1. Find the zeros of the quadratic function by graphing. Round to the nearest tenth if necessary.
f(x) = -2x² + 3x + 1
A 0.8,2.1) is a zero of the quadratic function because it is the peak of the parabola.
B (0,1) is a zero of the quadratic because it is where the parabola crosses the y-axis.
C (-0,3,0) and (1.8,0) are zeros of the quadratic function because it is where the parabola crosses the x-axis.
D (0.8,2.1) and (0,1) are zeros of the quadratic function because it is where the parabola crosses the x-axis.

Answers

Answer 1

The correct answer is C: (-0.3,0) and (1.8,0) are zeros of the quadratic function because they are the points where the parabola intersects the x-axis.

The right response is C: (- 0.3,0) and (1.8,0) are zeros of as far as possible since they are the places where the parabola meets the x-turn.

plot the y-get at (0,1),

x = - b/2a

To find the x-heading of the vertex, which is x = 3/4. Substitute this worth into the capacity to find the y-course of the vertex, which is

f(3/4) = 1/8.

Plot the vertex at (3/4, 1/8).

Then, utilize this data to plot the remainder of the parabola. The zeros are the places where the parabola crosses the x-focus, which are close (- 0.3,0) and (1.8,0) obviously following changing in accordance with the closest 10th.

To track down the zeros of the quadratic capacity by illustrating, one ought to at first plot the y-get at (0,1) and a brief time frame later utilize the vertex condition to track down the headings of the vertex. Following plotting the vertex, the remainder of the parabola can be drawn. The zeros of the capacity are the x-gets, which can be found by finding the places where the parabola combines the x-turn. For this current situation, the zeros are close (- 0.3, 0) and (1.8, 0) resulting to adjusting to the closest 10th.

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Related Questions

5. Which box-and-whisker plot represents this set of data? (1 point)
90, 98, 75, 84, 89, 91, 70, 81, 93, 84, 100

Answers

the points are 90,98,91,70 this is based off the box and whisker plot with y=mc+bc

what is the slope of the line below?

Answers

Answer:

B. Y= 5x - 2

Step-by-step explanation:

The Y is negative, you can see the number -5 below the point, if you go to the top, that is, to 0 and count down, the lines are two and the X is positive 5, you can see where the number 5 is and the point is above.

Billy Bob wants to paint the outside wall of his circular pool. The circular
wall is 4 feet tall and has a radius of 15 feet. If paint cost $28 per gallon and
covers 225 square feet, how much will it cost to paint the wall. The paint is
only avaliable in gallon containers.

Answers



The first step is to calculate the surface area of the circular wall of the pool, which can be calculated using the formula:

A = 2πrh

where A is the surface area, π is the mathematical constant pi (approximately equal to 3.14159), r is the radius of the circular wall, and h is the height of the wall.

In this case, the radius is 15 feet and the height is 4 feet, so:

A = 2π(15)(4)
A = 376.99 square feet

The next step is to calculate how many gallons of paint will be needed. Since one gallon of paint covers 225 square feet, we can divide the surface area by the coverage per gallon:

Gallons = A / Coverage per gallon
Gallons = 376.99 / 225
Gallons = 1.68

Since the paint is only available in gallon containers, Billy Bob will need to purchase 2 gallons of paint to ensure that he has enough to cover the entire surface.

Finally, we can calculate the total cost of the paint by multiplying the number of gallons by the cost per gallon:

Total cost = Number of gallons x Cost per gallon
Total cost = 2 x $28
Total cost = $56

Therefore, it will cost Billy Bob $56 to paint the circular wall of his pool.

The amount it would cost to paint the wall, given the cost of paint and the area covered is $ 56 .

How to find the cost to paint ?

The surface area of the circular wall would be :

A = 2 x π x r x h

The area is therefore:

= 2 x π x r x h

= 2 x 3. 14 x 15 x 4

= 376. 8 square feet

The number of gallons needed is therefore:

= 376. 8 / 225

= 1. 674

= 2 gallons

The cost of two gallons is:

= 2 x 28

= $ 56

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!! will give brainlist !!

Use trigonometric ratios to find the value of each variable. Round answers to the nearest tenth.

Answers

Answer:

Set your calculator to degree mode.

