Answer:
Option D. 0.115 M
Explanation:
The following data were obtained from the question:
Mass of CuSO4 = 36.8 g
Volume of solution = 2 L
Molar mass of CuSO4 = 159.62 g/mol
Molarity of CuSO4 =..?
Next, we shall determine the number of mole in 36.8 g of CuSO4.
This can be obtained as shown below:
Mass of CuSO4 = 36.8 g
Molar mass of CuSO4 = 159.62 g/mol
Mole of CuSO4 =.?
Mole = mass /Molar mass
Mole of CuSO4 = 36.8 / 159.62
Mole of CuSO4 = 0.23 mole
Finally, we shall determine the molarity of the CuSO4 solution as illustrated below:
Mole of CuSO4 = 0.23 mole
Volume of solution = 2 L
Molarity of CuSO4 =..?
Molarity = mole /Volume
Molarity of CuSO4 = 0.23 / 2
Molarity of CuSO4 = 0.115 M
Therefore, the molarity of the CuSO4 solution is 0.115 M.
Why is this dietary supplement best characterized as a mixture instead of a pure substance?
A. The percent daily value is less than 100 percent
B. Calcium citrate is composed of nonmetallic elements
C. A tablet contains different chemical compounds
D. Calcium citrate contains more than one element.
Answer:
C. A tablet contains different chemical compounds
Explanation:
The dietary supplement in this question depicts a kind of matter. Matter, in chemistry, can either be a pure substance or a mixture. Unlike elements and compounds (pure substances) which cannot be separated by physical means, mixtures can be separated using physical method.
A mixture is a combination of different substances with varying physical properties, which serves as basis of their physical separation. According to the image in the question, the Calcium citrate dietary supplement contains different chemical compounds like polyethylene glycol, sodium, methyl cellulose, magnesium silicate etc.
These chemical compounds retain their individual properties and can be separated easily via physical techniques, hence, the dietary supplement is a MIXTURE.
Which would have the LEAST gravitational potential energy (GPE)? A ball sitting on the ground An airplane flying 30,000 feet above the ground A rock sitting on top of Mt. Everest
Answer:
(A) A ball sitting on the ground
Explanation:
The option with the least gravitational potential energy in the question is : A: A ball sitting on the ground.
Gravitational potential energy can be regarded as the energy that is been stored in an object due to its vertical position or height. The energy is stored in the object due to the gravitational attraction of the Earth as regards the object.To calculate the Gravitational potential energy, we can use[tex]U= mgh[/tex]
h= height of the object
m= mass of the object.
In The first option, the ball is on the ground, so it has no height or vertical position making it the least object with Gravitational potential energy. Unlike the airplane that is of some miles to the ground.Therefore, option A is right.
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Consider the following weak acids and their Ka values: Acetic Acid Ka = 1.8×10^−5 Phosphoric Acid Ka = 7.5×10^−3 Hypochlorous Acid Ka = 3.5×10^−8. What weak acid-conjugate base buffer system from the acids listed is the best choice to prepare the following buffers. Explain your reasoning.
a. pH 2.8
b. pH 4.5
c. pH7.5
Answer:
a. Phosphoric Acid
b. Acetic Acid
c. Hypochlorous Acid
Explanation:
A buffer works when the pH of this one is in pKa ± 1. That means, to find which buffer system works in some pH you need to find pKa:
pKa = -log Ka
pKa Acetic acid:
-log1.8x10⁻⁵ = 4.74
pKa phosphoric acid:
-log7.5x10⁻³ = 2.12
pKa hypochlorous acid:
-log3.5x10⁻⁸ = 7.46
a. For a pH of 2.8 the best choice is phophoric acid because its effective range is: 1.12 - 3.12 and 2.8 is between these values.
b. pH 4.5. Acetic acid. effective between pH's 3.74 - 5.74
c. pH 7.5. Hypochlorous acid that works between 6.46 and 8.46
1. Properties that do not depend on the amount of matter present are... ????*
Extrinsic Properties
Chemical Properties
Intrinsic Properties
i
Answer:extrinisic properties
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How much acceleration does a 10 kg object have if pushed by a 75 N force?
a = 7.5 m/s²
Explanation:Hi there !
