Answer:
2 times some thing and plus 3 equals -7
Step-by-step explanation:
x = -5
Which size would you see on the box for a new television whose screen measures 36 inches wide by 27 inches high? A. 9" B. 45" C. 50" D. 63"
Answer: b) 45"
Step-by-step explanation:
Tv's are measured by their diagonal length.
Use Pythagorean Theorem to find the diagonal of the tv.
a² + b² = c²
36² + 27² = c²
1296 + 729 = c²
2025 = c²
√2025 = c
45 = c
what is the positive solution for the equation
Answer:
x=3
Step-by-step explanation:
4x^2 - 36 = 0
Add 36 to each side
4x^2 -36 +36 = 0+36
4x^2 = 36
Divide each side by 4
4x^2/4 =36/4
x^2 = 9
Take the square root of each sdie
sqrt(x^2) = ±sqrt(3)
x = -3,+3
We want the positive square root
x=3
12 and 3/6 -5 and 2/12
Answer:
7.33333333333 I think. Hope this helped.
Five thousand tickets are sold at $1 each for a charity raffle. Tickets are to be drawn at random and monetary prizes awarded as follows: 1 prize of $ 500 500, 3 prizes of $ 200 200, 5 prizes of $ 10 10, and 20 prizes of $5. What is the expected value of this raffle if you buy 1 ticket?
Answer:
-$0.75
Step-by-step explanation:
For calculation of expected value first we need to find out the probability distribution for this raffle which is shown below:-
Amount Probability
500 - 1 = $499 1 ÷ 5,000
200 - 1 = $199 3 ÷ 5,000
10 - 1 = $9 5 ÷ 5,000
5 - 1 = $4 20 ÷ 5,000
-$1 5,000 - 29 ÷ 5,000 = 4,971 ÷ 5,000
Now, the expected value of raffle will be
[tex]= \$499 \times (\frac{1}{5,000}) + \$199 \times (\frac{3}{5,000}) + \$9 \times (\frac{5}{5,000}) + \$4 \times (\frac{20}{5,000}) - \$1 \times (\frac{4,971}{5,000})[/tex]
= 0.0998 + 0.1194 + 0.009 + 0.016 - 0.9942
= -$0.75
The expected value of this raffle per ticket is $ 0.25.
Given that five thousand tickets are sold at $ 1 each for a charity raffle, and tickets are to be drawn at random and monetary prizes awarded as follows: 1 prize of $ 500, 3 prizes of $ 200, 5 prizes of $ 10, and 20 prizes of $ 5, to determine what is the expected value of this raffle if you buy 1 ticket, the following calculation must be performed:
(500 + 3 x 200 + 5 x 10 + 20 x 5) / 5000 = X (500 + 600 + 50 + 100) / 5000 = X 1250/5000 = X 0.25 = X
Therefore, the expected value of this raffle per ticket is $ 0.25.
Learn more in https://brainly.com/question/22097128
The office needs 8 new devices worth $8000. The order consists of new computers (C ) which cost $925 each and printers (P) which cost $1125 each. How many of the new devices are computers and how many are printers?
Answer:
The number of computer is 5 and printer is 3
What is 40% of 160?
Answer:
40% of 160 is 64
Step-by-step explanation:
You can easily find the answer in one step, just multiplying the whole (160) by the percentage (40) divided by 100.
So, 40% of 160 = 160 × 0.4 = 64.
Answer:
64
Step-by-step explanation:
You first have to subtract 40% from 160 and then you subtract that amount with is 96 from 160 and you get your answer 64
A linear function and its inverse are given.
y=4x-3
y=1/4x+3/4
Which tables could be used to verify that the functions are inverses of each other? Select two options.
x:1, 3, 5, 7, 9
y:1, 3, 5, 7, 9
x:-23, -15, -3, 1, 13
y:-5, -3, 0, 1, 4
x:-18, -12, 0, 3, 9
y:-24, -18, -6, -3, 3
x:-5, -3, 0, 1, 4
y:-23, -15, -3, 1, 13
x:-24, -18, -6, -3, 3
y:-18, -12, 0, 3, 9
Answer:
x: -5, -3, 0, 1, 4
y:-23, -15, -3, 1, 13 for the function.
x:-23, -15, -3, 1, 13
y: -5, -3, 0, 1, 4 for the inverse.
Step-by-step explanation:
we know that if we have the function f(x) = y, then the inverse of f(x) (let's call it g(x)) is such that:
g(y) = x.
now we have
y=4x-3
y=(1/4)x+3/4
The only table that works for our first function is:
x: -5, -3, 0, 1, 4
y:-23, -15, -3, 1, 13
You can see this by replacing the values of x and see if the value of y also coincides.
