Answer:
35%
(I replaced the 1st digit by a and the second digit by b)
Answer please!!! Will be very thankful
The estimate of the cost for a 20-ft cord is given as follows:
$74.66.
How to find the equation of linear regression?To find the regression equation, which is also called called line of best fit or least squares regression equation, we need to insert the points (x,y) in the calculator.
The points in the context of the problem are given as follows:
(3, 12.75), (5, 16), (6, 25.99), (50, 185).
Inserting these points into a calculator, the regression equation is given as follows:
y = 3.6794x + 1.06462.
Hence the estimate of the cost for a 20-ft cord is given as follows:
y = 3.6794(20) + 1.06462
y = $74.66.
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In the given Venn-diagram, if n(AUB) = 50, find n (A).
n°(A) = 2a
n°(B)=a
n(A[intersection]B)=20
Answer:
n(A U B) = n(A) + n(B) – n(A ∩ B)
putting values we get
50 = 2a + a - 20
solving eqn.
70 = 3a
a = 70 / 3
now n(a) = 2a
= 2 x 70/3
= 140/3
hence, n(a) = 140/3
Emilio puts $4,000.00 into an account to use for school expenses. The account earns 15% interest, compounded annually. How much will be in the account after 6 years?
Round your answer to the nearest cent.
Answer:
$10,359.73.
Step-by-step explanation:
We can use the formula for compound interest:
A = P(1 + r/n)^(nt)
where:
A = the amount of money after the specified time
P = the principal amount (the initial amount of money)
r = the annual interest rate (as a decimal)
n = the number of times the interest is compounded per year
t = the time (in years)
In this case, we have:
P = $4,000.00
r = 15% = 0.15
n = 1 (compounded annually)
t = 6 years
Substituting into the formula, we get:
A = 4000(1 + 0.15/1)^(1*6)
A = 4000(1.15)^6
A ≈ $10,359.73
Therefore, the amount in the account after 6 years, rounded to the nearest cent, is $10,359.73.
Recommend what grade 12s could do to minimise the impact of the anxiety they may feel on the day of the examination. In your answers, also indicate how that could enhance their performance in the examination.
Answer:
Experiencing anxiety on the day of the examination is a common problem for many students, especially those in grade 12 who may feel a lot of pressure to perform well. However, there are several strategies that they can use to minimize the impact of anxiety and enhance their performance in the examination. Some of these strategies include:
1. Get enough sleep: Getting enough sleep is essential for students to perform well on the day of the examination. Students should aim to get at least 7-8 hours of sleep before the exam day. A well-rested brain will be able to function better, and students will be less likely to feel anxious or stressed.
2. Eat a balanced breakfast: Eating a balanced breakfast on the day of the examination can help students feel more alert and focused. A healthy breakfast can also provide the necessary energy needed to get through the examination.
3. Plan your day: Plan your day well ahead of the examination. This will help you feel more in control and reduce feelings of anxiety. Set aside time to review notes, relax and mentally prepare for the exam.
4. Practice relaxation techniques: Practice relaxation techniques such as deep breathing or progressive muscle relaxation to help calm your nerves. These techniques can help students reduce stress levels and anxiety, which in turn can enhance their performance.
5. Avoid last-minute cramming: Cramming at the last minute can increase feelings of anxiety and negatively impact performance. Instead, spend time reviewing notes and practicing past papers in the days leading up to the examination.
6. Stay positive: It is essential to stay positive and avoid negative thoughts or self-doubt. Remind yourself of your hard work and preparation for the exam. Believe in your abilities, and focus on what you can do rather than what you cannot.
By implementing these strategies, grade 12 students can minimize the impact of anxiety on the day of the examination, and enhance their overall performance. Remember that exam performance is not just about what you know, but also about how you manage your anxiety and stress levels.
Work out the area of this circle.
Take to be 3.142 and write down all the digits given by your calculator.
13 cm
Answer:132.7495cm^2
Step-by-step explanation:
The formula for the area of a circle is πr^2.
We then substitute into this formula using 3.142 as π.
