4. 9 on richter scale use formula r=log(a/ao) to determine how many times stronger the wave amplitude a of the earthquake was an ao

Answer:

he needs 15 ounces more

Step-by-step explanation:

Findings of an intervention study with a convenience sample should be replicated before being applied to a wider population.

The correct answer is: d.
This is because a convenience sample may not be representative of the entire population, and thus, the findings might not be generalizable to a wider group of patients with related problems.

Replicating the study with a more diverse sample can help ensure the results are applicable to a broader population.

The correct answer is d :

Findings of an intervention study with a convenience sample should be replicated before being applied to a wider population.

Convenience sampling involves selecting participants based on their availability and willingness to participate, rather than randomly selecting them from a larger population.

As a result, convenience samples may not be representative of the larger population and may have biases that affect the generalizability of the findings.

Therefore, it is important to replicate the study using a more representative sample before drawing conclusions that can be applied to a wider population.

This helps to ensure that the findings are reliable and can be generalized to the broader population.

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The antiderivative of f(x) = 2cosx - 7sinx is F(x) = 2sinx + 7cosx + C.

To find the antiderivative of f(x) = 2cosx - 7sinx, we need to use the integration rules for the trigonometric functions. The integral of cosx is sinx, and the integral of sinx is -cosx, so we have:

∫2cosx dx - ∫7sinx dx

= 2∫cosx dx - 7∫sinx dx

= 2sinx - 7(-cosx) + C

where C is the constant of integration.

Therefore, the antiderivative of f(x) = 2cosx - 7sinx is F(x) = 2sinx + 7cosx + C.

An antiderivative of a function f(x) is a function F(x) whose derivative is equal to f(x). In other words, if we take the derivative of F(x), we get f(x). It is also known as an indefinite integral of f(x). The antiderivative of a function f(x) is not unique; there may be many functions whose derivative is equal to f(x), differing only by a constant term.

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A Type II error is when you fail to reject the null hypothesis when it is actually false. In this case, a Type II error would be to conclude that the true mean level of support for sustainability is 70 when, in fact, the mean is not equal to 70 (similar to option D, but specifically for a Type II error).

a. The null and alternative hypotheses for testing this claim are:
Hou = 70 (the true mean level of support for sustainability is 70)
Hau < 70 (the true mean level of support for sustainability is less than 70)

b. A Type I error is the rejection of the null hypothesis when it is actually true. In this problem, a Type I error would be to conclude that the true mean level of support for sustainability is less than 70 when, in fact, the true mean is equal to 70.
A Type II error is the failure to reject the null hypothesis when it is actually false. In this problem, a Type II error would be to conclude that the true mean level of support for sustainability is equal to or greater than 70 when, in fact, the true mean is less than 70.

Therefore, the correct answer is A. A Type I error would be to conclude that the true mean level of support for sustainability is not 70 when, in fact, the mean is equal to 70.
a. For this problem, the null and alternative hypotheses are:
Hou = 70 (the true mean level of support for sustainability is 70)
Hau ≠ 70 (the true mean level of support for sustainability is not 70)
b. A Type I error is when you reject the null hypothesis when it is actually true. In this case, a Type I error would be to conclude that the true mean level of support for sustainability is not 70 when, in fact, the mean is equal to 70 (option A).

A Type II error is when you fail to reject the null hypothesis when it is actually false. In this case, a Type II error would be to conclude that the true mean level of support for sustainability is 70 when, in fact, the mean is not equal to 70 (similar to option D, but specifically for a Type II error).

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a) The velocity at time t can be calculated using function v(t) = t² + 3t - 4.

b) The distance traveled during the time interval [0, 3] is approximately 30.5 meters.

