Question 1
B. Set of whole numbers
Eliminate A and C because negative integers are in those sets.Question 2
A. Set of real numbers
The equation represents a line, which has a domain of all real numbers.If the perimeter of the square is 4x then the domain of the function will be set of rational numbers and the domain of the function y=3x+8(3-x) is set of real numbers.
Given The perimeter of the square is f(x)=4x and the function is y=3x+8(3-x)
We will first solve the first part in which we have been given that the perimeter of the square is 4x and we have to find the domain of the function.
First option is set of rational numbers which is right for the function.
Second option is set of whole numbers which is not right as whole number involves 0 also and the side of the square is not equal to 0.
Third option is set of integers which is not right as integers involve negative number also and side of square cannot be negative.
Hence the domain is set of rational numbers.
Now we will solve the second part of the question
f(x)=3x+8(3-x)
we have not told about the range of the function so we can put any value in the function and most appropriate option will be set of real numbers as real number involve positive , negative and decimal values also.
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Anu's age exceeds Sumbo's age by 15 The sum of the square of their ages is 725. What are their ages?
Answer:
Anita= 25 years old
Sumbo= 10 years old
Step-by-step explanation:
Start by forming 2 equations that represent the given information.
Let Anu's and Sumbo's ages be A and S respectively.
A= S +15 -----(1)
A² +S²= 725 -----(2)
Now, solve for A and S by substitution.
Substitute (1) into (2):
(S +15)² +S²= 725
Expand:
S² +2(S)(15) +15² +S²= 725
2S² +30S +225= 725
-725 on both sides:
2S² +30S -500= 0
Divide both sides by 2:
S² +15S -250= 0
Factorise:
(S +25)(S -10)= 0
S +25= 0 or S -10= 0
S= -25 (reject) or S= 10
Sumbo's age cannot be a negative value hence -25 is rejected.
Substitute S= 10 into (1):
A= S +15
A= 10 +15
A= 25
There is a mound of g pounds of gravel in a quarry. Throughout the day, 200 pounds of gravel is added to the mound. Two orders of 700 pounds are sold and the gravel is removed from the mound. At the end of the day, the mound has 1,200 pounds of gravel.
Answer:
[tex]\fbox {2,400 pounds}[/tex]
Step-by-step explanation:
Information we have :
200 pounds is added2 orders of 700 pounds is removed1,200 pounds remainWhat we need to find :
Original amountSolving :
g + 200 - 2(700) = 1200g + 200 = 1200 + 1400g + 200 = 2600g = 2,400 pounds of gravelPlease hurry!!!! What is the domain of the function on the graph?
all real numbers
all real numbers greater than or equal to –2
all real numbers greater than or equal to –5
all real numbers greater than or equal to 0
A. all real numbers
the doman are the x values and in this equation they are infinite making the domain all real numbers
I NEED HELP ON THESE 2 PROBLEMS. pls good anawers or bad rating and report
Answer:
1.a. skew
1.b. parallel
1.c. none of the above
1.d. perpendicular
1.e. parallel
1.f. skew
2.a. never
2.b. always
2.c. always
2.d. sometimes, sometimes, sometimes
Step-by-step explanation:
For these questions, it is critical to know the definitions of each of the terms.
DefinitionsPerpendicular: Two intersecting lines that form a right angle.Parallel: Two non-intersecting lines that are coplanar.Skew: Two non-intersecting lines that are not coplanar.Problem Breakdown
1.a. skew [tex]\overset{\longleftrightarrow}{AB} \text{ and } \overset{\longleftrightarrow}{EF}[/tex]
Point E is not on line AB. Any three non-linear points form a unique plane (left face), so A, B, and E are coplanar. Point F is not in plane ABE. Since line EF and line AB do not intersect and are not coplanar, they are skew.
1.b. parallel [tex]\overset{\longleftrightarrow}{CD} \text{ and } \overset{\longleftrightarrow}{EH}[/tex]
Line CD is parallel to line AB, and line AB is parallel to line EH. Parallel lines have a sort of "transitive property of parallelism," so any pair of those three lines is coplanar and parallel to each other.
1.c. none of the above [tex]\overset{\longleftrightarrow}{AC} \text{ and } \overset{\longleftrightarrow}{GA}[/tex]
Line AC and line GA share point A, necessarily intersecting at A. Therefore, line AC and line GA cannot be parallel or skew.
