14. Lab Analysis: You forgot to label your chemicals and do not know whether your unknown solution is strontium nitrate or magnesium nitrate. You use the solutions potassium carbonate and potassium sulfate in order to determine your mistake. unknown + potassium carbonate & unknown + potassium sulfate . Write the complete balanced molecular equation(s) below of the reaction(s) that occurred, including the states of matter. HINT: Try writing ALL possible reactions that could have been created, and then decide which reactions actually occurred.

Answers

Answer 1

Unknown + Potassium Carbonate → Potassium Nitrate + Unknown Carbonate

[tex]Sr(NO_3)_2[/tex] + [tex]K_2CO_3[/tex] → [tex]2KNO_3[/tex] + [tex]SrCO_3[/tex] (if the unknown is strontium nitrate)

[tex]Mg(NO_3)_2[/tex]+ [tex]K_2CO_3[/tex] → [tex]2KNO_3[/tex] + [tex]MgCO_3[/tex] (if the unknown is magnesium nitrate)

Here are the balanced molecular equations for the reactions that could have occurred between the unknown solution (either strontium nitrate or magnesium nitrate) and potassium carbonate and potassium sulfate: Unknown + potassium carbonate → potassium nitrate + magnesium or strontium carbonate (depending on the unknown)

Unknown + potassium sulfate → potassium nitrate + magnesium or strontium sulfate (depending on the unknown)

Unknown + Potassium Sulfate → Potassium Nitrate + Unknown Sulfate

[tex]Sr(NO_3)_2[/tex] + [tex]K_2SO_4[/tex] → [tex]2KNO_3[/tex] + [tex]SrSO_4[/tex] (if the unknown is strontium nitrate)

[tex]Mg(NO_3)_2[/tex] + [tex]K_2SO_4[/tex] → [tex]2KNO_3[/tex] + [tex]MgSO_4[/tex] (if the unknown is magnesium nitrate)

To determine which reaction occurred, you would need to observe which products were formed. If [tex]SrCO_3[/tex] or [tex]SrSO_4[/tex] were formed, then the unknown was strontium nitrate.

If [tex]MgCO_3[/tex] or [tex]MgSO_4[/tex] were formed, then the unknown was magnesium nitrate.

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Related Questions

Help what’s the answer?

Answers

Goofy kid step by step all you need to do is

Hydrogen peroxide is a compound that contains two hydrogen atoms and two oxygen atoms. Which formula represents hydrogen peroxide?.

Answers

Answer: H2O2

Explanation: The formula that represents hydrogen peroxide is H2O2

How many moles of nitrogen gas will occupy a volume of 5L at 3. 85 atm and 27c?

Answers

The number of moles of nitrogen gas that will occupy a volume of 5L at 3.85 atm and 27°C is determined using the ideal gas law equation. After calculations, it is found to be approximately 0.7919 moles. Thus, 0.7919 moles of nitrogen gas occupy 5L at 3.85 atm and 27°C.

To calculate the number of moles of nitrogen gas that will occupy a volume of 5L at 3.85 atm and 27°C, we can use the ideal gas law equation:

PV = nRT

where P is the pressure in atmospheres, V is the volume in liters, n is the number of moles, R is the gas constant (0.08206 L·atm/K·mol), and T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin:

T = 27°C + 273.15 = 300.15 K

Next, we can rearrange the ideal gas law equation to solve for the number of moles:

n = PV / RT

Plugging in the values, we get:

[tex]n = \frac{{(3.85 \, \text{atm}) \cdot (5 \, \text{L})}}{{(0.08206 \, \text{L} \cdot \text{atm/K} \cdot \text{mol}) \cdot (300.15 \, \text{K})}}[/tex]

Simplifying the expression, we get:

n = 0.7919 moles

Therefore, 0.7919 moles of nitrogen gas will occupy a volume of 5L at 3.85 atm and 27°C.

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How many grams of calcium hydroxide will be formed in this reaction when 4.44 g of calcium oxide and 7.77 g of water are available to react? also identify the limiting an excess reactants. how much excess reactant is left over in grams?

Answers

Answer:

please provide more información or a photo

Explanation:

Of you want me to hwlp you please have more infor like a picture

In the equation:
2h2 + o2 + 2h2o

a. 1 l of hydrogen reacts with 2 l of oxygen
b. 1 l of hydrogen reacts with 22.4 l of oxygen.
c. 22.4 l of hydrogen react with 1 l of oxygen
d. 2 l of hydrogen react with 1 l of oxygen

Answers

In the equation 2h2 + o2 + 2h2o, the two hydrogen molecules (H2) react with one oxygen molecule (O2) to form two molecules of water (H2O). This reaction is known as combustion and it requires a certain ratio of hydrogen to oxygen in order for the reaction to take place.