To find the velocity function v(t), we need to integrate the acceleration function a(t) with respect to time:

a(t) = 2t + 3

∫a(t) dt = ∫(2t + 3) dt

v(t) = ∫(2t + 3) dt = t² + 3t + C

We need to find the constant C using the initial velocity v(0) = -4:

v(0) = 0² + 3(0) + C = C = -4

So the velocity function is:

v(t) = t² + 3t - 4

To find the distance traveled during the time interval [0, 3], we need to integrate the absolute value of the velocity function:

d(t) = ∫|v(t)| dt = ∫|t² + 3t - 4| dt

The velocity changes sign at t = -4 and t = 1, so we need to break the integral into three parts:

d(t) = ∫(-t² - 3t + 4) dt for 0 ≤ t ≤ 1

+ ∫(t² + 3t - 4) dt for 1 ≤ t ≤ 3

+ ∫(-t² - 3t + 4) dt for -4 ≤ t ≤ 0

Evaluating each integral, we get:

d(t) = [-1/3t³ - 3/2t² + 4t] for 0 ≤ t ≤ 1

+ [1/3t³ + 3/2t² - 4t + 11] for 1 ≤ t ≤ 3

+ [1/3t³ + 3/2t² + 4t] for -4 ≤ t ≤ 0

Now we can calculate the distance traveled by subtracting the distance traveled in the negative time interval from the distance traveled in the positive time interval:

d(3) - d(0) = [1/33³ + 3/23² - 43 + 11] - [-1/30³ - 3/20² + 40]

= 30.5

So the distance traveled during the time interval [0, 3] is approximately 30.5 meters.

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For Shasta assistance the cougar, we need to find the value of constant 'a' for the original function p(x) = x^a - a^x. First, let's find the derivative p'(x).
Using the power rule and the chain rule, we can find the derivative of p(x):
p'(x) = ax^(a-1) - a^(x)ln(a)
Given that p'(0) = ln(1/phi), we will now evaluate p'(x) at x = 0:
p'(0) = a(0)^(a-1) - a^(0)ln(a) = ln(1/phi)
Since any number raised to the power of 0 is 1, we can simplify the equation:
0^(a-1) = 1/a - ln(a) = ln(1/phi)
We know that ln(1/phi) = -ln(phi), where phi is the golden ratio, approximately 1.618. So, we have:
1/a - ln(a) = -ln(phi)
To solve for 'a', we can use numerical methods or software like Mathematica or Wolfram Alpha. By doing so, we find that the constant 'a' is approximately 1.44467.
So, the original function p(x) is approximately:
p(x) = x^1.44467 - 1.44467^x

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The equations for the parallel and perpendicular lines to the given line passing through point P(-1, 2) are:

Parallel line: y - 2 = -2(x + 1)
Perpendicular line: y - 2 = 1/2(x + 1)

The equations for the parallel and perpendicular lines to the given line passing through point P(-1,2).

First, let's find the slope of the given line, 2x + y = 4. We can rewrite it in slope-intercept form (y = mx + b) to determine the slope:

y = -2x + 4

The slope (m) of the given line is -2.

For the parallel line, the slope will be the same as the given line, so m_parallel = -2. Now we can use the point-slope form (y - y1 = m(x - x1)) and plug in the coordinates of point P(-1, 2) and the parallel slope:

y - 2 = -2(x + 1)

For the perpendicular line, the slope will be the negative reciprocal of the given line's slope, so m_perpendicular = 1/2. Now, we can use the point-slope form and plug in the coordinates of point P(-1, 2) and the perpendicular slope:

y - 2 = 1/2(x + 1)

So, the equations for the parallel and perpendicular lines to the given line passing through point P(-1, 2) are:

Parallel line: y - 2 = -2(x + 1)
Perpendicular line: y - 2 = 1/2(x + 1)

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The Function is: f(t) = (2/3)[tex]t^3[/tex] + (3/2[tex])t^2[/tex] - t + 2/3

To determine f(t) given f''(t) = 6(2t+1), f'(1) = 3, and f(1) = 4, we need to integrate the given function twice.

First, we integrate f''(t) = 6(2t+1) once to get f'(t):

f'(t) = 2[tex]t^2[/tex] + 3t + C1, where C1 is the constant of integration.

