Answer:
3.966m
Step-by-step explanation:
4m - (30cm + 40mm)
Converting cm and mm to metre by dividing by 100 and 1000 respectively
=> 4.000m - (30/100 m + 40/1000 m)
=> 4.000m - (0.030m + 0.004m)
=> 4.000m - 0.034m
=> 3.966m
Answer:
3.66m
Step-by-step explanation:
First, we have units measured in meters, centimeters, and millimeters. This means we have to convert everything to the same measurement.
The easiest way is to convert everything to meters, as that's what the unit in the final answer will be.
To convert centimeters to meters, divide by 100
30/100=0.3
To convert millimeters to meters, divide by 1,000
40/1000=0.04
Next, plug the values back into the original equation:
4m-(0.3+0.04)
solve the parenthesis first
4-0.34
3.66
So, this equals 3.66 meters.
Hope this helps! :)
A snack mix recipe calls for 5 3/4 cups of cereal and 3 5/12 cups less of raisins. how many cups of raisins are needed? write in simplest form
Answer is 7/3 cups.
To determine the amount of raisins needed for the snack mix, subtract 3 5/12 cups from 5 3/4 cups of cereal.
First, convert the mixed numbers to improper fractions:
5 3/4 = (5 × 4 + 3)/4 = 23/4
3 5/12 = (3 × 12 + 5)/12 = 41/12
Next, subtract the two fractions:
23/4 - 41/12
To subtract, find a common denominator. The least common multiple of 4 and 12 is 12. Convert both fractions to equivalent fractions with a denominator of 12:
(23/4) × (3/3) = 69/12
(41/12) × (1/1) = 41/12
Now, subtract the fractions:
69/12 - 41/12 = 28/12
Finally, simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor (4):
28/12 = (28 ÷ 4)/(12 ÷ 4) = 7/3
So, you need 7/3 cups of raisins for the snack mix.
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List the defining attributes of each 3-D figure. Then name the figure.
Vertices faces and edges are only a few of the many attributes of three-dimensional shapes. The 3D shapes' faces are their flat exteriors. An edge is the section of a line where two faces converge.
List out the attributes of 3-D figures.1) cube
A vertex is the intersection of three edges. A solid or three-dimensional form with six square faces is called a cube. These are the characteristics of the cube.
Every edge is equal.
8 vertex
6 faces
12 edges
2) Cuboid
When the faces of a cuboid are rectangular, it is often referred to as a rectangular prism. The angles are all 90 degrees each. It has a cuboid.
8 vertex
6 faces
12 edges
3) Prism
A prism is a three-dimensional form with two equal ends, flat faces, and identical sides.l cross-section down the length of it. The prism is typically referred to as a triangular prism since its cross-section resembles a triangle. There is no bend to the prism. A prism has also
6 vertex
9 edges
2 triangles and 3 rectangles
5 faces.
4) Pyramid
A pyramid is a solid object with triangle exterior faces that converge at a single point at its summit. The base of the pyramid may be triangular, square, quadrilateral, or any other polygonal shape. The square pyramid, which has a square base and four triangular faces, is the type of pyramid that is most frequently employed. Take a look at a square pyramid.
5 vertices
5 faces
8 edges
5) Cylinder
The term "cylinder" refers to a three-dimensional geometrical shape.two circular bases joined by a curving surface make up this figure. In a cylinder,
no vertex
2 edges
2 circles on flat faces
one curving face
6) Cone
A cone is a three-dimensional thing or solid with a single vertex and a circular base. A geometric shape known as a cone has a smooth downward slope from its flat, circular base to its top point or apex. In a cone
one vertex
1 edge
1 circle with a flat face.
one curving face
7) Sphere
A sphere is a perfectly round, three-dimensional solid figure, and every point on its surface is equally spaced from the point, which is known as the center. The radius of the sphere is the predetermined distance from the sphere's center.
a sphere is
zero vertex
zero edges
one curving face
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Find the area of the following shape. You must show all work to recive credit.
this is a writting question
The total area of the given figure is 12 units²
In the given figure, we have 3 shapes. One is rectangle and the other two are triangles. We can find areas of all three shapes and add to find the total area.
Finding area of the triangle ABC,
base of the triangle ABC = 4 units
height of the triangle ABC = 4 units
Area of the triangle ABC = 1/2 x base x height = 1/2 x 4 x 4 = 8 units²
Finding area of the triangle CDE,
base of the triangle CDE = 2 units
height of the triangle CDE = 2 units
Area of the triangle CDE = 1/2 x base x height = 1/2 x 2 x 2 = 2 units²
Finding area of the rectangle,
length of the rectangle = 2 units
breadth of the rectangle = 1 unit
Area of the rectangle = length x breadth = 2 x 1 = 2 units²
So, total area of the given figure = 8 units² + 2 units² + 2 units² = 12 units²
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1
(Lesson 8.2) Which statement about the graph of the rational function given is true? (1/2 point)
4. f(x) = 3*-7
x+2
A. The graph has no asymptotes.
B.
The graph has a vertical asymptote at x = -2.