Here correct answer is D)

In this equation, the ratio of hydrogen to oxygen is 2:1. This means that for every one liter of hydrogen, two liters of oxygen are needed in order for the reaction to take place.

In answer to the questions, a) one liter of hydrogen would react with two liters of oxygen, b) one liter of hydrogen would react with 22.4 liters of oxygen, c) 22.4 liters of hydrogen would react with one liter of oxygen, and d) two liters of hydrogen would react with one liter of oxygen.

This equation is a great example of the law of conservation of mass, as the total number of atoms on each side of the equation remain the same

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I need help!

Describe the bonding in water molecule using VBT. Show the overlap of hybridized orbitals leading to the formation of H2O molecule. Account for the bond angle 104. 5°. ​

Answers

Answer:

In Valence Bond Theory (VBT), the water molecule is formed by overlapping of two hydrogen 1s orbitals with two hybridized oxygen orbitals. The oxygen atom in the water molecule has two unpaired electrons in two 2p orbitals and two paired electrons in two 2s orbitals. It hybridizes the 2s and 2p orbitals to form four hybridized sp3 orbitals. These four sp3 hybridized orbitals point towards the corners of a tetrahedron.

The two hybridized orbitals of oxygen containing unpaired electrons overlap with the 1s orbitals of two hydrogen atoms. This overlapping results in the formation of two O-H sigma (σ) bonds. The two remaining hybridized orbitals containing the paired electrons do not participate in bond formation.

The bond angle in the water molecule is 104.5°, which is less than the tetrahedral angle (109.5°) because the two lone pairs of electrons on the oxygen atom exert greater repulsion than the two bonding pairs. This causes the bonding pairs to be pushed closer together, resulting in a smaller bond angle.

Calculate the specific heat in J/(g·ºC) of an unknown substance if a 2. 50-g sample releases 12. 0 cal as its temperature changes from 25. 0ºC to 20. 0ºC. ________J/(g·°C)

Answers

The specific heat in J/(g·ºC) of an unknown substance if a 2. 50-g sample releases 12. 0 cal as its temperature changes from 25. 0ºC to 20. 0ºC. 2.02  J/(g·ºC).

The specific heat of the unknown substance can be calculated using the formula:
q = m x c x ΔT


where q is the heat released, m is the mass of the substance, c is the specific heat, and ΔT is the change in temperature.

First, we need to convert the given heat release from calories to joules:
12.0 cal x 4.184 J/cal = 50.208 J

Next, we can plug in the given values and solve for c:
50.208 J = 2.50 g x c x (25.0°C - 20.0°C)
c = 2.02 J/(g·°C)


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(01. 05 MC)






During an experiment a thermometer was placed in a beaker containing hydrogen peroxide. The following observations were recorded when yeast granules were added to hydrogen peroxide.






Observation 1: Fizzing and bubbling took place.





Observation 2: The temperature began to rise.






Based on the observation, justify the type of change (physical or chemical) that took place

Answers

When yeast granules were added to hydrogen peroxide, two observations were made: fizzing and bubbling took place, and the temperature began to rise. These observations suggest that a chemical change occurred.

Chemical changes involve a transformation of the molecular structure of a substance, resulting in the formation of new substances with different properties. In this case, the hydrogen peroxide likely reacted with the yeast granules to produce oxygen gas and water, which caused the fizzing and bubbling.

The increase in temperature may be a result of the energy released during the chemical reaction.

Physical changes, on the other hand, involve a change in the physical state or appearance of a substance, without any alteration to its molecular structure. For example, melting ice is a physical change, as the solid ice changes to liquid water, but the molecules themselves remain unchanged.

In summary, the observations of fizzing and bubbling, as well as the temperature increase, suggest that a chemical change occurred when yeast granules were added to hydrogen peroxide. This change likely involved the production of oxygen gas and water.

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Help with my chemistry homework please

Answers

The term mole concept is used here to determine the number of grams of sucrose. The mole concept is a convenient method to express the amount of the substance. The grams of sucrose is  1509.5 g.