Newton's second law
F = m×a => a = F/m
1 N = 1kg·m/s²
a = (75kg.m/s²)/10kg
= 7.5 m/s²
Good luck !
A solution in which the pH is 1.6 would be described as
a.
very acidic
b.
slightly acidic
c.
very basic
d.
slightly basic
e.
neutral
Answer:
a. very acidic
Explanation:
A solution with a pH of 1.6 would be described as a very acidic solution.
The pH scale is a convenient scale for expressing the level of acidity or alkalinity of aqueous solutions.
The scale ranges from 1 to 14 in which case 1 is the lower limit and 14 the upper limit.
An acidic solution has a pH value less than 7. As pH decreases, the acidity of the solution increases. Neutral solutions have a pH of 7An alkaline solution has a pH greater than 7 and the level of alkalinity increases as pH increases.Why doesn't air pressure crush an empty soft-drink can that is sitting on a table in your house?
Answer:
The air inside and outside are equal so air particles can go in and out. The can is empty so the air particles go in and out. That is why the can wont get crushed.
Explanation:
Air pressure does not crush an empty soft-drink can that is sitting on a table in your house as the pressure is equal outside and inside of the can.
What is pressure?Pressure is defined as the force applied on an object perpendicular to it's surface per unit area over which it is distributed.Gauge pressure is a pressure which is related with the ambient pressure.
There are various units by which pressure is expressed most of which are derived units which are obtained from unit of force divided by unit of area . The SI unit of pressure is pascal .
It is a scalar quantity which is related to the vector area element with a normal force acting on it.It is distributed over solid boundaries and across arbitary sections of fluid normal to the boundaries at every point.
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An aqueous solution of calcium hydroxide is standardized by titration with a 0.117 M solution of hydrobromic acid.
Required:
a. If 24.7 mL of base are required to neutralize 16.0 mL of the acid. What is the molarity of the calcium hydroxide solution?
b. What volume of a 0.270 M hydrochloric acid solution is required to neutralize 22.8 mL of a 0.113 M calcium hydroxide solution?
c. How many milliliters of 10.8 M hydrobromic acid solution should be used to prepare 2.50 L of 0.400 M ?
Answer:
a) 0.0379 M
b) 24.89 mL
c) 0.09 mL
Explanation:
The equation of the reaction is:
2HBr(aq) + Ca(OH)2(aq) ---> CaBr2(aq) + 2H20(l)
a)
Concentration of acid CA = 0.117 M
Concentration of base CB= ??
Volume of acid VA = 16.0 ml
Volume of base VB = 24.7 ml
number of moles of acid NA = 2
number of moles of base NB= 1
From;
CA VA/CB VB = NA/NB
CAVANB =CBVBNA
CB = CAVANB/VBNA
CB = 0.117 *16 * 1/ 24.7 *2
CB = 1.872/49.4
CB = 0.0379 M
b)
CA = 0.270 M
CB = 0.113 M
VA = ??
VB =22.8mL
NA =2
NB =1
From;
CA VA/CB VB = NA/NB
CAVANB =CBVBNA
VA = CBVBNA/CANB
VA = 0.113 * 22.8 * 2/0.207 *1
VA = 24.89 mL
c)
using the dilution formula
C1V1 =C2V2
Where:
C1= initial concentration =10.8 M
V1 = initial volume = ??
C2= final concentration =0.400 M
V2= final volume = 2.5 L
V1 = C2V2/C1
V1 = 0.400 * 2.5/10.8
V1 = 0.09 mL
Select the correct word or phrase to complete the statements about ionic compounds.
The melting point of an ionic compound is likely to be
a molecular compound.
Answer:
The answers of the questions are found below
Explanation:
1.) higher than
2.) solution and the liquid taste
3.) hard
4.) have varying solubilities
-Just took it on edge and got them all right
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The complete statement about ionic compounds is:
The melting point of an ionic compound is likely to be higher than a molecular compound.
What are ionic compounds?Ionic compounds are those compounds that are formed by holding ions with an electrostatic force, called ionic bonding. The compounds contain negatively charged ions called anions and positively charged ions called cations. The anions and cations connect together to form a neutral compound.
The compounds are bound with an electrostatic force, so their melting point will be higher than the molecular compounds.