Then, using the fact that the other table must be for the inverse, we should se a table with the same values, but where the values of x and y are interchanged.
The second table is that one:
x:-23, -15, -3, 1, 13
y: -5, -3, 0, 1, 4
Answer: B and D
x:-23, -15, -3, 1, 13
y:-5, -3, 0, 1, 4
x:-5, -3, 0, 1, 4
y:-23, -15, -3, 1, 13
Step-by-step explanation:
0.580 80 repeating as a simplified fraction
Answer:
979
Step-by-step explanation:
Answer:
115/198
Step-by-step explanation:
khan
5. There are 400 students in the senior class at Oak Creek High School. All 2 points
of these students took the SAT. The distribution of their SAT scores is
approximately normal. The number of students who scored within 2
standard deviations of the mean is approximately *
-3
-2
0
1
2.
3
Answer:
The number of students who scored within 2 standard deviations of the mean is 380.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
The number of students who scored within 2 standard deviations of the mean is approximately
By the Empirical Rule, 95% of the students scored within 2 standard deviations of the mean
Out of 400
0.95*400 = 380
The number of students who scored within 2 standard deviations of the mean is 380.
Answer: 380
Step-by-step explanation: 95% of 400 is 380
A cyclist travels at an average speed of 8 km/h over a distance of 32 km. How many hours does it take him?
Answer:
4 hours.
Step-by-step explanation:
Well we can simply divide 32 by 8 and we get 4 hours:
32 miles ÷ 8 miles = 4 hours
It takes the cyclist 4 hours.
Answer:
4 hours
Step-by-step explanation:
As every speed limit sign tells you, ...
speed = miles/hours
Solving for time and using generic distance units, we get ...
time = distance/speed
Filling in the given values, we have ...
time = 32 km/(8 km/h) = (32/8) h = 4 h
It takes the cyclist 4 hours to travel 32 km.
The following is a Markov (migration) matrix for three locations
[1/5 1/5 2/5
2/5 2/5 1/5
2/5 2/5 2/5]
(a) Initially, there are 130 individuals in location 1, 300 in location 2, and 70 in location 3. How many are in each location after two time periods?
(b) The total number of individuals in the migration process is 500. After a long time, how many are in each location?
Answer:
(a) [tex]\mathbf{P_2 = \left[\begin{array}{c}140 \\ 160 \\ 200 \end{array}\right]}[/tex]
(b) After an infinite period of time; we will get back to a result similar to after the two time period which will be [tex]= \left[\begin{array}{c}140 \\ 160 \\ 200 \end{array}\right]}[/tex]
Step-by-step explanation:
The Markov Matrix can be interpret as :
[tex]M = \left[\begin{array}{ccc} \dfrac{1}{5} & \dfrac{2}{5} &\dfrac{1}{5} \\ \\ \dfrac{2}{5}&\dfrac{2}{5}&\dfrac{1}{5}\\ \\ \dfrac{2}{5}& \dfrac{2}{5}& \dfrac{2}{5} \end{array}\right][/tex]
From (a) ; we see that the initial population are as follows: 130 individuals in location 1, 300 in location 2, and 70 in location 3.
Le P represent the Population; So ; [tex]P = \left[\begin{array}{c}130 \\ 300 \\ 70 \end{array}\right][/tex]
The objective is to find How many are in each location after two time periods;
So, after two time period ; we have the population [tex]P_2 = [M]^2 [P][/tex]
where;
[tex][M]^ 2 = \left[\begin{array}{ccc} \dfrac{1}{5} & \dfrac{2}{5} &\dfrac{1}{5} \\ \\ \dfrac{2}{5}&\dfrac{2}{5}&\dfrac{1}{5}\\ \\ \dfrac{2}{5}& \dfrac{2}{5}& \dfrac{2}{5} \end{array}\right] \left[\begin{array}{ccc} \dfrac{1}{5} & \dfrac{2}{5} &\dfrac{1}{5} \\ \\ \dfrac{2}{5}&\dfrac{2}{5}&\dfrac{1}{5}\\ \\ \dfrac{2}{5}& \dfrac{2}{5}& \dfrac{2}{5} \end{array}\right][/tex]
[tex][M]^ 2 = \dfrac{1}{25} \left[\begin{array}{ccc} 1+2+4 & 1+2+4 &1+2+4 \\ \\ 2+2+4&2+2+4&2+2+4\\ \\ 2+4+4&2+4+4& 2+4+4 \end{array}\right][/tex]
[tex][M]^ 2 = \dfrac{1}{25} \left[\begin{array}{ccc}7&7&7 \\ \\ 8 &8&8\\ \\10&10& 10 \end{array}\right][/tex]
Now; Over to after two time period ; when the population [tex]P_2 = [M]^2 [P][/tex]
[tex]P_2 = \dfrac{1}{25} \left[\begin{array}{ccc}7&7&7 \\ \\ 8 &8&8\\ \\10&10& 10 \end{array}\right] \left[\begin{array}{c}130 \\ 300 \\ 70 \end{array}\right][/tex]
[tex]\mathbf{P_2 = \left[\begin{array}{c}140 \\ 160 \\ 200 \end{array}\right]}[/tex]
(b) The total number of individuals in the migration process is 500. After a long time, how many are in each location?