One mole of a substance is that amount of it which contains as many particles or entities as there are atoms in exactly 12 g of carbon 12. The equation used to calculate the number of moles is:

Number of moles = Given mass / Molar mass

1. Mass = 4.41 × 342.3 = 1509.5 g

2. Moles = 350 / 105.98 = 3.302

3. Mass = 7.38 × 36.45 = 269.001 g

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A solution consisting of 11. 4 g NH4Cl in 150 ml of water is titrated with 0. 20 M KOH.



a. How many milliliters of KOH are required to reach the equivalence point?


b. Calculate {Cl-], [K+], and [NH3] at the equivalence point. Assume volumes are additive

Answers

a.It requires 1066 mL of 0.20 M KOH  to reach the equivalence point.

b.The equivalence point, the concentration of [Cl-], [K+], and [[tex]NH_{3}[/tex]] in the solution, is 0.175 M.

What is the Equivalence point?

The chemical equivalent between the added titrant and the sample analyte is called the equivalence point in a titration.

a. We need to know how many moles of [tex]NH_{4}Cl[/tex] are in the solution to calculate the volume of 0.20 M KOH needed to achieve the equivalence point.

First, we can determine how many moles  [tex]NH_{4}Cl[/tex] are present in the solution:

moles [tex]NH_{4}Cl[/tex] = mass / molar mass

moles [tex]NH_{4}Cl[/tex] = 11.4 g / 53.49 g/mol (molar mass of [tex]NH_{4}Cl[/tex])

moles [tex]NH_{4}Cl[/tex] = 0.2132 mol

At the equivalence point, all the [tex]NH_{4}Cl[/tex] has interacted with the KOH, resulting in an equal amount of moles of [tex]NH_{3}[/tex] and [tex]H_{2} O[/tex]. This suggests that 0.2132 moles of KOH are also needed to react with [tex]NH_{4}Cl[/tex] The volume of 0.20 M KOH required to react with 0.2132 mol can be determined using the equation for the reaction between [tex]NH_{4}Cl[/tex] and KOH:

[tex]NH_{4}Cl[/tex] + KOH → [tex]NH_{3}[/tex] + [tex]H_{2}O[/tex] + KCl

moles KOH = moles [tex]NH_{4}Cl[/tex]

                   = 0.2132 mol

volume of KOH = moles KOH / concentration of KOH

                          = 0.2132 mol / 0.20 mol/L

                           = 1.066 L or 1066 mL

Therefore, 1066 mL of 0.20 M KOH is required to reach the equivalence point.

b. At the equivalence point, an equal amount of moles of KOH and [tex]NH_{4}Cl[/tex] interacted to create [tex]NH_{3}[/tex], [tex]H_{2}O[/tex], and KCl.

We may determine the concentration of [Cl-] and [K+] in the solution following the reaction at the equivalence point by assuming volumes are additive:

moles KCl = moles [tex]NH_{4}Cl[/tex]

                 = 0.2132 mol

volume of solution = 150 mL + volume of KOH added

                                = 150 mL + 1066 mL

                                = 1216 mL

                                 = 1.216 L

[Cl-] = moles KCl / volume of solution

[Cl-] = 0.2132 mol / 1.216 L

[Cl-] = 0.175 M

[K+] = moles KCl / volume of solution

[K+] = 0.2132 mol / 1.216 L

[K+] = 0.175 M

The fact that the reaction between [tex]NH_{4}Cl[/tex]and KOH is a one-to-one reaction can be used to compute the concentration of [[tex]NH_{3}[/tex]]. As a result, 0.2132 mol of NH3 is likewise created at the equivalence point. Using the overall volume of the solution, we can get the [[tex]NH_{3}[/tex]] concentration:

[[tex]NH_{3}[/tex]] = moles [tex]NH_{3}[/tex]/ total volume of solution

[[tex]NH_{3}[/tex]] = 0.2132 mol / 1.216 L

[[tex]NH_{3}[/tex]] = 0.175 M

Therefore, at the equivalence point, the concentration of [Cl-], [K+], and [[tex]NH_3}[/tex]] in the solution is 0.175 M.