C. The graph has a horizontal asymptote at y =
+
The statement about the graph of rational function which is true is option B. that is "The graph has a vertical asymptote at x = -2
What is a rational function?A rational function in mathematics is any function that can be described by a rational fraction, which is an algebraic fraction in which both the numerator and denominator are polynomials.
So the statement about the graph of the rational function indicated above is true, this is because the denominator of the rational function is (x+2), which equals zero when x=-2. Therefore, the function is undefined at x=-2 and the graph has a vertical asymptote at that point.
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The table shows the number of devices owned by a local company. What percent of these devices are tablets?
Laptop- 44
Tablet- 94
Desktop- 62
Laptop- 44, Tablet- 94, Desktop- 62, Percentage of tablets- 47%.
What percentage of the devices owned by the local company are tablets?To calculate the percentage of devices that are tablets, we need to find the proportion of tablets among all devices. In this case, there are 94 tablets out of a total of 200 devices (44 laptops + 94 tablets + 62 desktops).
To find the proportion, we divide the number of tablets by the total number of devices: 94/200 = 0.47.
To convert this proportion to a percentage, we multiply by 100: 0.47 * 100 = 47%.
47% of the devices owned by the local company are tablets.
This means that nearly half of the devices fall into the tablet category, making it a significant portion of their device inventory.
It's important to note that this calculation assumes the given numbers accurately represent the actual device distribution and that there are no missing or unaccounted devices.
By determining the percentage of tablets, we gain insight into the composition of the device inventory, which can be useful for decision-making and resource allocation within the local company.
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QR has endpoints at Q(5, –6) and R(6, 3). Find the midpoint M of QR.
Answer:
(5.5, -1.5)
Step-by-step explanation:
(x, y)midpoint = (x1 + x2)/2 , (y1 + y2)/2
= (6 + 5)/2, (3 - 6)/2
= (11/2, -3/2)
= (5.5, -1.5)
Libby starts draining the pool for cleaning. The function y = 10,080 - 720x represents the
gallons of water y remaining in the pool after x hours. Find the zero and explain what it means in the context of the situation
The zero of the function is 14. In the context of the situation, this means it will take 14 hours for Libby to completely drain the pool for cleaning.
To find the zero of the function, we need to determine the value of x when y equals 0.
0 = 10,080 - 720x
To solve for x, we will isolate the variable by following these steps:
1. Add 720x to both sides:
720x = 10,080
2. Divide both sides by 720:
x = 14
The zero of the function is 14, which means that after 14 hours, there will be no water remaining in the pool. In the context of the situation, this means it will take 14 hours for Libby to completely drain the pool for cleaning.
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Find the area of the surface obtained by rotating the curve of parametric equations x = 6 cos^3 θ, y = 6sin^3 θ, 0 ≤ θ ≤ π/2
The area of the surface obtained by rotating the curve of parametric equations x = 6 cos^3 θ, y = 6sin^3 θ, 0 ≤ θ ≤ π/2 is 96π/5 square units.
To find the area of the surface obtained by rotating the curve of parametric equations x = 6 cos^3 θ, y = 6sin^3 θ, 0 ≤ θ ≤ π/2, we can use the formula for surface area of revolution:
A = 2π ∫_a^b f(x) √(1+(f'(x))^2) dx
In this case, we need to first find the function y = f(x) that represents the curve. Using the given parametric equations, we can eliminate θ to get:
x = 6 cos^3 θ
x = 6 (1-sin^2 θ) cos^2 θ
y = 6 sin^3 θ
y = 6 (1-x/6)^(3/2)
So the function that represents the curve is y = 6 (1-x/6)^(3/2). Now we can use the formula for surface area of revolution:
A = 2π ∫_0^6 (6 (1-x/6)^(3/2)) √(1+(-3/4 (1-x/6)^(-1/2))^2) dx
A = 2π ∫_0^6 (6 (1-x/6)^(3/2)) √(1+9/16 (1-x/6)^(-1)) dx
A = 2π ∫_0^6 (6 (1-x/6)^(3/2)) √((25-9x)/(16(1-x/6))) dx
This integral can be evaluated using substitution and partial fractions. The final answer is:
A = 96π/5
Therefore, the area of the surface obtained by rotating the curve of parametric equations x = 6 cos^3 θ, y = 6sin^3 θ, 0 ≤ θ ≤ π/2 is 96π/5 square units.
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What does [OH-] equal when [H*] = 1. 15 x 108 M?
721*10-5 M
For water [OH⁻] equals 8.70 x 10⁻²³ M when [H⁺] = 1.15 x 10⁸ M .
How to find the value of OH-Assuming that the ion product constant for water is being questioned, Kw:
Kw = [H⁺] [OH⁻]
where Kw = ion product constant for water
kW at 25°C = 1.0 x 10⁻¹⁴
Since Kw is constant at a given temperature, if we know the concentration of [H⁺] or [OH⁻], we can find it with Kw the concentration of the new ion
given that [H⁺] = 1.15 x 10⁸ M, [OH⁻] can be determined as follows.
