Answer:
[tex]ans \: = \boxed{{4.8 \times 10}^{ - 4} Hz}[/tex]
Explanation:
[tex]given \to \\ f_{r} = 350 \: \\ v_{r} = {3 \times 10}^{8} \\ but \to \\ v = f \gamma \to \: \gamma = \frac{v}{f} : hence \to \\ \gamma _{r} = \frac{v_{r}}{f_{r}} = \frac{3 \times 10^{8} }{350} = \boxed{857,142.85714 \: m}\\ therefore \to \\ given \to \\ f_{w} = water \: frequency = \: \boxed{ ?}\: \\ v_{w} = 14 50 \\ but \to \\ v = f \gamma \to \: \gamma = \frac{v}{f} : hence \to \\ \gamma _{w} = \frac{v_{w}}{f_{w}} = \frac{1}{100} \times \gamma _{r} = \frac{1}{100} \times 857,142.85714 \\\gamma _{w} = \boxed{8,571.4285714 \: m} : hence \to \: \\ f_{w} = \frac{v_{w}}{ \gamma _{w}} = \frac{1450}{8,571.4285714} = \boxed{0.1691666667} \\ if \: the \: number \: of \: times = \boxed{ x} \\ f_{r} (x)=f_{w} \\ (x) = \frac{f_{w}}{f_{r}} = \frac{0.1691666667}{350} = 0.0004833333 \\ hence \to \\ the \: frequency \: of \: the \: radio \: wave \: is \to \: \boxed{{4.8 \times 10}^{ - 4} }\: \\ that \: of \: the \: wave \: created \: in \: the \: water.[/tex]
♨Rage♨
1.A runner has a displacement of 20 meters in 5 seconds, what is his velocity
during this time?
Answer:
The required velocity of runner is 4m/s.
A go-kart and rider have a mass of 14 kg. If the cart accelerates at 6 m/s² during a 40 m sprint in 100 seconds, how much power did the cart do?
Answer:
P=33.6 \ W
Explanation:
Mechanical Work and Power
Work is the amount of energy transferred by a force. It's a scalar quantity, with SI units of joules.
Being [tex]\vec F[/tex] the force vector and [tex]\vec s[/tex] the displacement vector, the work is calculated as:
[tex]W=\vec F\cdot \vec s[/tex]
If both the force and displacement are parallel, then we can use the equivalent scalar formula:
[tex]W=F.s[/tex]
Mechanical Power is the amount of energy transferred or converted per unit of time. The SI unit of power is the watt, equal to one joule per second.
The power can be calculated as:
[tex]\displaystyle P=\frac {W}{t}[/tex]
Where W is the work and t is the time.
If an object of mass m has an acceleration a, the net force is:
F=m.a
The go-kart and rider have a mass of m=14 kg and accelerate at [tex]6 m/s^2[/tex], thus the net force applied is:
[tex]F=14\cdot 6 = 84\ N[/tex]
The work done by the cart when traveling d= 40 m is:
[tex]W=84\cdot 40[/tex]
[tex]W=3,360\ J[/tex]
Finally, the power for t= 100 seconds is:
[tex]\displaystyle P=\frac {3,360}{100}[/tex]
P=33.6 \ W
provide two ways that objects can become charged
Answer:
friction, conduction and induction
Explanation:
Had it in class I had it correct hope this helps.
What are some signals of autism?
Answer:
The range and severity of symptoms can vary widely. Common symptoms include difficulty with communication, difficulty with social interactions, obsessive interests, and repetitive behaviors.
At any age
1. Loss of previously acquired speech, babbling or social skills.
2. Avoidance of eye contact.
3. Persistent preference for solitude.
4. Difficulty understanding other people's feelings.
5. Delayed language development.
6. Persistent repetition of words or phrases (echolalia)
7. Resistance to minor changes in routine or surroundings.
Have a nice day ✨__________ ___________ are movements you do to loosen up your joints.
