Explanation:
KE = 1/2mv^2
6,250 J =1/2(250kg) v ^2
6250 J = 125kgv^2
125kg. 125kg
v =
[tex] \sqrt{50} [/tex]
What is physical activity?
Answer:
answer is b. any movement that uses your muscles and requires energy
Explanation:
PLEASE HELP !!
Elements in period 2 on the periodic table all have blank
electron shells.
Answer:
Two orbitals for their electrons and six in the 2p subshell
Explanation:
Hope this helps :)
Temperature is
SELECT ALL THAT APPLY
a measurement of thermal energy
a constant value
able to change based on surrounding energy
conditions
equal to heat
Answer:
The 1st and the 3rd answer
A car traveling at 25 meters per second is brought to stop by a force over a 10 second timer interval. What was the acceleration of the car during the 10 second time interval.
Answer:
–2.5 m/s²
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 25 m/s
Final velocity (v) = 0 m/s
Time (t) = 10 s
Acceleration (a) =?
Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it can be expressed as:
a = (v – u) /t
Where:
a => is the acceleration
v => is the final velocity
u => is the initial velocity
t => is the time.
With the above formula, we can obtain the acceleration of the car as follow:
Initial velocity (u) = 25 m/s
Final velocity (v) = 0 m/s
Time (t) = 10 s
Acceleration (a) =?
a = (v – u) /t
a = (0 – 25) /10
a = –25 / 10
a = –2.5 m/s²
The acceleration of the car is –2.5 m/s². The negative sign indicate that the car is decelerating i.e coming to rest.
Which has more potential energy: a baseball held 1 m above the ground or a baseball held 2 m above the ground?
The baseball held 2 meters above the ground has more potential energy than the baseball held 1 meter above the ground.
The potential energy can be calculated with the following equation:
[tex] E_{p} = mgh [/tex]
Where:
m: is the mass of the baseball
g: is the acceleration due to gravity
h: is the height
We can see from equation (1) that the potential energy depends on height, mass, and gravity. Since the question refers to the same baseball, the mass is constant besides the acceleration due to gravity, so:
Potential energy above 1 m[tex] E_{p_{1}} = mg*1 = mg [/tex] (1)
Potential energy above 2 m[tex] E_{p_{2}} = mg*2 = 2mg [/tex] (2)
By entering equation (1) into 2 we have:
[tex] E_{p_{2}} = 2mg = 2E_{p_{1}} [/tex]
Hence, the potential energy of the baseball held 2 m above the ground is twice that of the baseball held 1 m above the ground.
Therefore, the baseball held 2 m above the ground has more potential energy.
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If you pedal harder so the bike tires push against the ground with
more force, what will happen to the bike?
Please helppp!!!
Answer:
friction from the ground rubs on the tire which gives it more force to move forward,
Explanation: without friction the bike wont be able to use the motion to move forward. but the tires start to wear out easily.
Whatb19 ÷117= some help me with this
Answer:
0.16239316239316239316239
Explanation:
ang haba nang solve ko dito hehe
A man pushed the box with a force of 20 N. The mass of the box doubled, but he still pushed with a force of 20 N.
Which option describes how the acceleration of the box after the mass was doubled?
a) The acceleration is 2x the original acceleration
b) Acceleration is 4x the original acceleration
c) Acceleration is 1/2x the original acceleration
d) Acceleration is 1/4x the original acceleration
Answer:
Option (c) Acceleration is 1/2x the original acceleration
Explanation:
To know the the correct answer to the question, we shall determine the acceleration of the box in each case.
Case 1:
Mass (m) = m
Force (F) = 20 N
Acceleration 1 (a₁) =?
F = ma₁
20 = m × a₁
Divide both side by m
a₁ = 20 / m
Case 2:
Mass (m) = 2m
Force (F) = 20 N
Acceleration 2 (a₂) =?
F = ma₂
20 = 2m × a₂
Divide both side by 2m
a₂ = 20 / 2m
a₂ = 10 / m
Finally, we shall determine the acceleration of the box after the mass was doubled. This can be obtained as illustrated below:
Acceleration 1 (a₁) = 20 / m
Acceleration 2 (a₂) = 10 / m
a₂ : a₁ = 10 / m : 20 / m
a₂ / a₁ = 10 / m ÷ 20 / m
a₂ / a₁ = (10 / m) × (m / 20)
a₂ / a₁ = ½
Cross multiply
a₂ = ½a₁
Thus, the acceleration of the box after the mass was doubled is ½ times the original acceleration.