This leaves us with 3.142x6.5(radius is half of diameter)^2
When you type it into your calculator it should give you
132.7495cm^2
Shane has 2 white shirts, 2 blue ones and 1 red one, He has gray pants and black pants. He hung them all up on hangers in his closet, but one shirt and a pair of pants fell on the floor. The probability that a red shirt and black slacks are on the floor is
The probability that a red shirt and black slacks are on the floor is 1/10.
What is the probability?Probability is the odds that a random event would happen. The odds that the event would happen has a probability value that lies between 0 and 1.
Probability that a red shirt and black slacks are on the floor = (number of red shirts / total number of shirts) x (number of black slacks / total number of slacks)
Total number of shirts = 2 + 2 + 1 = 5
Total number of slacks = 1 + 1 = 2
(1/5) x (1/2) = 1 /1 0
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En un grupo de 60 alumnos, 12 sacaron 10 en el examen de matemáticas. ¿Cuál es el porcentaje de alumnos que sacaron 10?
We can see that the percentage is 20%, then 20 percent of the students got a 10.
Which percentage of the students got a 10?To find this, we need to use the formula:
Percentage = 100%(number of students with a 10)/(total number of students)
Here we know the that the revelant numbers are:
Number of students with a 10 = 12
total number of students in the class = 60
Replacing that in the formula we will get the percentage:
P = 100%*(12/60)
P = 20%
So 20% of the total number of students got a 10.
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natalie has $330mto send at the amusment park of this total amount 5% is soent on games, 5/11 is for food and drinks, and she spends $13 on parking. the rest of her budget is spent on buying a ticket for herself and a friend. what is the price of one ticket
Answer:
Step-by-step explanation:
This is a word problem involving percentages. To solve it, we need to follow these steps:
Identify the given information and the unknown quantity. In this problem, we are given that Natalie has $330 to spend at the amusement park, 5% is spent on games, 5/11 is for food and drinks, and she spends $13 on parking. The unknown quantity is the price of one ticket.
Write an equation that relates the given information and the unknown quantity. We can use the fact that the sum of all parts of the whole is 100%1. Let x be the price of one ticket. Then we have:
games+food and drinks+parking+tickets0.05×330+115×330+13+2x=total amount=330
Solve the equation for the unknown quantity. We can simplify and rearrange the equation to get:
16.5+150+13+2x2x2xxx=330=330−16.5−150−13=150.5=2150.5=75.25
Therefore, the price of one ticket is $75.25.
The scatter plot shows the number of households, in millions, that have cable television over eight consecutive years.
Scatter plot with x axis labeled Time in Years and y axis labeled Number of Households with points at 1 comma 3 and 8 tenths, 2 comma 5 and 8 tenths, 3 comma 6 and 2 tenths, 4 comma 7 and 5 tenths, 5 comma 7 and 2 tenths, 6 comma 8 and 3 tenths, 7 comma 9 and 3 tenths, and 8 comma 8 and 5 tenths.
A) y = −2.78x + 33.6
B) y = −2.78x + 48.5
C) y = 2.78x + 33.6
D)y = 2.78x + 48.5
The equaltion for the line of best fit would be,
y = 0.67x + 4.05
The points on the scatter plot are: (1, 3.8), (2, 5.8), (3, 6.2) , (4, 7.5) , (5, 7.2), (6, 8.3), (7, 9.3), and (8, 8.5 )
First we find the mean of the x-values and mean of the y-values.
The mean of the x-values would be,
[tex]\bar{X}[/tex] = (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8) / 8
[tex]\bar{X}[/tex] = 4.5
and the mean of the y-values would be,
[tex]\bar{Y}[/tex] = (3.8 + 5.8 + 6.2 + 7.5 + 7.2 + 8.3 + 9.3 + 8.5) / 8
[tex]\bar{Y}[/tex] = 7.075
The sum of squares (SSX) = 42
And the sum of products (SP) = 28.2
Regression Equation would be,
y = mx + c
m = SP/SSX
= 28.2/42
= 0.67143
And the y-intercept would be,
c = 4.05357
So, the equation for the line of best fit would be,
y = 0.67143x + 4.05357
Number of Households = 0.67143 (time) + 4.05357
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Find the complete question below.