Kw = [H⁺] [ OH⁻]
plugging in the values
1.0 x 10⁻¹⁴ M² = (1.15 x 10⁸ M) * ([OH⁻])
[OH⁻] = (1.0 x 10⁻¹⁴ M² ) / (1.15 x 10⁸ M )
[OH⁻] = 8.70 x 10⁻²³ M
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Find the exact solutions of the equation in the interval (0, 2). (Enter your answers as a comma-separated list) 4 tan 2x - 4 cot x = 0 x= π/6 , π/2, 5π/6, 7π/6, 3π/2, 11π/6
Therefore, the solutions of tan x = -1/2 in the interval (0, 2) are:
x ≈ 2.034, 5.176
We can simplify the given equation as follows:
4 tan 2x - 4 cot x = 0
4(tan 2x - cot x) = 0
4[(2tan x)/(1 - tan^2 x) - (1)/(tan x)] = 0
Multiplying both sides by (1 - tan^2 x) * (tan x), we get:
8tan^3 x - 4tan^2 x - 8tan x + 4 = 0
Dividing both sides by 4 and rearranging, we get:
2tan^3 x - tan^2 x - 2tan x + 1 = 0
Factorizing, we get:
(tan x - 1)(2tan^2 x - tan x - 1) = 0
Using the quadratic formula to solve for the roots of 2tan^2 x - tan x - 1 = 0, we get:
tan x = [1 ± sqrt(1 + 8)] / 4 = [1 ± sqrt(9)] / 4 = 1, -1/2
Therefore, the solutions of the given equation in the interval (0, 2) are the values of x such that tan x = 1 or tan x = -1/2.
We know that tan (π/4) = 1 and tan (-π/4) = -1, so the solutions of tan x = 1 in the interval (0, 2) are:
x = π/4, 5π/4
We can find the solutions of tan x = -1/2 in the interval (0, 2) by finding the reference angle and using the signs of sine and cosine in the corresponding quadrants. We have:
tan x = -1/2
Let θ be the reference angle such that tan θ = 1/2. We know that θ is in the second or fourth quadrant.
In the second quadrant, sine is positive and cosine is negative, so we have:
sin θ = sqrt(1/(1 + tan^2 θ)) = sqrt(1/5)
cos θ = -tan θ = -1/2
Therefore, we get:
x = π - θ = π + arctan(1/2) ≈ 2.034
In the fourth quadrant, both sine and cosine are negative, so we have:
sin θ = -sqrt(1/(1 + tan^2 θ)) = -sqrt(1/5)
cos θ = -tan θ = -1/2
Therefore, we get:
x = 2π - θ = 2π + arctan(1/2) ≈ 5.176
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A standard piece of notebook paper measures 8.5 inches by 11 inches. By cutting a square out of each corner, the sides can be folded up to create a box with an open top. Determine the size of the square that needs to be cut out of each corner to create a box of maximum volume. For extra credit, perform this experiment from home and include a picture of the box you create. 3) (2 points) If f'(x)=6x² – 5 sin x+eˣ and f(0) = 20, determine the function f.
The size of the square that needs to be cut out of each corner to create a box of maximum volume is 5/3 inches.
To determine the function f given that f'(x)=6x² – 5 sin x+eˣ and f(0) = 20, we need to integrate f'(x) with respect to x to obtain f(x), and then use the initial condition f(0) = 20 to find the value of the constant of integration.
Integrating f'(x) with respect to x, we have:
f(x) = 2x³ + 5 cos x + eˣ + C
where C is the constant of integration.
Using the initial condition f(0) = 20, we have:
f(0) = 2(0)³ + 5 cos 0 + e⁰ + C = 6 + C = 20
Therefore, the constant of integration is C = 14, and the function f(x) is:
f(x) = 2x³ + 5 cos x + eˣ + 14
To determine the size of the square that needs to be cut out of each corner of a standard piece of notebook paper to create a box of maximum volume, we can start by drawing a diagram of the box and labeling the sides as follows:
| |
| |
| | h
| |
|__________|
L
Let x be the length of each side of the square that is cut out of each corner. Then, the length and width of the base of the box will be L - 2x and 11 - 2x, respectively, and the height of the box will be x. Therefore, the volume V of the box can be expressed as:
V(x) = x(L - 2x)(11 - 2x)
Expanding and simplifying, we get:
V(x) = -4x³ + 46x² - 110x
To find the size of the square that maximizes the volume of the box, we need to find the value of x that maximizes V(x). This can be done by finding the critical points of V(x) and determining whether they correspond to a maximum or minimum.
Taking the derivative of V(x) with respect to x, we get:
V'(x) = -12x² + 92x - 110
Setting V'(x) = 0 and solving for x, we get:
x = 5/3 or x = 11/6
To determine whether these values correspond to a maximum or minimum, we can use the second derivative test. Taking the second derivative of V(x) with respect to x, we get:
V''(x) = -24x + 92
Evaluating V''(5/3) and V''(11/6), we find that:
V''(5/3) = -4 < 0, so x = 5/3 corresponds to a maximum.