Next, we integrate f'(t) = 2[tex]t^2[/tex] + 3t + C1 once again to get f(t):

f(t) = (2/3)[tex]t^3[/tex] + (3/2)[tex]t^2[/tex] + C1t + C2, where C2 is the constant of integration.

Using the initial conditions f'(1) = 3 and f(1) = 4, we can solve for the constants C1 and C2:

f'(1) =[tex]2(1)^2 + 3(1) + C1 = 3[/tex]

C1 = -1

f(1) =[tex](2/3)(1)^3 + (3/2)(1)^2 - 1(1) + C2 = 4[/tex]

C2 = 2/3

Therefore, the final solution is:

f(t) =[tex](2/3)t^3 + (3/2)t^2 - t + 2/3[/tex]

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The standard deviation of the sample mean is also known as the standard error of the mean. It can be calculated by dividing the population standard deviation by the square root of the sample size. In this case, the population standard deviation is $2 and the sample size is 100. So, the standard deviation of the sample mean is $2/sqrt(100) = $2/10 = $0.2. Is there anything else you would like to know?

I'm sorry to bother you but can you please mark me BRAINLEIST if this ans is helpfull

To design a systematic sample for the telephone company's marketing survey of its 760,000 customers, the company can first divide the population into equal segments based on a predetermined interval size. For example, if the company wants a sample size of 250, it can divide the population into 3,040 segments (760,000/250). Then, they can randomly select one customer from the first segment, and then select every 3,040th customer after that to create a systematic sample.

This method ensures that every customer has an equal chance of being selected, while also keeping the sample size within the company's budget constraints. However, it is important to note that there may still be some statistical bias present in the sample, as certain customer demographics or behaviors may not be accurately represented in the sample. To minimize bias, the company can consider using stratified sampling or other techniques to ensure a more representative sample.

1. Define the population: In this case, the population consists of the 760,000 customers of the telephone company.

2. Determine the sample size: Due to budget constraints, the company wants a sample size of about 250 customers.

3. Create a sampling frame: List all the 760,000 customers in a systematic manner, such as alphabetically or by customer ID number.

4. Calculate the sampling interval: To select a systematic sample, divide the population size by the desired sample size. In this case, 760,000 customers divided by 250 gives a sampling interval of 3,040.

5. Choose a random starting point: Select a random number between 1 and 3,040 to serve as your starting point. For example, let's say you choose the number 1,500.

6. Apply the sampling interval: From the random starting point (1,500), select every 3,040 customers until you reach the end of the sampling frame. This will result in a systematic sample of 250 customers.

This method ensures that the sample is representative of the entire population and minimizes potential statistical bias. The company can then use this sample for its marketing survey while staying within its budget.

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The area of the surface is 25.1327 square units, under the condition that the rotating curve is y = √(16 - x²) and its range is -1≤x≤1

Therefore, the area of the surface obtained by rotating the curve y = √(16 - x²), -1≤x≤1 about the x-axis is given by the formula

A = 2π ∫[a,b] f(x) √(1 + [f'(x)]²) dx

Here
a=-1,
b=1,
f(x) = √(16 - x²).
Then,

f'(x) = -x/√(16 - x²)

√(1 + [f'(x)]²) = √(1 + x²/(16 - x²))

Now we can staging these values

A = 2π ∫[-1,1] √(16 - x²) √(1 + x²/(16 - x²)) dx

This integral can be evaluated applying trigonometric substitution.
Let x = 4sinα, then dx = 4cosα dα.

Applying these values into our integral gives:

[tex]A = 2\pi \int\limits[\pi /2,-\pi /2] 16cos^{2\alpha }d\alpha[/tex]

= π² × 8

= 25.1327

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The probability that all four drivers are wearing their seat belts is 0.456, or about 45.6%.

The probability of a driver wearing a seat belt is 1-0.22 = 0.78.

We can model the situation as a binomial distribution, where the number of trials (n) is 4 and the probability of success (p) is 0.78.

