Answer:
2.5 seconds
Explanation:
Time is equal to distance over speed
300 divide by 120 u get 2.5 seconds
20 points - Help me please with explanation of (A) and (B)
(a)to find voltage of battery we use the wire containg 4 ohm resistor and 3 ohm resistor
the voltage of 4ohm = Ri=4x1.5=6V
the voltage of 3 ohm = Ri=3x1.5=4.5v
since voltage is additive in series then Voltage of batteries = 4.5+6=10.5V
(b) the currrent flowing in 20 ohm resistor is the same as 8 ohm resistor so
Voltage of 8 ohm + voltage of 20 ohm= 10.5
8i+20i=10.5
28i=10.5
i=0.375 A
Sustained exercise that increases heart and lung fitness; may also alleviate depression and anxiety is called anaerobic exercise? True or false
Answer:
False
Explanation:
What torque is applied to Dead or Alive as they are spun right round? Assume their radius (all together) is 0.53 m. Answer in N-m.
Answer:
Es e mer freaks, tdk ijrmks rkspjbscfnk ijr freacbo erk eppnckl et orjubl nkvkn. \dk mkbtkr ji hess ji tdk mercs wknn efjvk tdk orjubl, djwkvkr. \dkrkijrk, tdk freacbo ijrmks kxkrt e tjrquk efjut tdk mkbtkr ji hess tdettkbls tj rjtetk tdk irjbt ji tdk mer ljwbwerl. \dcs, cb turb, meusks eb cbmrkeskl upwerl ijrmk tj fk kxkrtklfy tdk irjbt sprcbos, ubtcn tdk bkt tjrquk emtcbo jb tdk mer rkturbs tj zkrj.
<.
\dk ijrmk tdet emmknkretks e hjtjrmymnk cs e ijrwerl ijrmk eppnckl et orjubl nkvkn. \dk mkbtkr ji hess ji tdkhjtjrmymnk, djwkvkr, cs efjvk tdk orjubl. \dkrkijrk, tdk emmknkretcbo ijrmk kxkrts e tjrquk jb tdk mymnk tdettkbls tj rjtetk tdk irjbt wdkkn upwerl.
9.
Mjbsclkr eb ecrpnebk prjpknnkr jr e mkcncbo ieb tdet cs gust stertcbo tj rjtetk. Cb tdksk mesks, tdk bkt ijrmk cszkrj fkmeusk tdk mkbtkr ji hess cs bjt emmknkretcbo. Djwkvkr, tdk bkt tjrquk cs bjbzkrj ebl tdk ebouneremmknkretcjb cs bjbzkrj.
4.
E mer emmknkretcbo irjh rkst cs bjt cb stetcm kqucncfrcuh fkmeusk cts mkbtkr ji hess cs emmknkretcbo. ]chcnerny,eb ecrpnebk prjpknnkr tdet cs gust stertcbo up cs bjt cb stetcm kqucncfrcuh fkmeusk ct des eb ebouner emmknkretcjb.
50.
Sks. _dkb eb ecrpnebk
–
s kbocbk sterts up irjh rkst tdk prjpknnkr des e bjbzkrj rjtetcjben emmknkretcjb,tdjuod cts trebsnetcjben emmknkretcjb cs zkrj.
56.
\dk tecn rjtjr jb e dkncmjptkr des e djrczjbten excs ji rjtetcjb, es jppjskl tj tdk vkrtcmen excs ji tdk hecbrjtjr. \dkrkijrk, tdk tecn rjtjr prjlumks e djrczjbten tdrust tdet tkbls tj rjtetk tdk dkncmjptkr efjut e vkrtcmenexcs. Es e rksunt, ci tdk ebouner spkkl ji tdk hecb rjtjr cs cbmrkeskl jr lkmrkeskl, tdk tecn rjtjr meb kxkrt ebjppjscbo tjrquk tdet prkvkbts tdk kbtcrk dkncmjptkr irjh rjtetcbo cb tdk jppjsctk lcrkmtcjb.
5<.