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Calculate the molarity of the solutions described below. Round all answers to 2 decimal places. Hint: Use molar mass and dimensional analysis to convert grams into moles. A) 100.0 g of sodium chloride is dissolved in 3.0 L of solution. Answer: 0.57 M B) 72.5 g of sugar (C12H22O11) s dissolved in 1.5 L of solution. Answer: 0.13 M C) 125 g of aluminum sulfate is dissolved in 0.150 L of solution. Answer: M D) 1.75 g of caffeine (C8H10N4O2) is dissolved in 0.200 L of solution. Answer: M

Answers

Explanation:

A) To calculate the molarity of sodium chloride solution, we need to first convert the mass of sodium chloride into moles, using its molar mass of 58.44 g/mol:

100.0 g NaCl × (1 mol NaCl/58.44 g NaCl) = 1.71 mol NaCl

Then, we divide the number of moles by the volume of solution in liters to get the molarity:

Molarity = 1.71 mol NaCl ÷ 3.0 L = 0.57 M

Therefore, the molarity of the sodium chloride solution is 0.57 M.

B) To calculate the molarity of sugar (C12H22O11) solution, we need to first convert the mass of sugar into moles, using its molar mass of 342.3 g/mol:

72.5 g C12H22O11 × (1 mol C12H22O11/342.3 g C12H22O11) = 0.212 mol C12H22O11

Then, we divide the number of moles by the volume of solution in liters to get the molarity:

Molarity = 0.212 mol C12H22O11 ÷ 1.5 L = 0.13 M

Therefore, the molarity of the sugar solution is 0.13 M.

C) To calculate the molarity of aluminum sulfate solution, we need to first convert the mass of aluminum sulfate into moles, using its molar mass of 342.2 g/mol:

125 g Al2(SO4)3 × (1 mol Al2(SO4)3/342.2 g Al2(SO4)3) = 0.365 mol Al2(SO4)3

Then, we divide the number of moles by the volume of solution in liters to get the molarity:

Molarity = 0.365 mol Al2(SO4)3 ÷ 0.150 L = 2.43 M

Therefore, the molarity of the aluminum sulfate solution is 2.43 M.

D) To calculate the molarity of caffeine (C8H10N4O2) solution, we need to first convert the mass of caffeine into moles, using its molar mass of 194.2 g/mol:

1.75 g C8H10N4O2 × (1 mol C8H10N4O2/194.2 g C8H10N4O2) = 0.009 mol C8H10N4O2

Then, we divide the number of moles by the volume of solution in liters to get the molarity:

Molarity = 0.009 mol C8H10N4O2 ÷ 0.200 L = 0.045 M

Therefore, the molarity of the caffeine solution is 0.045 M

Answer:

Hi and sorry.

But what is the question in that?

There is already answers so i don't know how to help you.

Explanation:

Combustion of 13. 5 g of sample of an hydrocarbon yields 24. 41 g CO2 and 14. 49 g H2O. The molar mass of the compound is 246 g/mol. What are the empirical and molecular formulas?

Answers

1. Moles of CO₂ is 0.8047.

2. Moles of C is 1.6094.

3. C:H ratio is 1:3.

4. The Emperial formula is c6H6.

5. Emperical formula mass is 78g/mol.

1. Moles of CO₂ = 24.41 g / 44.01 g/mol = 0.5548 mol; Moles of H₂O = 14.49 g / 18.02 g/mol = 0.8047 mol


2. Moles of C = 0.5548 mol (1 C atom in CO₂); Moles of H = 0.8047 mol * 2 (2 H atoms in H₂O) = 1.6094 mol


3. C:H ratio = 0.5548:1.6094 ≈ 1:3 (divide by smallest value), but 1:2.89 is closer, which gives a ratio of 6:6 (multiply by 3 to get whole numbers)


4. Empirical formula: C₆H₆


5. Empirical formula mass: (6 * 12.01) + (6 * 1.01) = 78 g/mol. Molecular formula: (246 g/mol) / (78 g/mol) = 3; C₆H₆ * 3 = C₁₂H₁₂ (molecular formula)

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Arrange the acids h2se, h2te, and h2s in order of increasing acid strength.

Answers

The acid strength increases with increasing acidity, which is the tendency to donate a proton (H+). H2Te < H2Se < H2S

The acidity of an acid is related to its acid dissociation constant (Ka). The higher the Ka, the stronger the acid.

The Ka values for the given acids are:

H2S: Ka = [tex]9.0 × 10^-8[/tex]

H2Se: Ka = [tex]1.3 × 10^-8[/tex]

H2Te: Ka = [tex]3.3 × 10^-9[/tex]

Therefore, the order of increasing acid strength is:

H2Te < H2Se < H2S

This is because H2Te has the lowest Ka value, indicating that it is the weakest acid of the three. Conversely, H2S has the highest Ka value, indicating that it is the strongest acid of the three.

