-2√48 simplified is:
-8√3.
-4√3.
No solution.
None of these choices are correct.

The function that has a greater slope and greater y-intercept than the linear function represented in the table is,

⇒ y = 3x + 7.5

We have to given that;

The table below represents a linear equation.

Now, The equation of line is,

Take two points (- 1, 5) and (1, 9)

⇒ y - 5 = (9 - 5) / (1 + 1) (x + 1)

⇒ y - 5 = 4/2 (x + 1)

⇒ y - 5 = 2 (x+ 1)

⇒ y - 5 = 2x + 2

⇒ y = 2x + 7

Hence, By options,

The function that has a greater slope and greater y-intercept than the linear function represented in the table is,

⇒ y = 3x + 7.5

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Answer:

Set your calculator to degree mode.

cos(37°) = 52/x

x cos(37°) = 52

x = 52/cos(37°) = 65.1

The projection of (v + w) onto u is (-8 √(2)i + 6 √(2)j).

Now, let's consider the given vectors u = - i + j, v = 8i - 2j, and w = - 4j. The question asks us to find the projection of vector v + w onto the vector u, denoted as proj_u(v + w). To find this projection, we need to use the dot product between the two vectors.

First, we need to calculate v + w, which is (8i - 2j) + (-4j) = 8i - 6j. Next, we calculate the dot product of u and (v + w):

u · (v + w) = (-i + j) · (8i - 6j)

= -8i + 6j - 8i + 6j

= -16i + 12j

The dot product measures the similarity between two vectors, and in this case, it gives us the component of (v + w) that is parallel to u. To find the projection of (v + w) onto u, we need to divide this component by the magnitude of u:

proj_u(v + w) = (u · (v + w)) / ||u||

= (-16i + 12j) / √(2)

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Answer:

can i get a picture\

Step-by-step explanation:

thanks

Answer:

Step-by-step explanation:

1:4

The factor of 2xy + 30x^2 - xy - 16y^4 - yx - 5x^2 is 25x2−16y4=(5x+4y2)(5x−4y2)

We are given that;

2xy + 30x^2 - xy - 16y^4 - yx - 5x^2

Now,

Combine like terms by adding or subtracting the coefficients of the same variables. For example, 2xy - xy - yx = 0xy, and 30x^2 - 5x^2 = 25x^2. The polynomial becomes:

25x2−16y4

Check if there is a common factor for all the terms. In this case, there is no common factor other than 1, so we cannot use the greatest common factor method.

Check if the polynomial is a difference of two squares, which means it has the form a2−b2. In this case, we can see that both terms are perfect squares: 25x2=(5x)2 and 16y4=(4y2)2. Therefore, we can use the difference of two squares formula:

a2−b2=(a+b)(a−b)

Substituting a=5x and b=4y2, we get:

25x2−16y4=(5x+4y2)(5x−4y2)

Check if each factor can be further factored using any of the methods. In this case, neither factor can be further factored, so we are done.

Therefore, by factorization the answer will be 25x2−16y4=(5x+4y2)(5x−4y2)

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The function limit of f(x) as x approaches 2 is 67 and the limit of f²(x) as x approaches 2 is 4489.

The function f(x) can be rewritten as:

f(x) = (5x³ + 3x² - x)/(x+2)

Using direct substitution, we see that f(2) is undefined, as the denominator of the function becomes 0.

To evaluate the limit, we can use L'Hopital's rule:

[tex]\lim_{x \to 2\[/tex] f(x) = lim x→2 (5x³ + 3x² - x)/(x+2)

= [tex]\lim_{x \to 2\[/tex] (15x² + 6x - 1)/(1)

= (15(2)² + 6(2) - 1)/(1)

= 67

To find the limit of f²(x) as x approaches 2, we can simply square the limit:

f(x) = [tex]\lim_{x \to 2\}[/tex]f²(x)

= [tex]\lim_{x \to 2[/tex] f²(x)  

= 67²

= 4489

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Answer: 116.985 mm2

Step-by-step explanation:

Answer:

No solution.

Step-by-step explanation:

To solve this problem, all you have to do is graph the lines and see where they intersect.

This is what you would do to solve a normal problem. However, these lines are parallel this means that the solution to these lines is no soultion

i. The sample mean and median for the data for the two companies are 8.1 and 8.25 respectively.

ii. The line graph of the data is illustrated below.

iii. Yes, The steel rods supplied by Company B may be more flexible than those supplied by Company A.

iv. If you are looking for steel rods with higher flexibility, I would recommend Company B based on the higher median, the apparent differences in the box and whisker plot, and the confidence interval indicating a higher mean flexibility for their rods.