Any three points form a unique plane, so these two lines are coplanar, however, do they form a right angle? If the figure is cube-shaped, as depicted, then no.
Note that each line segment AC, AG, and CG are all the diagonal of a cube face. A cube has equal edge lengths, so each of those diagonals would be equal. Thus, triangle ACG is an equilateral triangle.
All equilateral triangles are equiangluar, and by the triangle sum theorem, the measures of the angles of a planar triangle must sum to 180°, forcing each angle to have a measure of 60° (not a right angle). So, lines AC and GA are not perpendicular. (If the shape were a rectangular prism, these lines still aren't perpendicular, but the proof isn't as neat, there is a lot to discuss, and a character limit)
"none of the above"
1.d. perpendicular [tex]\overset{\longleftrightarrow}{DG} \text{ and } \overset{\longleftrightarrow}{HG}[/tex]
Line DG and line HG share point G, so they intersect. Both lines are the edges of a face, so they intersect at a right angle. Perpendicular
1.e. parallel [tex]\overset{\longleftrightarrow}{AC} \text{ and } \overset{\longleftrightarrow}{FH}[/tex]
Line AC is a diagonal across the top face, and line FH is a diagonal across the bottom face. They are coplanar in a plane that cuts straight through the cube from top to bottom, but diagonally through those faces.
1.f. skew [tex]\overset{\longleftrightarrow}{CD} \text{ and } \overset{\longleftrightarrow}{AG}[/tex]
Point A is not on line CD, and any three non-linear points form a unique plane (the top face), so C, D, and A are coplanar. Point G is not in plane ACD. Since line CD does not intersect and is not coplanar with line AG, by definition, the lines are skew.
2.a. Two lines on the top of a cube face are never skew
Two lines are on a top face are necessarily coplanar since they are both in the plane of the top face. By definition, skew lines are not coplanar. Therefore, these can never be skew.
2.b. Two parallel lines are always coplanar.
If two lines are parallel, by definition of parallel lines, they are coplanar.
2.c. Two perpendicular lines are always coplanar
If two lines AB and CD are perpendicular, they form a right angle. To form a right angle, they must intersect at the right angle's vertex (point P).
Note that A and B are unique points, so either A or B (or both) isn't P; similarly, at least one of C or D isn't P. Using P, and one point from each line that isn't P, those three points form a unique plane, necessarily containing both lines. Therefore, they must always be coplanar.
2.d. A line on the top face of a cube and a line on the right side face of the same cube are sometimes parallel, sometimes skew, and sometimes perpendicular
Consider each of the following cases:
Parallel: Consider line CD (top face), and line GF (right face). They are coplanar and don't intersect. By definition, parallel.Skew: Consider line AD (top face), and line GF (right face). They aren't coplanar and don't intersect. By definition, skew.Perpendicular: Consider line AD (top face), and line GD (right face). They do intersect at D, and form a right angle. By definition, perpendicular.None of the above: Consider line AC (top face), and line GC (right face). These lines intersect at C, but as discussed in part 1.c, they form a 60° angle, not a right angle. By definition, "none of the above".These 4 cases prove it is possible for a pair of top face/right face lines to be parallel, perpendicular, skew, or none of the above. So, those two lines are neither "always", nor "never", one of those choices. Therefore, they are each "sometimes" one of them.
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match the expressions given in words with their values when m = 6. 2 15 42 3 21
The matching is done below
What is expression?An expression is a combination of numbers, variables, functions (such as addition, subtraction, multiplication or division etc.)
1) 3 is the difference of 2 times d minus 3.
As, 2*d - 3
=2*3 - 3
=6 - 3
= 3
2) 4 is 4 added to the difference of d minus 3.
or, 4 + (d - 3)
or, 4 + (3 - 3)
or, 4 + 0 = 4
3) 0 is the difference of d minus 3 divided by 2.
(d - 3)/2
= (3 - 3)/2
= 0/2
= 0
4) 2 is the quotient of 12 divided by the difference of 3 times d minus 3.
12/(3d - 3)
=12/(3*3 - 3)
=12/(9 - 3)
=12/6
= 2
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what would 41.2 hours converted into minutes?
