Air resistance is exerted by an engine
what's the dimension symbol for amount of substance
Answer:
The mole (symbol: mol) is the unit of measurement for amount of substance in the International System of Units (SI). It is defined as exactly 6.022 140 76 × 1023 particles, which may be atoms, molecules, ions, or electrons.
Explanation:
A man walks 40 m North, then 70 m East and then 40
m south. What is his displacement
from the starting point?
Answer:
Displacement = 70 m towards east
Explanation:
Displacement is the shortest distance between the two points.
Let us say that he starts at the point O and travels in a path ABC.
If we join the initial and final point of the path travelled by him, it will give the displacement of the man.
Distance from O to A = 40 m
Distance from A to B = 70 m
Distance from B to C = 40 m
Distance from O to A = Distance from B to C
We want the displacement which is distance between the points O and C
In rectangle opposite sides are equal. Hence Distance from O to C = Distance from A to B
Displacement = Distance from A to B
Hope it helps,
Please mark me as the brainliest.
Thank you
Answer:
Displacement = 70 m towards east
Explanation:
Force = mass X acceleration. Acceleration due to gravity is 9.8 m/s/s regardless of height or mass. This means a single object will hit the ground with the same force regardless of the height it is dropped from. If this is true, I normally drop a pumpkin from different heights during this unit. why does dropping the pumpkin stay together when dropped from one meter but break apart when dropped from a height of 5 meters?
which simple machines make up a wheel barrow
Answer:
a lever and a wheel and axle (i guess)
Explanation:
don't have any
What is a black hole's escape velocity?
The simplest definition of a black hole is an object that is so dense that not even light can escape its surface. If we squished the Earth's mass into a sphere with a radius of 9 mm, the escape velocity would be the speed of light. Just a wee-bit smaller, and the escape velocity is greater than the speed of light.
HopeItHelps!
Use the worked example above to help you solve this problem. The amount of charge that passes through a filament of a certain lightbulb in 2.09 s is 1.56 C. (a) Find the current in the bulb. A (b) Find the number of electrons that pass through the filament in 5.24 s. electrons (c) If the current is supplied by a 12.0-V battery, what total energy is delivered to the lightbulb filament
Answer:
a) i = 0.746 A, b) # _electron = 2.44 10¹⁹ electrons, c) E = 1.87 10⁴ J
Explanation:
a) The definition of current is the charge per unit of time
i = Q / t
i = 1.56 / 2.09
i = 0.746 A
b) Let's look for the cargo in passing at this time
i = Q / t
Q = i t
Q = 0.746 5.24
Q = 3.904 C
an electron has a charge e = -1.6 10⁻¹⁹ C, let's use a direct proportions rule
# _electron = 3.904 C (1 electron / 1.6 10⁻¹⁹)
# _electron = 2.44 10¹⁹ electrons
the number of electrons has to be an integer
c) In this part you are asked to calculate the power
P = V i
P = 12 0.746
P = 8.952 W
P = E/t
E = P t
E = 8.952 2.09
E = 1.87 10⁴ J
An automobile tire is filled to a gauge pressure of 200 kPa when its temperature is (Gauge pressure is the difference between the actual pressure and atmospheric pressure.) After the car has been driven at high speeds, the tire temperature increases to (a) Assuming that the volume of the tire does not change and that air behaves as an ideal gas, find the gauge pressure of the air in the tire. (b) Calculate the gauge pressure if the tire expands so the volume of the enclosed air increases by 10 percent.
This question is incomplete, the complete question is;
An automobile tire is filled to a gauge pressure of 200 kPa when its temperature is 20°C (Gauge pressure is the difference between the actual pressure and atmospheric pressure.)