The scatter plot shows the number of households, in millions, that have cable television over eight consecutive years.
Scatter plot with x axis labeled Time in Years and y axis labeled Number of Households with points at 1 comma 3 and 8 tenths, 2 comma 5 and 8 tenths, 3 comma 6 and 2 tenths, 4 comma 7 and 5 tenths, 5 comma 7 and 2 tenths, 6 comma 8 and 3 tenths, 7 comma 9 and 3 tenths, and 8 comma 8 and 5 tenths.
what is the graphed line of the equation 2x + 3y = -6
The graphed line of the equation is attached 2x + 3y = -6
What is linear equation?A linear equation is an expression that consists of a single power of the variable(s) in which it contains. This formulation can be impeccably illustrated in the following way:
ax + b = 0
The given equation 2x + 3y = -6 can be rearranged to get
y = -2/3x - 2
The x variables is plugged in to solve for y and used for the table of values for the graph
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50 Points! Solve each equation or inequality. Only looking for an answer to B. Photo attached. Please show as much work as possible. Thank you!
The equation 5ʷ ⁺ ³ = 17 when solved for w is approximately w = 0.41 and the solution to the inequality is b ≤ 1.87
Solving the equations or inequalities for wFrom the question, we have the following parameters that can be used in our computation:
5ʷ ⁺ ³ = 17
Take the logarithm of both sides
So, we have
w + 3 = ln(17)/ln(3)
Evaluate the quotient
This gives
w + 3 = 2.59
So, we have
-3 + w + 3 = 2.59 - 3
Evaluate
w = 0.41
For the second expression, we have
2ᵇ ⁺ ¹ ≤ 7.31
Take the logarithm of both sides
So, we have
b ≤ ln(7.31)/ln(2) - 1
So, we have
b ≤ 1.87
Hence, the equation when solved for w is approximately w = 0.41
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Suppose that the functions and are defined as follows.
1) (f - g) (x) = f(x) - g(x) = x ≤ 1/4
Domain of the function is : [1/4, infinity)
2) → [tex]\frac{f}{g}(x) =\frac{f(x)}{g(x)} = \frac{-x+4}{\sqrt{4x-1} }[/tex]
Domain of the function : (1/4, infinity)
We have the function are as follows:
f(x) = -x + 4
g(x) = [tex]\sqrt{4x+1}[/tex]
To find the f - g and f/g and also their domains using interval notation.
Now, (f - g) (x) = f(x) - g(x)
= [tex]-x+4-\sqrt{4x+1}[/tex]
= 4x + 1 ≤ 0
= x ≤ 1/4
Domain of the function is : [1/4, infinity)
→ [tex]\frac{f}{g}(x) =\frac{f(x)}{g(x)} = \frac{-x+4}{\sqrt{4x-1} }[/tex]
=> 4x - 1 > 0
=> x > 1/4
Domain of the function : (1/4, infinity)
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consider the time taken to completion time (in months) for the construction of a particular model of homes: 4.1 3.2 2.8 2.6 3.7 3.1 9.4 2.5 3.5 3.8 Find the mean, median mode, first quartile and third quartile. Find the outlier?
Sum
Mean = (4.1 + 3.2 + 2.8 + 2.6 + 3.7 + 3.1 + 9.4 + 2.5 + 3.5 + 3.8) / 10
Mean = 36.7 / 10
Mean = 3.67
To find the median, we need to put the values in order:
2.5, 2.6, 2.8, 3.1, 3.2, 3.5, 3.7, 3.8, 4.1, 9.4
The middle number is the median, which is 3.35 in this case (3.2+3.5)/2.
To find the mode, we look for the value that appears most often. In this case, there is no mode as no value appears more than once.
To find the first quartile (Q1), we need to find the value that separates the bottom 25% of the data from the top 75%. We can do this by finding the median of the lower half of the data:
2.5, 2.6, 2.8, 3.1, 3.2
The median of this lower half is 2.8, so Q1 = 2.8.
To find the third quartile (Q3), we need to find the value that separates the bottom 75% of the data from the top 25%. We can do this by finding the median of the upper half of the data:
3.7, 3.8, 4.1, 9.4
The median of this upper half is 3.95, so Q3 = 3.95.