For Company A, the sample mean can be calculated by adding all the values and dividing by the number of values:

Mean of Company A = (9.3 + 8.8 + 6.8 + 8.7 + 8.5 + 6.7 + 8.0 + 6.5 + 9.2 + 7.0) / 10 = 8.1

To find the median, we first need to arrange the data in ascending order:

6.5, 6.7, 6.8, 7.0, 8.0, 8.5, 8.7, 8.8, 9.2, 9.3

Since there are an even number of values, the median is the average of the two middle values:

Median of Company A = (8.0 + 8.5) / 2 = 8.25

For Company B, the sample mean can be calculated similarly:

Mean of Company B = (11.0 + 9.8 + 9.9 + 10.2 + 10.1 + 9.7 + 11.0 + 11.1 + 10.2 + 9.6) / 10 = 10.2

Arranging the data in ascending order, we get:

9.6, 9.7, 9.8, 9.9, 10.1, 10.2, 10.2, 10.2, 11.0, 11.1

Since there are an odd number of values, the median is the middle value:

Median of Company B = 10.2

Next, let's plot the data for both companies on the same chart and observe any apparent differences. We can use a box and whisker plot to do this.

Looking at the box and whisker plot, we can see that the median of Company B (represented by the line in the middle of the box) is higher than the median of Company A. Additionally, the box for Company B is taller than the box for Company A, indicating that the range of values for Company B is greater than that of Company A. These observations suggest that the steel rods supplied by Company B may be more flexible than those supplied by Company A.

To determine if there is a significant difference between the means of the two companies, we can use a 90% confidence interval of the mean. This interval gives us a range within which we can be 90% confident that the true population mean lies.

Using a t-distribution with 18 degrees of freedom (10 + 10 - 2), we can find the 90% confidence interval for the difference between the means of the two companies. The formula for the confidence interval is:

Difference in means ± (t-value x standard error of difference in means)

The t-value for a 90% confidence interval with 18 degrees of freedom is approximately 1.734.

Now, we can calculate the margin of error by multiplying the t-value (1.734) by the standard error:

Margin of Error = 1.734 * 0.393 ≈ 0.682

Finally, we can construct the 90% confidence interval for the difference in means as:

Difference in means ± Margin of Error

Calculating the difference in means (mean of Company B - mean of Company A), we have:

Difference in means = 10.2 - 8.1 = 2.1

Therefore, the 90% confidence interval is:

2.1 ± 0.682

This means that we can be 90% confident that the true population mean difference between the two companies' steel rods lies between 1.418 and 2.782.

Based on this analysis, we can conclude that Company B tends to supply steel rods that are more flexible compared to Company A. However, it's important to note that this study was conducted on a small sample size, so further investigation with larger sample sizes would be beneficial to confirm the findings.

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Answer:$578.81

Step-by-step explanation:

✨magic✨

Answer:

128 servings

Step-by-step explanation:

It takes 1 1/4 cups to make 10 servings

1 1/4 as a mixed fraction = 5/4  

So 5/4 cups makes 10 servings

1 cup makes 10 ÷ 5/4

Use the fraction rule for division
a/b ÷ c/d = a/b x c/d

10 ÷ 5/4 = 10 x 4/5 = 8 servings from 1 cup

1 gallon = 16 cups

At 8 servings per cup, total number of servings for 16 cups
= 8 x 16 = 128 servings ANSWER

Answer: We can use Bayes' theorem to find the probability that a randomly chosen applicant has a graduate degree, given that they are male. Bayes' theorem states:

P(A|B) = P(B|A) * P(A) / P(B)

where A and B are events, P(A|B) is the conditional probability of event A given that event B has occurred, P(B|A) is the conditional probability of event B given that event A has occurred, P(A) is the prior probability of event A, and P(B) is the prior probability of event B.

In this case, we want to find P(grad degree | male), which is the probability that an applicant has a graduate degree given that they are male. Using Bayes' theorem, we have:

P(grad degree | male) = P(male | grad degree) * P(grad degree) / P(male)

We are given that 134 applicants are male, and 40 of those males have a graduate degree. Therefore:

P(male | grad degree) = 40 / total number of applicants with a graduate degree

We are not given the total number of applicants with a graduate degree, but we can find it using the fact that 40 applicants are male and have a graduate degree, and that there are 134 male applicants in total. Therefore:

total number of applicants with a graduate degree = 40 / (40/134) = 118.33 (rounded to the nearest whole number)

Next, we need to find the prior probability of having a graduate degree, P(grad degree). We can use the total number of applicants and the number of applicants with a graduate degree to calculate this probability:

P(grad degree) = number of applicants with a graduate degree / total number of applicants = 118 / 300 = 0.3933 (rounded to four decimal places)

Finally, we need to find the prior probability of being male, P(male). This probability can be calculated similarly:

P(male) = number of male applicants / total number of applicants = 134 / 300 = 0.4467 (rounded to four decimal places)

Now, we can substitute these values into Bayes' theorem to find the probability that a randomly chosen applicant has a graduate degree, given that they are male:

P(grad degree | male) = (40 / 118) * 0.3933 / 0.4467 = 0.332 (rounded to three decimal places)

Therefore, the probability that a randomly chosen applicant has a graduate degree, given that they are male, is approximately 0.332 or 33.2%.