2) tan(43°) = x/8.2

x = 8.2tan(43°) = 7.6

3) sin(29°) = 3.5/x

x sin(29°) = 3.5

x = 3.5/sin(29°) = 7.2

The radius of a cylindrical water tank is 6 ft, and its height is 16 ft. Helpppppp I’m running out of time

What is the volume of the tank?
Use the value 3.14 for , and round your answer to the nearest whole number.
Be sure to include the correct unit in your answer.
6 ft
16 ft
0
ft

Answers

Answer:

V 1809 ft^3

Step-by-step explanation:

Given:

r (radius) = 6ft

h (height) = 16ft

π = 3,14

Find: V (volume) - ?

[tex]v = \pi {r }^{2} \times h[/tex]

[tex]v = 3.14 \times {6}^{2} \times 16 ≈1809 \: {ft}^{3} [/tex]

Principle amount is 22,000. Interest rate is 4.5%.
1. Determine interest earned each year.
2. Write a recurrence relation to model the value of investment from year to year. Let Sn be the value after n years.
3. Determine value of interest after 5 years.​

Answers

Answer:

1. $990

2. Sn = Sn-1 + (r/100) * Sn-1

3. $27,037.44

Step-by-step explanation:

1. The interest earned each year can be calculated using the simple interest formula:

Simple Interest = (Principal * Rate * Time) / 100

Here, Principal = $22,000, Rate = 4.5%, and Time = 1 year

So, the interest earned each year would be:

= (22,000 * 4.5 * 1) / 100

= $990

Therefore, the interest earned each year would be $990.

2. The recurrence relation to model the value of investment from year to year is:

Sn = Sn-1 + (r/100) * Sn-1

where Sn represents the value of the investment after n years, Sn-1 represents the value after n-1 years, and r represents the annual interest rate.

Using this recurrence relation, we can calculate the value of the investment for different years:

- S1 = 22,000 + 990 = 22,990

- S2 = 22,990 + (4.5/100) * 22,990 = 24,026.55

- S3 = 24,026.55 + (4.5/100) * 24,026.55 = 25,103.46

And so on...

3. To determine the value of the investment after 5 years, we can simply substitute n = 5 in the recurrence relation:

S5 = S4 + (r/100) * S4

= S3 + (r/100) * S3 + (r/100) * S3

= S2 + (r/100) * S2 + (r/100) * S2 + (r/100) * S2

= S1 + (r/100) * S1 + (r/100) * S1 + (r/100) * S1 + (r/100) * S1

Substituting values from previous calculations:

S1 = 22,000 + 990 = 22,990

So,

S5 = 22,990 + (4.5/100) * 22,990 + (4.5/100) * 22,990 + (4.5/100) * 22,990 + (4.5/100) * 22,990

= $27,037.44

Therefore, the value of the investment after 5 years would be $27,037.44.

For the following right triangle, find the side length x. Round your answer to the nearest hundredth

Answers

The side length x of the given right angle triangle is: 14.97

How to use Pythagoras Theorem?

When two sides of a right-angled triangle are given and one side is to be found, we can do so using the Pythagoras theorem. In the given triangle the base is x, the perpendicular is 10 and the hypotenuse is 18.

According to the Pythagoras Theorem, the following equation can be written as:

x² = 18² - 10²

x = √224

x = 14.97

Thus, that is the missing length of the given right triangle

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Kyle is buying gifts for Megan's birthday and needs to stay in budget

Cake = half his money + 36.50
Decorations = half of what he had left + 36.50
Sweets = half of what he had left + 18.25

Now he is out of money, what did he start with?

Answers

Answer: Let's start by using algebra to represent the problem.

Let X be the amount of money that Kyle started with.

Then we can create the following equations:

Cake = 0.5X + 36.50Decorations = 0.5(X - Cake) + 36.50Sweets = 0.5(X - Cake - Decorations) + 18.25

And we know that he's out of money, so:

Cake + Decorations + Sweets = XWe can use substitution to solve for X.