Bj. Ci tdk lcvkr
–
s cbctcen ebouner hjhkbtuh cs zkrj, ct hust stey zkrj ubnkss eb kxtkrben tjrquk emts jb dkr.E lcvkr bkkls tj stert jii wctd et nkest e shenn ebouner spkkl, wdcmd meb tdkb fk cbmrkeskl fy ijnlcbo cbtj etumakl pjsctcjb.
]jnutcjbs tj Prjfnkhs ebl Mjbmkptuen Kxkrmcsks
5.
Pcmturk tdk Prjfnkh
7 \dk ijrmk cs eppnckl cb e lcrkmtcjb pkrpkblcmuner tj tdk deblnk ji tdkwrkbmd ebl et tdk kbl ji tdk deblnk.
]tretkoy7
[sk kquetcjb 55-5 tj icbl tdk ijrmk irjh tdk abjwb tjrquk ebl tdk nkbotd ji tdkwrkbmd.
]jnutcjb7
]jnvk kquetcjb 55-5 ijr
I
7
( )( )
scb5; Bh90 Bscb0.6; hscb30
r I I r
ό δ ό δ
8⋋8 8 8°
Cbscodt7
E njbokr wrkbmd meb kxkrt e nerokr tjrquk ijr tdk sehk ehjubt ji ijrmk.6.
Pcmturk tdk Prjfnkh
7 \dk wkkl cs punnkl fy kxkrtcbo e ljwbwerl ijrmk jb tdk kblji tdk tjjn deblnk.
]tretkoy7
]kt tdk tjrquk jb tdk tjjn kquen tj tdk ijrmk kxkrtkl fy tdk wkkl tchks tdkhjhkbt erh ebl sjnvk ijr tdk ijrmk.
]jnutcjb7
]jnvk kquetcjb 55-5 ijr
I
7
wkklwkklwkklwkkl
5.6= Bh=5 B0.0<0 h
I r I r
ό ό
8⋋8 8 8
Cbscodt7
\dk tjrquk hust fk tdk sehk kvkrywdkrk jb tdk tjjn. \dkrkijrk, tdk debl hust kxkrt e5.6= Bh0.66 h;.9 B
⋋ 8
ijrmk tj prjlumk e =5-B ijrmk et tdk wkkl. \dk ijrmk cs huntcpnckl fy e iemtjr ji 66<;.;.
8
Explanation:
The torque applied will be the average of the 3 torque calculated.
Torque = 12.01 Nm
Torque of a couple is the product of a force and its perpendicular distance to the direction of the force. Torque is synonymous to moment.
From the question, the given radius is 0.53m. The perpendicular distance for each torque will be 2 x 0.53 = 1.06 m
We will calculate for each torque
T1 = F1d
T1 = 8 x 1.06 = 8.48 Nm
T2 = F2d
T2 = 15 x 1.06 = 15.9 Nm
T3 = F3d
T3 = 11 x 1.06 = 11.66 Nm
The torque applied will be the average of the 3 torque calculated. That is,
Torque = (8.48 + 15.9 + 11.66)/3
Torque = 36.04 /3
Torque = 12.01 Nm
Learn more here: https://brainly.com/question/23169143
If you can run 10.43 m in 14.22 s. How fast are you running?
Answer:
I am 15th in my state for 55m hurdles with a time of 10.4 seconds
Explanation:
BAM
Answer: 44 m per minute
Explanation:
three properties of an ideal fluid that obey Bernoulli’s principle
Answer:
Bernoulli's theorem, in fluid dynamics, relation among the pressure, velocity, and elevation in a moving fluid (liquidor gas), the compressibility and viscosity (internal friction) of which are negligible and the flow of which is steady, or laminar.
Three properties of an ideal fluid that obey Bernoulli’s principle are :
1) incompressible
2) subjected to conservative forces
3) non - viscous
What is Bernoulli's principle ?Bernoulli's principle states that as the speed of moving fluid increases , the pressure within fluid decreases or it states that if the fluid flows horizontally so that no change in gravitational potential energy occurs, then a decrease in fluid pressure is associated with an increase in fluid velocity.