To find the outlier, we can use the rule that any value more than 1.5 times the interquartile range (IQR) away from the nearest quartile is considered an outlier. The IQR is the difference between Q3 and Q1:
IQR = Q3 - Q1
IQR = 3.95 - 2.8
IQR = 1.15
1.5 times the IQR is 1.5 * 1.15 = 1.725.
The only value that is more than 1.725 away from either Q1 or Q3 is 9.4. Therefore, 9.4 is the outlier in this data set.
Answer:
Step-by-step explanation:
Mean is the average of the data vales : 38.7 (sum of all values) divided by 10 (the number of values). Mean = 38.7/10 = 3.87
Median is the "middle" number" = put the date in order and find the middle value:
2.5, 2.6, 2.8, 3.1, 3.2, 3.5, 3.7, 3.8, 4.1, 9.4, since there is no middle data value, find the average of the 2 in the middle.
3.2 + 3.5/2 = 6.7 ÷ 2 = 3.35 - median
All values appear once so there is no mode.
First quartile is the middle of the lower set of data = 2.8
Third quartile is the middle of the upper set = 3.8
The outlier is 9.4.
How to calculate the outlier:
First you need the IQR which is the diffence of Q3 - Q1,
so the IQR is 3.8- 2.8 = 1
Outliers are the quartile + or - (1.5)(IQR)
Q1 -(1.5)(1) = 2.8 - 1.5 = 1.3
Q3 - (1.5)(1)= 3.8 + 1.5 =4.5
So anything below 1.3 or above 4.5 is an outlier.
There is one 9.4
Help with math problems
Step-by-step explanation:
Please it would be very helpful and useful if you try to use a calculator. Good luck.
Among the products of a company, brand A has 40% of the market share. A market research firm finds that if a person uses brand A, the probability that he/she will be using it again next year is 30%. On the other hand if a person is not using the product at present, the probability that he/she will be using it next year is 60%. Required: a) Find the transition matrix. b) Find the percentage of the market share that brand A gets after two years. c) Want percentage of the market share will be handled by brand A on the long run, if the transition matrix does not change?
a) The transition matrix is [tex]\left[\begin{array}{ccc} 0.3&0.7 \\ 0.6&0.4\end{array}\right][/tex]
b) After two years, brand A is expected to have 40.4% of the market share.
c) Brand A is expected to have 37.5% of the market share.
a) The transition matrix can be constructed using the probabilities provided in the problem. Let P be the matrix where the (i, j)-th entry represents the probability of transitioning from state i to state j. In this case, there are two states: using brand A (state 1) and not using brand A (state 2).
Using the information given in the problem, we can fill in the entries of the matrix as follows:
P = [tex]\left[\begin{array}{ccc} 0.3&0.7 \\ 0.6&0.4\end{array}\right][/tex]
b) To find the percentage of the market share that brand A gets after two years, we need to multiply the initial market share vector (40% for brand A and 60% for other brands) by the transition matrix twice:
| 0.4 0.6 | × P × P = | 0.404 0.596 |
Therefore, after two years, brand A is expected to have 40.4% of the market share.
c) To find the long-run market share for brand A, we need to find the steady-state vector of the transition matrix P. This is the vector π such that:
πP = π
and
π ₁+ π₂ = 1
where π₁ is the long-run probability of being in state 1 (using brand A) and π₂ is the long-run probability of being in state 2 (not using brand A).
Solving the equations above, we get:
π = | 0.375 0.625 |
This means that in the long run, brand A is expected to have 37.5% of the market share.
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An equilateral triangle is shown inside a square inside a regular pentagon inside a regular hexagon. Write an expression for the exact area of each shaded region in the figure. Then find the approximate area of the entire shaded region, rounded to the nearest whole unit.
An expression for the exact area of each shaded region in the figure include the following:
Shaded area = area of the regular hexagon - area of the regular pentagon + area of the square - area of the equilateral triangle.