The probability that all four drivers are wearing their seat belts can be calculated using the binomial probability formula:

P(X = 4) = (n choose X) * [tex]p^X * (1 - p)^(n - X)[/tex]

where n = 4, X = 4, p = 0.78, and (n choose X) = 1.

Plugging in these values, we get:

[tex]P(X = 4) = 1 * 0.78^4 * (1 - 0.78)^(4 - 4)[/tex]

= 0.456

Therefore, the probability that all four drivers are wearing their seat belts is 0.456, or about 45.6%.

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The equation we can use to find t is:

t/5 + t/3 = 1

Let's start by finding the individual rates of worker A and worker B in assembling the shelving unit.

Worker A can assemble a shelving unit in 5 hours, so their rate is:

1 unit / 5 hours = 1/5 units per hour

Similarly, worker B can assemble a shelving unit in 3 hours, so their rate is: 1 unit / 3 hours = 1/3 units per hour

Now, let t be the time in hours it takes for worker A and worker B to assemble a shelving unit together. During this time, worker A will have completed a fraction of the shelving unit equal to t/5 (since their rate is 1/5 units per hour), and worker B will have completed a fraction of the shelving unit equal to t/3 (since their rate is 1/3 units per hour).

The total fraction of the shelving unit completed in time t is the sum of the fractions completed by each worker. So we have:

t/5 + t/3 = 1

Multiplying both sides by the least common multiple of 5 and 3 (which is 15), we get:

3t + 5t = 15

8t = 15

Dividing both sides by 8, we get:

t = 15/8

Therefore, it takes approximately 1.875 hours, or 1 hour and 52.5 minutes, for worker A and worker B to assemble a shelving unit together.

So the equation we can use to find t is:

t/5 + t/3 = 1

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To find the time it takes for Worker A and Worker B to assemble a shelving unit together, we can set up an equation based on their work rates. The equation is 1/5 + 1/3 = 1/t. Solving for t, we find that it takes approximately 1.875 hours or 1 hour and 52.5 minutes for both workers to assemble the shelving unit together.

To find the time it takes for Worker A and Worker B to assemble a shelving unit together, we can set up an equation using the concept of work rate. Worker A can assemble one shelving unit in 5 hours, so their work rate is 1 unit per 5 hours. Similarly, Worker B can assemble one shelving unit in 3 hours, so their work rate is 1 unit per 3 hours.

To find the combined work rate of Worker A and Worker B, we can add their individual work rates. Let's represent the time it takes for them to assemble the shelving unit together as 't'. The equation for their combined work rate is:

1/5 + 1/3 = 1/t

To solve for 't', we can multiply both sides of the equation by the least common multiple (LCM) of 5 and 3, which is 15. This gives us:

3 + 5 = 15/t

8 = 15/t

t = 15/8

Therefore, it takes approximately 1.875 hours or 1 hour and 52.5 minutes for Worker A and Worker B to assemble a shelving unit together.

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The closest option to the correct answer is B. 4/15.

Using the following formula for the probability density function of a continuous uniform distribution, we can resolve this issue:

f(x) = 1/(b-a), a < x < b

where a and b represent the distribution's minimum and maximum values, respectively.

Since a and b are equal to 15, the probability density function is as follows:

f(x) = 1/15, 0 < x < 15

The likelihood that the area under the density curve between x = 5 and x = 10 is 5< x <10 This can be found by coordinating the thickness capability somewhere in the range of 5 and 10:

P(5 < x < 10) = ∫(5 to 10) f(x) dx

= ∫(5 to 10) 1/15 dx

= [x/15]_(5 to 10)

= (10/15) - (5/15)

= 1/3

Therefore, the answer is not one of the options provided. However, if we round 1/3 to the nearest option, we get:

B. 4/15

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By trigonometric identity tanα= 1/2.

What is trigonometric identity?

Trigonometric Identities are used whenever trigonometric functions are involved in an expression or an equation. Trigonometric Identities are true and it is proven for every value of variables occurring on both sides of an equation. These identities involve certain trigonometric functions for example sine, cosine, tangent, cotangent of one or more angles.

tanα is a trigonometric identity.

tanα= perpendicular/ base in any right angled triangle.[ by the property of trigonometry]

given tanα = 1/2 so perpendicular is 1 unit and base is 2 unit

Hence, tanα = 1/2.