V''(11/6) = 20 > 0, so x = 11/6 corresponds to a minimum.
Therefore, the size of the square that needs to be cut out of each corner to create a box of maximum volume is 5/3 inches.
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Find u × v, v x u, and v x v.
u = 2i + 6k
v = 4i + 7j - 5k.
To find u × v, we use the cross product formula:
u × v = | i j k |
| 2 0 6 |
| 4 7 -5 |
Expanding the determinant, we get:
u × v = (0*-5 - 6*7) i - (2*-5 - 6*4) j + (2*7 - 0*4) k
u × v = -42i - 22j + 14k
To find v × u, we use the same formula but switch the order of u and v:
v × u = | i j k |
| 4 7 -5 |
| 2 0 6 |
Expanding the determinant, we get:
v × u = (7*6 - (-5)*0) i - (4*6 - (-5)*2) j + (4*0 - 7*2) k
v × u = 42i + 18j - 14k
Finally, to find v × v, we again use the cross product formula with v as both inputs:
v × v = | i j k |
| 4 7 -5 |
| 4 7 -5 |
Expanding the determinant, we get:
v × v = (7*(-5) - (-5)*7) i - (4*(-5) - (-5)*4) j + (4*7 - 7*4) k
v × v = 0i - 0j + 0k
v × v = 0
So the cross product of v with itself is the zero vector.
To find u × v, v × u, and v × v, we'll use the cross product formula:
u × v = (u_yv_z - u_zv_y)i + (u_zv_x - u_xv_z)j + (u_xv_y - u_yv_x)k
Given u = 2i + 6k and v = 4i + 7j - 5k, we have:
u_x = 2, u_y = 0, u_z = 6
v_x = 4, v_y = 7, v_z = -5
Now, calculate u × v:
(0 * (-5) - 6 * 7)i + (6 * 4 - 2 * (-5))j + (2 * 7 - 0 * 4)k
= (-42)i + (34)j + (14)k
u × v = -42i + 34j + 14k
Next, calculate v × u:
(7 * 6 - (-5) * 0)i + ((-5) * 2 - 4 * 6)j + (4 * 0 - 7 * 2)k
= (42)i + (-34)j + (-14)k
v × u = 42i - 34j - 14k
Finally, calculate v × v:
(7 * (-5) - (-5) * 7)i + ((-5) * 4 - 4 * (-5))j + (4 * 7 - 7 * 4)k
= (0)i + (0)j + (0)k
v × v = 0i + 0j + 0k
In summary:
u × v = -42i + 34j + 14k
v × u = 42i - 34j - 14k
v × v = 0i + 0j + 0k
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Certain pieces of antique furniture increased very rapidly in price in the 1970s and 1980s. For example, the value of a particular rocking chair is well approximated by V = 115(1.6), where V is in dollars andtis the number of years since 1975. Find the rate, in dollars per year, at which the price is increasing.
rate = dollars/yr
The given equation for the value of the rocking chair is V = 115(1.6)^t, where t is the number of years since 1975. To find the rate at which the price is increasing, we need to find the derivative of this equation with respect to time:
dV/dt = 115(1.6)^t * ln(1.6)
This tells us that the rate of increase in value is proportional to the current value of the chair, which makes sense since the value is increasing at a faster rate as the chair becomes more valuable.
To find the rate in dollars per year, we can evaluate the derivative at t = 0 (since we want to know the rate at the present time, which is 2021 - 1975 = 46 years after 1975):
dV/dt = 115(1.6)^0 * ln(1.6) = 30.03
Therefore, the rate at which the price of the rocking chair is increasing is approximately $30.03 per year.
It seems that there is a missing exponent in the given formula for the value of the rocking chair. The correct formula should include an exponent 't' as in V = 115(1.6)^t, where V is the value in dollars and t is the number of years since 1975.
To find the rate at which the price is increasing, we need to find the derivative of the value function with respect to time (t). The derivative of V = 115(1.6)^t is dV/dt = 115 * ln(1.6) * (1.6)^t.
To find the rate in dollars per year, we need to evaluate this expression at a specific time (t). For example, to find the rate in the year 1980 (5 years since 1975), we can plug in t = 5:
Rate = 115 * ln(1.6) * (1.6)⁵ ≈ $419.20 per year
So, in 1980, the price of the rocking chair was increasing at a rate of approximately $419.20 per year.
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Find the value of m if third quartile (Q3) of the data given below is 128. (Income Rs. ) 0-30, 30-60, 60-90, 90-120, 120-150, 150-180 (No. Of Labour) 2, 8 ,22 ,24 ,m ,9
The value of median m that makes Q₃ equal to 128 is approximately 18.75.
What is median?The median is the value that divides the higher half of a population, a probability distribution, or a sample of data from the lower half. It can be conceptualised as a data set's "middle" value to put it simply.
To find the value of m, we need to first calculate the median and third quartile of the data.
To calculate the median, we need to find the value that splits the data into two halves. Since the data is already sorted into intervals, we can find the cumulative frequency for each interval and use it to determine the median interval. The median interval is the interval that contains the median. We can then use the formula for the median of grouped data to calculate the median value.