How to calculate the area of a regular polygon?In Mathematics and Geometry, the area of a regular polygon can be calculated by using the following formula:
Area of a regular polygon = (n × s × a)/2
Where:
n is the number of sides.s is the side length.a is the apothem.Based on the diagram (see attachment), the area of the first shaded region is given by;
Area of first shaded region = Area regular hexagon - Area regular pentagon
For the area of the second shaded region, we have;
Area of second shaded region = Area of a square - Area of the equilateral triangle
Therefore, the total area of all of the shaded regions is given by;
Total shaded area = {area of the regular hexagon - area of the regular pentagon} + area of the square - {area of the equilateral triangle}.
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solve for x, neg x over 4 = 12
Two cars are traveling in the same direction. The first car is going 45 mi/h and the second car is going 60 mi/h. The first car left 2 hours before the second car. How many hours will it take for the second car to travel the same distance as the first car
The time taken for the second car to travel the same distance as the first car is 6 hours.
What is the time of motion of the second car?
The time taken for the second car to travel the same distance as the first car is calculated as follows;
let the time taken for the second car to travel the same distance = t
distance traveled by second car = 60t
the time taken for the first car = t + 2
distance traveled by the first car = 45(t + 2)
Since both distance are equal, we will have the following equations;
60t = 45 (t + 2)
60t = 45t + 90
15t = 90
t = 90/15
t = 6
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what is 5w–4w–w+6w simplified
The value of the expression 5w–4w–w+6w is 6w
What is simplification of expression?When you simplify an expression, you're basically trying to write it in the simplest way possible. At the end, there shouldn't be any more adding, subtracting, multiplying, or dividing left to do.
For example, 2( 3a+5) can be simplified by using 2 to multiply both 3a and 5. This will give 6a+10. This means that the simplification of 2(3a+5) = 6a+10.
Similar , 5w-4w-w+6w can be simplified into:
5w+6w-4w-w
= 11w-5w
= 6w.
Therefore,the value of the expression 5w–4w–w+6w is 6w
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The sum of matrix A and B where B is the identity matrix with respect to addition will give the matrix.
Select one:
Matrix A
Matrix 0
Matrix B
Matrix AB
The sum of any matrix with the identity matrix of the same size, with respect to addition, will give the matrix itself. Therefore, the sum of matrix A and B, where B is the identity matrix, will give the matrix A.
So the answer is: Matrix A.Suppose that the functions and are defined as follows.
The value of the function f/g is (x - 1) / (x + 8)
Let's start by writing out the functions we are given:
f(x) = 4 / (x + 8)
g(x) = x / (x - 1)
To find f/g, we need to divide f(x) by g(x). We can do this by multiplying f(x) by the reciprocal of g(x), which is (x - 1) / x. Multiplying f(x) by this reciprocal gives us:
f(x) * (x - 1) / x = 4 / (x + 8) * (x - 1) / x
To simplify this expression, we can first find a common denominator for the two fractions on the right-hand side:
4 / (x + 8) * (x - 1) / x = 4(x - 1) / x(x + 8)
Now we can simplify this expression by canceling out any common factors in the numerator and denominator. In this case, we can cancel out a factor of 4 and a factor of (x - 1):
4(x - 1) / x(x + 8) = (x - 1) / (x + 8)
Therefore, the quotient of f(x) and g(x), or f/g, is:
f/g = (x - 1) / (x + 8)
We can interpret this expression as a new function, h(x), where h(x) = f(x) / g(x) = (x - 1) / (x + 8). This new function takes a value of x and returns the ratio of f(x) to g(x) at that value.
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Help please
Expand the logarithm as much as possible
In(9/x)
The logarithm expression In(9/x) can be expanded as In(9) - In(x)
Expanding the logarithm as much as possibleFrom the question, we have the following parameters that can be used in our computation:
In(9/x)
Using the logarithmic identity log a/b = log a - log b, we can expand ln(9/x) as follows:
ln(9/x) = ln(9) - ln(x)
Therefore, ln(9/x) can be expressed as the difference of two natural logarithms: ln(9) and ln(x).