Thus, the melting point of an ionic compound is likely to be higher than a molecular compound.
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Need help with 8 plssss
Answer:
c,a,b,d
Explanation:
An analytical chemist weighs out 0.055g of an unknown triprotic acid into a 250mL volumetric flask and dilutes to the mark with distilled water. She then titrates this solution with 0.1300M NaOH solution. When the titration reaches the equivalence point, the chemist finds she has added 6.6mL of NaOH solution. Calculate the molar mass of the unknown acid. Be sure your answer has the correct number of significant digits.
Answer:
Mass of the unknown acid is 4.0g
Explanation:
The determine the molar mass of the unknown acid, the steps below can be followed
Firstly, determine the concentration of the acid, the formula below can be used;
ConcA × Va/ConcB × Vb = Na/Nb
Where ConcA is the concentration of the unknown acid
ConcB is the concentration of the NaOH base
Va is the volume of acid and Vb is the volume of base
Since, the titration was said to have reached an equivalent point, it means the number of moles of the acid (Na) was equal to the number of moles of the base (Nb) and thus both will be assumed to be 1
Thus
ConcA × 250/0.13 × 6.6 = 1/1
ConcA = 0.13 × 6.6/250
ConcA = 0.003432M
Then, determine the actual number of moles (n) of the unknown acid used,
ConcA = no of moles of acid/volume of acid (in dm³ or L)
To convert mL to L, we divide by 1000
Hence, 250ml = 0.25L
0.003432 = n/0.25
n = 0.003432 × 0.25
n = 0.01373 moles
To determine the molar mass;
n = mass/molar mass
The mass was given in the question to be 0.055g
Thus
0.01373 = 0.055/molar mass
molar mass = 0.055/0.01373
molar mass = 4.0g
Show the net dipole moment (μ = 0 D) of the compounds
a) CBr4
b) cis-1,2-Dibromoethene
c) trans:-1,2-Dibromoethene
d) 1,1-Dibromoethene
Answer:
A
Explanation:
Using the equation above, the dipole moment is calculated to be 1.85 D by multiplying the distance between the oxygen and hydrogen atoms by the charge difference between them and then finding the components of each that point in the direction of the net dipole moment (the angle of the molecule is 104.5˚).
what do elements have to do with geology?
Answer:
Geology is the world... Elements make it up
Explanation:
Answer:
A lot of the elements are found in rocks, minerals, and well since they are elements make they make up everything on earth.
Explanation:
Calculate the number of grams of CuSO4 found in 3.29 mL of a 4.00 M CuSO4 solution. ______ grams CuSO4
Answer:
0.0132 g CuSO₄
General Formulas and Concepts:
[tex]\text{Molarity}=\frac{\text{moles of solute}}{\text{liters of solution}}[/tex]
Explanation:
Step 1: Define variables
3.29 mL
4.00 M CuSO₄
x g CuSO₄
Step 2: Define conversions
1000 mL = 1 L
Step 3: Solve
Convert mL to L: [tex]\text{3.29 mL}(\frac{\text{1 L}}{\text{1000 mL}} )[/tex] = 0.00329 LSubstitute: [tex]\text{4.00 M} \ CuSO_4=\frac{\text{x g} \ CuSO_4}{\text{0.00329 L}}[/tex]Multiply both sides by L: [tex]\text{0.01316} \ CuSO_4=\text{x g} \ CuSO_4[/tex]Rewrite: [tex]x = 0.01316 \ g \ CuSO_4[/tex]Step 4: Simplify
We are given 3 sig figs.
0.01316 g CuSO₄ ≈ 0.0132 g CuSO₄
The nuclear fission of U-235 can occur by different pathways. If 1 neutron is absorbed by U-235 to produce 36 neutrons and Kr-94, identify other nucleus that is produced using the boxes and pull-down menu provided. g
Answer:
See explanation
Explanation:
What I have written in the image attached is called a nuclear equation. It differs from a chemical reaction equation in the sense that it involves transformations that occur in the nucleus of atoms.
The nuclear equation must be balanced. This means that the mass and charge on both sides of the reaction equation must be the same.