As we know that Bernoulli's principle is only valid for ideal fluids which have following properties :
1) Should be incompressible
2) subjected to conservative forces
3) It should be non - viscous which means there is no internal friction in the flow .
learn more about Bernoulli's principle :
https://brainly.com/question/2249706?referrer=searchResults
#SPJ3
How much work is required to stretch a spring 0.133 m if its force constant is 9.67 N/m?
Answer:
refer to attachment
Explanation:
hope it will helps u
Answer: 5cm
Explanation:
what causes diffferent air density?
Answer:
The temperature and gravity both affects the density
A Spring is pulled to 10cm and held in place with a force of 500N .what is the spring constant
We are given:
extension of the spring (x) = 10 cm OR 0.1 m
Force applied to keep it in position (F) = 500 N
Solving for the spring constant:
We know that F = kx (when the spring is extended)
replacing the variables with the given values
500 = k * 0.1
k = 5000 N/m
This means that to extend the spring by 1 m, we have to apply a force of 5000 N
he triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 2.00 103 N with an effective perpendicular lever arm of 2.80 cm, producing an angular acceleration of the forearm of 145 rad/s2. What is the moment of inertia of the boxer's forearm
Answer:
Moment of inertia = 0.3862kg-m²
Explanation:
2.00x10³
2.80cm
145 rad
r = r⊥ x F
F is an applied force
r⊥ is the distance between the applied force and axis
Force exerted = 2.00x10³
r⊥ = 2.8cm = 0.028m
Alpha = 145rad/s²
r = 0.028m x 2.00x10³
r = 56.0N-m
To get the moment of inertia
56.0N-m² = (145rad/s²) x I
The I would be:
I = (56.0N-m²)/(145rad/s²)
I = 56/145
= 0.3862Kg-m²
This is the moment of inertia.
Thank you!
The most commonly accepted theory of muscle growth states that ______________ ________ within a muscle activate a(n) ________________ response process that causes dormant cells to build and regenerate muscle tissue.
A. contractions; inhibitory
B. tension; neurological
C. microscopic tears; inflammatory
D. stress; cytokines
Answer:
C
Explanation:
The most commonly accepted theory of muscle growth states that microscopic tears within a muscle activate an inflammatory response process that causes dormant cells to build and regenerate muscle tissue; this is option c.
What is the significance of the microscopic tears in muscle?It has negative consequences on the muscle, and it is also known as "microtrauma," which occurs as a result of muscle contraction and is a normal part of the muscle repair and growth process. Here, the fibers in the muscle are damaged, and in response, the body initiates a repair process. This leads to muscle growth and increased strength and is helpful for muscle repair.
Hence, the most commonly accepted theory of muscle growth states that microscopic tears within a muscle activate an inflammatory response process that causes dormant cells to build and regenerate muscle tissue; this is option c.
Learn more about the microscopic tears in muscle here.
https://brainly.com/question/29457664
#SPJ2
significance of practicals in the discipline of geography
HELP!!! An object accelerates from rest to 85 m/s over a distance of 36 m. What acceleration did it
experience?
Answer:
Explanation:
Given:-
Initial velocity (u) = 0m/s
Final velocity (v) = 85m/s
Distance covered (s) = 36m
To Find:-
Acceleration of the object (a)
Solution:-
By using 3rd equation of motion
→ v² = u² +2as
Substitute the value we get
→ 85² = 0² +2×a×36
→ 7225 = 0 + 72 ×a
→ a = 7225/72
→ a = 100.34m/s²
∴ The acceleration of the object is 100.34m/s²
Additional Information!!
The rate of change of velocity at per unit time is called acceleration .
✧ SI unit of acceleration is m/s²
✧ It is vector Quantity ( both magnitude and directio
A golf ball (m=26.7g) is struck a blow that makes an angle of 33.6 degrees with the horizontal. The drive lands 190m away on a flat fairway. The acceleration of gravity is 9.8 m/s^2 . If the golf club and ball are in contact for 7.13 ms, what is the average force of impact?