Substitute the first equation into the second equation to get:

Decorations = 0.5(X - (0.5X + 36.50)) + 36.50Decorations = 0.25X + 9.25

Substitute the first two equations into the third equation to get:

Sweets = 0.5(X - (0.5X + 36.50) - (0.25X + 9.25)) + 18.25Sweets = 0.25X + 4.75

Substitute all three equations into the fourth equation to get:

(0.5X + 36.50) + (0.25X + 9.25) + (0.25X + 4.75) = X

Simplify and solve for X:

1X + 50.50 = X50.50 = 0.5XX = 101

Therefore, Kyle started with $101.

Add: -8x8 + (-3x8 + 3)
Enter the correct answer.

Answers

43 because when I multipleded all those answer I got my answer 43
-85 is the correct answer

N Heracio's Computer Time Shopping Research 10% Videos 15% Homework 20% Games 20% Social dia 25% Heracio used the computer a total of 40 hours last week. How many more hours did Heracio use the computer to do homework than shop online?​

Answers

Answer: According to the problem, N Heracio used the computer for 40 hours last week. We are asked to find the difference between the time spent on shopping online and doing homework.

To do this, we first need to find the amount of time spent on each activity. We can do this by multiplying the total computer time by the percentage of time spent on each activity:

Time spent on videos = 10% of 40 hours = 4 hours

Time spent on homework = 15% of 40 hours = 6 hours

Time spent on games = 20% of 40 hours = 8 hours

Time spent on social media = 25% of 40 hours = 10 hours

Time spent on shopping online = 20% of 40 hours = 8 hours

Therefore, Heracio spent 6 hours on homework and 8 hours on shopping online.

The difference between these two amounts is:

6 hours - 8 hours = -2 hours

This means that Heracio spent 2 hours more on shopping online than on doing homework.

Step-by-step explanation:

Simplify the polynomial expression. (x+7)^2

Answers

Answer:

x²+14x+49

Step-by-step explanation:

(a+b)²=a²+2ab+b²

(x+7)²=x²+2×7×x+7²=x²+14x+49

A leading magazine (like Barron's) reported at one time that the average number of weeks an individual is unemployed is 32 weeks. Assume that for the population of all unemployed individuals is normally distributed and the population mean length of unemployment is 32 weeks and that the population standard deviation is 3.9 weeks. Suppose you would like to select a random sample of 66 unemployed individuals for a follow-up study.

Answer the following, rounding all answers to three decimal places.

Find the probability that a single randomly selected value is greater than 31.9.
P(X > 31.9) = ???

Find the probability that a sample of size
is randomly selected with a mean greater than 31.9.
P(M > 31.9) = ???

Answers

The probability that a single randomly selected value is greater than 31.9 is 0.511.

The probability that a sample of size 66 is randomly selected with a mean greater than 31.9 is 0.641.

How to calculate the probability

Probability that a single randomly selected value is greater than 31.9:

z = (31.9 - 32) / 3.9 = -0.026

We can find the probability:

P(X > 31.9) = P(Z > -0.026) = 0.511

Also, μ = 32, σ = 3.9, n = 66

z = (31.9 - 32) / (3.9 / √66) = -0.363

Using a standard normal distribution table or calculator, we can find the probability:

P(M > 31.9) = P(Z > -0.363) = 0.641

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Solve for X. *
-48-x=-39

Answers

Answer:

x = - 9

Step-by-step explanation:

-48 - x = -39

Add 48 on both sides

-x = 9

Divided both sides by -1

x = - 9

So, the answer is x = - 9

Which digits replace A, B and C in the
boxes?
+
15.73
32.4 A
C. 16
48.B 4
1

Answers

Answer:

Step-by-step explanation:

Select all the correct answers.
If the measure of angle 0 is 2n/3, which statements are true?

Answers

Answer:
Angle 0 is 6.28/3. or 2.093.
Step-by-step explanation:
Pie is an irrational number, so it will be repeating forever. A simple way to get pie is just 3.14. 3.14 times 2 is 6.28. Divide 6.28 by 3 to get 2.093 repeating, but simplified is 2.093.

37. When making biscuits, a baker
mixes flour and sugar in the ratio
4:1. If he uses 6kg of sugar when
making some biscuits, how much
flour should he use?
(a) 30kg
(b) 24kg
C 10kg
D 8kg
E 1.5kg

Answers

The baker should use 24kg amount of flour when making the biscuits. The correct answer is (b) 24kg.

To determine the amount of flour the baker should use when making biscuits, we can use the given ratio of flour to sugar, which is 4:1.