Cumulative frequency for each interval:
- Interval 0-30: 2
- Interval 30-60: 2+8=10
- Interval 60-90: 10+22=32
- Interval 90-120: 32+24=56
- Interval 120-150: 56+m
- Interval 150-180: 56+m+9=65+m
Since there are 6 intervals, the median interval is the 3rd interval, which is 60-90. The lower limit of this interval is 60, and the cumulative frequency up to this interval is 32. The frequency of this interval is 22. Using the formula for the median of grouped data:
Median = L + ((n/2 - CF) / f) * w
where L is the lower limit of the median interval, CF is the cumulative frequency up to the median interval, n is the total sample size, f is the frequency of the median interval, and w is the width of the interval.
Plugging in the values, we get:
Median = 60 + ((50 - 32) / 22) * 30
Median = 60 + (18 / 22) * 30
Median = 60 + 15.45
Median ≈ 75.45
Now, to find the third quartile (Q₃), we need to find the value that splits the upper 50% of the data. Since Q₃ is the 75th percentile, the cumulative frequency up to Q₃ is 0.75 times the total sample size:
Q₃ = L + ((0.75 * n - CF) / f) * w
We know that Q₃ is 128, and we can plug in the values for L, n, CF, f, and w that correspond to the interval that contains Q₃:
128 = 120 + ((0.75 * 85 - 56 - m) / (24)) * 30
Simplifying and solving for m, we get:
m = 120 + ((0.75 * 85 - 56) / (24)) * 30 - 128
m ≈ 18.75
Therefore, the value of m that makes Q₃ equal to 128 is approximately 18.75.
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Solve the equation and check your solution: -2(x - 1) = 2 - 2x
The figure 2 is dilated from figure 1. Find the scale factor.
The prism is completely filled with 135 cubes that have edge length of 13ft. What is the volume of the prism?Enter your answer in the box
The volume of the prism is 2.98×10⁵ cubic feets according to the stated number and dimensions of constituting prism.
The volume of any shape is it's capacity to contain the item in it. It is the product of all its sides.
Volume of cube = side × side × side
Since there are multiple prisms of specific sides completely contained in the prism, their number will also be multiplied.
Volume of cube = 136 × 13 × 13 × 13
Performing multiplication on Right Hand Side of the equation
Volume of cube = 298,792 cubic feets
Hence, the volume of cube is 2.98×10⁵ cubic feet.
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Order from least to greatest
30.
4,0.91,8
50
Answer:
0.91
30.4
850
Step-by-step explanation:
What is the lateral area of the cone to the nearest whole number? The figure is not drawn to scale.
*
Captionless Image
34311 m^2
18918 m^2
15394 m^2
28742 m^2
The lateral area of the cone is 18918 m²
How to find the lateral area of the cone?
The lateral area of the cone can be determined using the formula:
A[tex]_{L}[/tex] = πrL
Where is the r is the radius of circular base of the cone and L is the slant height
In this case:
r = 140/2 = 70m
L = √(50² + 70²) (Pythagoras theorem)
L = 10√74 m
A[tex]_{L}[/tex] = π * 70 * 10√74
A[tex]_{L}[/tex] = 18918 m²
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A study of the demand for air travel between two cities depends on the airfare according to the following demand equation. q=55.1−0.023p
The demand equation can be used to estimate the demand for air travel at different price levels, and can help airlines make pricing decisions based on the expected demand.
The demand equation is given as:
q = 55.1 - 0.023p
where q is the quantity demanded and p is the price of the airfare.
This equation shows an inverse relationship between price and quantity demanded. As the price of the airfare increases, the quantity demanded decreases, and vice versa.
For example, if the airfare price is $100, we can calculate the quantity demanded as:
q = 55.1 - 0.023(100) = 52.8
This means that at a price of $100, the quantity demanded is approximately 52.8 units.
Similarly, if the airfare price is $200, we can calculate the quantity demanded as:
q = 55.1 - 0.023(200) = 50.4
This means that at a price of $200, the quantity demanded is approximately 50.4 units.
So, demand equation can be used to estimate the demand for air travel at different price levels, and can help airlines make pricing decisions based on the expected demand.
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What is the solution to the equation log(4x + 4) = 2 ? show your work
Answer:
Isolate the variable by dividing each side by factors that don't contain the variable.
Exact Form:
x = −1/2
Decimal Form:
x = −0.5
Step-by-step explanation:
Answer:
x = 24
Step-by-step explanation:
using the rule of logarithms
[tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex]
note that log x represents [tex]log_{10}[/tex] x
given
log(4x + 4) = 2 , then
4x + 4 = 10² = 100 ( subtract 4 from both sides )
4x = 96 ( divide both sides by 4 )
x = 24
A quantity with an initial value of 8200 grows continuously at a rate of 0. 55% per decade. What is the value of the quantity after 97 years, to the nearest hundredth?
Answer: 4000. 4
As per the growth function, the value of the quantity after 97 years would be $67,458.85.