Answer:
Th average force impact is [tex]F = 168.298 \ N[/tex]
Explanation:
From the question we are told that
The mass of the golf ball is [tex]m_g = 26.7 \ g = 0.0267 \ kg[/tex]
The angle made is [tex]\theta = 33.6 ^o[/tex]
The range of the golf ball is [tex]R = 190 \ m[/tex]
The duration of contact is [tex]\Delta t = 7.13 \ ms = 7.13 *10^{-3} \ s[/tex]
Generally the range of the golf ball is mathematically represented as
[tex]R = \frac{v^2 sin2(\theta)}{g}[/tex]
Here v is the velocity with which the golf club propelled it with, making v the subject
[tex]v = \sqrt{\frac{R * g}{sin 2 (\theta)} }[/tex]
=> [tex]v = \sqrt{\frac{190 * 9.8}{sin 2 (33.6)} }[/tex]
=> [tex]v = 44.94 \ m/s[/tex]
Generally the change in momentum of the golf ball is mathematically represented as
[tex]\Delta p = m * (v - u )[/tex]
here u is the initial velocity of the ball before being stroked and the value is 0 m/s
[tex]\Delta p = 0.0267 * ( 44.94 - 0 )[/tex]
=> [tex]\Delta p = 1.19996 \ kg \cdot m/s[/tex]
Generally the average force of impact is mathematically represented as
[tex]F = \frac{\Delta p }{\Delta t}[/tex]
=> [tex]F = \frac{1.19996 }{7.13 *10^{-3}}[/tex]
=> [tex]F = 168.298 \ N[/tex]
At its peak, a tornado is 74.0 m in diameter and carries 335-km/h winds. What is its angular velocity in revolutions per second?
Answer:
0.399 rev/s
Explanation:
Given that,
The diameter of a tornado, d = 74 m
Radius, r = 37 m
Linear velocity, v = 335 km/h = 93.05 m/s
We need to find the angular velocity in revolutions per second. Let it is [tex]\omega[/tex]. The relation between angular velocity and linear velocity is as follows :
[tex]v=r\omega\\\\\omega=\dfrac{v}{r}\\\\\omega=\dfrac{93.0556}{37}\\\\\omega=2.51\ rad/s[/tex]
or
[tex]\omega=\dfrac{2.51}{2\pi}\\\\\omega=0.399\ rev/s[/tex]
So, the angular velocity of the blade is 0.399 rev/s.
True or False: In a p-n junction diode, the absolute value of the electric field is the largest at the metallurgical junction (exactly where p-type and n-type semiconductors meet).
Answer:
false
Explanation:
In a p-n junction diode, the absolute value of the electric field is the largest at the metallurgical junction is false statement.
What is electric field?An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. It can also refer to a system of charged particles' physical field.
In a p-n junction diode, the absolute value of the electric field is the not largest at the metallurgical junction field is maximum at the depletion region.
In a p-n junction diode, the absolute value of the electric field is the largest at the metallurgical junction is false statement.
To learn more about electric field refer to the link:
brainly.com/question/15800304
#SPJ5
Which is the function of a nucleus within a eukaryotic cell?
O A) Transport materials within the cell.
O B) Control what materials move into and out of the cell.
OC) Provide the cell with energy to perform its other functions.
OD) Store genetic information that provides instructions for the cell.
Next 100 points if u answer this
Answer: When frequency increases more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.
The frequency and wavelength of a wave are related. When frequency increases more wave crests pass a fixed point each second. ... So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.
uncountable the number of times that something happens during a period of time. frequency of: Changes in sea temperature will increase the frequency of hurricanes. with increasing frequency (=more often): Accidents occur here with increasing frequency.
Explanation:
The second-order dark fringe in a single-slit diffraction pattern is 1.40 mm from the center of the central maximum. Assuming the screen is 89.0 cm from a slit of width 0.710 mm and assuming monochromatic incident light, calculate the wavelength of the incident light.