Since the ratio is 4:1, for every 4 parts of flour, there is 1 part of sugar. Therefore, the ratio of flour to sugar can be expressed as 4/1.

If the baker uses 6kg of sugar, we can set up a proportion to find the corresponding amount of flour:

4/1 = x/6

Cross-multiplying, we get:

4 * 6 = 1 * x

24 = x

Therefore, the baker should use 24kg of flour when making the biscuits.

In summary, the correct answer is (b) 24kg.

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LESSON 26 SESSION 3
There are at least 12 people on a bus.
a. Write and graph an inequality to show the number of people who may be on
the bus.

Answers

An inequality to show the number of people  is  p ≥ 12

Writing and graphing an inequality to show the number of people

Let p be the number of people on the bus. We know that there are at least 12 people on the bus, so we can write:

p ≥ 12

This inequality means that the number of people on the bus, p, must be greater than or equal to 12.

To graph this inequality, we can draw a horizontal line at y = 12 on the y-axis, and shade the area above the line, since any value of p that is greater than or equal to 12 satisfies the inequality.

Here's a graph of the inequality attached

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help pls i dont understand this

Answers

The equation that can be used to determine the cost of each admission ticket is 4x + $25.00 = $175.00.

The cost in dollars of the admission ticket is $ 37.50.

How to find the cost of the tickets ?

Let x be the cost, in dollars, of each admission ticket, including tax.

The total cost of 4 admission tickets can be expressed as 4x, since the cost of each ticket is the same.

The total cost of 4 admission tickets and parking is given as $175.00, so we can write:

4x + $25.00 = $175.00

Simplifying the equation, we can solve for x:

4x = $175.00 - $25.00

4x = $150.00

x = $37.50

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A tunnel is shaped in the form of a semi-ellipse. The width of the tunnel is 20 feet and the height of the tunnel is 12 feet. A train is 10 feet wide and centered in the tunnel. Determine whether a 10-foot high train would have clearance to pass through. If so, by how much? If not, by how much? (Nearest inch.)

Answers

Since the tunnel is in the shape of a semi-ellipse, we can use the formula for the equation of a semi-ellipse:

(x^2 / a^2) + (y^2 / b^2) = 1

where "a" is the horizontal radius (half of the width) and "b" is the vertical radius (half of the height).

In this case, we have:

a = 20/2 = 10 feet
b = 12/2 = 6 feet

We can assume that the train is centered in the tunnel, so we need to find the height of the semi-ellipse at the center (i.e., the value of "y" when "x" is 0).

Plugging in the values for "a" and "b", we get:

(0^2 / 10^2) + (y^2 / 6^2) = 1

Simplifying, we get:

y^2 / 36 = 1

y^2 = 36

y = ±6 feet

Therefore, the height of the semi-ellipse at the center is 6 feet.

To determine whether a 10-foot high train would have clearance to pass through, we need to check whether the height of the semi-ellipse at the sides is greater than or equal to 10 feet.

Plugging in the values for "a" and "b" and solving for "y" when "x" is 5 feet (half of the train's width), we get:

(5^2 / 10^2) + (y^2 / 6^2) = 1

Simplifying, we get:

y^2 / 36 = 0.75

y^2 = 27

y ≈ ±5.2 feet

Since the height of the semi-ellipse at the sides is about 5.2 feet, a 10-foot high train would not have clearance to pass through. The clearance is less than 5.2 - 5 = 0.2 feet (or about 2.4 inches).

Therefore, the train would not fit through the tunnel with 10 feet of clearance.

I really need hel with this please

Answers

The resulting matrix after row 1 is multiplied by 2 is given as follows:

[tex]\left[\begin{array}{ccc}14&-8&16\\-12&7&-13\end{array}\right][/tex]

How to do the row operation?

The matrix in the context of this problem is defined as follows:

[tex]\left[\begin{array}{ccc}7&-4&8\\-12&7&-13\end{array}\right][/tex]

The first row is given as follows:

7, -4 and 8.

Multiplying the first row by two, we have that:

7 x 2 = 14.-4 x 8 = -8.8 x 2 = 16.

(when we multiply a matrix by a constant, each element of the matrix is multiplied by the constant).