In your problem, you have a quantity with an initial value of 8200 that grows continuously at a rate of 0.55% per decade. To find the value of the quantity after 97 years, we can use the following growth function:
A(t) = A₀[tex]e^{kt}[/tex]
In this formula, A(t) represents the value of the quantity after time t, A₀ represents the initial value of the quantity (in this case, 8200), e represents Euler's number (a mathematical constant equal to approximately 2.718), k represents the growth rate (in this case, 0.0055 per decade), and t represents the time elapsed (in this case, 97 years).
To solve for the value of the quantity after 97 years, we simply plug in the values we know and solve for A(t):
A(t) = 8200[tex]e^{(0.0055/10\times97)}[/tex]
= 8200[tex]e^{0.5285}[/tex]
≈ 67,458.85
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Question 1(Multiple Choice Worth 2 points)
(Circle Graphs MC)
The circle graph describes the distribution of preferred transportation methods from a sample of 400 randomly selected San Francisco residents.
circle graph titled San Francisco Residents' Transportation with five sections labeled walk 40 percent, bicycle 8 percent, streetcar 15 percent, bus 10 percent, and cable car 27 percent
Which of the following conclusions can we draw from the circle graph?
Together, Streetcar and Cable Car are the preferred transportation for 168 residents.
Together, Walk and Streetcar are the preferred transportation for 55 residents.
Bus is the preferred transportation for 45 residents.
Bicycle is the preferred transportation for 50 residents.
Question 2(Multiple Choice Worth 2 points)
(Appropriate Measures MC)
The box plot represents the number of tickets sold for a school dance.
A horizontal line labeled Number of Tickets sold that starts at 8, with tick marks every one unit up to 30. The graph is titled Tickets Sold for A Dance. The box extends from 17 to 21 on the number line. A line in the box is at 19. The lines outside the box end at 10 and 27.
Which of the following is the appropriate measure of center for the data, and what is its value?
The mean is the best measure of center, and it equals 19.
The median is the best measure of center, and it equals 4.
The median is the best measure of center, and it equals 19.
The mean is the best measure of center, and it equals 4.
Question 3(Multiple Choice Worth 2 points)
(Comparing Data LC)
The histograms display the frequency of temperatures in two different locations in a 30-day period.
A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 14. A shaded bar stops at 10 above 60 to 69, at 9 above 70 to 79, at 5 above 80 to 89, at 4 above 90 to 99, and at 2 above 100 to 109. There is no shaded bar above 110 to 119. The graph is titled Temps in Sunny Town.
A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 16. A shaded bar stops at 2 above 60 to 69, at 4 above 70 to 79, at 12 above 80 to 89, at 6 above 90 to 99, at 4 above 100 to 109, and at 2 above 110 to 119. The graph is titled Temps in Desert Landing.
When comparing the data, which measure of center should be used to determine which location typically has the cooler temperature?
Median, because Desert Landing is symmetric
Mean, because Sunny Town is skewed
Mean, because Desert Landing is symmetric
Median, because Sunny Town is skewed
Question 4(Multiple Choice Worth 2 points)
(Appropriate Measures MC)
A charity needs to report its typical donations received. The following is a list of the donations from one week. A histogram is provided to display the data.
10, 11, 35, 39, 40, 42, 42, 45, 49, 49, 51, 51, 52, 53, 53, 54, 56, 59
A graph titled Donations to Charity in Dollars. The x-axis is labeled 10 to 19, 20 to 29, 30 to 39, 40 to 49, and 50 to 59. The y-axis is labeled Frequency. There is a shaded bar up to 2 above 10 to 19, up to 2 above 30 to 39, up to 6 above 40 to 49, and up to 8 above 50 to 59. There is no shaded bar above 20 to 29.
Which measure of variability should the charity use to accurately represent the data? Explain your answer.
The range of 13 is the most accurate to use, since the data is skewed.
The IQR of 49 is the most accurate to use to show that they need more money.
The range of 49 is the most accurate to use to show that they have plenty of money.
The IQR of 13 is the most accurate to use, since the data is skewed.
Question 5(Multiple Choice Worth 2 points)
(Making Predictions MC)
A recent conference had 900 people in attendance. In one exhibit room of 80 people, there were 65 teachers and 15 principals. What prediction can you make about the number of principals in attendance at the conference?
There were about 820 principals in attendance.
There were about 731 principals in attendance.
There were about 208 principals in attendance.
There were about 169 principals in attendance.
Question 6(Multiple Choice Worth 2 points)
(Creating Graphical Representations LC)
A teacher was interested in the subject that students preferred in a particular school. He gathered data from a random sample of 100 students in the school and wanted to create an appropriate graphical representation for the data.
Which graphical representation would be best for his data?
Stem-and-leaf plot
Histogram
Circle graph
Box plot
Answer 1: Together, Streetcar and Cable Car are the preferred transportation for 168 residents.
How to solveThe circle graph shows the percentage of residents who prefer each transportation method, and the total sample size is 400.
For streetcar, (15/100) x 400 = 60 residents prefer it, and for cable car, (27/100) x 400 = 108 residents prefer it.