A .Dynamic Stretches
B. Static Stretches
Answer:
Dynamic stretches
Explanation:
Dynamic stretches are active movements where joints and muscles go through a full range of motion. When you do dynamic stretches you do not hold the stretch, instead you stretch with movement.
Find the minimum diameter the larger cylinder of a hydraulic press can have if it is to lift a 1.1 x 10^4 N car with an applied liquid pressure of 420 N/cm^2 in the smaller cylinder, having a diameter of 1.5 cm.
Answer:
diameter = 5.78 cm .
Explanation:
According to Pascal's law, pressure will be equally transferred from smaller to larger cylinder.
Let the radius of larger cylinder be r cm
cross sectional area = π r²
pressure created on larger cylinder = 1.1 x 10⁴ / π r²
This pressure must be equal to 420 N / cm²
1.1 x 10⁴ / π r² = 420
r² = 8.34
r = 2.89 cm
diameter = 5.78 cm .
a table is pushed 15m across a room with a force of 50n.
a) what is the work don?
b) if it takes 20 seconds to push the table across the room.what is the power?
Answer:
The work is 750 J
The power is 37.5 watt
Explanation:
Mechanical Work and Power
Mechanical work is the amount of energy transferred by a force. It's a scalar quantity, with SI units of joules.
Being [tex]\vec F[/tex] the force vector and [tex]\vec s[/tex] the displacement vector, the work is calculated as:
[tex]W=\vec F\cdot \vec s[/tex]
If both the force and displacement are parallel, then we can use the equivalent scalar formula:
W=F.s
Power is the amount of energy transferred or converted per unit of time. In the SI, the unit of power is the watt, equal to one joule per second.
The power can be calculated as:
[tex]\displaystyle P=\frac {W}{t}[/tex]
Where W is the work and t is the time.
a)
The table is pushed d=15 m across a room with a force F=50 N, thus the work is:
W=50 * 15 = 750 J
The work is 750 J
b)
The time needed to push the table is t=20 seconds, thus:
[tex]\displaystyle P=\frac {750}{20}=37.5[/tex]
The power is 37.5 watt
engineers are using computer models to study train collisions design safer train cars. They start by modeling an elastic collision between two train cars traveling toward each other. Car one is traveling south at 18 M/S and has a full load, giving it a total mass of 14,650 kg. Kartoo is traveling north at 11 m/s and has a mass of 3825 kg. After the collision car one has a final velocity of 6 M/S south what is the final velocity of car 2?
Answer:
The final velocity of the second car is 57 m/s south.
Explanation:
This is an elastic collision between two train cars. In this case, the total kinetic energy between the two bodies will remain the same.
The formula to apply is :
[tex]m_1v_1i +m_2v_2i=m_1v_1f+m_2v_2f[/tex]
where ;
[tex]m_1=mass of object 1\\v_1i=initial velocity object1\\m_2=mass of object2\\v_2i=initial velocity object 2\\v_1f=final velocity object 1\\v_2f=final velocity object 2[/tex]
Given in the question that;
[tex]m_1=14650kg\\v_1i=18m/s\\m_2=3825kg\\v_2i=11m/s\\v_1f=6m/s\\v_2f=?[/tex]
Apply the formula as;
[tex]m_1v_1i +m_2v_2i=m_1v_1f+m_2v_2f[/tex]
{14650*18}+{3825*11} = {14650 *6} + {3825 * v₂f}
263700+42075=87900 + 3825v₂f
305775 =87900 + 3825v₂f
305775-87900 = 3825v₂f
217875=3825v₂f
217875/3825 =v₂f
56.96 = v₂f
57 m/s = v₂f { nearest whole number}
Answer:
35 m/s south
Explanation:
took the test
How do you increase the amount of electrical energy produced from running water?
Answer:
To increase the volume of moving water, impoundments or dams are used to collect the water. An opening in the dam uses gravity to drop water down a pipe called a penstock. The moving water causes the turbine to spin, which causes magnets inside a generator to rotate and create electricity.