Emissions of sulfur dioxide by industry set off chemical changes in the atmosphere that result in "acid rain".
The acidity of liquids is measured by pH on a scale of 0 to 14. Distilled water has pH 7.0, and lower pH values indicate acidity.
Normal rain is somewhat acidic, so "acid rain" is sometimes defined as rainfall with a pH below 5.0.
The pH of rain at one location varies among rainy days according to a Normal distribution with mean 5.43 and standard
deviations 0.54.
What proportion of rainy days have rainfall with pH below 5.0? Use software or Table A to find the answer.
(Enter your answer rounded to four decimal places.)
Using the normal distribution, it is found that 0.2119 = 21.19% of rainy days have rainfall with pH below 5.0.
Normal Probability DistributionThe z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.The mean and the standard deviation are given, respectively, by:
[tex]\mu = 5.43, \sigma = 0.54[/tex]
The proportion of rainy days have rainfall with pH below 5.0 is the p-value of Z when X = 5, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{5 - 5.43}{0.54}[/tex]
Z = -0.8
Z = -0.8 has a p-value of 0.2119.
0.2119 = 21.19% of rainy days have rainfall with pH below 5.0.
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find arc length
x=t^(3)-2t
y=t^(2)-3
Answer:
Step-by-step explanation:
Express cos A as a fraction in simplest terms.
Answer:
See below
Step-by-step explanation:
Here is one way
cos^2 + sin^2 = 1
cos^2 = 1 - sin^2
For angle A cos^2 = 1 - (10/26)^2
cos ^2 = 1 - 100/676
= 576/676
cos A = 24/26 = 12/13
Another way would be to use the Pythagorean theorem to find length of AB .... then cos A = length AB / 26
What is the formula for finding the area of abc?
The formula for finding the area of the triangle ΔABC will be half of the product of the base and height. Then the formula is A = 1/2 x BC x AD.
What is the area of the triangle?The area of the triangle is given as
A = 1/2 x B x H
Where B is the base and H is the height of the triangle.
The triangle is given below,
We have
B = BC
H = AD
Then we have
A = 1/2 x BC x AD
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Suppose you start with a full tank of gas (20 gallons) in your truck. After driving 3 hours, you now have 2 gallons left. If x is the number of hours you have been driving, then y is the number of gallons left in the tank. At what rate is the gas left in the tank changing? State your answer as a reduced fraction. Find an equation of a line in the form y = mx + b that describes the amount of gas in your tank.
The rate of the gas left in the tank will be -6 and the equation will be given as y = -6x + 20.
What is an expression?Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.
Given that:-
Suppose you start with a full tank of gas (20 gallons) in your truck. After driving 3 hours, you now have 2 gallons left. If x is the number of hours you have been driving, then y is the number of gallons left in the tank.The rate of gas will be calculated as:-
Suppose the hours are represented by x and the gallons are represented by y.
The rate of the gas will be the slope so the slope will be calculated as:-
[tex]m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m = \dfrac{2-20}{3-0}[/tex]
[tex]m =\dfrac{-18}{3}[/tex]
m = -6
The equation will be given as:-
y = mx + c
y = -6x + 20
Therefore the rate of the gas left in the tank will be -6 and the equation will be given as y = -6x + 20.
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What is the solution set for the following inequality? 4x – 3 + 6x > 5x + 7
Answer:
you got that
Step-by-step explanation:
wet wet wet
Answer:
{ x : x > 2 }
Step-by-step explanation:
4x - 3 + 6x > 5x + 7 , that is
10x - 3 > 5x + 7 ( subtract 5x from both sides )
5x - 3 > 7 ( add 3 to both sides )
5x > 10 ( divide both sides by 5 )
x > 2
also can someone check this too? just want to make sure i got the the first part right before proceed further
Answer:
the answers are all right
If anyone can help me to solve this.
Answer:
x=50
Step-by-step explanation:
3x-5=145(vertically opposite angle)
3x=145+5
3x=150
x=150/3
x=50
DON'T FORGET TO WRITE DEGREE
Answer:
x = 50
Step-by-step explanation:
Vertically opposite angles are of equal measure.
Solving:3x - 5 = 145
3x = 145 + 5
3x = 150
x = 50
That's all i know, Hope it helps!