We know, for single slit :
[tex]y =\dfrac{ n\lambda L}{a}\\\\\lambda = \dfrac{ya}{nL}[/tex] ...1)
[tex]y = 1.4\ mm = 1.4 \times 10^{-3}\ m[/tex]
n = 2
L = 89 cm = 0.89 m
[tex]a=7.1\times 10^{-4}\ m[/tex]
Putting all these in equation 1), we get :
[tex]\lambda = \dfrac{ya}{nL}\\\\\lambda = \dfrac{1.4\times 10^{-3}\times 7.1\times 10^{-4}}{2\times 0.89 }\\\\\lambda = 5.584 \times 10^{-7}\ m[/tex]
Therefore, wavelength of the incident light is [tex]5.584 \times 10^{-7}\ m[/tex] or 558.4 nm.
Hence, this is the required solution.
If you jump upward with a speed of 1.70 m/s how high will you be when you stop rising?
Answer:
How long do you jump (sec) ?
Explanation:
1. Two forces F~
1 and F~
2 are acting on a block of mass m=1.5 kg. The magnitude of
force F~
1 is 12N and it makes an angle of θ = 37◦ with the horizontal as shown in
figure-1. The block is sliding at a constant velocity over a frictionless floor.
Figure-1
(a) Find the value of the normal force on the block.
[3 marks]
(b) Find the magnitude of force F~
2 that is acting on the block
[4 marks]
(c) Find the magnitude of force F~
2 if the block accelerates with a magnitude of
a = 2.5 m/s2 along the direction of F~
2 . [3 mark
Answer:
(a) Normal force=7.48 N
Explanation:
N+F~1 sinθ-mg=0
=>N=1.5*9.8-12 sin37◦
=>N=14.7-7.22=7.48 N
If the velocity of Homer the astronaut (mass =200 kg) is 5 m/s and he runs into and grabs his stationary pal Larry (mass = 150 kg), what is the new velocity of the astronauts after the collision?
We are given:
Homer the Astronaut:
Mass of Homer the astronaut(m1) = 200 kg
initial velocity of Homer the astronaut(u1) = 5 m/s
Larry the Pal:
Mass of Larry the Pal (m2) = 150 kg
initial velocity of Larry the Pal (u2) = 0 m/s
Since they will move together after the collision, they will have the same velocity:
v1 = v2 = V
Solving for the Final velocity:
from the law of conservation of momentum:
m1u1 + m2u2 = m1v1 + m2v2
since v1 = v2 = V:
m1u1 + m2u2 = V(m1 + m2)
replacing the variables with the given values
200 * 5 + 150 * 0 = V(200 + 150)
1000 = 350V
V = 1000 / 350
V = 2.86 m/s
Suppose an empty grocery cart rolls downhill in a parking lot. The cart has a maximum speed of 1.3 m/s when it hits the side of the store and comes to rest 0.30 s later. If an unbalanced force of —65 N stops the cart, what is the mass of the grocery cart?
The cart comes to rest from 1.3 m/s in a matter of 0.30 s, so it undergoes an acceleration a of
a = (0 - 1.3 m/s) / (0.30 s)
a ≈ -4.33 m/s²
This acceleration is applied by a force of -65 N, i.e. a force of 65 N that opposes the cart's motion downhill. So the cart has a mass m such that
-65 N = m (-4.33 m/s²)
m = 15 kg
Leoni is participating in four drawing competitions. If the probability of her losing any
drawing competition is 0.7, find the probability of her winning
a) at least one competition.
b) exactly two competitions.
Answer:
(a) [tex]Probability = 0.7599[/tex]
(b) [tex]Probability = 0.2646[/tex]
Explanation:
Represent losing with L and winning with W.