Step-by-step explanation:

Answer: [tex]\frac{2}{5}[/tex] x [tex]\frac{4}{5}[/tex] = [tex]\frac{8}{25}[/tex]

Step-by-step explanation:

We can do this by counting the boxes for both the Width and the Length.

If we look at the width of these boxes (horizontally) then we see that there are 5 boxes all together, with 2 shaded green.

this means that 2 out of 5 of the boxes are shaded for the width, giving us the fraction: [tex]\frac{2}{5}[/tex]

Then for the Length (vertically) we see that there are also 5 boxes, but this time 4 are shaded. This gives us the fraction:  [tex]\frac{4}{5}[/tex].

Then, to fill the equation in, we do: [tex]\frac{2}{5}[/tex] x [tex]\frac{4}{5}[/tex] , which gives us          [tex]\frac{8}{25}[/tex]

2 x 4 = 8

5 x 5 = 25

To double check this answer, we can count how many boxes are shaded green.

We see that 8 are shaded green, out of the 25 boxes that are there.

Therefore, giving us a complete answer of:  [tex]\frac{2}{5}[/tex] x [tex]\frac{4}{5}[/tex] = [tex]\frac{8}{25}[/tex]

Answer:

Would buy Would not

again buy again Total

Aalora 77 16 93

Mederac 48 23 71

Total 125 39 164

71/164 = 43.3% of the customers purchased Mederac.

So the group that accounts for about 43% of the respondents is the percentage of the customers who purchased Mederac.

695 divided by 70=9.92 hours

[tex]x=\textit{gallons of solution at 10\%}\\\\ ~~~~~~ 10\%~of~x\implies \cfrac{10}{100}(x)\implies 0.10 (x) \\\\\\ y=\textit{gallons of solution at 60\%}\\\\ ~~~~~~ 60\%~of~y\implies \cfrac{60}{100}(y)\implies 0.6 (y) \\\\\\ \textit{150 gallons of solution at 50\%}\\\\ ~~~~~~ 50\%~of~150\implies \cfrac{50}{100}(150)\implies 75 \\\\[-0.35em] ~\dotfill[/tex]

[tex]\begin{array}{lcccl} &\stackrel{gallons}{quantity}&\stackrel{\textit{\% of gallons that is}}{\textit{fertilizer only}}&\stackrel{\textit{gallons of}}{\textit{fertilizer only}}\\ \cline{2-4}&\\ \textit{Sol'n of 10\%}&x&0.10&0.10x\\ \textit{Sol'n of 60\%}&y&0.60&0.60y\\ \cline{2-4}&\\ mixture&150&0.5&75 \end{array} \\\\\\ \begin{cases} x + y = 150\\\\ 0.10x+0.60y=75 \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{using the 1st equation}}{x+y=150}\implies y=150-x \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the 2nd equation}}{0.10x+0.60y=75}\implies \stackrel{\textit{substituting on the 2nd equation from above}}{0.10x+0.60(150-x)=75} \\\\\\ 0.10x+90-0.60x=75\implies 90-0.50x=75\implies 90=0.50x+75 \\\\\\ 15=0.50x\implies \cfrac{15}{0.50}=x\implies \boxed{30=x}\hspace{5em}\stackrel{ 150~~ - ~~30 }{\boxed{y=120}}[/tex]

The equation of the circle in this problem is given as follows:

x² + y² = 90000

The equation of a circle of center [tex](x_0, y_0)[/tex] and radius r is given by:

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

The radius of a circle represents the distance between the center of the circle and a point on the circumference of the circle, while the diameter of the circle is the distance between two points on the circumference of the circle that pass through the center. Hence, the diameter’s length is twice the radius length.

The center for this problem is given as follows:

(0,0).

The radius is given as follows:

300 ft.

Hence the equation is of:

x² + y² = 90000

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If  u = - 3i + 2i,  v = 2i - 2j and w = - 4j, 5u(3v - 4w) is a scalar quantity with a value of 440.