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Step-by-step explanation:

why do you feel this is so complicated ?

you look up the formulas, grab a calculator and then just calculate the results.

please let me know, if you don't understand something :

the diameter is a line from one end of the circle to the other going through the center point of the circle.

therefore, the diameter is 2 times the distance from the center to its arc.

the radius is only one time the distance of the center of the circle to the arc.

so, radius = diameter/2 = 14/2 = 7 M.

the circumference of a circle is

2pi×r = 2×7×pi = 14pi = 43.98229715... M

the area of a circle is

pi×r² = pi×7² = 49pi = 153.93804... M²

12 units is the perimeter of triangle ABC.

What does a triangular response mean?

It has three straight sides and is a two-dimensional figure. As a 3-sided polygon, a triangle is included. Three triangle angles added together equal 180 degrees.

                           Three edges and three vertices make up the three sides of a triangle, which is a three-sided polygon. The fact that the interior angles of a triangle add up to 180 degrees is the most crucial aspect of triangles.

Coordinates of triangle ABC:

A = (-1,3), B = (3,6), C = (3,3)

Distance formula (x₁ , y₁ ) (x₂ , y₂ )

 d = √(x₂ - x₁)² + (y₂ - y₁)²

Distance of AB: A = (-1,3), B = (3,6)

  AB = √(3 - (-1))² + (6 - 3)²  = 5 Units

Distance of BC: B = (3,6) , C = (3,3)

       BC = √(3 - 3)² + (3 - 6)² = 3 units

Distance of CA:  C = (3,3) , A = (-1,3)

   CA =√((-1) - 3)² + (3 - 3 )²  = 4 Units

Perimeter of the triangle ABC = AB +BC + CA

= 5 units + 3 units + 4 units = 12 units

12 units is the perimeter of triangle ABC.

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The Radius of convergence is r = 1/2.

To find the radius of convergence of the power series, we can use the ratio test:

r = lim |a_{n+1}(x-2)^{n+1}| / |a_n(x-2)^n|

= lim |a_{n+1}| / |a_n| |x-2|

= lim ((2n+3)/(3n+1)) |x-2|

where we used the recurrence relation to simplify the expression for |a_{n+1}/a_n|. The limit exists and is finite for all x, so the radius of convergence is the value of |x-2| for which the limit is 1:

1 = lim ((2n+3)/(3n+1)) |x-2|

= lim ((2n+3)/(3n+1)) |x-2|/|n|

= |x-2| lim ((2/n)+(3/(n(3n+1))))

= |x-2| * 2

Therefore, the radius of convergence is r = 1/2.

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20e^(4x) – (1/x)

Explanation: To find the derivative of f(x), we need to apply the chain rule and the product rule.

f(x) = 5e^(4x) – ln(x)

Using the product rule, we have:

f'(x) = (5e^(4x))(4) – (1/x)

Simplifying:

f'(x) = 20e^(4x) – (1/x)

Therefore, the derivative of f(x) is f'(x) = 20e^(4x) – (1/x).

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If John reads 110 pages on Saturday and 80 pages each-day after, then the expression representing number of pages after "x" days is "110 + 80x".

An "Expression" is defined as a mathematical-statement which consists of numbers, variables, operators combined together in a meaningful way.

To calculate the total number of pages John-reads after "x" days, we use the following expression:

⇒ Total number of pages = (Pages read on Saturday) + (Pages read each day for "x" days),

We know that, John reads "110-pages" on Saturday and "80-pages" each day after,

We substitute these values into expression,

So, Total number of pages = 110 + 80x

Where: "x" represents number-of-days after Saturday for which we want to calculate total number of pages John reads.

Therefore, the expression for total number of pages John reads after "x" days is 110 + 80x.