After a long time; that is referring to an infinite time (n)
So; [tex]P_n = [M]^n [P][/tex]
where ;
[tex][M]^n \ can \ be \ [M]^2 , [M]^3 , [M]^4 .... \infty[/tex]
; if we determine the respective values of [tex][M]^2 , [M]^3 , [M]^4 .... \infty[/tex] we will always result to the value for [tex][M]^n[/tex]; Now if [tex][M]^n[/tex] is said to be a positive integer; then :
After an infinite period of time; we will get back to a result similar to after the two time period which will be [tex]= \left[\begin{array}{c}140 \\ 160 \\ 200 \end{array}\right]}[/tex]
Solve for x. e^x - e ^ -x / e^x + e ^-x = t
Answer:
D
Step-by-step explanation:
(eˣ − e⁻ˣ) / (eˣ + e⁻ˣ) = t
Multiply by eˣ/eˣ.
(e²ˣ − 1) / (e²ˣ + 1) = t
Solve for e²ˣ.
e²ˣ − 1 = (e²ˣ + 1) t
e²ˣ − 1 = e²ˣ t + t
e²ˣ = 1 + e²ˣ t + t
e²ˣ − e²ˣ t = 1 + t
e²ˣ (1 − t) = 1 + t
e²ˣ = (1 + t) / (1 − t)
Solve for x.
2x = ln[(1 + t) / (1 − t)]
x = ½ ln[(1 + t) / (1 − t)]
Use log rule.
x = ln(√[(1 + t) / (1 − t)])
Express (In 35+ln(1/7))/ In 25 in terms of In 5 and In 7
Properties of the logarithm: for any base of logarithm,
log(a*b) = log(a) + log(b)
If we replace b with 1/b, or b^-1, we have
log(a/b) = log(a) + log(1/b) = log(a) - log(b)
since
log(1/b) = log(b^-1) = - log(b)
using the power property of logarithms,
log(b^n) = n log(b)
Now,
ln35 = ln(5*7) = ln5 + ln7
ln(1/7) = - ln7
ln25 = ln(5^2) = 2 ln5
Putting everything together, we have
(ln35 + ln(1/7))/ln25 = (ln5 + ln7 - ln7)/(2 ln5) = ln5/(2 ln5) = 1/2
Mileage tests were conducted on a randomly selected sample of 100 newly developed automobile tires. The results showed that the mean tread life was 50,000 miles, with a standard deviation of 3,500 miles. What is the best estimate of the mean tread life in miles for the entire population of these tires?
Answer:
The best estimate of the mean of the population is 50,000 miles, which is the sample mean.
To make a better inference, we know that the 95% confidence interval for the mean is (49,306; 50,694).
Step-by-step explanation:
The unbiased point estimation for the population mean tread life is the sample mean (50,000 miles), as it is the only information we have.
Although, knowing the standard deviation, we can calculate a confidence interval to make a stronger inference.
We calculate a 95% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=50000.
The sample size is N=100.
When σ is not known, s divided by the square root of N is used as an estimate of σM:
[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{3500}{\sqrt{100}}=\dfrac{3500}{10}=350[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=100-1=99[/tex]
The t-value for a 95% confidence interval and 99 degrees of freedom is t=1.98.
The margin of error (MOE) can be calculated as:
[tex]MOE=t\cdot s_M=1.98 \cdot 350=694.48[/tex]
Then, the lower and upper bounds of the confidence interval are:
[tex]LL=M-t \cdot s_M = 50000-694.48=49306\\\\UL=M+t \cdot s_M = 50000+694.48=50694[/tex]
The 95% confidence interval for the mean is (49306, 50694).
Inflation causes things to cost more, and for our money to buy less (hence your grandparents saying "In my day, you could buy a cup of coffee for a nickel"). Suppose inflation decreases the value of money by 4% each year. In other words, if you have $1 this year, next year it will only buy you $0.96 worth of stuff. How much will $100 buy you in 25 years?
