0.39 recurring as a fraction please [ 3 and 9 are both recurring]

Answer:

Solution : AP = 19 , 15 , 11 , 7 , 3.....

Common difference ( d ) = 15 - 19 = -4.

Answer:

The common difference is -4.

Step-by-step explanation:

Subtract a term from the next term.

11 - 15 = -4

The common difference is -4.

At first, he made [tex]2\frac{5}{8}[/tex] kg of tuna filling.

Mr Abdul made tuna and curry potato filling for some puffs.

3/5 of the filling he made was tuna and the rest was curry potato.

So, amount of curry potato = 1- 3/5 = 2/5

Ratio of tuna & curry potato = tuna : curry potato

                                               = 3/5 : 2/5  = 3 : 2

Let amount of tuna = 3x & amount of curry potato = 2x

After he used 1/8kg of the tuna filling and made another 3/4 kg of curry potato filling.

According to the question, he then had equal amounts of tuna filling and curry potato filling left.

So, 3x - 1/8 = 2x + 3/4

Multiplying 8 in both sides we get,

⇒ 24x - 1 = 16x +6

⇒ 24x - 16x = 7

⇒ 8x = 7

⇒ x = 7/8

So, 3x = (3×7/8) = 21/8 kg = [tex]2\frac{5}{8}[/tex] tuna filling at first.

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Answer:

Reflexive Property

Answer:

y=6,x=0

Step-by-step explanation:

here's an attachment with how to solve

Without the table indicating the stated premium rates and applicable discounts, the monthly property insurance cannot be computed. Hence, on the assumption that the rate is 2.5% and the discount applicable is 7.5% the premium per month will come to $152.24

The simple definition of Property Insurance is, it is an insurance policy that covers a policyholder for the structure of a building and its contents against stated or agreed perils.

Given (based on assumption) that the applicable annual rate is 2.5%

and that:

Hence annual premium will be:

= (67,000 + 12000) * (2.5/100) * 0.925

Annual Premium Payable = $1,826.89.............A

Recall that we are asked to derive the monthly Insurance premium.

This is thus given as: Answer in A/12

→  1,826.89/12

= $152.24

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The solutions of the given equation are x= (√5+3)/2 & x= (-√5+3)/2

If ax²+bx+c = 0 is a quadratic equation ,where a,b,c are real numbers, Then the solution is x = (-b±√(b²-4ac))/2a , where a≠0

The given equation is, 4x²-12x+9 = 5

So, 4x²-12x+9 = 5

⇒ 4x²-12x+9-5 = 0

⇒ 4x²-12x+4 = 0

Comparing this equation with ax²+bx+c = 0 we get,

a = 4, b = -12, c = 4

Applying sridharacharya formula we get,

x = (-(-12)±√((-12)²-4×4×4))/(2×4)

  = (12±√(144-64)/8

  = (12±√80)/8

  = (3±√5)/2

The values of x are (√5+3)/2 & (-√5+3)/2

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Two sets of angles are corresponding angles will be ∠w = ∠v and ∠x = ∠y. Then the correct option is A.

A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.

Two similar triangles are shown below:

Then two sets of angles are corresponding angles will be

∠w = ∠v and ∠x = ∠y

Then the correct option is A.

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Answer:

D

Step-by-step explanation:

On graphing the 3 equations, we find that the central area (triangle) formed by the 3 inequalities is the solution.

Answer:

D

Step-by-step explanation:

When graphing inequalities:

Given inequalities:

[tex]\begin{cases}y > \dfrac{1}{2}x-1\\\\y\leq -x+1\\\\y > -2x-1 \end{cases}[/tex]

From inspection of the given graphs, the red dashed line is the first inequality as it is the only inequality with a positive slope.

The blue sold line is the second inequality, as it is the only inequality with the sign that suggest a solid line.

Therefore, by process of elimination, the green dashed line is the third inequality.

Using the inequality signs and their definitions for shading, find the graph that has:

The only graph that matches these conditions is graph D

Answer:

6 because 30 divided by 5 is 6 so he would have 1$ change

Answer:

Toby can buy 6 T-shirts with 1 extra dollar leftover

Step-by-step explanation:

Hook me up with a 5 star and a thanks :)

Answer:

x = 6

Step-by-step explanation:

.16x + 2 * .02 = (x + 2) * .17
.16x + .4 = .17x + .34
.06 = .01x
6 = x

Answer:

Summer is incorrect

Step-by-step explanation:

It definitely matters which side is side "c".  Side "c" must be the hypotenuse (the side across from the right angle).

The other two sides are the legs (sides touching the right angle), and either leg can be "a" or "b", but the hypotenuse must be "c".

