation anyways.
you can text me below in the comments section if that's not you want, I will try to answer if I can!!!
Answer:
3y(y - 2)(y - 1)
Step-by-step explanation:
Simplify by factoring
3y(y² - 3y + 2)
= 3y(y - 2)(y - 1)
Anne is taking courses in both mathematics and English. She estimates her probability of passing mathematics at 0. 42 and passing English at 0. 47 , and she estimates her probability of passing at least one of the courses at 0. 7. What is the probability that Anne could pass both courses?
The probability that Anne could pass both mathematics and English courses is 0.19 or 19%.
To find the probability that Anne could pass both mathematics and English, we can use the formula for the probability of the union of two events: P(A ∪ B) = P(A) + P(B) - P(A ∩ B), where A is the event of passing mathematics, B is the event of passing English, and A ∩ B is the event of passing both courses.
We are given:
P(A) = probability of passing mathematics = 0.42
P(B) = probability of passing English = 0.47
P(A ∪ B) = probability of passing at least one course = 0.7
Now we need to find the probability of passing both courses, P(A ∩ B).
Using the formula, we have:
0.7 = 0.42 + 0.47 - P(A ∩ B)
To find P(A ∩ B), we rearrange the equation:
P(A ∩ B) = 0.42 + 0.47 - 0.7
Now, calculate the probability:
P(A ∩ B) = 0.19
So, the probability that Anne is 0.19 or 19%.
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10 problemas de ecuaciones de primer grado relacionada los datos con el cambio climático
Answer: Si la emisión de gases de efecto invernadero aumenta en un 5% anual, ¿cuánto aumentará la temperatura global en 20 años?
Solución: Dado que cada
Step-by-step explanation:
Una empresa produce 400 toneladas de dióxido de carbono al año. Si cada tonelada de dióxido de carbono contribuye al calentamiento global en 0.05 grados Celsius, ¿cuál será el aumento de temperatura causado por la empresa en un año?
Solución: 400 x 0.05 = 20 grados Celsius
La temperatura media de la Tierra ha aumentado en 1 grado Celsius desde la era preindustrial.
Si el aumento de temperatura está directamente relacionado con la cantidad de dióxido de carbono en la atmósfera, ¿cuánto dióxido de carbono adicional se ha emitido desde la era preindustrial hasta ahora?
Solución: Dado que cada tonelada de dióxido de carbono contribuye a un aumento de 0.05 grados Celsius, 1 / 0.05 = 20. Por lo tanto, se han emitido 20 veces la cantidad de dióxido de carbono necesario para contribuir a un aumento de 1 grado Celsius.
Una central térmica produce 1000 megavatios de electricidad al día. Si la eficiencia de conversión de la central térmica es del 30%, ¿cuántas toneladas de dióxido de carbono se emiten al día?
Solución: La eficiencia de conversión de la central térmica es del 30%, lo que significa que se pierde el 70% de la energía.
Por lo tanto, la cantidad de energía producida por la central térmica es de 1000 x 0.3 = 300 megavatios. Si cada megavatio produce 0.5 toneladas de dióxido de carbono, entonces la central térmica emite 300 x 0.5 = 150 toneladas de dióxido de carbono al día.
Si se reduce la emisión de dióxido de carbono en un 20%, ¿en qué medida se reducirá el aumento de temperatura global?
Solución: Si se reduce la emisión de dióxido de carbono en un 20%, se reducirá el aumento de temperatura global en un 20% x 0.05 = 0.01 grados Celsius.
Si la temperatura media en una ciudad ha aumentado en 0.5 grados Celsius en los últimos 10 años, ¿cuál es la tasa de aumento de temperatura por año?
Solución: La tasa de aumento de temperatura por año es de 0.5 grados Celsius / 10 años = 0.05 grados Celsius por año.
Si la concentración de dióxido de carbono en la atmósfera es de 400 partes por millón (ppm) y se espera que aumente en un 2% anual, ¿cuál será la concentración de dióxido de carbono en 10 años?
Solución: El aumento anual de la concentración de dióxido de carbono es de 400 x 0.02 = 8 ppm. Por lo tanto, la concentración de dióxido de carbono en 10 años será de 400 + 8 x 10 = 480 ppm.
Si la emisión de gases de efecto invernadero aumenta en un 5% anual, ¿cuánto aumentará la temperatura global en 20 años?
Solución: Dado que cada
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Use the ratio test to find the radius of convergence of the power series 3x+36x^2+243x^3+1296x^4+6075x^5+
The radius of convergence is 1/3. To find the radius of convergence for the power series using the ratio test, we need to analyze the general term of the series. The given series is:
Σ(an * x^n)
where an is the coefficient of the term with x raised to the power n. The coefficients in the given series are:
a1 = 3
a2 = 36
a3 = 243
a4 = 1296
a5 = 6075
...
Notice that each coefficient is a multiple of 3^n. Thus, we can write the general term as:
an = 3^n
Now, we apply the ratio test. The ratio test states that the series converges if the limit as n approaches infinity of the absolute value of the ratio of consecutive terms is less than 1:
lim (n → ∞) |(a(n+1) * x^(n+1)) / (an * x^n)|
= lim (n → ∞) |(3^(n+1) * x^(n+1)) / (3^n * x^n)|
To simplify, divide 3^(n+1) by 3^n:
= lim (n → ∞) |(3 * x)|
The series converges when |3 * x| < 1. To find the radius of convergence, solve for |x|:
|x| < 1/3
The radius of convergence is 1/3.
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