To evaluate the expression 5u(3v - 4w), we need to first perform the scalar multiplication and then the vector subtraction. We can start by computing the scalar multiplication of 3v - 4w:

3v - 4w = 3(2i - 2j) - 4(-4j) = 6i + 14j

Next, we can perform the scalar multiplication of u and the vector 6i + 14j:

5u(3v - 4w) = 5(-3i + 2j)(6i + 14j)

Expanding the product, we get:

5(-18i² + 36ij + 42ij - 28j²)

Since i² = j² = -1, we can simplify this expression as:

5(18 + 70) = 440

Therefore, 5u(3v - 4w) is a scalar quantity with a value of 440.

The key concept used in this problem is the distributive property of scalar multiplication over vector addition and subtraction. This property allows us to simplify expressions that involve scalar multiplication and vector operations by distributing the scalar to each component of the vector.

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Answer:A

Step-by-step explanation:

Answer:

10. 120 Degrees 12. 60 Degrees

Step-by-step explanation:

#12. Since CAD is 30, and BAD is a 90 degree angle, angle BAF is 60 degrees. Since BAF is 60 degrees and FAE and BAF are vertical angles, they have the same angle measure. 60 Degrees.

#10. Since BAF is 60, and FAE and BAF are on a line, we can do 180-60 to get the measure in degrees of that angle. FAE = 120 Degrees.

Answer:

Step-by-step explanation:

10. somewhere between 126 and 129, i feel its 128

12. between 60 and 65

Answer:   is d

Step-by-step explanation:

well it is just     3 times 3 times 3 times 3

The matrix after the row operation is given as follows:

[tex]\left[\begin{array}{ccc}1&-\frac{4}{7}&\frac{8}{7}\\-12&7&-13\end{array}\right][/tex]

The row operation is given as follows:

Division by 7 = multiplication by 1/7, as the element at the desired position is of 7.

The matrix in the context of this problem is defined as follows:

[tex]\left[\begin{array}{ccc}7&-4&8\\-12&7&-13\end{array}\right][/tex]

We want to have element 1 into row 1 and column 1, that is, the element of 7 at row 1 and column 1 of the matrix must assume a value of -1.

An example of a valid row operation is the multiplication of the row by a constant, and as the element has a value of 7, the constant to obtain a value of 1 is:

7/k = 1

k = 7.

Dividing every element of the first row by 7, the resulting matrix is then given as follows:

[tex]\left[\begin{array}{ccc}1&-\frac{4}{7}&\frac{8}{7}\\-12&7&-13\end{array}\right][/tex]

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The TRUE statement about Alexander's deposit of $3,200 into a savings account that has a simple interest rate of 1% calculated quarterly is a. He will earn $8 in interest each quarter, totaling $32 in interest for the year.

Simple interest describes an interest system that does not compound the interest.

Compounding involves charging interest on both interest and principal.

For the simple interest system, the interest amount is computed only on the principal, using the following SI formula.

Principal deposit, P = $3,200

Interest rate, R = 1%

Interest period, P = 1 year

Interest system = Simple interest quarterly

Simple interest (SI) formula = P x R x T

Simple interest for each quarter = $8 ($3,200 x 0.01 x 1/4)

Simple interest for the year = $32 ($3,200 x 0.01)

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Answer:

Distance that car B travels =1.2× distance that car A travels

=1.2×221.5=265.8 km

Answer:

car B travels a distance of 265.8 km during the same time.

Step-by-step explanation:

Car A travels 221.5 km at a given time.

To find the distance traveled by car B, which is 1.2 times the distance traveled by car A, we can multiply the distance of car A by 1.2:

Distance of Car B = 1.2 * Distance of Car A

Distance of Car B = 1.2 * 221.5 km

Distance of Car B = 265.8 km

Therefore, car B travels a distance of 265.8 km during the same time.

Answer:

70 , 18

Step-by-step explanation:

Keeping x as Father and y as son;

5 years ago Person X was 5 times older than Person y , so the equation will be:

x - 5= 5(y-5)

x = 5y - 20

simularily after 8 years , x will be 3 times older than y , so

x + 8 = 3(y + 8.)

I will now try to find y by equating value of x into y:

5y - 20 + 8 = 3y + 24

5y - 3y = 24 + 20 - 8

2y = 44 - 8 = 36

y = 18

so x will be =  5 (18) - 20.

x = 90-20 = 70 years.

therefore father is 70 years , and son is 18 years old.

Answer:

8+(3)-9=8+3-9=11-9=2

Step-by-step explanation:

by using PEMDAS rule

Start with :

P : Paranthesis

E: exponents

M: Multiplication

D : division

A: Addition

S:Subtraction