So:
[tex]L = 0.7[/tex] --- Given
[tex]n = 4[/tex]
Probability of winning would be:
[tex]W = 1 - L[/tex]
[tex]W = 1 - 0.7[/tex]
[tex]W = 0.3[/tex]
The question illustrates binomial probability and will be solved using the following binomial expansion;
[tex](L + W)^4 = L^4 + 4L^3W + 6L^2W^2 + 4LW^3 + W^4[/tex]
So:
Solving (a): Winning at least 1
We look at the above and we list out the terms where the powers of W is at least 1; i.e., 1,2,3 and 4
So, we have:
[tex]Probability = 4L^3W + 6L^2W^2 + 4LW^3 + W^4[/tex]
Substitute value for W and L
[tex]Probability = 4 * 0.7^3*0.3 + 6*0.7^2*0.3^2 + 4*0.7*0.3^3 + 0.3^4[/tex]
[tex]Probability = 0.7599[/tex]
Hence, the probability of her winning at least one is 0.7599
Solving (a): Wining exactly 2
We look at the above and we list out the terms where the powers of W is exactly 2
So, we have:
[tex]Probability = 6L^2W^2[/tex]
Substitute value for W and L
[tex]Probability = 6*0.7^2*0.3^2[/tex]
[tex]Probability = 0.2646[/tex]
Hence, the probability of her winning exactly two is 0.2646
For a given centrifugal pump, if the speed of rotation of the impeller is cut in half, how does the power required to drive the pump change
Answer:
The power required to drive the pump is reduced in [tex]\frac{1}{8}[/tex].
Explanation:
From Turbomachinery, we find that power required to drive the pump ([tex]\dot W[/tex]) is directly proportional to the cube of the speed of rotation of the impeller ([tex]\dot n[/tex]). That is:
[tex]\dot W \propto \dot n^{3}[/tex]
[tex]\dot W = k\cdot \dot n ^{3}[/tex] (Eq. 1)
Where [tex]k[/tex] is the proportionality constant.
And now we eliminate the proportionality constant by constructing the following relationship:
[tex]\frac{\dot W_{B}}{\dot W_{A}} = \left(\frac{\dot n_{B}}{\dot n_{A}}\right)^{3}[/tex] (Eq. 2)
If we know that [tex]\frac{\dot n_{B}}{\dot n_{A}} = \frac{1}{2}[/tex], then:
[tex]\frac{\dot W_{B}}{\dot W_{A}} = \frac{1}{8}[/tex]
The power required to drive the pump is reduced in [tex]\frac{1}{8}[/tex].
What is the largest planet in our galaxy
2. Solid is a state in which in maintain a fixed volume and shape
1
1
I'm
Ye
2
3
4
5
6
8
W
E
R.
T
Y
U
HELP ASAP!!
The table below lists protected constitutional rights and how they may be limited.
Protected Rights Limitations
Property rights ?
Unwarranted search and seizure Crime suspects may be searched
Which phrase completes the table? (3 points)
Group of answer choices
Poll taxes
Eminent domain
Jury trial
Background checks
Answer:
jury trial
Explanation:
rights to a fair trial by jury, or the whole innocent until proven guilty ya know
If the_____of a wave increases, its frequency must decrease.
a. period
b. energy
c. amplitude
d. velocity
Answer:wrong. Jts not velocity. Its period.
Explanation:
Took the test
what is the relevant similarity of the following argument?
"Tolerating a vicious dictator is like tolerating a bully on the block. If you let the bully push you around, sooner or later he will beat you up and take everything you have. If you let a dictator have his way, he will abuse his people and rob them of life and liberty. If you stand up to the bully just once or- better yet- knock him senseless with a stick, he will never bother you again. LIkewise, if you refuse to be coerced by a dictator or if you attack him, his reign will be over. Therefore, the best course of action for people oppressed by a dictator is to resist and attack."
a.
there are no relevant similarities
b.
tolerating a bully or dictator leads to further abuse
c.
the best course of action for people oppressed by a dictator is to resist and attack.
When were Earth’s landmasses first recognizable as the continents we know today? 10 million years ago 135 million years ago 180 million years ago 300 million years ago
Answer:
b
Explanation:
i took the test
Earth’s landmasses were first recognized as the continents we know today
135 million years ago.
Landmass is defines as a large area of land. It can also be referred to as the
continents we have today. There are seven types of earth landmasses and
they are
Asia, Africa, North America, South America, Antarctica, Europe, and Australia.They were first discovered around 135 million years ago by the early
dwellers of the earth.
Read more on https://brainly.com/question/18125355