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HELP CHEMISTRY!! What does the hump in the middle of each energy diagram represent? (exothermic & endothermic diagrams)

Answers

Answer:

Activation Energy

Explanation:

















I know you dont need this

3. A 385 g drinking glass is filled with a hot liquid. The liquid transfers 7032 J of energy to the glass. If the
temperature of the glass increases by from 12 to 24°C, what is the
specific heat of the glass?

Answers

The specific heat of the glass is 1.58 J/(g°C).

The specific heat of a substance is the amount of energy required to raise the temperature of one unit of mass of the substance by one degree Celsius.

To find the specific heat of the glass, we can use the formula:

Q = mcΔT

where Q is the amount of energy transferred to the glass, m is the mass of the glass, c is the specific heat of the glass, and ΔT is the change in temperature of the glass.

We are given:

m = 385 g

Q = 7032 J

ΔT = 24°C - 12°C = 12°C

Substituting these values into the formula, we get:

7032 J = (385 g) c (12°C)

Solving for c, we get:

c = 7032 J / (385 g * 12°C)

c = 1.58 J/(g°C)

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PLEASE HELP QUICKLY
The diagram shows the potential energy changes for a reaction pathway. (10 points)

Part 1: Does the diagram illustrate an endothermic or an exothermic reaction? Give reasons in support of your answer.

Part 2: Describe how you can determine the total change in enthalpy and activation energy from the diagram and if each is positive or negative.

Answers

Part 1: This diagram depicts an endothermic reaction. Because the products have a higher potential energy than the reactants, energy is absorbed during the reaction.

Furthermore, the energy level of the products is greater than the reaction's activation energy, showing that energy must be given to the system for the reaction to occur.

Part 2: To calculate the total enthalpy change (H) from the diagram, subtract the energy of the reactants from the energy of the products. Because the energy of the products is greater than the energy of the reactants in an endothermic reaction, H will be positive.

To calculate the activation energy (Ea) from the diagram, subtract the energy of the reactants from the energy of the transition state. The activation energy is the smallest amount of energy required for the reaction to occur, hence it is the difference in energy between the reactants and the highest point on the diagram.

Ea will be positive in this situation because energy must be added to the system to achieve the transition state.

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yellow scale lichen on rock
a population
On a rock in coastal Maine, the fungus, the algae, and the bacteria make up which of the
following? Select all that apply.
part of a community
Lichen growing on a rock in coastal
Maine may appear to be a single
organism. But lichen is actually
formed when algae and fungi grow
together.
part of an ecosystem
These different organisms live
together in a symbiotic relationship. In
the yellow scale lichen, the fungus
provides protection, moisture, and
nutrients for the algae. The algae
carry out photosynthesis to produce
food that is used by the fungus.
Different type of bacteria may also live
within the fungus.
WILL MARK BRAINIEST

Answers

On a rock in coastal Maine, the fungus, the algae, and the bacteria make up part of an ecosystem.

What is ecosystem?

An ecosystem consists of all the organisms and the physical environment with which they interact.

In the yellow scale lichen, the fungus provides protection, moisture, and nutrients for the algae. The algae carry out photosynthesis to produce food that is used by the fungus.

Ecosystem function is generally described as the capacity of natural processes and components to provide goods and services that satisfy human needs, either directly or indirectly.

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Write a conversation between you and your friend about a job agency and it's reliability. ​

Answers

When discussing a job agency and its reliability, a conversation between friends may touch on several aspects of the agency's services. They might consider the agency's reputation within the industry, the quality of the jobs the agency offers, and the level of support they provide to job seekers.

The agency's reputation, screening process, communication, and track record, the conversation might also touch on other factors that can affect an agency's reliability. These may include the types of industries and job roles the agency specializes in, the geographic region it serves and the fees it charges for its services.

If the agency primarily focuses on entry-level jobs or temporary positions, it may not be the best fit for job seekers looking for long-term career growth. If the agency only operates in a specific region or industry, it may not be able to offer the same level of job opportunities as larger agencies with a broader reach.

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The solubility of a gas is 0. 650 g/L at a pressure of 109 kPa. What is the solubility of the gas if the pressure is increased to 131 kPa?

Answers

The solubility of the gas increases to 0.780 g/L when the pressure is increased to 131 kPa.