Identify the relationship between strong forces and electric forces in the nucleus.
A. Both forces push protons apart
B. Both forces act only on neutrons
C. Strong forces only act on neutrons and electric forces act only pn proton.
D. Strong forces oppose electric forces.
Answer:
C
Explanation:
The strong force holds together quarks, the fundamental particles that make up the protons and neutrons of the atomic nucleus, and further holds together protons and neutrons to form atomic nuclei. As such it is responsible for the underlying stability of matter.
Suppose 550 g of water at 32 degrees * C is poured into a 210 - g aluminum can with an initial temperature of 15 degrees * C . Find the final temperature of the system, assuming that no thermal energy is exchanged with the surroundings.
Answer:
about 30.714degC
Explanation:
Assuming
specific heat of water at 4200 J/kg * K
specific heat of aluminum 900 J/kg * K
(actual values to higher precision differ, and also change slightly with temperature).
To raise the aluminum's temp by 1K we need 900J * (210g / 1kg) = 189J
189J given by the water decreases its temp by 1K * (189J / 4200J) * (1kg / 550g) = 0.0(81)K.
So every K the temp of aluminum rises, 0.0(81)K falls the temp of the water.
At a difference of (32degC - 15degC) = 17K, we infer the temp will balance out after 17K / (1K + 0.0(81)K) "steps", so about 15.714.
The final temperature will be around 30.714degC
The final temperature of the water-aluminum mixture is 30.7 ⁰C.
The given parameters;
mass of the water, = 550 ginitial temperature of the water, = 32⁰Cmass of the aluminum, 210 ginitial temperature of the aluminum = 15⁰ Cspecific heat capacity of water = 4.184 J/g⁰Cspecific heat capacity of aluminum = 0.9 J/g⁰CThe final temperature of the mixture is determined by applying the principle of conservation of energy;
Heat lost by the water = Heat gained by the aluminum
[tex]mc_w \Delta t = mc_{AL} \Delta t\\\\550 \times 4.184 \times (32 - t) = 210\times 0.9 \times (t - 15)\\\\73638.4 - 2301.2t = 189t - 2835\\\\76473.4 = 2490.2t\\\\t =\frac{76473.4}{2490.2} \\\\t = 30.7 \ ^0C[/tex]
Thus, the final temperature of the water-aluminum mixture is 30.7 ⁰C.
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The graph show a distance travelled by four cars (A, B, C& D) over a period of time . Which car travelled at a greatest speed? *
Answer:
Car A traveled with the greatest speed.
Explanation:
We know that the steepness of the slope of the line on the distance-time graph represents speed.
Important Tip:
If the slope of the line is more vertical — steep — the speed will be fast.If the slope of the line is more horizontal — flatter — the speed will be slow.For example, at t = 5 seconds, the A car has covered more than 80 meters while all the other cars have covered less than 80 meters during the same period.
IIn fact, during the entire journey, it is clear that from the graph that the slope of the line of A car is more vertical — steep — than the slopes of cars B, C, and D.
Therefore, car A traveled with the greatest speed.
What can be used to plot the magnetic field around a bar magnet?
Answer:
A bar magnet creates a magnetic field around it. The field cannot be seen, but its effects can be observed. This is how the magnetic field around a magnet is detected. Iron fillings can be used to study the presence of magnetic field and a compass can be used to plot the field lines.
Explanation:
34 Which of these human characteristics shows discontinuous variation?
A blood group
B hair color
C height
D weight
Answer:
Blood group
Explanation:
Answer:
A. Blood group.
Explanation:
They could purely random genetic changes.
HELP ASAP!!! The gravitational pull of the Moon is much less than the
gravitational pull of Earth.
Which two statements are true for an object with a mass of 20 kilograms that
weighs 44 pounds on Earth?