After the car has been driven at high speeds, the tire temperature increases to 55°C
(a) Assuming that the volume of the tire does not change and that air behaves as an ideal gas, find the gauge pressure of the air in the tire. (kPa)
(b) Calculate the gauge pressure if the tire expands so the volume of the enclosed air increases by 10 percent. (kPa)
Answer:
a) the gauge pressure of the air in the tire is 236 kPa
b) the gauge pressure if the tire expands so the volume of the enclosed air increases by 10 percent is 205.33 kPa
Explanation:
Given the data in the question;
Gauge pressure at 20°C = 200 kPa
Absolute pressure at 20°C is; p = 200 + 101.3 = 301.3 kPa
Initial temperature T = 20°C = 20 + 273 = 293 k
Final temperature T" = 55°C = 55 + 273 = 328 K
Now, at constant volume, P"/P = T"/T
P"T = PT"
P" = PT" / T
P" = PT" / T
we substitute
P" = ( 301.3 × 328 ) / 293
P" = 98826.4 / 293
P" = 337.29
so Gauge pressure at 55°C is;
⇒ P" - 101.3
⇒ 337.29 - 101.3 = 235.99 ≈ 236 kPa
Therefore, the gauge pressure of the air in the tire is 236 kPa
b)
Final Volume V'' = V + 10% of V
V" = V + 0.1V
V" = 1.1V
we know that;
P"V"/T" = PV/T
P" = P (T"/T)(V/V")
we substitute
P" = 301.3 (328 /293 )(V/1.1×V)
P" = × 1/1.1 × V/V
P" = 337.29 × 1/1.1
P" = 306.628 kPa
so, absolute pressure at 55°C = 306.628 - 101.3 = 205.33 kPa
Therefore, the gauge pressure if the tire expands so the volume of the enclosed air increases by 10 percent is 205.33 kPa
Determine the speed of sound on a cold winter day (Temperature = 3ºC). *
Answer:
Temperature and Speed of Sound
Temperature of AirSpeed of Sound Waves (m/s)0 °C33120 °C343100 °C386
Explanation:
Explain why two electric charges of the same magnitude, when on a collision course with each other, won't actually collide
(serious answers only)
Answer:
Explanation:
When two charges of equal magnitude and sign approach each other, they interact through Coulomb's law
F = [tex]k \frac{q_ 1q_2}{z^2 }[/tex]k q1 q2 / r2
In you case the house are of equal magnitude and sign
q1 = q2 = q
F = k q2 / r2
Let's analyze this expression, the charge is repulsive on each charge, when they are on a collision course as they approach they feel an electric field opposite to their direction of movement, this field decreases its speed, the closer they get, the greater the repulsive force. , up to the point where this force is equal to or greater than the impulse, therefore the point where the velocity reaches zero, for this reason the particles do not actually touch
. A single strand of wire of adjustable length is wound around the circumference of a round balloon that has a diameter of 21.0 cm. A uniform magnetic field with a magnitude of 1.40 T is perpendicular to the plane of the loop. If the balloon is blown up such that its diameter and the diameter of the wire loop increase to 31.0 cm in 0.048s, what is the magnitude of the average value of the emf induced in the loop
Answer:
EMF = 1.1929 V
Explanation:
In this case we need to use the following expression:
EMF = B *ΔA / t (1)
Where:
B: Magnetic field
ΔA: Difference of area of the balloon
t: time
To get the area, we have the innitial diameter of the balloon, and the expanded diameter when the balloon is blown up, so, assuming the circunference of the balloon, the area can be determined with:
A = π r² (2)
So, let's calculate the Area of the balloon before and after the blown. Remember to use the units in meter (I just divided the diameter by 2 to get the ratio, and then divide by 100 to convert the units of cm to m)
A₁ = π * (0.105)² = 0.0346 m²
A₂ = π * (0.155)² = 0.0755 m²
Now that we have both areas, let's calculate ΔA:
ΔA = A₂ - A₁
ΔA = 0.0755 - 0.0346 = 0.0409 m²
Finally, we can determine the value of the EMF, using (1):
EMF = 1.4 * 0.0409 / 0.048
EMF = 1.1929 VHope this helps
What is the magnitude of the electric field strength between them, if the potential 7.05 cm from the zero volt plate (and 2.95 cm from the other) is 293 V?
Answer:
E = 4156.02 Vm⁻¹
Explanation:
The magnitude of the uniform electric field between the plates can be given by the following formula:
[tex]E = \frac{\Delta V}{d}\\[/tex]
where,
E = Electric field strength = ?
ΔV = Potetial Difference = 293 V
d = distance between plates = 7.05 cm = 0.0705 m
Therefore,
[tex]E = \frac{293\ V}{0.0705\ m}\\\\[/tex]
E = 4156.02 Vm⁻¹
A girl and a boy are riding on a merry-go-round that is turning at a constant rate. The girl is near the outer edge, and the boy is closer to the center. Who has greater angular displacement?
a) boy
b) girl
c) both have the same angular displacement
Answer:
c) both have the same angular displacement
Explanation:
In this scenario, girl and a boy are riding on a merry-go-round that is turning at a constant rate. The girl is near the outer edge, and the boy is closer to the center. Therefore, both have the same angular displacement.
A 30.0 uC charge is moved 5.00 m West in an electric field of 4000 V/m pointing 40.0° North of East. What potential difference did the charge move through?