According to Henry's law, the solubility of a gas in a liquid is directly proportional to the pressure of the gas above the liquid. Thus, we can use the following equation to calculate the new solubility:

S₂ ÷ S₁ = P₂ ÷ P₁

where S₁ is the initial solubility, S₂ is the new solubility, P₁ is the initial pressure, and P₂ is the new pressure.

Plugging in the given values, we have:

S₂ ÷ 0.650 g/L = 131 kPa ÷ 109 kPa

Solving for S₂, we get:

S₂ = (0.650 g/L) × (131 kPa ÷ 109 kPa)

S₂ = 0.780 g/L

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1.

What is the boiling point of a solution prepared by dissolving 2. 50 g of biphenyl (C12 H10)

in 85. 0 g of benzene. The molecular weight of biphenyl is 154 g. ​

Answers

The boiling point of the solution is 80.58 °C, which is prepared by dissolving 2. 50 g of biphenyl (C₁₂ H₁₀).

To determine the boiling point of the solution, we need to use the equation;

Δ[tex]T_b}[/tex] = [tex]K_{b}[/tex] x m

Where ΔTb is boiling point elevation, is molal boiling point elevation constant, and m is molality of the solution.

First, we to calculate the molality of the solution;

moles of biphenyl =2.50 g / 154 g/mol

= 0.0162 mol

mass of benzene = 85.0 g

moles of benzene = 85.0 g / 78.11 g/mol

= 1.088 mol

molality = moles of solute/mass of solvent (in kg)

molality = 0.0162 mol / 0.085 kg

= 0.19 mol/kg

Next, we need to look up the molal boiling point elevation constant ([tex]K_{b}[/tex]) for benzene. The value of [tex]K_{b}[/tex] for benzene is 2.53 °C/m.

Finally, we alculate the boiling point elevation;

Δ[tex]T_b}[/tex] = [tex]K_{b}[/tex] x m

Δ[tex]T_b}[/tex] = 2.53 °C/m x 0.19 mol/kg

= 0.481 °C

The boiling point elevation (Δ[tex]T_b}[/tex]) is the difference between the boiling point of the solution and the boiling point of the pure solvent. The boiling point of pure benzene is 80.1 °C. Therefore, the boiling point of the solution will be;

Boiling point of solution = 80.1 °C + 0.481 °C

= 80.58 °C

So, the boiling point of the solution is 80.58 °C.

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Why is there no relation between reactant and product molecules in redox reactions

Answers

Answer:

Explanation:

In redox (reduction-oxidation) reactions, the transfer of electrons between species occurs. As a result, the number of atoms and molecules of the reactants and products can be different. This is because, during the reaction, electrons can be gained or lost by the atoms, leading to the formation of new species with different numbers of atoms.

For example, consider the reaction between copper and silver ions in a solution:

Cu(s) + 2Ag+(aq) → Cu2+(aq) + 2Ag(s)

In this reaction, one copper atom reacts with two silver ions to form one copper ion and two silver atoms. The number of reactant molecules does not necessarily match the number of product molecules.

Therefore, in redox reactions, the relationship between reactant and product molecules is not necessarily direct, and the number of atoms or molecules in the reactants and products can be different due to electron transfer.

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Describe the following mixtures by checking all of the terms that apply.

Cranberry juice smoke

THESE ARE THE ANSWERS!!!!!

Answers

The appropriate term for the following mixtures are;

Cranberry juice: homogeneous, solution Smoke: heterogeneous, colloid

What is a mixture?

A mixture is a substance made when two or more substances are combined, but they are not combined chemically.

The components of a mixture can be easily separated because each component keep their original properties or identity.

A homogenous mixture is a gaseous, liquid or solid mixture that has the same proportions of its components throughout a given sample e.g. juice while heterogenous mixture is a mixture in which the composition is not uniform throughout the mixture e.g. smoke.

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Answer:

Its in my screenshot

Explanation:

Calculate the amount of electrical energy (in kWh) needed to produce
1.00E3 kg of aluminum using electrolysis if the applied voltage is 6.00 V. (1
kWh = 3.6E6 J)

Answers

The amount of electrical energy (in kWh) needed to produce 1 kWh of electrical energy is 1 kWh or 3.6E6 J. The actual amount of energy needed may vary depending on the efficiency of the power generation system used.