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The given question is incomplete, th complete question is

John reads 110 pages on Saturday and 80 pages each day after. Write an expressions to tell how many pages he reads after "x" days.

Answer: B    (-3x+14)

Step-by-step explanation:

We need to solve 20-3(x+2)

Following PEMDAS firstly we'll do -3(x + 2)    or      (x + 2) times -3.

-3*x = -3x

-3*2 = -6

We now have 20 - 3x - 6. We can group like terms.

14 - 3x or -3x + 14.

Answer:

B:-3x+14

Step-by-step explanation:

20-3(x+2).

20-3x-6.

-3x-6+20

-3x+14

Line segment FG is shifted 10 units to the right and 7 units down to form segment F'G'. Since the y-coordinate is unchanged, the length of segment F'G' is equal to the length of segment FG, which is 17 units.

A line segment is a part of a line that connects two distinct points, and has finite length. It can be measured in terms of distance.

Coordinates are values that indicate a specific location on a plane or in space, given as ordered pairs or triples of numbers respectively, usually represented as (x, y) or (x, y, z).

According to the given information:

The length of the line segment F'G' can be found using the distance formula, which is:

d = √((x2 - x1)² + (y2 - y1)²)

where ([tex]X_{1} ,Y_{1}[/tex]) and ([tex]X_{2} ,Y_{2}[/tex]) are the coordinates of the endpoints of the segment.

For line segment FG, ([tex]X_{1} ,Y_{1}[/tex]) = (-9,-5) and ([tex]X_{2} ,Y_{2}[/tex]) = (8,-5). So we have:

d = √((8 - (-9))² + (-5 - (-5))²)

d = √(17² + 0²)

d = √(289)

d = 17

Therefore, the distance between F'G' is also 17 units as the translation does not affect the length of the line segment.

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Mr. Red's speed was 10 yards per second when he ran from the 0 line to the finish line, which was a distance of 40 yards.

To find Mr. Red's speed, we need to use the formula

speed = distance ÷ time

We know that Mr. Red ran from the 0 line to the finish line, which is a distance of 40 yards. We also know that he did this in 4 seconds. So, we can plug these values into the formula

speed = 40 yards ÷ 4 seconds

Simplifying, we get

speed = 10 yards per second

Therefore, Mr. Red's speed is 10 yards per second. It's important to note that this is his average speed over the entire 4-second interval.

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The time when the concentration of the drug is at a maximum is approximately 4.90 hours.

To find the time when the concentration of the drug is at a maximum, we need to find the value of t that maximizes the concentration function C(t).

We can start by taking the derivative of C(t) with respect to t:

C'(t) = [(0.6)(t² + 24) - (0.6t)(2t)] / (t² + 24)²

Simplifying this expression, we get

C'(t) = [0.6(24 - t²)] / (t² + 24)²

To find the maximum value of C(t), we need to find the value of t that makes C'(t) equal to zero. So, we set C'(t) = 0 and solve for t:

0.6(24 - t²) = 0

24 - t² = 0

t² = 24

t = ±√(24) ≈ ±4.90

Since we are interested in a positive value of t, we take t ≈ 4.90 as the time when the concentration of the drug is at a maximum.

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The mean for the random variable X, the number of twos thrown out of ten tosses is 1/6. The answer is A. 2.98, rounded to two decimal places.

To find the mean for the random variable X, we need to multiply the probability of each possible outcome (i.e. the number of twos thrown out of ten tosses) by that outcome, and then add up all the results.

For example, the probability of throwing no twos (i.e. getting other numbers on all ten tosses) is (5/6)¹⁰, and the corresponding outcome is 0. So the contribution to the mean from this outcome is 0×(5/6)¹⁰.

Similarly, the probability of throwing one two (i.e. getting a two once and other numbers on the remaining nine tosses) is 10×(1/6)×(5/6)⁹, and the corresponding outcome is 1. So the contribution to the mean from this outcome is 1×10×(1/6)×(5/6)⁹.