Answer:
20000sin(40) V
Explanation:
Consider component to the east of electric field:
[tex]E_{x} =4000 sin(40)[/tex]
The charge move along this component for 5 meter
Potential difference:
[tex]5E_{x} =20000sin(40)[/tex] = 12900 V (corr, to 3 sig,fig.)
The potential difference through which the charge moved is approximately 20.0 V.
To calculate the potential difference (ΔV) through which the charge moved, we can use the formula:
ΔV = q * E * d * cos(θ)
where:
q = charge = 30.0 uC = 30.0 x 10⁻⁶ C (converted to coulombs)
E = electric field = 4000 V/m
d = displacement = 5.00 m
θ = angle between the electric field and the displacement = 40.0°
Now, substitute the values into the formula:
ΔV = (30.0 x 10⁻⁶ C) * (4000 V/m) * (5.00 m) * cos(40.0°)
First, convert the angle to radians:
θ_radians = 40.0° * (π/180) ≈ 0.6981 radians
Now, calculate ΔV:
ΔV = (30.0 x 10⁻⁶ C) * (4000 V/m) * (5.00 m) * cos(0.6981) ≈ 0.02 V
So, the potential difference through which the charge moved is approximately 20.0 V.
To learn more about potential difference, here
https://brainly.com/question/23716417
#SPJ2
what is the effect of divorce on females?
Answer:
Numerous studies have shown that the economic costs of divorce fall more heavily on women. After separation, women experience a sharper decline in household income and a greater poverty risk (Smock 1994; Smock and Manning
Answer:
sadness and stress...................
Albert's laboratory is filled with a constant uniform magnetic field pointing up everywhere. Into this magnetic field albert throws some charges. He throws the charges in different directions, and observes the resulting magnetic forces on them. Given the sign of each charge and the direction of its velocity, determine the direction of the magnetic force (if any) acting on the charge.
Resulting magnetic force:
Positive charge moving south:
Negative charge moving west:
Negative charge not moving at all:
Positive charge moving up:
Positive charge moving east:
Negatve charge moving down:
Negative charge moving north:
Positive charge not moving at all:
Positive charge moving west:
Negative charge moving south:
Negative charge moving east:
Positive charge moving north:
options: up, down, no force, north, south, east, west
Answer:
Follows are the solution to this question:
Explanation:
The magnetic force is parallel to a [tex]\bar{V} \times \bar{B}[/tex] axis, through right law. The direction would be in a reverse way for a positive particle. The gravitational flux is upward.
1) Its magnet strength will be directed westward.
2) The [tex]\bar{V} \times \bar{B}[/tex] path is parallel to the east. The permanent magnet is oriented against the south so because the object is considered impolite.
3) Its gravitational field of the velocity v of the object is zero. Thus no force was its solution.
4) The magnetic field and velocity are all on the same track. The magnetic strength is also zero. Consequently, the answer is no power.
5) Its gravitational field is to the south.
6) Its magnetic field, as well as the speed, are different. Which magnet strength is also zero. Consequently, no power is the answer.
7) Accessible in French only. The [tex]\bar{V} \times \bar{B}[/tex] direction parallel to the east. Its magnetic energy is guided west because the particle is charged negatively.
8) Unless the particle velocity is 0, the magnetic strength is 0. Consequentl, no power is the response.
9) Its magnet power is from the north.
10) Another one of these: The [tex]\bar{V} \times \bar{B}[/tex] is parallel to the west. Its gravitational field is oriented to the east as the object is negatively charged.
11) The Pope said the following: The [tex]\bar{V} \times \bar{B}[/tex] direction is parallel to the south. The gravitational fluid is transmitted towards the North because a particle is considered impolite.
12) The gravitational field is from the east.
A piece of glass with index of refraction 1.50 is coated with a coating of thickness 138 nm and index of refraction 1.22. Light traveling perpendicular to the surface of the glass reflects at the interface between air and the coating, and at the interface between the coating and the glass. What is the largest vacuum wavelength for which the interference between the two reflected rays is completely destructive
Answer:
Explanation:
At both interface light is travelling from a medium of lower refractive index to medium of higher refractive index. So the phase difference of 180⁰ occurring at both interface will cancel out .
Net path difference = 2 μ t where μ is refractive index of thin layer and t is its thickness
For destructive interference
2 μ t = (2n + 1 )λ / 2 where λ is wavelength of light , n is any number
λ = 4 μ t / ( 2 n + 1 )
For largest wavelength , n = 0
λ = 4 μ t
= 4 x 1.22 x 138 nm
= 673.44 nm .
In the Styrofoam ball investigation, it is likely that the charges on the ball and rod are
?