Take the equation, a² + b² = c², and subtract c² from both sides:

[tex]a^{2} +b^{2} -c^{2} =0[/tex]

It won't matter which leg is "a" or "b", because of the commutative property of addition.  Note that "a²" and "b²" are added together, and due to the commutative property of addition, we can add in either order and get the same result.

However, since the c² term is connected by subtraction, and subtraction doesn't have a commutative property, it can't be subtracted in any order.  Meaning which side it is is important.

Answer:     [tex]\boldsymbol{2(x-2)(5x+7)}[/tex]

========================================================

Work Shown:

[tex](4x^2-16)+3(2x-4)(x+1)\\\\4(x^2-4)+3*2(x-2)(x+1)\\\\4(x-2)(x+2)+3*2(x-2)(x+1) \ \text{ ... difference of squares rule}\\\\2*2(x-2)(x+2)+3*2(x-2)(x+1)\\\\2(x-2)(2(x+2)+3(x+1))\\\\2(x-2)(2x+4+3x+3)\\\\\boldsymbol{2(x-2)(5x+7)}\\\\[/tex]

The answer has been confirmed with WolframAlpha which is basically a calculator app, but does a ton more than any average calculator.

The CAS (computer algebra system) in the app GeoGebra is another tool I use all the time.

Yet another way to confirm the answer is to graph the original expression and the answer as separate functions. You should find they produce the exact same curve. One curve perfectly overlaps the other. This visually verifies the two expressions are the same thing, just written a different way of course.

Let me know if you have any questions about any step. The basic idea I did was to pull out the GCF and then combine like terms.

Answer:

x = 21

Step-by-step explanation:

3x - 4 = 2x + 17 because of alternate angles

3x - 2x = 17 + 4

x = 21

The multiplication law states that

So

Answer:

1 = 1

Step-by-step explanation:

We all know the law of exponents,the one we'll use to solve this is the multiplication law:

Solved:

x^0 = 1

Alternate method:

5^3 and 5^3 cancels, which results to

The equivalent expression to given expression is 1/3.

Equivalent expressions are defined as algebraic expressions which give the same resulting expression. An algebraic expression (or) a variable expression is defined as a combination of terms by the operations such as addition, subtraction, multiplication, division.

Here, given expression

    [tex]\sqrt{2/x^2} X \sqrt{x^2/18}[/tex]

=   [tex]\sqrt{2 X x^2/18x^2}[/tex]

=    [tex]\sqrt{1/9}[/tex]

=   1/3

Thus, the equivalent expression to given expression is 1/3.

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Answer:

21% of 456 = 0.21 x 400 + 0.21 x 50 + 0.21 x 6 = 95.76

Step-by-step explanation:

Answer:

g(x) = x^2+4

Step-by-step explanation:

The graph of f(x) = x^2 is translated up 4 units to become g(x) = x^2+4

Answer:

Linear pair of angles are formed when two lines intersect each other at a single point. Therefore, <ADC and <FDA are a linear pair.

Step-by-step explanation:

Answer:

Using the concepts of coordinate system and equation of line, we find that y ≥ (1/3)x + 3 and 3x-y > 2 are represented by the graph.

Step-by-step explanation:

Equation of line passes through points (a, b) and (c, d) is given by:

y-b = [(d-b) / (c-a)] / (x-a)

Given that the first solid line (≤ or ≥) has a positive slope and goes through (0, 3) and (3, 4).

y-3 = [(4-3) / (3-0)] / (x-0)

y-3 = x / 3

y - (1/3)x = 3

Also, everything above the line is shaded, i.e. the inequality represents the first graph: y ≥ (1/3)x + 3

The second dashed line (< or >) has a positive slope and goes through (0, - 2) and (1, 1).

y+2 = [(1+2) / (1-0)](x-0)

y+2 = 3x

3x-y = 2

Everything to the right of the line is shaded.

i.e. inequality represents the second graph: 3x-y > 2

Hence, the system of linear inequalities is represented by the graph :

y ≥ (1/3)x + 3

3x-y > 2

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Answer:

D

Step-by-step explanation:

Got it right on edge 2022

Answer:

d. 15

Step-by-step explanation:

Let A and C be the initial number of marbles Ali and Cho have, respectively.

We are told that:

A = 3C  [Ali had 3 times as many marbles as cho does]

We then discover that  

C-4 = A-18   [After cho gives 4 marbles to Ali, Ali has 18 more marbles than cho does]

How many more marbles does cho have in the beginning?

We have 2 equations and 2 unknowns (A and C).  That means we can likely rearrange one of the equations and isolate one unknown on the left, and then use that in the second equation.

The first equation already has one of the unknowns isolated (A) so I'll use that in equation 2.