A kilowatt-hour is a unit of energy commonly used by electric companies to measure the amount of energy consumed by households or businesses over a period of time. One kilowatt-hour (kWh) is equal to the amount of energy consumed by a 1,000 watt appliance for one hour.
We know that 1 kWh is equal to 3.6E6 J (joules). This means that to produce 1 kWh of electrical energy, we need to generate 3.6E6 J of energy.

In practical terms, the amount of electrical energy needed to produce 1 kWh depends on the efficiency of the power generation system. For example, a coal-fired power plant may require more energy input (e.g. coal) to generate 1 kWh of electrical energy compared to a renewable energy source such as solar or wind power.

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A balloon with 0. 50 L of nitrogen is placed in a freezer at 273 K. What will the new


volume be if the temperature of the balloon is raised to 325 K when removed from the


freezer?

Answers

The new volume of the balloon at a temperature of 325 K is approximately 0.59 L.

We use the combined gas law to solve this problem, which relates the pressure, volume, and temperature of the gas;

P₁V₁/T₁ = P₂V₂/T₂

where P is pressure, V is volume, and T temperature.

We know the initial volume (V₁) is 0.50 L and the initial temperature (T₁) is 273 K. We also know that the pressure remains constant, so we can set P₁ = P₂. Finally, we need to find V₂, the new volume at a temperature of T₂ = 325 K.

Substituting these values into the equation, we get;

P₁V₁/T₁ = P₂V₂/T₂

P₁ (0.50 L)/(273 K) = P₂ V₂/(325 K)

Simplifying, we get;

V₂ = (P₁/P₂) × (T₂/T₁) × V₁

We don't know the pressure of the gas, but we know it remains constant, so we can cancel it out;

V₂ = (T₂/T₁) × V₁

Plugging in the numbers, we get:

V₂ = (325 K/273 K) × 0.50 L

V₂ = 0.59 L

Therefore, the new volume of the balloon is 0.59 L.

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What mass of sucrose (C12H22011) must be burned in order to liberate


27,584 KJ?


Show all work

Answers

1674.64 g of sucrose must be burned to liberate 27,584 KJ.

To find the mass of sucrose (C₁₂H₂₂O₁₁) that must be burned to liberate 27,584 KJ, you'll need to use the heat of combustion and the following equation:
mass of sucrose = (energy required) / (heat of combustion)

First, find the heat of combustion of sucrose. The heat of combustion of sucrose is approximately -5640 KJ/mol.
Next, convert the energy required from KJ to mol by dividing by the heat of combustion:
mol sucrose = 27,584 KJ / (-5640 KJ/mol) = -4.89 mol

(Note that the negative sign indicates the reaction is exothermic, but we're interested in the magnitude of the value, so we'll proceed with the absolute value.)

Now, calculate the molar mass of sucrose:
C₁₂H₂₂O₁₁ = (12 × 12.01) + (22 × 1.01) + (11 × 16.00) = 144.12 + 22.22 + 176.00 = 342.34 g/mol

Finally, calculate the mass of sucrose by multiplying the moles by the molar mass:
mass of sucrose = 4.89 mol × 342.34 g/mol = 1674.64 g
So, approximately 1674.64 g of sucrose must be burned to liberate 27,584 KJ.

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Part A
Predict the sign of the entropy change, ΔS∘, for each of the reaction displayed.
Drag the appropriate items to their respective bins.
Help
Reset
Ag+(aq)+Cl−(aq)→AgCl(s)
2KClO3(s)→2KCl(s)+3O2(g)
2N2O(g)→2N2(g)+O2(g)
2Mg(s)+O2(g)→2MgO(s)
C7H16(g)+11O2(g)→7CO2(g)+8H2O(g)
H2O(l)→H2O(g)
Positive
Negative
SubmitHintsMy AnswersGive UpReview Part
Part B
Calculate the standard entropy change for the reaction
2Mg(s)+O2(g)→2MgO(s)
using the data from the following table:
Substance ΔH∘f (kJ/mol) ΔG∘f (kJ/mol) S∘ [J/(K⋅mol)]
Mg(s) 0.00 0.00 32.70
O2(g) 0.00 0.00 205.0
MgO(s) -602.0 -569.6 27.00
Express your answer to four significant figures and include the appropriate units.
ΔS∘ =

Answers

The standard entropy change for the reaction [tex]2Mg(s)+O_2(g)\rightarrow 2MgO(s)[/tex] is -405.6 J/(K⋅mol).

What is entropy ?