A. the same
B. opposite
C. constantly changing.
Answer:
answer = opposite
they are not changing being in a place as being they-self
the same would not be true because its different then the Styrofoam and it could only be different and its make the most sense aswell.
Both ball and rod has opposite charges on their bodies because of presence of different charges on it.
What are the charges on ball and rod?In the Styrofoam ball investigation, it is likely that the charges on the ball and rod are opposite because Styrofoam ball is negatively charged due to the presence of electrons while on the other hand, the rod is positively charged because of lining of positive charges on the rod.
So we can conclude that both ball and rod has opposite charges on their bodies because of presence of different charges on it.
Learn more about charges here: https://brainly.com/question/25923373
#SPJ2
How can you explain the process of reflection based from your experience?
Answer:
Reflection brings learning to life. Reflective practice helps learners find relevancy and meaning in a lesson and make connections between educational experiences and real life situations. It increases insight, and creates pathways to future learning. Reflection is called by many different names in the education field including processing, reviewing, and debriefing. I personally have moved towards referring to this key ingredient in teaching and group facilitation as reflection or reflective practice.
Explanation:
unlike punishment, reinforcement ____
A. indicates what not to do
B. promotes discrimination
C. promotes generalization
D. indicate what to do
Answer:
B...................
In SI units, what is the magnitude the net force acting on a 1,152 kg car that accelerates uniformly along a straight line from a speed of 3 m/s to a speed of 17 m/s in 5s?
Answer:
Fnet = 14515.2 Newton
Explanation:
Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.
Mathematically, net force is given by the formula;
[tex] Fnet = Fapp + Fg[/tex]
Where;
Fnet is the net force. Fapp is the applied force. Fg is the force due to gravitation.Given the following data;
Mass = 1,152 kg
Initial velocity, u = 3m/s
Final velocity, v = 17m/s
Time, t = 5 seconds
To find the magnitude of the net force;
First of all, we would determine the acceleration of the car.
Acceleration = (v-u)/t
Acceleration = (17 - 3)/5
Acceleration = 14/5
Acceleration = 2.8m/s
To find the applied force;
Fapp = mass * acceleration
Fapp = 1,152 * 2.8
Fapp = 3225.6 N
Next, we would find the force exerted on the car due to gravity.
Fg = mass * acceleration due to gravity
We know that acceleration due to gravity is equal to 9.8m/s²
Fg = 1152 * 9.8
Fg = 11289.6N
Substituting the values into the equation, we have;
Fnet = 3225.6 + 11289.6
Fnet = 14515.2 Newton
Physical quantities are generally not purely numerical: They have a particular dimension or combination of dimensions associated with them. Thus, your height is not 74, but rather 74 inches, often expressed as 6 feet 2 inches. Although feet and inches are different units they have the same dimension--length.
Required:
a. Find the dimensions [V] of volume.
b. Find the dimensions [v] of speed.
Answer:
a, The dimension of volume is L³
b. The dimension of speed = L/T
Explanation:
The three fundamental quantities are Mass, Length and time. Other physical quantities are obtained from or derived from these three. These other quantities are known as derived quantities. The units of the fundamental quantities are Kilogram (kg) for Mass, meters for length, and second for time.
In the given question:
a. Volume = length * breadth * height
since breadth and height all measure length, the dimension of volume becomes:
volume = length * length * length = L³
Thus, the dimension of volume is L³
b. Speed, v = distance/time
Distance measures length, therefore, the dimension of speed will be:
Speed = length / time = L/T
Therefore, the dimension of speed = L/T
Soda pop cane are made of aluminum having thickness of 0.12 mm. They are typically kept at a temperature of 4°C in refrigerator. Such cane has height of 4.83 inch and diameter of 2.6 inch. Suppose you bought such a cold soda pop and brought into the class where the temperature is 25°C.
Required:
Calculate the rate of heat transfer of the coke cane to the surroundings.
Answer:
Explanation:
For flow of heat through conduction , the formula is
Q = KA( T₂ -T₁ ) / d where K is thermal conductivity of material , A is surface area , T₂ - T₁ is temp diff .
Thermal conductivity of aluminum is 205 W /m.s
Surface area of cane = 2π r² + 2π r h where r is radius and h is height of cane .