Which of the following probabilities is the greatest for a standard normal distribution? P (negative 1.5 less-than-or-equal-to z less-than-or-equal-to negative 0.5) P (negative 0.5 less-than-or-equal-to z less-than-or-equal-to 0.5) P (0.5 less-than-or-equal-to z less-than-or-equal-to 1.5) P (1.5 less-than-or-equal-to z less-than-or-equal-to 2.5)
The probability P(-0.5 ≤ z ≤ 0.5) is the greatest for a standard normal distribution, and the value of P(-0.5 ≤ z ≤ 0.5) is 38.2% option second is correct.
What is a normal distribution?It's the probability curve of a continuous distribution that's most likely symmetric around the mean. On the Z curve, at Z=0, the chance is 50-50. A bell-shaped curve is another name for it.
We have a statement:
Which of the following probabilities is the greatest for a standard normal distribution:
The options are:
P(-1.5 ≤ z ≤ -0.5)
P(-0.5 ≤ z ≤ 0.5)
P(0.5 ≤ z ≤ 1.5)
P(1.5 ≤ z ≤ 2.5)
As we know from the normal distribution curve we can find the probability between the range given. At Z=0, the chance is 50-50.
From the Z-curve:
P(-1.5 ≤ z ≤ -0.5) = 9.2% + 15% = 24.2%
P(-0.5 ≤ z ≤ 0.5) = 19.1% + 19.1% = 38.2%
P(0.5 ≤ z ≤ 1.5) = 15% + 9.2% = 24.2%
P(1.5 ≤ z ≤ 2.5) = 4.4% + 1.7% = 6.1%
Thus, the probability P(-0.5 ≤ z ≤ 0.5) is the greatest for a standard normal distribution, and the value of P(-0.5 ≤ z ≤ 0.5) is 38.2% option second is correct.
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Answer:
B) P (-0.5 <= z <= 0.5)
Step-by-step explanation:
A group fitness gym classifies its fitness class attendees by class type and member status. The marketing team has gathered data from a random month, in which there
were 2039 class attendees. The data is summarized in the table below.
Class Type and Member Status of Class
Attendees
Class Type
Barre
Boot Camp
Boxing
Spinning
Yoga
Member
.240
204
288
191
177
Non-Member
185
155
234
271
94
What is the probability that a class attendee is a non-member of the gym and is attending a barre class or is a member of the gym and is attending a boot camp class?
Enter a fraction or round your answer to 4 decimal places, if necessary.
The probability that a class attendee is a non-member of the gym and is attending a barre class or is a member of the gym and is attending a boot camp class is 0.009.
What is the probability?Probability refers to a possibility that deals with the occurrence of random events.
The marketing team has gathered data from a random month, in which there were 2039 class attendees.
The probability that a class attendee is a non-member of the gym and is attending a barre class
= 185/2039
= 0.09
The probability that a class attendee is a member of the gym and is attending a boot camp class
= 204/2039
= 0.10004
The probability for both the event would be
= 0.09 x 0.10004
= 0.009
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Which sequences are geometric? Check all that apply.
5, 10, 20, 50,...
3, 12, 48, 192,...
3, 15, 75, 375,...
8, 15, 75,375,...
14, 21, 28, 35,...
17, 20, 23, 26,...
2, 10, 50, 250,...
Answer:
The first, third and last sequences
The velocity of a car over five hours is given by v(t)=60ln(t+1),0≤t≤5 in kilometers per hour. What is the total distance traveled from t=0 to t=5? Round your answer to the nearest whole number and do not include units.
Step-by-step explanation:
as the velocity is not constant over time, we actually have to integrate v(t) over the interval 0<=t<=5 to get the distance.
v(t) = 60×ln(t + 1)
V(t) = 60 × integral(ln(t + 1)) between 0 and 5.
integral(ln(t + 1)) = (t + 1)ln(t + 1) - t + C
V(t) = 60 × ((t + 1)ln(t + 1) - t + C)
the distance traveled between t = 0 and t = 5 is then
60 × ((5 + 1)ln(5 + 1) - 5 + C) - 60 × ((0 + 1)ln(0 + 1) - 0 + C) =
= 60×(6ln(6) - 5 + C) - 60×(1ln(1) + C) =
= 60×(5.750556815... + C) - 60×C =
= 60×5.750556815... = 345.0334089... ≈ 345 km
Inverse Function: One to one function...Help needed! 15 pts for your help!