On the left hand side the U-235 interacts with a neutron. The total mass on the left hand side is 236 while the total charge is 92. If we sum up the masses and charges of Ba and Kr, we also get a total of 236 mass units and a charge of 92.
Hence the other nucleus is barium-141
PLS HELP WILL DO BRAINLIEST! PLS PLS PLS PLS PLS HELP ASAP Atoms of two different elements must have different
electrical charges.
numbers of neutrons.
atomic numbers.
energy levels.
the answer is atomic numbers
Answer:
atomic numbers
Explanation:
In order for two atoms to be different, they have to have a different number of protons. Protons are represented by the atomic number. Thus, atoms of two DIFFERENT elements must have different atomic numbers.
I took the test and got 100%
Hope this helps!
The current disintegration rate for carbon-14 is 14.0 Bq. A sample of wood discovered in an archaeological excavation is found to have a carbon-14 decay rate of 0.875 Bq. If the half-life of carbon-14 is 5,700 y, approximately how old is the wood sample?
Answer:
The wood sample has an age of approximately 22800 years.
Explanation:
The Becquerel ([tex]Bq[/tex]) is a SI unit which describes radioactive activity related to decay of radioactive isotopes, which is equivalent to [tex]\frac{1}{s}[/tex]. The decay of radioactive isotope is described by the following ordinary differential equation:
[tex]\frac{dN}{dt} = -\frac{N}{\tau}[/tex] (Eq. 1)
Where:
[tex]\frac{dN}{dt}[/tex] - Disintegration rate, measured in [tex]\frac{1}{s}[/tex].
[tex]N[/tex] - Amount of remaining radioactive nuclei, dimensionless.
[tex]\tau[/tex] - Time constant, measured in seconds.
By integration the solution of this differential equation is obtained:
[tex]\int {\frac{dN}{N} } = -\frac{t}{\tau}\int dt[/tex]
[tex]\ln N = -\frac{t}{\tau} + C[/tex]
[tex]N(t) = N_{o}\cdot e^{-\frac{t}{\tau} }[/tex] (Eq. 2)
Let [tex]N_{1}[/tex] and [tex]N_{2}[/tex] different disintegration rates for Carbon-14 samples, so that:
[tex]N_{1} = N_{o} \cdot e^{-\frac{t_{1}}{\tau} }[/tex] (Eq. 3)
[tex]N_{2} = N_{o}\cdot e^{-\frac{t_{2}}{\tau} }[/tex] (Eq. 4)
If we divide (Eq. 4) by (Eq. 3), then:
[tex]\frac{N_{2}}{N_{1}} = \frac{N_{o}\cdot e^{-\frac{t_{2}}{\tau} }}{N_{o}\cdot e^{-\frac{t_{1}}{\tau} }}[/tex]
[tex]\frac{N_{2}}{N_{1}} = e^{-\frac{1}{\tau}\cdot (t_{2}-t_{1}) }[/tex] (Eq. 5)
If [tex]\Delta t = t_{2}-t_{1}[/tex], we proceed to clear that variable:
[tex]\ln \frac{N_{2}}{N_{1}} = -\frac{1}{\tau}\cdot \Delta t[/tex]
[tex]\Delta t = -\tau\cdot \ln \frac{N_{2}}{N_{1}}[/tex] (Eq. 6)
Time constant is also a function of half-life ([tex]t_{1/2}[/tex]), measured in seconds:
[tex]\tau = \frac{t_{1/2}}{\ln 2}[/tex]
If [tex]t_{1/2} = 1.798\times 10^{11}\,s[/tex], [tex]N_{1} = 14\,\frac{1}{s}[/tex] and [tex]N_{2} = 0.875\,\frac{1}{s}[/tex], the age of the wood sample is:
[tex]\tau = \frac{1.798\times 10^{11}\,s}{\ln 2}[/tex]
[tex]\tau = 2.594\times 10^{11}\,s[/tex]
[tex]\Delta t = -(2.594\times 10^{11}\,s)\cdot \ln \left(\frac{0.875\,\frac{1}{s} }{14\,\frac{1}{s} } \right)[/tex]
[tex]\Delta t \approx 7.192\times 10^{11}\,s[/tex]
[tex]\Delta t \approx 22805.682\,yr[/tex]
The wood sample has an age of approximately 22800 years.