Together, Streetcar and Cable Car are the preferred transportation for 60 + 108 = 168 residents.
Answer 2: The median is the best measure of center, and it equals 19.
The box plot shows the distribution of the number of tickets sold for a school dance.
The median is the middle value of the data when arranged in order, and it is represented by the line in the box. In this case, the median is 19. The mean, on the other hand, can be influenced by extreme values, and we cannot determine it from the box plot alone.
Answer 3: Median, because Sunny Town is skewed.
When comparing the data, we need to consider the measure of center that is less affected by extreme values, and that is the median.
The median is the middle value of the data when arranged in order. The histogram for Sunny Town is skewed to the right, which means that there are some very high values that are affecting the mean.
Therefore, the median is the better measure of center to determine which location typically has the cooler temperature.
Answer 4: The IQR of 13 is the most accurate to use, since the data is skewed.
The histogram shows the frequency of donations received by a charity, and the data is skewed to the right.
The IQR (Interquartile Range) is the difference between the third quartile (Q3) and the first quartile (Q1), which represents the middle 50% of the data.
The IQR is less sensitive to extreme values and is a better measure of variability for skewed data. In this case, the IQR is 49 - 42 = 7, which is the most accurate measure of variability to use.
Answer 5: There were about 15 principals in attendance.
In the exhibit room, out of 80 people, 15 are principals.
We can assume that the proportion of principals in the exhibit room is the same as the proportion of principals in the conference.
Therefore, the estimated number of principals in the conference is (15/80) x 900 = 168.75, which is approximately 169.
Answer 6: Histogram
The teacher wants to represent the subject preferences of 100 students. A histogram would be the best graphical representation to use because it shows the frequency distribution of a continuous variable, which in this case could be the number of students who prefer each subject.
A stem-and-leaf plot is used for small datasets, and a box plot is used to display the distribution of a continuous variable across categories. A circle graph is more appropriate for displaying categorical data, such as the percentage of students who prefer each subject.
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Lesson 10. 3 name two streets that appear to be parallel
Answer:
Step-by-step explanation:
where are the streets
For the week, Castle Manufacturing has a beginning cash balance of 100,000. They spend 99,000 on direct materials, 19,000 on direct labor, and 29,000 on manufacturing overhead. They also have cash sales of 10,000, accounts receivable collections of 220,000 and asset sales of 30,000. They also purchased assets in the amount of 20,000 and had sales commissions and other administrative expenses in the amount of 40,000. What was Castle Manufacturing cash balance at the end of the week?
Castle Manufacturing's cash balance at the end of the week would be $153,000.
To determine the cash balance, we must consider the beginning cash balance, cash inflows and cash outflows.
Beginning cash balance: $100,000
Cash inflows:
- Cash sales: $10,000
- Accounts receivable collections: $220,000
- Asset sales: $30,000
Total cash inflows: $260,000
Cash outflows:
- Direct materials: $99,000
- Direct labor: $19,000
- Manufacturing overhead: $29,000
- Purchase of assets: $20,000
- Sales commissions and administrative expenses: $40,000
Total cash outflows: $207,000
Ending cash balance: Beginning cash balance + Total cash inflows - Total cash outflows
= $100,000 + $260,000 - $207,000
= $153,000
Therefore, Castle Manufacturing's cash balance at the end of the week would be $153,000.
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A school chess club needs to raise at least $750 to attend a state competition.
The inequality which can be used to determine amount the club needs to raise during remaining months is 400 + 4n ≥ 750.
The goal of the school chess club is to raise at least $750 in total so that they can attend a state competition. They have already raised $400, but they still need to raise more money. Let's call the amount they need to raise each month "n".
Since the club has 4 months remaining until the competition, they will need to raise a total of "4n" dollars during that time period.
To determine the minimum amount they need to raise each month, the inequality can be written as : 400 + 4n ≥ 750,
4n ≥ 350 ; n ≥ 87.5.
This means that the chess-club needs to raise at least $87.50 each month in order to reach their goal of $750 in 4 months.
Therefore, the required inequality is 400 + 4n ≥ 750.
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The given question is incomplete, the complete question is
A school chess club needs to raise at least $750 to attend a state competition. The club has already raised $400 and there are 4 months remaining until the competition. Write an inequality which can be used to determine the dollar amount the club will need to raise during the remaining months?
When he was 30, Kearney began investing $200 per month in various securities for his retirement savings. His investments averaged a 5. 5% annual rate of return until he retired at age 68. What was the value of Kearney's retirement savings when he retired? Assume monthly compounding of interest
To calculate the value of Kearney's retirement savings when he retired, we need to use the formula for compound interest:
A = P(1 + r/n)^(nt)
where:
A = final amount
P = initial principal (the amount Kearney invested each month)
r = annual interest rate (5.5%)
n = number of times interest is compounded per year (12, since we're assuming monthly compounding)
t = number of years
First, we need to calculate the total number of payments Kearney made into his retirement savings:
68 - 30 = 38 years
Since Kearney made monthly payments, the total number of payments is:
38 years x 12 months/year = 456 payments
Next, we need to calculate the value of each payment after it has earned interest. We can use the same formula as above, but with t = 1 (since we're calculating the value of one payment period):
P' = P(1 + r/n)^(nt)
P' = 200(1 + 0.055/12)^(12*1)
P' = 200(1.00458333333)^12
P' = 200(1.00458333333)^12
P' = 200(1.00458333333)^12
P' = 243.382740047
So each $200 payment is worth $243.38 after one month of earning interest.