Answer:
Step-by-step explanation:
hello :
Use the Pythagorean Theorem to find the length of the leg in the triangle shown below.
The figure shows a right triangle with one leg marked 12. The hypotenuse is marked 15.
Answer:
9
Step-by-step explanation:
The Pythagorean Theorem is a² + b² = c². c² is the hypotenuse while a² and b² are the legs.
So plugging it into the equation,
a² + 12² = 15²
a² + 144 = 225
a² = 81
a = 9
steps:
1. square the values
2. isolate the missing value
3. take the square root of both sides
Please help!
38 [tex]\frac{22}{75}[/tex] + 3 [tex]\frac{11}{15}[/tex] = ?
The value of [tex]38 \frac{22}{75} + 3\frac{11}{15}[/tex] is [tex]42\frac{2}{75}[/tex]
How to add the fractions?The summation expression is given as:
[tex]38 \frac{22}{75} + 3\frac{11}{15}[/tex]
Rewrite as:
[tex]38 + 3 + \frac{22}{75} + \frac{11}{15}[/tex]
Evaluate the sum and take LCM
[tex]41 + \frac{22 + 5 * 11}{75}[/tex]
Evaluate the sum
[tex]41 + \frac{77}{75}[/tex]
Express as mixed number
[tex]41 + 1\frac{2}{75}[/tex]
Add
[tex]42\frac{2}{75}[/tex]
Hence, the value of [tex]38 \frac{22}{75} + 3\frac{11}{15}[/tex] is [tex]42\frac{2}{75}[/tex]
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The graph of the function f(x) = -(x+3)(x-1) is
shown below.
-6
-4 -2
6
A
2
-2
4
-6
2
4
6 X
What is true about the domain and range of the
function?
O The domain is all real numbers less than or equali
to 4, and the range is all real numbers such that -31
≤x≤ 1.
The domain is all real numbers such that-3≤x≤
1, and the range is all real numbers less than or
equal to 4.
The domain is all real numbers, and the range is all
real numbers less than or equal to 4.
The domain is all real numbers less than or equal
to 4, and the range is all real numbers.
Using the concepts of domain and range of a function, the correct statement regarding the graph of the function f(x) = -(x + 3)(x - 1) is given by:
The domain is all real numbers, and the range is all real numbers less than or equal to 4.
What are the domain and the range of a function?The domain of a function is the set that contains all the values of the input.The range of a function is the set that contains all the values of the output.In a graph:
The domain is given by the x-values, the horizontal axis.The range is given by the y-values, the vertical axis.The graph of f(x) = -(x + 3)(x - 1) is given at the end of the answer, hence:
The domain is all real values, as the function keeps going to infinity.The range is all values of y that are less than or equal to 4.Hence the correct statement is:
The domain is all real numbers, and the range is all real numbers less than or equal to 4.
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A water ride with heights above and below the starting point can be modeled by the function y = 3 sin ( π 2 ( x + 3 ) − 2 ) . Within the interval 0 < x < 5 , when does the ride have a height 1 foot below the starting point?
The value of x for a height 1 foot below the starting point will be the negative 2.76.
What is trigonometry?The connection between the lengths and angles of a triangular shape is the subject of trigonometry.
A water ride with heights above and below the starting point can be modeled by the function is given below.
y = 3 sin (π / 2 (x + 3) − 2), Within the interval 0 < x < 5
We know that π / 2 = 90°
Then the value of x for a height 1 foot below the starting point will be
1 = 3 sin (90 (x + 3) − 2)
1/3 = sin (90 (x + 3) − 2)
19.47 = 90 (x + 3) − 2
21.47 = 90 (x + 3)
0.2385 = x + 3
x = -2.76
Then the value of x will be the negative 2.76.
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What is the value of log5^125?
Step-by-step explanation:
I'm going to assume you mean
[tex]log(5^{125})[/tex] which can be rewritten as [tex]125 log(5)[/tex] since if you start with [tex]log(a) = x = > 10^x=a\\(10^x)^c=a^c\\c *log(a^c)[/tex]since when you do (10^x)^c you're just multiplying the exponent which is represented by the x but is equal to the log you just multiply the log which is why you can bring it in front.