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Consider the bridge shown. Use the figure and the fact that AGC is congruent to EGC to complete parts (a) through (e). Round each answer to the nearest tenth
Therefore, the width of the bridge is approximately 5.9 feet. Therefore, the height of the bridge is approximately 8.4 feet. Therefore, the length of CH is approximately 36.9 feet. Therefore, the measure of angle BHC is approximately 189 degrees. Therefore, the answer to part (e) is no.
What is triangle?A triangle is a closed, two-dimensional shape with three straight sides and three angles. It is one of the basic shapes in geometry, and is formed by connecting three non-collinear points. The sum of the interior angles of a triangle is always 180 degrees, and there are several types of triangles including equilateral, isosceles, and scalene.
Here,
To solve this problem, we will use the fact that AAGC is congruent to AEGC. This means that angle ACG is equal to angle AEC, and angle AGC is equal to angle AEG.
(a) To determine the width AE of the bridge, we can use the tangent function. We have:
tan(27°) = AE/12
Solving for AE, we get:
AE = 12 tan(27°) ≈ 5.9 ft
(b) To determine the height CG of the bridge, we can use the same approach. We have:
tan(36°) = CG/12
Solving for CG, we get:
CG = 12 tan(36°) ≈ 8.4 ft
(c) To determine the length of CH, we can use the Pythagorean theorem. We have:
CH² = CG² + GH²
Substituting the values we found earlier, we get:
CH² = (8.4 ft)² + (40 ft - 5.9 ft)²
CH² = 70.56 ft² + 1288.41 ft²
CH² = 1358.97 ft²
Taking the square root, we get:
CH ≈ 36.9 ft
(d) To determine the measure of angle BHC, we can use the fact that angles AGC and AEG are congruent. We have:
angle BHC = 180° - angle AHC - angle CHB
angle AHC = angle ACG - angle HCG = 27° - 36° = -9° (note that this is a negative angle because it is measured clockwise)
angle CHB = angle CGB - angle HCG = 36° - 36° = 0°
Substituting these values, we get:
angle BHC = 180° - (-9°) - 0°
angle BHC = 189°
(e) To determine whether CH bisects angle ZACG, we need to show that angle CAH is congruent to angle CAG. We have:
angle CAH = 180° - angle HCG - angle ACG
= 180° - 36° - 27°
= 117°
angle CAG = 180° - angle ACG - angle AGC
= 180° - 27° - 27°
= 126°
Since angle CAH is not congruent to angle CAG, we can conclude that CH does not bisect angle ZACG.
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The number of meters a student swam this week are listed.
200, 450, 600, 650, 700, 800
What is the appropriate measure of variability for the data shown, and what is its value?
The range is the best measure of variability and equals 600.
The IQR is the best measure of variability and equals 250.
The mean is the best measure of variability and equals about 567.
The median is the best measure of variability and equals 625.
The appropriate measure of variability for the data shown and its value is A. The range is the best measure of variability and equals 600.
What is the range?The range is one of the three measures of variability.
The range shows the difference between the highest value and the lowest value in a data set.
The other measures of variability are the IQR (Interquartile Range) and the the Standard Deviation.
Range:Highest value = 800 m
Lowest value = 200 m
The range = 600 m (800 - 200)
IQR = 400 (600 - 200)
Mean = 567 (3,400 ÷ 6)
Median = 625 [(650 + 600) ÷ 2]
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tamara plays video games for the same amount of time each day. in 4 days she played video games for 48 minutes in 9 days how many minutes did she play video games
Answer:
Step-by-step explanation:
Its simple, you need to find x
4 days the same amount of time (x) gives 48 min
4x = 48
x = 48/4
x = 12
then to get the amount of minutes in 9 days it would be:
9x=days
9(12)=108
the answer would be 108 min
Answer:
108 mins
Step-by-step explanation:
48 mins/4 days = x mins/9 days
4x= 432
x=108 mins
) In the figure below, two secants are drawn to a circle from exterior point U.
Suppose that UW=40, UY=64, and UX= 8. Find UZ.