Eq. 1:   A = 3C

Eq. 2:  C-4 = A-18

Use the definition of A from Eq. 1 (=3C) to replace A in Eq. 2:

Eq. 2:  C-4 = A-18

          C-4 = (3C)-18    [Replace A with 3C, as promised in E1q. 1]

        -2C = -14

            C=7

If C = 7, then from Eq. 1,  A = 21

In the beginning, Ali has 21 marbles and Cho has 7.

Cho has 15 more marbles than Ali in the beginning.

a. 5

b. 9

c. 10

d. 15

Answer:

Step-by-step explanation:

Comment

Expand the second and 3rd factors first. Then worry about the x.

Solution

x(x + 2)(x + 4)

first: x * x =  x^2

Outside: 4*x = 4x

Inside: 2*x = 2x

Last: 2*4 = 8

Combine

x^2  + 4x + 2x + 8

x^2 + 6x + 8

Now is the time to worry about the extra x

x(x^2 + 6x + 8)

remove the brackets.

x*x^2 + x*6x + 8*x                

Combine

Answer: x^3 + 6x^2 + 8x            

The number of simulations in which was there was an on-time departure for all three flights is; 6

We are given;

Number of Simulations = 20

Numbers that represent late departure = 0, 1, 2 or 3

Numbers that represent On-time departure = 4, 5, 6, 7, 8 or 9.

Now, the 20 simulations as seen online are;

339 931 317 444 432 858 194 192 649 709

742 626 702 258 955 880 505 854 774 132

To know the number of simulations that were on-time departure, we need to find the ones that don't include 0, 1, 2 or 3.

Looking at the simulations, the ones that represent on-time departure are 444, 858, 649, 955, 854, 774.

Thus, there are 6 simulations in which was there an on-time departure for all three flights

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Answer:

(2*2*1.5*1/3)+(2*1.5*4)= 14

Step-by-step explanation:

To find the area of a pyramid, you use the equation of 1/3 *lwh. When we place the values in there, we get 2*2*1.5*1/3, which is equal to 2. Then we solve the bottom part. Since it is a rectangular prism, we use the equation of lwh. When we insert the values, we get 2*1.5*4, which is equal to 12. Now, we take these two values of 2 and 12 and we combine them, giving us our final answer of 14.

Step-by-step explanation:

I am not sure what your problem here is.

you understand the inequality signs ?

anyway, to get

6×f(-2) + 3×g(1)

we can calculate every part of the expression separately, and then combine all the results into one final result.

f(-2)

we look at the definition.

into what category is -2 falling ? the one with x<-2, or the one with x>=-2 ?

is -2 < -2 ? no.

is -2 >= -2 ? yes, because -2 = -2. therefore, it is also >= -2.

so, we have to use

1/3 x³

for x = -2 that is

1/3 × (-2)³ = 1/3 × -8 = -8/3

g(1)

again, we look at the definition.

into what category is 1 falling ? the one with x > 2 ? or the one with x <= 1 ?

is 1 > 2 ? no.

is 1 <= 1 ? yes, because 1=1. therefore it is also <= 1.

so we have to use

2×|x - 1| + 3

for x = 1 we get

2×0 + 3 = 3

6×f(-2) = 6 × -8/3 = 2× -8 = -16

3×g(1) = 3× 3 = 9

and so in total we get

6×f(-2) + 3×g(1) = -16 + 9 = -7

The equation is [tex]f(t)=50(0.5)^{\frac {10}{5.3}}[/tex] and approximately 13.52  milligram remains

The missing information in the question is:

[tex]f(t)=m(0.5)^{\frac th}[/tex]

When the mass is 50 mg, it means that:

m = 50

So, we have:

[tex]f(t)=50(0.5)^{\frac th}[/tex]

When 10 years remain in the life of the substance, it means that:

t = 10

So, we have:

[tex]f(t)=50(0.5)^{\frac {10}h}[/tex]

The half life is 5.3. So, we have

[tex]f(t)=50(0.5)^{\frac {10}{5.3}}[/tex]

Evaluate the equation

f(t) = 13.52

Hence, the required equation is [tex]f(t)=50(0.5)^{\frac {10}{5.3}}[/tex] and approximately 13.52  milligram remains

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Answer:c

Step-by-step explanation:

It is to be noted that the Graph of the indicated inequalities is herewith attached.

As indicated above, this is a graph of a system of inequalities, where:

Y > -4x-1 and

y <3/2x-1

No. the point (-1, 1) is not included in the solution area for the system.

Step 1 - Plug in (-1, 1) in to the first equation. where y = -1 and x = 1.

Hence,

-1 > -4(1) -1

4 +1 < -1

4 < 0 (This is False)

Step 2  - Plug in (-1, 1) in to the second equation. where y = -1 and x = 1.

-1 < (3/2)(1) - 1

-1 < 1/2 (This is true).

Thus (-1, 1) is only partially included in the solution area.)

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