Entropy is a measure of the randomness or disorder in a system. It is a thermodynamic property that can be used to measure the amount of energy that is unavailable for work in a thermodynamic process. Entropy is closely related to the second law of thermodynamics and can be used to assess the direction of a thermodynamic process. Entropy is also a measure of the amount of information contained in a system. High entropy systems have more randomness and disorder, while low entropy systems have less.

The entropy change for the reaction [tex]2Mg(s)+O_2(g) \rightarrow 2MgO(s)[/tex] is calculated using the following equation: [tex]\Delta S^\circ = \Sigma S^\circ products -\Sigma S^\circ reactants[/tex]

Substituting the values from the table:

[tex]\Delta S^\circ = (2 \times 27.00 J/(Kmol)) - (32.70 J/(Kmol) + 205.0 J/(Kmol))\\\Delta S^\circ = -405.6 J/(Kmol) .[/tex]

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HELP ME PLEASEEEE


The student produced less magnesium oxide than expected.

Suggest two reasons why.

Answers

There could be several reasons why a student produced less magnesium oxide than expected. Here are two possibilities: Incomplete reaction,  Loss of product

Incomplete reaction: Magnesium oxide is produced when magnesium metal is heated in the presence of oxygen. However, if the reaction is incomplete, then less magnesium oxide will be produced. One reason for incomplete reaction could be that the temperature was not high enough to provide the necessary activation energy.

Loss of product: It is possible that some of the magnesium oxide that was produced was lost during the experiment. For example, if the magnesium oxide was not handled carefully after it was produced, it may have been spilled or blown away.

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The following reaction occurs when a burner on a gas stove is lit:


CH4(g) + 2O2(g) ⇄ CO2(g) + 2H20(g)


Evaluate the following statements and select the correct grouping. True statements are marked with a T, and false statements are marked with an F.


The system cannot reach equilibrium because it is not a closed system.

Increasing the concentration of the CH4 will increase the production of CO2 and water.

Increasing the temperature of the flame will increase the production of CO2 and water.

Adding CO2 will increase the volume of methane and oxygen

Answers

The correct grouping is:

F, T, T, F

Explanation:

- The first statement is false. Although the system is not closed in the strictest sense, it can still reach equilibrium because the reactants and products are all gases and can interact with each other.
- The second statement is true. According to Le Chatelier's principle, increasing the concentration of a reactant will shift the equilibrium towards the products, in this case, CO2 and water.
- The third statement is also true. Increasing the temperature will increase the rate of the forward reaction, causing the equilibrium to shift towards the products.
- The fourth statement is false. Adding CO2 to the system will not affect the volume of methane and oxygen. It may, however, affect the equilibrium position by shifting it towards the reactants, as Le Chatelier's principle predicts that adding a product will shift the equilibrium towards the reactants.

What is the volume of a 2. 00 M solution that contains 3. 75 moles of solute?

Answers

The volume of a 2.00 M solution that contains 3.75 moles of solute can be calculated using the formula V = n/C, where V is the volume of the solution, n is the number of moles of solute, and C is the concentration of the solution in units of M (moles per liter).

Plugging in the given values, we get V = 3.75 moles / 2.00 M = 1.88 L. Therefore, the volume of the solution is 1.88 liters. In 100 words, the volume of a solution can be determined by knowing the amount of solute present and the concentration of the solution.

This is because the concentration of a solution is defined as the amount of solute dissolved in a given volume of solution. Using the formula for concentration, we can determine the amount of solute dissolved in a given volume of solution.

Then, by rearranging the formula to solve for volume, we can determine the volume of the solution required to dissolve a specific amount of solute.

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Which term names the result of two or more atoms combining chemically?.

Answers

The term that names the result of two or more atoms combining chemically is a molecule.

A molecule is formed when two or more atoms combine chemically by sharing electrons in a covalent bond.

This bonding occurs when atoms have unpaired electrons in their outermost shell, and they share these electrons to complete their valence shells. In a covalent bond, the electrons are shared between atoms, rather than being transferred, as in an ionic bond.

Molecules can be formed between atoms of the same element or different elements, depending on the chemical properties of the atoms.

For example, two oxygen atoms can combine to form an oxygen molecule (O2), while a hydrogen atom can combine with an oxygen atom to form a water molecule (H2O).

Molecules are the building blocks of all substances in the universe. They are responsible for the chemical and physical properties of substances, such as their melting and boiling points, solubility, and reactivity.

Understanding the formation and behavior of molecules is essential for understanding chemistry and the world around us.

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