Explanation:
Hope this helped, Have a Great Day!!
5 points
At 55 minutes how fast is the object moving?*
velocity
B01
B
60
40
А
20
me
min
D
20
40
10
20
30
50
55 m/s
60 m/s
20 m/s
0 m/s
Answer:
9 answer hai brown
a match is being is an example of
A match is being is an example of multiple energy transformations
What best describes the volcanic process of magma with dissolved water vapor and other gases as it nears the Earth surface?
Pressure on the molten rock lessens and the gases quickly dissipate into the atmosphere.
Explosive gases such as methane and ethane combine with oxygen and ignite violently in the atmosphere.
Pressure on the molten rock lessens the rock rapidly expands to the point that it explodes and ejects into the atmosphere.
Pressure on the molten rock lessens and the gases dissolved in rock can bubble and expand rapidly causing violent eruptions.
Answer:
Pressure on the molten rock lessens and the gases dissolved in rock can bubble and expand rapidly causing violent eruptions.
Explanation:
that's just how it works lol. hope this helps :]
Answer:D
Explanation: got it right on mine
10. A golf ball is propelled with an initial velocity of 60
meters per second at 37° above the horizontal. The
horizontal component of the golf ball's initial veloc-
ity is
the horizontal component of the golf ball's initial velocity is 47.92 m/s.
The given parameters;
initial velocity of the golf, v = 60 m/s
angle of projection of the golf, Ф = 37°
The horizontal component of the golf ball's initial velocity is calculated as follows;
[tex]v_0_x = v\times cos(\theta)\\\\[/tex]
[tex]v_0_x[/tex] = 60 m/s x cos (37)
[tex]v_0_x[/tex] = 60 m/s x 0.7986
[tex]v_0_x[/tex] = 47.92 m/s
Thus, the horizontal component of the golf ball's initial velocity is 47.92 m/s.
Learn more here: https://brainly.com/question/14304606
A bus covers 10 km in 7 minutes. Find the speed of the bus in km/h
Answer:
Explanation: so how many minutes are in an hour 60 right, and the bus travels 10km in 7 minutes right so use math the bus travels 14km in 10 minutes so the bus travels 98km in an hour
15. Calculate The coefficient of kinetic friction be-
tween a large box and the floor is 0.21. A person pushes
horizontally on the box with a force of 160 N for a
distance of 2.3 m. If the mass of the box is 72 kg, what is
the total work done on the box?
Answer:
Wt = 26.84 [N]
Explanation:
In order to solve this problem we must use the definition of work in physics. Which tells us that this is equal to the product of force by distance.
In this case, we must sum the works of the force applied by the box and the friction force that also acts on the box.
The friction force is defined as the product of the normal force by the coefficient of friction.
f = N*μ
where:
N = normal force = m*g [N] (units of Newtons)
m = mass = 72 [kg]
g = gravity acceleration = 9.81 [m/s²]
f = friction force [N]
μ = friction coefficient = 0.21
f = 72*9.81*0.21
f = 148.32 [N]
Now the total work:
Wt = WF - Wf
where:
Wt = total work [J] (units of Joules)
WF = work by the pushing force [J]
Wf = work done by the friction force [J]
Wt = (160*2.3) - (148.32*2.3)
Wt = 26.84 [N]
Note: The friction force exerts a negative work, because this force is acting in opposite direction to the movement, therefore the negative sign.
A runner is training and runs past meter mark 65 and starts a stopwatch. After the runner passes meter mark 15 the stopwatch stops at 8 seconds. What was the runners velocity?
Question 5 options:
-6.25 m/s
6.25 m/s
8.13 m/s
-1.88 m/s
Answer:
-6.25 m/s
Explanation:
i took the quiz
this will give brainliest
Answer:
It is likely to be option B: 50 degrees and 50 degrees
Hope it helps.......... pls mark as brainliest.
A passenger on a jet airplane claims to be able to walk at a speed in excess of 500 mph. Can this be true?