U
Applying the Intersecting Secants and Tangents Theorem, the measures are: CD = 19.5 units; UZ = 12.8 units
How to Apply the Intersecting Secants and Tangents Theorem?a. Apply the intersecting secant-tangent theorem to create the equation below:
EG² = EC * ED
Plug in the values:
13² = 6.5 * (6.5 + CD)
169 = 42.25 + 6.5CD
169 - 42.25 = 6.5CD
126.75/6.5 = CD
CD = 19.5 units
b. Apply the intersecting secants theorem to create the equation below:
UX * UY = UZ * UW
Plug in the values:
8 * 64 = UZ * 40
512/40 = UZ
UZ = 12.8
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35. The equation v=20Vt + 273 relates the speed v, in m/s, to the air
temperature t in Celsius degrees.
a. Find the temperature when the speed of sound is 340 m/s.
b. Find the temperature when the speed of sound is 320 m/s.
a. The temperature is about 3.35 degrees Celsius at 340 m/s, the speed of sound.
b. The temperature is about 2.35 degrees Celsius at 320 m/s, or the speed of sound.
Describe Speed?Speed is a scalar physical quantity that quantifies the rate of motion of an object. It is described as the distance that an object covers in a specific period of time. Meters per second (m/s) is the SI unit for measuring speed.
The speed formula is as follows:
Speed = distance / time
Depending on the purpose, speed can also be stated in different units, such as kilometres per hour (km/h), miles per hour (mph), or feet per second (ft/s).
The concept of speed, which is used to describe how objects move, is important to physics. It plays a significant role in a variety of fields of science, engineering, and technology, including sports, aircraft, and transportation. For the purpose of analysing and forecasting the behaviour of physical systems, it is essential to comprehend the idea of speed.
a. We can change v = 340 into the equation and solve for t to determine the temperature when the speed of sound is 340 m/s:
v = 20Vt + 273
340 = 20Vt + 273
67 = 20Vt
t = 67/20
Therefore, the temperature is about 3.35 degrees Celsius when the sound travels at 340 m/s.
b. We may once more enter v = 320 into the equation and solve for t to determine the temperature when the speed of sound is 320 m/s:
v = 20Vt + 273
320 = 20Vt + 273
47 = 20Vt
t = 47/20
As a result, the temperature is roughly 2.35 degrees Celsius at 320 m/s, the speed of sound.
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College Level Trig Question Please Help!
The solution of the trigonometric problem is y = -3
How is this so ?Starting with the equation
3/2 cos^-1(y/6) = pi
First, we can simplify by dividing both sides by 3/2 ....
cos^-1(y/6) = pi / (3/2)
cos^- 1(y/6) = 2pi / 3
Next, we can take the cosine of both sides to get...
cos (cos^-1(y/6 ) )
= cos( 2pi/3)
y/6 = -1/2
y = -3
Therefore, the exact solution to the equation 3/2 cos^-1(y/6) = pi is y = -3.
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Someone help i really need help with this
The cost of each admission tickets is 37.5 dollars.
How to find the cost in dollars of each admission ticket?Ms Boi spent a total of 175 dollars for 4 admission ticket and for parking at a baseball game. The cost of each admission ticket was the same amount, including tax. The cost of the parking was 25 dollars.
Therefore, the equation that can be use to determine the cost, i of each admission ticket can be represented as follows:
Therefore,
175 = 4i + 25
subtract 25 from both sides of the equation
175 = 4i + 25
175 - 25 = 4i + 25 - 25
150 = 4i
divide both sides by 4
i = 150 / 4
i = 37.5 dollars
Therefore,
cost of each admission ticket = 37.5 dollars
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Which statement concerning the equation x² - 1 = x is true?
Its discriminant is 0, so it has no solution.
Its discriminant is 5, so it has two real solutions.
Its discriminant is 0, so it has one real solution.
Its discriminant is -3, so it has two complex solutions.
The quadratic equation is solved and discriminant is 5, so it has two real solutions
Given data ,
The given equation is a quadratic equation in the standard form ax² + bx + c = 0, where a = 1, b = -1, and c = -1
The discriminant of a quadratic equation is given by b² - 4ac. So, the discriminant of the given equation is
(-1)² - 4(1)(-1) = 1 + 4 = 5
Since the discriminant is positive (not zero or negative), the equation has two real solutions.
Hence , its discriminant is 5, so it has two real solutions
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