You can then approximate the value of log(5) using a calculator and multiply by 125 to get around 87.371
Complete the table for the given rule. Rule: Y = X + 8
X | Y
2. _
0. _
4. _
Y=x+8
Table
[tex]\boxed{\begin{array}{c|c}\bf x&\bf y\\ \rm 2&\rm 10\\ \rm 0&\rm 8\\ \rm 4&\rm 12\end{array}}[/tex]
How?
x=2
y=2+8=10x=0
y=0+8=8x=4
y=4+8=12Answer:
[tex]\large\begin{array}{| c | c |}\cline{1-2} x & y \\\cline{1-2} 2 & 10 \\\cline{1-2} 0 & 8 \\\cline{1-2} 4 & 12 \\\cline{1-2}\end{array}[/tex]
Step-by-step explanation:
Given rule:
[tex]y=x+8[/tex]
The rule tells us that to the corresponding y-values, simply substitute the given value of x into the given rule:
[tex]x=2 \implies y=2+8=10[/tex]
[tex]x=0 \implies y=0+8=8[/tex]
[tex]x=4 \implies y=4+8=12[/tex]
Therefore, the completed table is:
[tex]\large\begin{array}{| c | c |}\cline{1-2} x & y \\\cline{1-2} 2 & 10 \\\cline{1-2} 0 & 8 \\\cline{1-2} 4 & 12 \\\cline{1-2}\end{array}[/tex]
n studying the sampling distribution of the mean, you were asked to list all the different possible samples from a small population and then find the mean of each of them. Consider the following: Personal phone calls received in the last three days by a new employee were 2, 4, and 7. Assume that samples of size 2 are randomly selected with replacement from this population of three values. What different samples could be chosen? What would be their sample means?
The Total outcome with replacement will be given by ,3² = 9, the mean of the samples will be 2 , 4.5 , 3 , 7 , 4
What is Mean ?Mean predicts the central tendency of a data set , It is determined by the ratio of sum of all the numbers to the total numbers in the data set.
On the basis of given data
The number given is 2,4,7
Size of the sample = 2 with replacement
The Total outcome with replacement will be given by
3² = 9
Possible outcome can be
2,2 2,4 2,7 4,4 4,2 4,7 7,7 7,2 7,4
The sample mean can be calculated as
(a+b)/2
(2+2)/2 = 2
similarly the mean of the samples will be 2 , 4.5 , 3 , 7 , 4
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Find the least number which when divided by 12, 18 and 20 leaves no reminder.
Answer:
180
Step-by-step explanation:
Find the LCM of 12, 18, and 20
[tex]12 = 2 \times 2 \times 3[/tex]
[tex]18 = 2 \times 3 \times 3[/tex]
[tex]20 = 2 \times 2 \times 5[/tex]
LCM = 2 × 2 × 3 × 3 × 5 = 180
help asap pls ill mark brainliest fr
order them from least to greatest solve them first
Answer:
1/2 - 1/3,
1 - 1/2,
1/4 + 1/2
Step-by-step explanation:
1/4 + 1/2 = 1/4 + 2/4 = 3/4
1/2 - 1/3 = 3/6 - 2/6 = 1/6
1 - 1/2 = 2/2 - 1/2 = 1/2
Hence, the desired order is
1/2 - 1/3,
1 - 1/2,
1/4 + 1/2
need some help asap, giving brainliest
Answer:
16.19
Step-by-step explanation:
Use the cosine rule:
[tex]\sqrt{a^{2} +b^{2} -2abcosy} \\\\\sqrt{16^{2} +20^{2} -(2)(16)(20)cos(52)} \\\\\\= 16.19cm[/tex]
Jordan and Taylor are collecting canned foods for the homeless. They hope to collect 10 cans per day to reach their goal. They have already collected 120 cans. If the
function for this problem is f(c) = 10r+120, determine how many cans Jordan and Taylor will have collected after 8 days.
Answer:
200 cans.
Step-by-step explanation:
f(c)=10r + 120
Put t=8 into it
T(c) = 10 x 8 + 120
=200 cans
(Use substitution method)