Explain!
Answer:noo
Explanation:impossible
I need the answer ASAP!
How does the Newton’s Law relate to the force of gravity
Answer:
Newton's second law of motion states that the acceleration of a system is directly proportional to and in the same direction as the net external force acting on the system, and inversely proportional to its mass. If the only force acting on an object is due to gravity, the object is in free fall.
Explanation:
Hope this helps :)
Si se hace avanzar un carro de 200 kg de masa desde el reposo aplicando una fuerza de 800 N. Calcular a) Su aceleración. b) La velocidad final del carro.
Explicación:
a) Según la segunda ley de movimiento de Newton;
Fuerza = Masa * aceleración
Dado
Masa del coche = 200 kg
Fuerza aplicada = 800N
aceleración = Fuerza / Masa
aceleración = 800/200
aceleración = 4m / s²
b) Para que obtengamos la velocidad final del automóvil, necesitaremos el tiempo.
Suponiendo que el tiempo necesario es de 2 segundos
Sabemos que aceleración = velocidad / tiempo
velocidad = aceleración * tiempo
velocidad = 4 * 2
velocidad = 8 m / s
Por lo tanto, la velocidad final será de 8 m / s si el tiempo es de 2 s.
Why might measuring changes in speed or direction be important?
How does acceleration measure. A.change in speed over time
B. Change in displacement overtime
C. Change in distance over time
D. Change in velocity over time
Answer:
D
Explanation:
Acceleration is the rate of change in velocity experienced by an object, measured in meter per second.
Answer:
Change in velocity
Explanation:
a-pe-x
1. What are valence electrons used for by an element?
Answer:
An element's valence electron tells us about its ability to react and not react. More rules to this, but that's the gist of it. it also helps us form bonds
Explanation:
Valence electrons are used by an element for bonding and ionization, contributing to the element's chemical reactivity and behavior.
Valence electrons also play a vital role in ionization, which refers to the process of gaining or losing electrons to form ions. Elements tend to gain or lose electrons in order to achieve a stable electron configuration, typically by acquiring a full valence shell.
Metals, located on the left side of the periodic table, have fewer valence electrons, often one or two, and tend to lose them to form positive ions (cations). This characteristic makes them good conductors of electricity.
Nonmetals, located on the right side of the periodic table, have a nearly full valence shell and tend to gain electrons to achieve a stable configuration, forming negative ions (anions). Nonmetals generally do not conduct electricity as well as metals.
In summary, valence electrons are used by an element for bonding, where they participate in the formation of covalent and ionic bonds, and for ionization, where they are gained or lost to form ions and achieve a stable electron configuration.
To know more about electrons here
https://brainly.com/question/12001116
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HELP!! Explain why a more streamlined car generally will have a better fuel economy than a bulkier car with the same mass.
Answer: A streamlined car will be more aerodynamic causing it be more fuel efficient.
Explanation: Aerodynamic-of or having a shape which reduces the drag from air moving past. A bulkier car will be less aerodynamic meaning that the air that hits it won't go around but push it back causing it to use more power which causes it to use more fuel. A streamlined car will allow air to flow around and over the car, a streamlined car will usually be less like a box and have more curves.
pls help i will give u brianliest!
Answer:
Explanation:
neautrons and protons
Calcula la fuerza magnética de una carga que se desplaza hacia la derecha con una velocidad de 5 X 10 a la 6 metros sobre segundo. Que forma un campo magnético de 0.8 Teslas. Recuerda que la carga de un electrón es de 1.602 X 10 a la menos 19 [Coulombs]
Answer:
La fuerza magnética del electrón es 6.41x10⁻¹³ N.