O A The object's weight would be the same on the Moon
B. The object's weight would be less on the Moon
C. The object's mass would be the same on the Moon
DD. The object's mass would be less on the Moon
Answer:
I'm pretty sure its B and C
Explanation:
B bc the weight is gravitational pull x mass so when the object has same mass the weight is smaller on moon
C bc mass is the same - you can't change it
The correct answers are B and C
An apple in a tree has a GPE of 175 J and a mass of 0.36 KG how high from the ground is the apple Solve for  height
Answer:
The height of the apple from the ground is at 49552.61071 m or is approximately at 5.0 × 10 m
Explanation:
the gazelle travels 2 km in a half hour.The gazelle's average speed is:
1/2 kmh
1km/h
4km/h
Answer:
distance =2km
time =1/2hour
speed =distance /time =2/1/2=4km/h
The average speed of the gazelle is equal to 4 Km/h. Therefore, option (C) is correct.
What is the average speed?The average speed can be defined as the total distance traveled in a fixed interval of time. It can be determined by dividing the total distance traveled by the total time.
The average velocity of the object is a single value if the object moves uniformly, it will travel the same distance in the same interval of time.
The mathematical expression for the average speed is as follows:
The average speed = Total distance covered/Total time taken
Given, the distance traveled by gazelle = 2 Km
The time taken by the gazelle to travel this distance = 1/2 hr = 0.5 hr
The average speed = 2Km/ 0.5 hr = 4 Km/hr
Therefore, the gazelle's average speed is equal to 4 Km/hr.
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4.Your friend tells you the weight of aparticular sample of chalk is 17.85 grams. Is there anything wrong with your friend ’statement?
A. No, because grams are the right units for weight.
B. No, because mass and weight are really the same thing.
C.Yes, because your friend should have reported the mass in kilograms.
D. Yes, because mass and weight are measured in different units
Answer:
A i tooook theee quizzz too
A space station travels 5000 kilometers in 4 hours. What is its speed?
Group of answer choices
20000 kilometers/hour
12500 kilometers/hour
2000 kilometers/hour
1250 kilometers/hour
Answer:
it is 1250 because it moves 5000 in four hours then it means that it is moving at 1250 an hour
Explanation:
A school bus uses petroleum as chemical potential energy. This energy
is
transferred through the engine, which in turn moves the bus. The movement of the
bus is an example of what type of energy?
Answer: kinetic
Explanation: Just took a test and it was right
PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer this correctly!!!! (40pts)
Answer: According to http://www.scifun.org, "Bernoulli's Principle says that the pressure decreases inside a stream of flowing air. When the balloon begins to move out of this low pressure stream, the higher pressure of the air in the room pushes it back into the moving stream"
why sounds hear clearly at night than day?
No one give proper answer.
when you carry the 2 and add the 3 its Z
NEED HELP HELP HELP WILL GIVE BRAINLIST PLEASE
DESCRIBE THE IMAGE FORMS WHEN THE OBJECT NEAR TO THE CONCAVE MIRROR
Hope it helps
. A boy wishes to throw a ball through a house via two small openings, one in the front and the other in
the back window, the second window being directly behind the first. If the boy stands at a distance of 5m
in front of the house and the house is 6m deep and if the opening in the front window is 5m above him
and that in the back window 2m higher, calculate the velocity and the angle of projection of the ball that
will enable him to accomplish his desire.