Answer:
Step-by-step explanation:
[tex]100 (0.96)^{25} =[/tex] around 36.04
HELP...it has timer
Answer:
lily has a larger ratio
Step-by-step explanation:
Evaluate: 5-^2 =
pls help
Answer:
1/25
Step-by-step explanation:
5^-2
We know that a^ -b = 1/ a^b
5^-2 = 1/ 5^2
= 1/25
Based on historical data, your manager believes that 36% of the company's orders come from first-time customers. A random sample of 195 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is between 0.34 and 0.49
Answer:
[tex] P(0.34 <\hat p<0.49)[/tex]
And the distribution for the sample proportion is given by;
[tex]\hat p \sim N(p, \sqrt{\frac{p(1-p)}{n}})[/tex]
And we can find the mean and deviation for the sample proportion:
[te]\mu_{\hat p}= 0.36[/tex]
[tex]\sigma_{\hat p} =\sqrt{\frac{0.36(1-0.36)}{195}}= 0.0344[/tex]
And we can use the z score formula given by:
[tex] z = \frac{0.34 -0.36}{0.0344}= -0.582[/tex]
[tex] z = \frac{0.49 -0.36}{0.0344}= 3.782[/tex]
And we can use the normal distribution table and we got:
[tex] P(-0.582 <z< 3.782) =P(z<3.782)-P(z<-0.582)=0.99992-0.2803= 0.71962[/tex]
Step-by-step explanation:
For this case we know that the sample size is n =195 and the probability of success is p=0.36.
We want to find the following probability:
[tex] P(0.34 <\hat p<0.49)[/tex]
And the distribution for the sample proportion is given by;
[tex]\hat p \sim N(p, \sqrt{\frac{p(1-p)}{n}})[/tex]
And we can find the mean and deviation for the sample proportion:
[tex]\mu_{\hat p}= 0.36[/tex]
[tex]\sigma_{\hat p} =\sqrt{\frac{0.36(1-0.36)}{195}}= 0.0344[/tex]
And we can use the z score formula given by:
[tex] z = \frac{0.34 -0.36}{0.0344}= -0.582[/tex]
[tex] z = \frac{0.49 -0.36}{0.0344}= 3.782[/tex]
And we can use the normal distribution table and we got:
[tex] P(-0.582 <z< 3.782) =P(z<3.782)-P(z<-0.582)=0.99992-0.2803= 0.71962[/tex]
which quadrilateral will always have four reflection symmetry
Step-by-step explanation:
a rectangle has reflectional symmetry when reflected over the line through the midpoints of its opposite sides
Answer: A square always has a four reflection symmetry no matter the size.
A field is in the shape of a rectangle 5/6 mile long and 3/4 mile wide. What is the area of the field? *
Area = length x width
Area = 5/6 x 3/4
= (5x3) / (6x4)
= 15/24
= 5/8 square miles
Find the distance between the pair of points: (9,−3) and (0,−10).
Answer:
√130 is the distance between (9,-3) (0,-10)
sorry it’s hard to see. please help!!!
last year we had 250 of employees and due to attrion we lost 12% we only have blank employees left ?
Answer:
220
Step-by-step explanation:
If we lost 12% we still have 100 - 12 = 88% of the employees left. 88% can be written as 0.88. 0.88 * 250 = 220 employees left.
If a graph of y=-9x+ 3 were changed to a graph of y=-9x + 1, how would the
y-intercept change?
Answer:
y-intercept decreased by 3-1= 2 points
Step-by-step explanation:
y=-9x+ 3 ⇒ y-intercept= 3
y=-9x + 1 ⇒ y-intercept= 1
y-intercept decreased by 3-1= 2 points = the line shifted down by 2 points
Answer:
Hello!
Answer: y-intercept decreased by 2 points because 3-1=2
I hope I was of help. If not, please let me know! Thanks!