Hence the resulting matrix is given as follows:

[tex]\left[\begin{array}{ccc}14&-8&16\\-12&7&-13\end{array}\right][/tex]

(the second row was kept constant, while the first row was multiplied by 2).

Missing Information

The matrix is:

[tex]\left[\begin{array}{ccc}7&-4&8\\-12&7&-13\end{array}\right][/tex]

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HELPPPPPPPPPP... please help i don't get this whatsoever and my teacher doesn't really help. i dont get none of it at all. please help asap !

Answers

Answer:

I can tell

Step-by-step explanation:

Ok so to help you understand it do you see the button that says video? Yeah, click it. A video will pop up and explain it to you! :)

PLSSS HELP ITS DUE TOMMROW I WILL GIVE U MORE POINTS WHEN I GET MORE PLSSS

Answers

Answer:

[tex]A_{\text{red}} = 1766.25 \text{ in}^2[/tex]

Step-by-step explanation:

We can see that there are four bands total on the target, two of which are red bands. With this information, we can solve for the radius of the circle within each band, since we know that each band is the same width:

[tex]r_1 = \dfrac{1}{4} \cdot 30 = 7.5\\[/tex]

[tex]r_2 = \dfrac{2}{4} \cdot 30 = 15\\[/tex]

[tex]r_3 = \dfrac{3}{4} \cdot 30 = 22.5\\[/tex]

[tex]r_4 = 30[/tex]

We can now find the area of each red band by subtracting:

the area of the circle within the white band just inward of the red band

-- from --

the area of the circle within the red band.

Finding the area of the outer red band:

[tex]A_{\text{outer red}} = A(\text{circle within outer red}) - A(\text{circle within outer white})[/tex]

[tex]A_{\text{outer red}} = A(\odot \text{ with radius }r_4) - A(\odot \text{ with radius } r_3)[/tex]

↓ substituting the radius values into the circle area formula ([tex]\pi r^2[/tex])

[tex]A_{\text{outer red}} = (\pi \cdot 30^2) - (\pi \cdot 22.5^2)[/tex]

↓ using 3.14 for [tex]\pi[/tex]

[tex]A_{\text{outer red}} = (3.14 \cdot 30^2) - (3.14 \cdot 22.5^2)[/tex]

↓ evaluating the right side

[tex]A_{\text{outer red}} = 2826 - 1589.625[/tex]

[tex]A_{\text{outer red}} = 1236.375 \text{ in}^2[/tex]

Finding the area of the inner red band:

[tex]A_{\text{inner red}} = A(\text{circle within inner red}) - A(\text{circle within inner white})[/tex]

[tex]A_{\text{inner red}} = A(\odot \text{ with radius }r_2) - A(\odot \text{ with radius } r_1)[/tex]

↓ substituting the radius values into the circle area formula ([tex]\pi r^2[/tex])

[tex]A_{\text{inner red}} = (\pi \cdot 15^2) - (\pi \cdot 7.5^2)[/tex]

↓ using 3.14 for π

[tex]A_{\text{inner red}} = (3.14 \cdot 15^2) - (3.14 \cdot 7.5^2)[/tex]

↓ evaluating the right side

[tex]A_{\text{inner red}} = 706.5 - 176.625[/tex]

[tex]A_{\text{inner red}} = 529.875 \text{ in}^2[/tex]

Finally, we can find the area of all of the red on the target by adding the area of the outer and inner red bands.

[tex]A_{\text{red}} = A_{\text{outer red}} + A_{\text{inner red}}[/tex]

[tex]A_{\text{red}} = 1236.375 \text{ in}^2 + 529.875 \text{ in}^2[/tex]

[tex]\boxed{A_{\text{red}} = 1766.25 \text{ in}^2}[/tex]

50 Points! Multiple choice algebra question. Photo attached. Thank you!

Answers

Answer:

Step-by-step explanation:

C (Wait for another defendant, check with him and write this answer)

Hey!
Answer: C
(If you need more help with algebra, try Microsoft Maths Solver)

Question 6 of 10
True or false? If you took a true "if-then' statement and reversed the clauses,
the new statement would also be true.
OA. True
OB.
False

Answers

The statement that "if you took a true "if-then' statement and reversed the clauses, the new statement would also be true" is False.

Why is this false ?

