3. Find the value of x.
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Answer:

2/3

Step-by-step explanation:

3x-5=-3

3x=-3+5

3x=2

x=2/3

Answer:

i don't know the right answer plse

Answer:

Something with coordinates lines and negative and positive numbers.

Answer:

A graph is usually consisted with coordinates lines and negative and positive numbers. There must be a y axis and x axis.

Because you have not listed the statements, whatever statement is closest to this is the correct option.

Answer:

Step-by-step explanation:

-4x <_ -8

x <_ -8 ÷-4

x <_ 2

Answer:

c

Step-by-step explanation:

Step-by-step explanation:

tan = perpendicular / base

acc. to diagram ,

angle C = 90°

such that

AB is hypotenuse

acc to theta ,

AC is perpendicular and BC is base

therefore

tan theta = AC / BC

tan theta = 8/15

Answer:

[tex]2\frac{1}{4}[/tex]

Step-by-step explanation:

Question has missing details (See attachment).

Given

[tex]Orange\ Juice = 1\frac{1}{4}quart[/tex]

[tex]Pineapple\ Juice = 2\frac{1}{2}quart[/tex]

[tex]Seltzer = 1\frac{1}{2}quart[/tex]

Required

Determine how much juice than seltzer used.

To do this, we first calculate the total amount of juice

[tex]Juice = Orange + Pineapple[/tex]

[tex]Juice = 1\frac{1}{4} + 2\frac{1}{2}[/tex]

[tex]Juice = \frac{5}{4} + \frac{5}{2}[/tex]

Take LCM

[tex]Juice = \frac{5+10}{4}[/tex]

[tex]Juice = \frac{15}{4}[/tex]

Then subtract the amount of seltzer used.

[tex]Juice - Seltzer = \frac{15}{4}-1\frac{1}{2}[/tex]

[tex]Juice - Seltzer = \frac{15}{4}-\frac{3}{2}[/tex]

Take LCM

[tex]Juice - Seltzer = \frac{15 - 6}{4}[/tex]

[tex]Juice - Seltzer = \frac{9}{4}[/tex]

[tex]Juice - Seltzer = 2\frac{1}{4}[/tex]

The amount of juice used more than seltzer is [tex]2\frac{1}{4}[/tex]

Answer: 3 3/4 quarts

Hope this helps

Answer:

Remember while answering, 1 kilometer = 1,000 meters

5,000 ⇒ 5

6,000 ⇒ 6

7,000 ⇒ 7

8,000 ⇒ 8

9,000 ⇒ 9

Step-by-step explanation:

1 kilometer is 1,000 meters because "kilo" means 1,000

Knowing this we can make an equation to figure this out

When we know x, or meters, we can do y = x/1,000

When we know y, or kilometers, we can do x = 1,000y

Answer:

21.73

Step-by-step explanation:

calculator

Answer: Kingda Ka is a launched roller coaster located at Six Flags Great Adventure in Jackson, New Jersey. Designed by Werner Stengel, Kingda Ka is an Accelerator Coaster model from Intamin that opened as the tallest and fastest roller coaster in the world on May 21, 2005.

Step-by-step explanation:

Answer:

2 times taller

Step-by-step explanation:

[tex]\frac{6}{10} = \frac{x}{20}[/tex]

120=12x

x = 12ft

x=height of street light

the street light is 12 feet tall so the street light is 12 times taller than the person

Answer:

4144

Step-by-step explanation:

hope this helps

Answer:

the answer is 4,144

Step-by-step explanation:

Answer:

here this is the answer

106

Answer:

I Dont Know

Step-by-step explanation:

Answer: The first one

Step-by-step explanation:

-6c + 11d = 20

-6c + 11d = 20

They're the same equation meaning they'll be on the same line. They would have infinite solutions.

Answer: The first one

Step-by-step explanation:

-6c + 11d = 20

-6c + 11d = 20

Answer:

Perpendicular lines are lines that cross perfectly to create a 90 degree angle! Kinda like a big cross. with a right angle in the center area

Step-by-step explanation:

Answer:

[tex] A_{sector} \approx \: 80.38 \: {ft}^{2} [/tex]

Step-by-step explanation:

[tex] A_{sector} = \frac{ \theta}{360 \degree} \times \pi {r}^{2} \\ \\ A_{sector} = \frac{144 \degree}{360 \degree} \times 3.14 \times {(8)}^{2} \\ \\ A_{sector} = 0.4 \times 3.14 \times {(8)}^{2} \\ \\ A_{sector} = 80.384 \\ \\ A_{sector} \approx \: 80.38 \: {ft}^{2} [/tex]

Answer:

12

Step-by-step explanation:

so basically

(x^2+2)*(1-3x)=-3x^3+x^2-6x+2

now plug in -1

-3(-1)^3+(-1)^2-6(-1)+2=12

hope this helped :)

The correct value of (fg)(-1) is "12". A further solution of the given query is provided below.