Step-by-step explanation:
2. A manufacturer produces light bulbs at a Poisson rate of 300 per hour. The probability that a light bulb is defective is 0.012. During production, the light bulbs are tested, one by one, and the defective ones are put in a special can that holds up to a maximum of 50 light bulbs. On average, how long does it take until the can is lled
Answer:
On average it will take 13 hrs 53 minutes before the van is filled
Step-by-step explanation:
The first thing we need to do here is to find find the number of defective light bulbs
Using the poisson process, that would be;
λ * p
where λ is the poisson rate of production which is 300 per hour
and p is the probability that the produced bulb is defective = 0.012
So the number of defective bulbs produced within the hour = 0.012 * 300 = 3.6 light bulbs per hour
Now, let X be the time until 50 light bulbs are produced. Then X is a random variable with the parameter (r, λ) = (50, 3.6)
What we need to find however is E(X)
Thus, the expected value of a gamma random variable X with the parameter (x, λ) is;
E(X) = r/λ = 50/3.6 = 13.89
Thus the amount of time it will take before the Can will be filled is 13 hrs 53 minutes
What graph is the function y= -2 cos20
Answer:
Step-by-step explanation:
When the health department tested private wells in a county for two impurities commonly found in drinking water, it found that 10% of the wells had neither impurity, 90% had impurity A, and 20% had impurity B. (Obviously, some had both impurities.) If a well is randomly chosen from those in the county, find the probability distribution for Y, the number of impurities found in the well.
Answer:
P(Y= 0) = 0.1
P(Y= 0) = 0.7
P(Y= 0) = 0.2
Step-by-step explanation:
Let Y be number of impurities that can be found in the well,
Let A denote the event that impurity A is randomly found in the well
Here Y can have three values i.e 0 , 1 and 2
✓It will take take the value of 0 when there is no impurity found in the well
✓It will take the value of 1 when when exactly one impurity vis found in the well
✓It will take the value of 2 when when both impurities vis found in the well
CHECK THE ATTACHMENT FOR DETAILED EXPLATION
Which equation can be used to determine the distance between the origin and (–2, –4)? d = StartRoot ((0 minus 2) + (0 minus 4)) squared EndRoot d = StartRoot (0 minus (negative 2)) squared + (0 minus (negative 4)) squared EndRoot d = StartRoot ((0 minus 2) minus (0 minus 4)) squared EndRoot d = StartRoot (0 minus (negative 2)) squared minus (0 minus (negative 4)) squared EndRoot
Answer:person up top is right it’s B
Step-by-step explanation: on edg 2020
Answer:
The answer is B
Step-by-step explanation:
lol yw guys
In a video game an object represented by the point (2,7) is rotated counterclockwise 175 degrees around an origin. What are the new coordinates that represent the point?
Answer:
(-2.60, -6.80)
Step-by-step explanation:
The new coordinates can be found by multiplying by the rotation matrix:
[tex]\left[\begin{array}{c}x'&y'\end{array}\right]=\left[\begin{array}{cc}\cos{\theta}&-\sin{\theta}\\\sin{\theta}&\cos{\theta}\end{array}\right]\left[\begin{array}{c}x&y\end{array}\right][/tex]
That is, ...
x' = x·cos(175°) -y·sin(175°) = 2(-0.9962) -7(0.0872) = -2.60
y' = x·sin(175°) +y·cos(175°) = 2(0.0872) +7(-0.9962) = -6.80
The new coordinates are ...
(x', y') = (-2.60, -6.80)
A taxi company manager is trying to decide whether the use of radial tires instead of regular belted tires improves fuel economy. Twelve cars were equipped with radial tires and driven over a prescribed test course. Without changing drivers, the same cars were then equipped with regular belted tires and driven once again over the test course. The gasoline consumption, in kilometers per liter, was recorded as follows:
Car Radial-Tires Belted-Tires
1 4.2 4.1
2 4.7 4.9
3 6.6 6.2
4 7.0 6.9
5 6.7 6.8
6 4.5 4.4
7 5.7 5.7
8 6.0 5.8
9 7.4 6.9
10 4.9 4.7
11 6.1 6.0
12 5.2 4.9
A two-sample t-test was used to compare the mean kilometers per liter for the two types of tires using a .05 level of significance. The resulting p-value was .0152.
State the null and alternate hypotheses, state whether the null hypothesis should be rejected or not rejected and your reason for that conclusion, state the meaning of that conclusion specifically in terms of the problem being studied.
Answer:
Step-by-step explanation:
Corresponding gasoline consumption when radial tires is used and gasoline consumption when regular belted tires is used form matched pairs.
The data for the test are the differences between the gasoline consumption when radial tires is used and gasoline consumption when regular belted tires is used.
μd = the gasoline consumption when radial tires is used minus the gasoline consumption when regular belted tires is used.
For the null hypothesis
H0: μd ≥ 0
For the alternative hypothesis
H1: μd < 0
The resulting p-value was .0152.
Since alpha, 0.05 > than the p value, 0.0152, then we would reject the null hypothesis. Therefore, at 5% significance level, we can conclude that the gasoline consumption when regular belted tires is used is higher than the gasoline consumption when radial tires is used.