By reversing the clauses within an accurate "if-then", one will manifest a new statement known as the "converse" of the initial formula. Though, it is not inevidably true.

For instance, if the original expression was "If it rains, then the ground gets wet", its converse is "If the ground gets wet, then it rains". Unfortunately, that specific converse has the potential to be incorrect since there are several other methodologies from which the land can gain moisture beside rain (e.g. sprinkler system, someone unintentionally pouring water, etc.).

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Please solve
1.) 4(v + 1) = 16

Answers

Answer:

it's an easy one

Step-by-step explanation:

1. combine those -->4v+4=16

2. subtract the like terms--> 4v=16-4--> 4v=12

3. divide--> v=12/4-->3

4. Answer--> v=3

Element X is a radioactive isotope such that its mass decreases by 59% every hour. I
an experiment starts out with 530 grams of Element X, write a function to represent
the mass of the sample after t hours, where the rate of change per minute can be
found from a constant in the function. Round all coefficients in the function to four
decimal places. Also, determine the percentage rate of change per minute, to the
nearest hundredth of a percent.

Answers

The percentage rate of change per minute is approximately 0.98%

The mass of the sample decreases by 59% every hour, so we can write the following differential equation:

dm/dt = -0.59m

Rate of change of the mass (dm/dt) is equal to the mass (m) multiplied by the constant -0.59.

We can solve this differential equation using separation of variables:

dm/m = -0.59 dt

Integrating both sides, we get:

ln|m| = -0.59t + C

where C is the constant of integration.

To find C, we can use the initial condition that the mass of the sample is 530 grams at t=0:

ln|530| = C

C = ln(530)

So the solution to the differential equation is:

ln|m| = -0.59t + ln(530)

[tex]m(t) = 530 e^(^-^0^.^5^9^t^)[/tex]

This function represents the mass of the sample after t hours, where the rate of change per minute is given by the constant

k = -0.59/60 = -0.00983 (rounded to 5 decimal places).

To find the percentage rate of change per minute, we can multiply k by 100 to convert it to a percentage:

-0.00983 × 100 = -0.983%

Therefore, the percentage rate of change per minute is approximately 0.98%

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Choose the correct Set-builder form for
the following set written in Roster form:
{4, 5, 6, 7, 8}

Answers

The value of correct Set-builder form is,

⇒ { x | x ∈ IR ; 4 ≤ x ≤ 8 }

We have to given that;

The set is,

⇒ {4, 5, 6, 7, 8}

Thus, We can write correct Set-builder form as,

⇒ {4, 5, 6, 7, 8}

⇒ { x | x ∈ IR ; 4 ≤ x ≤ 8 }

So, The value of correct Set-builder form is,

⇒ { x | x ∈ IR ; 4 ≤ x ≤ 8 }

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A triangular prism and it’s net are shown below. The top and the bottom of the prism are shaded. All lengths are in centimeters.)

Answers

The solution is: the area of the shaded base in square centimeters is:

B= 15 cm²

Here, we have,

The base of the triangular shaped wedge of cheese is a right-triangle.To find the area of a right-triangle you apply the formula for half base by height.

A=1/2*b*h

 = base area

 = B

In this case, assume the sides of the triangle given are;

a=5 cm and b=6 cm,

thus area will be 1/2*6*5 =15 cm²

Hence, the area of the shaded base in square centimeters is :

B= 15 cm²

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complete question:

Evelyn cut a wedge of cheese into the shape of a triangular prism-like the one shown below. The shaded part represents one of the bases of the prism.

A formula for the volume of a triangular prism is v=Bh . Which equation can be used to find B , the area of the shaded base in square centimeters?

How to provide appropriate commentaries Thet will assist learners in the completing the sum of 8+(6-3)-9

Answers

Answer:

Step-by-step explanation:

8+(6-3)-9

The first action is addition in parentheses

(6-3) = 3

The second action is addition and then subtraction, you can subtract first and then add, it makes no difference because the answer will be the same in all cases

8 + 3 - 9 = 11 - 9 = 2

The number of times 100 groups took a selfie is as follows


find the probability a group will take their selfie exactly 5 times

Answers

Answer: 0.12

Step-by-step explanation:

just divide whatever is under 5 with the total amount of frequency

so then you do 12/100 which is 0.12

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