If the earth was a guava fruit, the space where the seeds are would be the core/mantle
You have a 50.0g samples of silver, a 50g sample of iron, and a 50g sample of water. You add 100 J of energy to each sample. Which substance will have the largest resulting temperature change? Which substance will have the smallest temperature change?
Answer:
Silver.
Explanation:
Hello!
In this case, we can consider the specific heat as the property that we can analyze in order to answer to this question. In such a way, as the specific heat is known as the energy required to modify the temperature of 1 g of the substance by 1 °C, since the masses of all the substances are the same, we can that their specific heats are respectively 0.240, 0.444 and 4.184 J/(g°C), from the equation:
[tex]Q=mCp\Delta T[/tex]
We can see that the higher the specific heat (Cp) the lower the change in temperature considering their inversely proportional relationship. However, as 100 J of energy is applied to all the substances, we can see that silver will exhibit the largest temperature change because a higher change is needed to fit with the provided energy.
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The distribution coefficient between methylene chloride and water for solute Y is 14. An amount of 72.0 g of Y is dissolved in 180 mL of water. a) What weight of Y would be removed from water with a single extraction with 180-mL of methylene chloride? Report to 1 decimal place. b) What total weight of Y would be removed from water (the original solution) with two successive extractions with 90-mL portions each of methylene chloride?
Answer:
a)Weight of Y extracted from water in single extraction = 67.2 g
b) Total weight of Y extracted from water in two successive extractions = 70.9 g
Explanation:
Distribution coefficient, Kd = Cs / Cm
where Cs is concentration of solute in methylene chloride; Cm is concentration of solute in water
a) Let x g of solute Y be extracted into methylene chloride
72.0 - x g of Y will be left in water
Kd = (x/180 mL of methylene chloride) / (72.0 - x/180 mL of water) = 14
14 = 180 * x / 180 * 72.0 - x
x = 14(72.0 - x)
x = 1008 - 14x
15x = 1008
x = 1008/15
x = 67.2 g
Weight of Y extracted from water in single extraction = 67.2 g
b) First extraction: Let x g of solute Y be extracted into methylene chloride
72.0 - x g of Y will be left in water
14 = x/90 / 72.0 - x/180
14 = 180x/ 90(72.0 - x)
14 = 2x/ 72.0 - x
2x = 14(72.0 - x)
2x = 1008 - 14x
16x = 1008
x = 63.0 g
Second extraction: Amount of solute left in water after first extraction = 72 - 63 = 9.0 g
Let x g of solute Y be extracted into methylene chloride
9.0 - x g of Y will be left in water
14 = x/90 / 9.0 - x/180
14 = 180x/ 90(9.0 - x)
14 = 2x/ 9.0 - x
2x = 14(9.0 - x)
2x = 126 - 14x
16x = 126
x = 7.90 g
Total weight of Y extracted = (63 + 7.90) g
Total weight of Y extracted from water in two successive extractions = 70.9 g
a) The Weight of Y extracted from water in single extraction is 67.2 g
b) The Total weight of Y extracted from water in two successive extractions should be 70.9 g
Calculation of weight:Here
The distribution coefficient, Kd should be
= Cs / Cm
where
Cs should be a concentration of solute in methylene chloride;
Cm should be a concentration of solute in water
a) Let us assume x g of solute Y that should be extracted into methylene chloride
So,
72.0 - x g of Y will be left in water
And, now
Kd = (x/180 mL of methylene chloride) / (72.0 - x/180 mL of water) = 14
So,
14 = 180 * x / 180 * 72.0 - x
x = 14(72.0 - x)
x = 1008 - 14x
15x = 1008
x = 1008/15
x = 67.2 g
b)
Now First extraction:
Let x g of solute Y be extracted into methylene chloride
So,
72.0 - x g of Y will be left in water
14 = x/90 / 72.0 - x/180
14 = 180x/ 90(72.0 - x)
14 = 2x/ 72.0 - x
2x = 14(72.0 - x)
2x = 1008 - 14x
16x = 1008
x = 63.0 g
Second extraction:
Amount of solute left in the water after the first extraction that should be
= 72 - 63
= 9.0 g
Now
Let x g of solute Y be extracted into methylene chloride
9.0 - x g of Y will be left in water
14 = x/90 / 9.0 - x/180
14 = 180x/ 90(9.0 - x)
14 = 2x/ 9.0 - x
2x = 14(9.0 - x)
2x = 126 - 14x
16x = 126
x = 7.90 g
Total weight of Y extracted = (63 + 7.90) g
= 70.9g
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How many moles of Sr2+ are present in 250 mL of a 0.45 M solution of strontium phosphide?