We can do this for all possible outcomes (i.e. throwing 0, 1, 2, …, 10 twos), and add up the results to get the mean.

Using this method, we get:

Mean(X) = 0×(5/6)¹⁰ + 1×10×(1/6)×(5/6)⁹ + 2×(1/6)²×(5/6)⁸ + 3×(1/6)^3×(5/6)⁷ + 4×(1/6)⁴×(5/6)⁶ + 5×(1/6)⁵×(5/6)⁵ + 6×(1/6)⁶×(5/6)⁴ + 7×(1/6)⁷×(5/6)³ + 8×(1/6)⁸×(5/6)² + 9×(1/6)⁹×(5/6) + 10×(1/6)¹⁰

Using a calculator, we get:

Mean(X) ≈ 2.98

Therefore, the answer is A. 2.98, rounded to two decimal places.

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The line 7x + 8y = 0 in the xy-plane, is rotated about the y-axis then equation of generated surfaces is (x² + (y - 8t)²) = 64t²

The equation given is the equation of a circle that has been rotated about the y-axis.

The equation gives the coordinates of a point on the circle centered at (0, 8t) with a radius of 8t.

The equation can be derived by taking the equation of a circle in the xy-plane, 7x + 8y = 0, and substituting y with (y - 8t) to reflect the rotation about the y-axis.

Hence, the line 7x + 8y = 0 in the xy-plane, is rotated about the y-axis then equation of generated surfaces is (x² + (y - 8t)²) = 64t²

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Answer:

b

Step-by-step explanation:

To find the change in temperature, we need to subtract the initial temperature from the final temperature:

Change in temperature = Final temperature - Initial temperature

Change in temperature = 67.9 - 83.8

Change in temperature = -15.9

Therefore, the change in temperature is -15.9 degrees, which means the temperature decreased by 15.9 degrees.

The answer is option B, -15.9.

The sample size must be at least 12 if you want the standard error of the sample average to be 1.5.

To find the sample size needed, we can use the formula for standard error:
SE = σ/√n
Where SE is the standard error, σ is the population standard deviation (which is the square root of the variance), and n is the sample size.
In this case, we are given that the population mean is 100 and the variance is 25, so the standard deviation is √25 = 5.
We want the standard error to be 1.5, so we can plug in the values:
1.5 = 5/√n
To solve for n, we can isolate the variable by squaring both sides:
(1.5)^2 = (5/√n)^2
2.25 = 25/n
n = 25/2.25
n ≈ 11.11
So the sample size must be at least 12 (since we can't have a fraction of a person). This will give us a standard error of approximately 1.5.

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The expression that could Mr. Jackson use to find the cost of ordering n lunches is 6.25n + 3.50

To find the cost of ordering n lunches, Mr. Jackson can use an expression. An expression is a combination of numbers, variables, and mathematical operations that represents a value. In this case, the expression that Mr. Jackson can use to find the cost of ordering n lunches is:

6.25n + 3.50

In this expression, n represents the number of lunches that Mr. Jackson orders. When Mr. Jackson orders n lunches, he has to pay $6.25 for each lunch, so the cost of the lunches will be 6.25n. In addition, Mr. Jackson has to pay a one-time delivery fee of $3.50, which is represented by the constant term 3.50 in the expression.

To use this expression to find the cost of ordering a specific number of lunches, Mr. Jackson can substitute the value of n into the expression and simplify. For example, if Mr. Jackson orders 10 lunches, the cost would be:

6.25(10) + 3.50 = 62.50 + 3.50 = 66.00

So the cost of ordering 10 lunches would be $66.00.

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Since we have been told that the angles are complementary then it follows that cos y = 5/13

Complementary angles are a pair of angles whose measures add up to 90 degrees. In other words, if angle A measures x degrees, then its complement, angle B, measures (90 - x) degrees.

Now we know that the adjacent of the angle would be;

13^2 = 12^ + x^2

x = √13^2  - 12^2

x = 5

Cos y = 5/13

Then the cosine of the angle y from the relation that we can see in the problem is given as 5/13.

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