Explanation:
Podemos encontrar la fuerza magnética (F) usando la ley de Lorentz:
[tex] F = qv\times B [/tex]
En donde:
q: es la carga del electrón = 1.602x10⁻¹⁹ C
v: es la velocidad del electrón = 5x10⁶ m/s
B: es el campo magnético = 0.8 T
[tex] F = qv\times B = 1.602 \cdot 10^{-19} C*5\cdot 10^{6} m/s*0.8 T = 6.41 \cdot 10^{-13} N [/tex]
Por lo tanto, la fuerza magnética del electrón es 6.41x10⁻¹³ N.
Espero que te sea de utilidad!
The diagram below shows the velocity vectors for two cars that are moving relative to each other.
From the frame of reference of car 1, what is the velocity of car 2?
Answer:
The answer is "[tex]5 \ \frac{m}{s} \ west[/tex]"
Explanation:
[tex]\to \vec{V_1} = (25 \frac{m}{s}) (\hat{-i})\\\\\to \vec{V_2} = (20 \frac{m}{s}) (\hat{-i})\\\\[/tex]
velocity of car | respect to car :
[tex]\to \vec{V_{12}} = \vec{V_1} - \vec{V_2}\\\\[/tex]
[tex]=\vec{-25} \hat{i}+ \vec{20} \hat{i}\\\\= 5 \ \frac{m}{s} \ west[/tex]
Answer:
70 m/s east
Explanation:
One of the largest pipe organs is in the aŭditorium organ in the Fox Theatre. The pipe is 32
ft. long and produces a sound with a wavelength of about 8.8m. If the speed of sound in air is 346
m/s what is the frequency of this sound? What is the period? Show all work and explain your
answer. (12 pts.)
Answer:
Explanation:
Wave Period and Frequency In this video Paul Andersen explains how the period is the time between wave and the frequency is the number of ... Your browser does not currently recognize any of the video formats available. ... Show less Show more ... Waves: Light, Sound, and the nature of Reality.
A golf ball is hit horizontally off the edge of a 30 m high cliff and lands a distance of 25 m from the edge of the cliff. What was the initial vertical velocity of the golf ball?At what time did the golf ball hit the ground?What was the initial horizontal velocity of the golf ball? What was the final horizontal velocity of the golf ball?
Answer:
V₀y = 0 m/s
t = 2.47 s
V₀ₓ = 61.86 m/s
Vₓ = 61.86 m/s
Explanation:
Since, the ball is hit horizontally, there is no vertical component of velocity at initial point. So, the initial vertical velocity (V₀y) will beL
V₀y = 0 m/s
For the initial vertical velocity of golf ball we consider the vertical motion and apply 2nd equation of motion:
Y = V₀y*t + (0.5)gt²
where,
Y = Height = 30 m
g = 9.8 m/s²
t = time to hit the ground = ?
Therefore,
30 m = (0 m/s)(t) + (0.5)(9.8 m/s²)t²
t² = 30 m/4.9 m/s²
t = √6.122 s²
t = 2.47 s
For initial vertical velocity we analyze the horizontal motion of the ball. We neglect the frictional effects in horizontal motion thus the speed remains uniform. Hence,
V₀ₓ = Xt
where,
V₀ₓ = Initial vertical Velocity = ?
X = Horizontal Distance = 25 m
Therefore,
V₀ₓ = (25 m)(2.47 s)
V₀ₓ = 61.86 m/s
Due, to uniform motion in horizontal direction:
Final Vertical Velocity = Vₓ = V₀ₓ
Vₓ = 61.86 m/s
NEED HELP TODAY
Which of the following is true about the speed of light?
A. It depends on the wavelength
B. In a vaccum, it is a constant value that does not depend on the observer
C. It is the slowest in a vacuum unless the observer is moving towards the source
D. In a vacuum, it varies depending on the color of the light
Answer:
I am pretty sure it is B My friend hope you are well
Explanation:
Answer:
B- It is a constant when the light is traveling in a vacuum.
Explanation:
"Light in a vacuum always travels at the same speed." Those additional three words in a vacuum are very important. A vacuum is a region with no matter in it. So a vacuum would not contain any dust particles (unlike a vacuum cleaner, which is generally full of dust particles)