Moles of Sr²⁺ = 0.3375
Further explanationMolarity is a way to express the concentration of the solution
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
[tex]\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}[/tex]
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
So to find the number of moles can be expressed as
[tex]\boxed{\bold{n=V\times M}}[/tex]
Strontium phosphide (Sr₃P₂)
Sr₃P₂ ⇒ 3Sr ²⁺ + 2P³⁻
mol of Sr₃P₂[tex]\tt 0.45~M \times 0.25~L=0.1125[/tex]
mol of Sr ²⁺mol ratio Sr₃P₂ : Sr ²⁺ = 1 : 3
[tex]\tt \dfrac{3}{1}\times 0.1125=0.3375[/tex]
A boiler operates at steady state. The entering water is saturated liquid at P = 5 bar and has a flow rate of 10,000 kg/hr. The existing steam is also at P = 5 bar and T = 400o C. The pipe entering the boiler is 8 cm in diameter, and the pipe leaving the boiler is 30 cm in diameter. What is the rate at which heat is added in the boiler?
Answer:
The rate at which heat is added in the boiler is 8128.610 kilowatts.
Explanation:
A boiler is a device that works at steady state, whose function is pressurizing and heating water. All gravitational electric and magnetic effects can be neglected. From First Law of Thermodynamics the boiler is characterized by the following model:
[tex]\dot Q_{in} + \dot H_{in}-\dot H_{out} + \dot K_{in} - \dot K_{out}= 0[/tex] (Eq. 1)
Where:
[tex]\dot Q_{in}[/tex] - Heat transfer rate, measured in kilowatts.
[tex]\dot H_{in}[/tex], [tex]\dot H_{out}[/tex] - Inlet and outlet fluid enthalpy rates, measured in kilowatts.
[tex]\dot K_{in}[/tex], [tex]\dot K_{out}[/tex] - Inlet and outlet kinetic energy rate, measured in kilowatts.
And by the Principle of Mass Conservation we have that:
[tex]\dot m_{in}-\dot m_{out} = 0[/tex] (Eq. 2)
Where [tex]\dot m_{in}[/tex] and [tex]\dot m_{out}[/tex] are mass flows at entrance and exit of the boiler, measured in kilograms per second.
Then, we clear the heat transfer rate and expand (Eq. 1) by definitions of enthalpy and kinetic energy, as well as (Eq. 2):
[tex]\dot Q_{in} = \dot H_{out}-\dot H_{in}+\dot K_{out}-\dot K_{in}[/tex]
[tex]\dot Q_{in} = \dot m \cdot \left[(h_{out}-h_{in}\right)+\frac{1}{2}\cdot (v_{out}^{2}-v_{in}^{2})\left][/tex] (Eq. 3)
Speeds of fluid entering and exiting the boiler ([tex]v[/tex]), measured in meters per second, are found by applying the following formula:
[tex]\dot m = \left(\frac{\pi}{4} \right)\cdot \frac{D^{2}\cdot v}{\nu}[/tex]
[tex]v = \frac{4\cdot \dot m\cdot \nu}{\pi\cdot D^{2}}[/tex] (Eq. 4)
Where:
[tex]\nu[/tex] - Specific volume of fluid, measured in cubic meters per kilogram.
[tex]D[/tex] - Inner diameter of pipe, measured in meters.