Given functions are:

[tex]f(x) = x^2+2[/tex]

[tex]g(x) = 1-3x[/tex]

Now,

⇒ [tex](fg) = (x^2+2)(1-3x)[/tex]

By applying multiplication, we get

           [tex]=x^2+2-3x^3-6x[/tex]

           [tex]=-3x^3+x^2-6x+2[/tex]...(equation 1)

By substituting the value "-1" in place of "x" in equation 1, we get

⇒ [tex](fg)(-1) = -3(-1)^3+(-1)^2-(6)(-1)+2[/tex]

                  [tex]=-3(-1)+1+6+2[/tex]

                  [tex]=3+1+6+2[/tex]

                  [tex]=12[/tex]

Thus the right answer is (fg)(-1) = 12.

Learn more:

https://brainly.com/question/10057660

Answer:

23d

Step-by-step explanation:

Answer:

4d +24c

Step-by-step explanation:

Answer: 12 adult tickets where sold

Step-by-step explanation:

Step-by-step explanation:

Answer:25.1

Step-by-step explanation:

The bearing of point Q from point P is 80 degrees.

To find the bearing of point Q from point P, we need to determine the angle between the bearing of point P from the common point N and the bearing of point Q from the common point N.

Given that point P is on a bearing of 300 degrees from the common point N, and point Q is on a bearing of 20 degrees from the common point N, we can find the bearing of Q from P as follows:

Calculate the angle between the bearing of P from N and the bearing of Q from N:

Angle = Bearing of Q from N - Bearing of P from N

Angle = 20 degrees - 300 degrees

Angle = -280 degrees

Adjust the angle to be within the range of 0 to 360 degrees:

Since the angle is negative, we can add 360 degrees to it to bring it within the range of 0 to 360 degrees:

Adjusted Angle = -280 degrees + 360 degrees

Adjusted Angle = 80 degrees

Therefore, the bearing of point Q from point P is 80 degrees.

To know more about bearing click here :

https://brainly.com/question/29094086

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Answer:

The value of the house on 1st January 2015 was of $650,000.

Step-by-step explanation:

Decimal multipliers:

For a increase of a%, the decimal multiplier is given by [tex]\frac{100+a}{100}[/tex]

For a decrease of a%, the decimal multiplier is given by [tex]\frac{100-a}{100}[/tex]

Rami bought a house on 1st January 2015.

For a value of x.

In 2015 the house increased in value by 15%.

This means that x is multiplied by [tex]\frac{100+15}{100} = \frac{115}{100} = 1.15[/tex]

In 2016 the house decreased in value by 8%.

This means that 1.15 times x is multiplied by [tex]\frac{100-8}{100} = \frac{92}{100} = 0.92[/tex]

On 1st January 2017 the value of the house was $687700.

The value of these multiplications is 687700.

What was the value of the house on 1st January 2015?

This is x, so:

[tex]x*1.15*0.92 = 687700[/tex]

[tex]x = \frac{687700}{1.15*0.92}[/tex]

[tex]x = 650000[/tex]

The value of the house on 1st January 2015 was of $650,000.

Answer:

530.66 cm squared

Step-by-step Explanation:

Diameter of the circle = 26 cm

Radius of the circle (r) = 26/2 = 13 cm

[tex]A_{circle} = \pi {r}^{2} \\ \\ A_{circle} = 3.14 \times {(13)}^{2} \\ \\ A_{circle} = 3.14 \times 169 \\ \\ A_{circle} =530.66 \: {cm}^{2} [/tex]

Answer:

The area of 530.66 cm squared.

Option (a) 530.66 cm² is the correct answer.

Step-by-step explanation:

Given :

To Find :

Using Formulas :

[tex]\star{\small{\underline{\boxed{\sf{\red{R = \dfrac{D}{2}}}}}}}[/tex]

[tex]\star{\small{\underline{\boxed{\sf{\red{Area_{(Circle)} = \pi{r}^{2}}}}}}}[/tex]

Solution :

Finding the radius of circle by substituting the values in the formula :

[tex]{\longrightarrow{\sf{Radius = \dfrac{D}{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Radius = \dfrac{26}{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Radius = \cancel{\dfrac{26}{2}}}}}[/tex]

[tex]{\longrightarrow{\sf{Radius = 13}}}[/tex]

[tex]\star{\underline{\boxed{\sf{\red{Radius = 13 \: cm}}}}}[/tex]

Hence, the radius of circle is 13 cm.

[tex]\rule{200}2[/tex]

Now, finding the area of circle by substituting the values in the formula :

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \pi{r}^{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = 3.14 \times {(13)}^{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314}{100} \times {(13 \times 13)}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314}{100} \times 169}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314 \times 169}{100}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{53066}{100}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = 530.66}}}[/tex]

[tex]\star{\small{\underline{\boxed{\sf{\red{Area_{(Circle)} = 530.66 \: {cm}^{2}}}}}}}[/tex]

Hence, the area of circle is 530.66 cm².

[tex]\rule{300}{1.5}[/tex]

Answer:

[tex]\displaystyle d = \sqrt{74}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Algebra II

Step-by-step explanation:

Step 1: Define

Point (6, 2) → x₁ = 6, y₁ = 2

Point (1, -5) → x₂ = 1, y₂ = -5

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d