A = 2π r ( r + h )
= 2 x 3.14 x 1.3 x .0254 ( 1.3 x .0254 + 4.83 x .0254 )
= .20736 ( .033 + .12268 )
A = .03228 m²
thickness d = .12 x 10⁻³ m
Putting the values ,
Q = 205 x .03228 x ( 25 - 4 ) / .12 x 10⁻³
= 1158 x 10³ J /s
Two loudspeakers, A and B are driven by the same amplifier and emit sinusoidal waves in phase. Speaker B is 2.00 m to the right of speaker A. The frequency of the sound waves produced by the loudspeakers is 206 Hz. Consider a point P between the speakers and along the line connecting them, a distance x to the right of A. Both speakers emit sound waves that travel directly from the speaker to point P. For what values of x will:
a. destructive interference occur at P
b. constructive interference occur at P
Answer:
a) 0, ±1.65 b) ± 0.825m
Explanation:
This is a sound interference exercise, it can be described by the path difference between the two waves
for the case of constructive interference
Δr = 2n λ/ 2 n = 0, 1, 2 ...
for the case of destructive interference
Δr = (2n + 1) λ/ 2
the speed of sound is related to the wavelength
v = λ f
λ = v / f
λ= 340/206
λ = 1.65 m
let's set a reference system in the center between the two speakers
a) let's find the distances for constructive interference
Δr = 2n 1.65 / 2
Δr = 1.65 n
* the first interference occurs at n = 0
Δr = 0
therefore the interference in the center is maximum
* n = 1
Dr = 1.65 m
the second inference occurs at 1.65 m from the center, therefore there is a right wing and a left wing,
We do not have any more interference between the speakers because
n = 2 Δr = 3.3m this distance can be from the speaker
b) let's look for the destructive interference points
Δr = (2n + 1) 1.65 / 2
Δr = (2n + 1) 0.825
m = 0 Δr = 0.825m
m = 1 Δr = 2,475m
We can see that we only have the first destructive interference, one on each side.
Question 3 (5 points)
Yissel was going to be late to Mr. Scharff's science class. Just as the bell was about to ring. Vissel ran the last little bit of the hallway at 2.47
meters/second for 8 seconds to beat the bell. How far away was Yissel from Mr. Scharff's classroom when she started to run?
microwaves are produced by
Answer:
Microwaves are basically extremely high frequency radio waves, and are made by various types of transmitter. In a mobile phone, they're made by a transmitter chip and an antenna, in a microwave oven they're made by a "magnetron". Their wavelength is usually a couple of centimetres. Stars also give off microwaves.
Transduction is:
A. sending information to the central nervous system.
B. turning energy into nerve impulses.
C. the process of seeing and hearing.
D. transferring information
Answer:
D
Explanation:
the answer is d because process of genetic recombination in bacteria in which genes from a host cell (a bacterium) are incorporated into the genome of a bacterial virus (bacteriophage) and then carried to another host cell when the bacteriophage initiates another cycle of infection
An equipotential surface that surrounds a point charge q has a potential of 536 V and an area of 1.20 m2. Determine q.
Answer:
q = 1.84×10^-8coulombs
Explanation:
Surface area = 4πr²
r is the distance
1.2 = 4(3.14)r²
1.2 = 12.56r²
r² = 1.2/12.56
r² = 0.0956
r = √0.0956
r = 0.309m
Get the charge C
V = kq/r
536 = 9.0×10^9q/0.309
536×0.309 = 9×10^9q
165.73 = 9×10^9q.
q = 165.73/9×10^9
q = 1.84×10^-8coulombs
Messages from the Perseverance Rover on Mars reach Earth in 11 min. The speed of light is 3.00 x 108 m/s. Using this information, how far is Mars from Earth?
Answer:
[tex]d=1.98\times 10^{11}\ m[/tex]
Explanation:
Messages from the Perseverance Rover on Mars reach Earth in 11 min i.e. time is 660 s
The speed of light is [tex]3\times 10^8\ m/s[/tex]
We need to find the distance between Mars and Earth. Let the distance be d.
We know that,
Distance = speed × time
So,
[tex]d=660\times 3\times 10^8\\\\d=1.98\times 10^{11}\ m[/tex]
So, Mars is [tex]1.98\times 10^{11}\ m[/tex] from the Earth.
Will mark BRAINLYEST
Answer:
A dribble ends when the player touches the ball with both hands simultaneously or permits the ball to come to rest in one or both hands. The ball being touched with both hands simultaneously (dribble with both hands) is a double dribble
Nothing in the rulebook that says a player cannot start a dribble with two hands. A dribble can end when touching both hands simultaneously, but a single dribble is OK as long as you catch the ball
Explanation:
Answer:
No, so it's false you're correct.
Hope this helped
3. 20P. The potential energy of a two particles is given by
Explanation:
The potential energy of two particles system will be given by the negative of work by gravitational force due to particle (1)as the second particle is brought from infinity : Gravitational potential energy Second particle is brought in the gravitation of first particle.