Entrance ([tex]\dot m = 2.778\,\frac{kg}{s}[/tex], [tex]\nu_{in} = 0.001093\,\frac{m^{3}}{kg}[/tex] and [tex]D_{in} = 0.08\,m[/tex])
[tex]v_{in} = \frac{4\cdot \left(2.778\,\frac{kg}{m^{3}} \right)\cdot \left(0.001093\,\frac{m^{3}}{kg} \right)}{\pi\cdot (0.08\,m)^{2}}[/tex]
[tex]v_{in}\approx 0.604\,\frac{m}{s}[/tex]
Specific enthalpy at given conditions is:
[tex]h_{in} = 640.09\,\frac{kJ}{kg}[/tex] (From Saturated Water tables)
Exit ([tex]\dot m = 2.778\,\frac{kg}{s}[/tex], [tex]\nu_{out} = 0.61731\,\frac{m^{3}}{kg}[/tex] and [tex]D_{out} = 0.30\,m[/tex])
[tex]v_{out} = \frac{4\cdot \left(2.778\,\frac{kg}{m^{3}} \right)\cdot \left(0.61731\,\frac{m^{3}}{kg} \right)}{\pi\cdot (0.30\,m)^{2}}[/tex]
[tex]v_{out} \approx 24.261\,\frac{m}{s}[/tex]
Specific enthalpy at given conditions is:
[tex]h_{out} = 3272.4\,\frac{kJ}{kg}[/tex] (From Superheated Steam tables)
If we know that [tex]\dot m = 2.778\,\frac{kg}{s}[/tex], [tex]h_{in} = 640.09\,\frac{kJ}{kg}[/tex], [tex]h_{out} = 3272.4\,\frac{kJ}{kg}[/tex], [tex]v_{in}\approx 0.604\,\frac{m}{s}[/tex], [tex]v_{out} \approx 24.261\,\frac{m}{s}[/tex], the heat transfer rate is:
[tex]\dot Q = \left(2.778\,\frac{kg}{s} \right)\cdot \left\{ \left(3272.4\,\frac{kJ}{kg}-640.09\,\frac{kJ}{kg} \right)+\frac{1}{2}\cdot \left[\left(24.261\,\frac{m}{s} \right)^{2}-\left(0.604\,\frac{m}{s} \right)^{2}\right] \right\}[/tex]
[tex]\dot Q = 8128.610\,kW[/tex]
The rate at which heat is added in the boiler is 8128.610 kilowatts.
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Answer:
a
Explanation:
Explain how this chemical equation demonstrates the Law of Conservation of Matter (Mass).
Answer:
Explanation:
The equation must be balanced on both sides to show the law of conservation of mass. So, as long as it is equaled, the law is shown.
Fluorine is the first element in Group 17 of the periodic table. Bromine is the third element in the same group. Which statement is true of both
elements?
A. Both of their ions will have the same positive charge.
B. The charge on the ion formed by fluorine will be less than the charge on the bromine ion.
C. The charge on the ion formed by fluorine will be greater than the charge on the ion formed by bromine.
D. Both of their ions will have the same negative charge.
Answer:D. Both of their ions will have the same negative charge
Explanation:
What is chemical energy? (2 points)
a
Energy that is stored or released during a chemical reaction
b
Energy that is destroyed during a physical change
c
Energy that is released during a phase change
d
Energy that is created when a substance is being burned
Answer: a
Energy that is stored or released during a chemical reaction
Explanation: a battery has chemical energy when u but in something that u can power with batteries it starts a chemical reaction.
Hope I helped :)
Explanation:
Chemical energy
Chemical energy is energy stored in the bonds of chemical compounds, like atoms and molecules. This energy is released when a chemical reaction takes place.
Usually, once chemical energy has been released from a substance, that substance is transformed into a completely new substance.
What quantity (moles) of NaOH must be added to 1.0 L of 1.8 M HC2H3O2 to produce a solution buffered at pH
Answer:
a) What quantity (moles) of NaOH must be added to 1.0 L of 1.8 M HC2H3O2 to produce a solution buffered at pH = pKa?
Step 1: Data given
Volume of HC2H3O2 = 1.0 L
Molarity of HC2H3O2 = 1.8 M
Ka = 1.8*10^-5
ph = pK = -log(1.8*10^-5) = 4.74
Step 2:
Use the Henderson-Hasselbalch equation.
pH = pKa + log(A-/HA)
4.74 = 4.74 + log(A-/HA)
0 = log(A-/HA)
A-/HA = 1
Consider X = moles of NaOH added (and moles of A- formed)
Remaining moles of HA = 1.8 - X
moles of A- = X
HA = 1.8 - X
X/(1.8-X) = 1
X =0.9
We have to add 0.9 mole NaOH to 1.0 L of 1.8 M HC2H3O2
To control we can do the following equation:
4.74 = 4.74 + log(0.9/0.9) = 4.74
b) What quantity (moles) of NaOH must be added to 1.0 L of 1.8 M HC2H3O2 to produce a solution buffered at pH = 4.00?