Now we can use the formula for the future value of an annuity to calculate the total value of Kearney's retirement savings:
A = P'[(1 + r/n)^(nt) - 1]/(r/n)
A = 243.38[(1 + 0.055/12)^(12*38) - 1]/(0.055/12)
A = 243.38[1.93378208462 - 1]/(0.055/12)
A = 243.38[34.3478377249]
A = $8,351.53
Therefore, the value of Kearney's retirement savings when he retired was approximately $8,351.53.
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When Kearney retired at age 68, the value of his retirement savings was $557,123.35.
To find the value of Kearney's retirement savings when he retired, we'll use the Future Value of an Annuity formula. Here are the given values and the formula:
Monthly investment (PMT) = $200
Annual interest rate (r) = 5.5% = 0.055
Monthly interest rate (i) = (1 + r)^(1/12) - 1 ≈ 0.004434
Number of years of investment (n) = 68 - 30 = 38 years
Number of months of investment (t) = 38 years * 12 months = 456 months
Future Value of Annuity (FV) formula:
FV = PMT * [(1 + i)^t - 1] / i
Now, we'll plug in the values and calculate the Future Value:
FV = 200 * [(1 + 0.004434)^456 - 1] / 0.004434
FV ≈ 200 * [12.2883] / 0.004434
FV ≈ 557123.35
The value of his retirement savings was approximately $557,123.35.
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The gcf of 16mn and 24m
Kevin needs 2/3 of a yard to make a pillow. He has 3 1/3 yards of fabric. How many pillows can he make? A). 2 2/9 B. ) 3 2/3 C. ) 5 D. ) 6
The number of pillows requiring [tex]\frac{2}{3}[/tex] yards that can be made from [tex]3\frac{1}{3}[/tex] yards is 5. Thus the right answer to the given question is C.
Material required for making one pillow = [tex]\frac{2}{3}[/tex] yards
Total material = [tex]3\frac{1}{3}[/tex] yards
To find the number of pillows made we have to divide the material required for one pillow by the total material available to Kevin for making pillows
Number of pillows = [tex]3\frac{1}{3}[/tex] ÷ [tex]\frac{2}{3}[/tex]
= [tex]\frac{10}{3}[/tex] ÷ [tex]\frac{2}{3}[/tex]
To divide two fractions, we take the reciprocal of the second number and multiply it by the first number.
= [tex]\frac{10}{3}[/tex] * [tex]\frac{3}{2}[/tex]
= 5
Thus, the number of pillows made is 5.
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A sample of 60 Grade 9 students' ages was obtained to estimate the mean age of all Grade 9 students. Consider that
X
= 15. 3 years and the population variance is 16. (Note: Standard Deviation is the square root of variance). Assume that the distribution is normal.
Answer the following questions:
1. What is the point estimate for
μ
?
2. Find the 95% confidence interval for
μ
.
3. Find the 99% confidence interval for
μ
.
4. What conclusions can you make based on each interval estimate ?
The point estimate for μ is 15.3 years, based on the sample of 60 Grade 9 students.
How to find the age of all Grade 9 of students?Based on the statistical techniques given information, the point estimate for the population mean age of all Grade 9 students is 15.3 years. This means that if we assume that the sample is representative of the entire population of Grade 9 students, then we estimate that the average age of all Grade 9 students is 15.3 years.
To estimate the precision of this point estimate, we can calculate confidence intervals. For a 95% confidence interval, we can use the formula:
CI = X ± (Zα/2) * (σ/√n)
where X is the point estimate, Zα/2 is the critical value of the standard normal distribution for a 95% confidence level (1.96), σ is the population standard deviation (which we assume to be known as 4), and n is the sample size (which is 60).
Substituting the values, we get the 95% confidence interval as:
CI = 15.3 ± (1.96) * (4/√60) = (14.33, 16.27)
This means that we can be 95% confident that the true population mean age of Grade 9 students lies between 14.33 and 16.27 years.
For a 99% confidence interval, we can use the same formula with a different value of Zα/2 (2.58 for a 99% confidence level). Substituting the values, we get the 99% confidence interval as:
CI = 15.3 ± (2.58) * (4/√60) = (13.94, 16.66)
This means that we can be 99% confident that the true population mean age of Grade 9 students lies between 13.94 and 16.66 years.
Based on the confidence intervals, we can conclude that the sample provides evidence that the true mean age of all Grade 9 students is likely to be between 14.33 and 16.27 years with a 95% confidence level, and between 13.94 and 16.66 years with a 99% confidence level. However, we cannot be completely certain that the true population mean falls within these intervals as there is always some level of uncertainty associated with sample-based estimates.
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