Answer:
1) The angle of projection of the ball is approximately 52.496° above the horizontal
2) The velocity with which the boy throws the ball to enable him accomplish his desire is approximately 14.769 m/s
Explanation:
In the projectile motion of the ball, the parameters are;
The distance the boy stands from the front of the house = 5 m
The depth of the house, front to back = 6 m
The height of the opening of the front window above him = 5 m
The height of the back window = 2 m higher than the front window
Therefore, the height of the back window = 5 m + 2 m = 7 m
1) The general formula for the vertical height of a parabolic projectile motion is given as follows;
y = a·x² + b·x + c
At y = 0, x = 0, therefore, c = 0
At y = 5, x = 5, we have;
5 = a·5² + b·5
∴ 5 = 25·a + 5·b...(1)
At y = 7, x = 11, we have;
7 = a·11² + b·11
7 = 121·a + 11·b...(2)
Making 'a' the subject of equation (1) and (2) and equating both values of 'a' gives;
For equation (1);
a = (5 - 5·b)/25 = 1/5 - b/5
a = 1/5 - b/5
For equation (2);
a = (7 - 11·b)/121 = 7/121 - b/11
a = 7/121 - b/11
∴ 1/5 - b/5 = 7/121 - b/11
1/5 - 7/121 = b/5 - b/11
86/605 = 6·b/55
b = (86/605) × (55/6) = 43/33
b = 43/33
a = 1/5 - b/5 = 1/5 - (43/33)/5 = -2/33
∴ y = (-2/33)·x² + (43/33)·x
The slope of the curve = dy/dx = d((-2/33)·x² + (43/33)·x)/dx = -4/33·x + 43/33
The slope of the curve at any point on the projectile = -4/33·x + 43/33
The slope at the origin is given by plugging x = 0 as follows
The slope at the origin = -4/33 × 0 + 43/33 = 43/33
The slope at the origin = tan(θ) = 43/33
Where;
θ = The angle of projection of the ball
∴ θ = arctan(43/33) ≈ 52.496°
The angle of projection of the ball, θ ≈ 52.496° above the horizontal
2) At the back widow, the equation for the vertical height, 'h', is given as follows;
[tex]h = (tan \angle \theta) \cdot x - \left(\dfrac{g}{2 \cdot v_1^2 \cdot cos^2 \angle \theta } \right )\cdot x^2[/tex]
Where;
h = The vertical height of the back window = 7 m
tan∠θ = 43/33
x = The horizontal distance of the back window from the boy = 5 m + 6 m = 11 m
g = The acceleration due to gravity = 9.8 m/s²
v₁ = The velocity with which the boy throws the ball
cos²∠θ = cos²(arctan(43/33)) = 1089/2938
Plugging in the values gives;
[tex]7 = \left (\dfrac{43}{33} \right) \times 11 - \left(\dfrac{9.8}{2 \cdot v_1^2 \cdot \dfrac{1089}{2938} } \right )\cdot 11^2[/tex]
[tex]\therefore v_1^2 = \dfrac{71981}{330}[/tex]
[tex]\therefore v_1 = \sqrt{\dfrac{71981}{330}} \approx \pm14.769[/tex]
The velocity with which the boy throws the ball to enable him accomplish his desire, v₁ ≈ 14.769 m/s.
If an object is placed between a convex lens and its focal point, which type of image will be produced?
A.
real, inverted, and magnified
B.
real, upright, and smaller
C.
virtual, inverted, and magnified
D.
virtual, upright, and magnified
E.
real, inverted, and smaller
Answer:
A
Explanation:
Beacuse it has 2 angles
Answer:
b I do believe sorry if I'm wrong
Which would not increase the rate at which a sugar cybe dissolves?
A. reducing the amount of solvent. B. forces attract.
C. sugar decants. D. water molecules collide.
If it took Mrs. Coleman 1.4 s to go from the 10 m mark to the 15 m mark, what was Mrs. Coleman's average speed?
Answer:
1m every 0.28 seconds
Explanation:
she travelled 5 m in 1.4 s, so divide it by itself, 1.4s divided by 5 m gets you 0.28s for 1m
which statement is the most correct statement about a gas
A gas takes the shape of it's container
A gas is not affected by changes in pressure
A gas has very little thermal energy
A gas holds it's shape
Answer:
A gas takes the shape of its container
Why isn't the story of Israel not fully accurate?
Answer:
wait what do you mean? And why is this in physics?
Is this about the iron dome or something biblical?
Explanation:
Answer:
the story of Israel is part of the Bible that's what what you're your lesson is
Explanation:
True or false
Forces/Dynamics
Answer:they answer is false
Answer:
6.T
7.T
8.F
9.F
10.T
Explanation:
Describe what a high and low frequency electromagnetic wave look like:
We have that for the Question "Describe what a high and low frequency electromagnetic wave look like:" it can be said that
A high frequency wave will have shorter wavelength whereas a low frequency wave will have long wavelengthA high frequency wave will have shorter period whereas a low frequency wave will have long periodA high frequency wave will be Faster whereas a low frequency wave will have slower
From the question we are told
Describe what a high and low frequency electromagnetic wave look like:
Generally the equation for the frequency is mathematically given as
[tex]f=\frac{1}{t}\\\\and\\\\f=\frac{v}{\lambda}\\\\[/tex]
Therefore
A high frequency wave will have shorter wavelength whereas a low frequency wave will have long wavelengthA high frequency wave will have shorter period whereas a low frequency wave will have long period
A high frequency wave will be Faster whereas a low frequency wave will have slower
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