Step 1: Data given
Volume of HC2H3O2 = 1.0 L
Molarity of HC2H3O2 = 1.8 M
Ka = 1.8*10^-5
ph = 4
Step 2:
Use the Henderson-Hasselbalch equation.
pH = pKa + log(A-/HA)
4 = 4.74 + log(A-/HA)
-0.74 = log(A-/HA)
A-/HA = 0.182
Consider X = moles of NaOH added (and moles of A- formed)
Remaining moles of HA = 1.8 - X
moles of A- = X
HA = 1.8 - X
X/(1.8-X) = 0.182
X =0.277
We have to add 0.277 mole NaOH to 1.0 L of 1.8 M HC2H3O2
To control we can do the following equation:
4 = 4.74 + log(0.277/1.523)
c) What quantity (moles) of NaOH must be added to 1.0 L of 1.8 M HC2H3O2 to produce a solution buffered at pH = 5.00
Step 1: Data given
Volume of HC2H3O2 = 1.0 L
Molarity of HC2H3O2 = 1.8 M
Ka = 1.8*10^-5
ph = 5
Step 2:
Use the Henderson-Hasselbalch equation.
pH = pKa + log(A-/HA)
5 = 4.74 + log(A-/HA)
0.26 = log(A-/HA)
A-/HA = 1.82
Consider X = moles of NaOH added (and moles of A- formed)
Remaining moles of HA = 1.8 - X
moles of A- = X
HA = 1.8 - X
X/(1.8-X) = 1.82
X =1.16
We have to add 1.16 mole NaOH to 1.0 L of 1.8 M HC2H3O2
To control we can do the following equation:
5 = 4.74 + log(1.16/0.64) = 5
Explanation:
Which of the following best describes the structure of a protein?
a
Carbon ring(s)
b
Hydrocarbon(s)
c
Single or double helix
d
Globular or fibrous
Answer:
I'm pretty sure its d.
Explanation:
because a gbular protein is a protein that is round in shape, and a fibrous is a long a thin shaped protein. Which those are two kinds of proteins.
Consider the reactionI2(g) + Cl2(g)2ICl(g)Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.41 moles of I2(g) react at standard conditions.S°surroundings = J/K
We know,
[tex]\Delta H_{I_2(g)}=62.438\ KJ/mol\\\\\Delta H_{Cl_2(g)}= 0.0\ KJ/mol\\\\\Delta H_{ICl(g)}=17.78\ KJ/mol[/tex]
For given reaction, [tex]I_2(g)+Cl_2(g)\ -->\ 2ICl(g)[/tex]
[tex]\Delta H_{rxn}=2\Delta H_{ICl(g)}-\Delta H_{I_2(g)}-\Delta H_{Cl_2(g)}\\\\\Delta H_{rxn}=2(17.78)-0-62.438\ KJ/mol\\\\\Delta H_{rxn}=-26.878\ KJ/mol[/tex]
For , 2.41 moles of [tex]I_2[/tex] :
[tex]\Delta H_{rxn}=2.41\times (-26.878)\ KJ\\\\\Delta H_{rxn}=-64.78\ KJ[/tex]
We know :
[tex]\Delta S = -\dfrac{\Delta H_{rxn}}{T}\\\\\Delta S = -\dfrac{-64.78}{298}\ KJ/K\\\\\Delta S =-0.21738 \ KJ/K\\\\\Delta S=-217.38\ J/K[/tex]
Hence, this is the required solution.
Question 5 of 5
Which two phrases describe the nature of an electromagnetic force?
O A. Acts only when objects touch each other
B. Produced by interactions between magnetic objects
O c. Not a fundamental force of nature
O D. Produced by interactions between electrically charged objects
Answer:
I think it's A and D
Explanation:
I'm not sure if it's right
Answer:
The answer is B and D
Explanation:
trust fr
